I'm still new to coding and I don't know how to split string in the stateful widget.
to split String str = "Hello World!";
you can simply use split method like str.split(' ')
Refer this official documentation.
You can use String's .split() method to achieve this, passing in a string containing just a space as your delimiter. For example:
'Hello World'.split(' ') will return ['Hello', 'World'].
Related
Does anyone know a method that allows you to replace all the characters in a word with a single character?
If not, can anyone suggest a way to basically print _ (underscore) the number of times which is the length of the string itself without using any loops or ifs in the code?
mystring = '_'*len(mystring)
Of course, I'm guessing at the name of your string variable and the character that you want to use.
Or, if you just want to print it out, you can:
print('_'*len(mystring))
import re
str = "abcdefghi"
print(re.sub('[a-z]','_',str))
I am a beginner in programming. I have a string for example "test:1" and "test:2". And I want to remove ":1" and ":2" (including :). How can I do it using regular expression?
Hi andrew it's pretty easy. Think of a string as if it is an array of chars (letters) cause it actually IS. If the part of the string you want to delete is allways at the end of the string and allways the same length it goes like this:
var exampleString = 'test:1';
exampleString.length -= 2;
Thats it you just deleted the last two values(letters) of the string(charArray)
If you cant be shure it's allways at the end or the amount of chars to delete you'd to use the version of szymon
There are at least a few ways to do it with Groovy. If you want to stick to regular expression, you can apply expression ^([^:]+) (which means all characters from the beginning of the string until reaching :) to a StringGroovyMethods.find(regexp) method, e.g.
def str = "test:1".find(/^([^:]+)/)
assert str == 'test'
Alternatively you can use good old String.split(String delimiter) method:
def str = "test:1".split(':')[0]
assert str == 'test'
I have a raw string literal which is very long. Is it possible to split this across multiple lines without adding newline characters to the string?
file.write(r#"This is an example of a line which is well over 100 characters in length. Id like to know if its possible to wrap it! Now some characters to justify using a raw string \foo\bar\baz :)"#)
In Python and C for example, you can simply write this as multiple string literals.
# "some string"
(r"some "
r"string")
Is it possible to do something similar in Rust?
While raw string literals don't support this, it can be achieved using the concat! macro:
let a = concat!(
r#"some very "#,
r#"long string "#,
r#"split over lines"#);
let b = r#"some very long string split over lines"#;
assert_eq!(a, b);
It is possible with indoc.
The indoc!() macro takes a multiline string literal and un-indents it at compile time so the leftmost non-space character is in the first column.
let testing = indoc! {"
def hello():
print('Hello, world!')
hello()
"};
let expected = "def hello():\n print('Hello, world!')\n\nhello()\n";
assert_eq!(testing, expected);
Ps: I really think we could use an AI that recommend good crates to Rust users.
Here is my problem
String text = "I am here"
resutl = ofy().load().type(M.class).filter("good = "+text).first().now();
Since text contains space, how do I pass it to Objectify? Do I place it in single quotes? double quotes? what?
The filter() method takes two parameters:
ofy().load().type(M.class).filter("good =", text).first().now();
There is no need to escape the value.
ofy().load().type(M.class).filter("good",text).first().now()
There is no need for "=". It is a default operator.
Suppose I have a string "That question is on the minds of every one.".
I want to compare each word in string with a set of word I.e. (to , is ,on , of) and if those word occurs I want to append some string on the existing string.
Eg.
to = append "Hi";
Is = append "Hello";
And so on.
To be more specific I have used StringTokenizer to get the each word and compared thru if else statement. However we can use Switch also but it is available in Jdk 1.
7.
I don't know if this is what you mean, but:
You could use String.split() to separate the words from your string like
String[] words = myString.split(" ");
and then, for each word, compare it with the given set
for(String s : words)
{
switch(s)
{
case("to"):
[...]
}
}
Or you could just use the String.contains() method without even splitting your string, but I don't know if that's what you wanted.
Use a HashMap<String,String> variable to store your set of words and the replacement words you want. Then split your string with split(), loop through the resulting String[] and for each String in the String[], check whether the HashMap containsKey() that String. Build your output/resulting String in the loop - if the word is contained in the HashMap, replace it with the value of the corresponding key in the HashMap, otherwise use the String you are currently on from the String[].