I have to make a code taking a name and turning it into a last name, first initial and middle initial format - python-3.x

Question

I have to make a code taking a name and turning it into a last name, first initial, middle initial format. My code works assuming there is a middle name but breaks if not provided a middle name. Is there a way to ignore not having a middle name and to just default to last name and first initial? I'm super new to python3 so I'm sorry if my code is uber bad.
Heres my code :
your_name = input()
broken_name = your_name.split()
first_name = broken_name[0]
middle_name = broken_name[1]
last_name = broken_name[2]
middle_in = middle_name[0]
first_in = first_name[0]
print(last_name+',',first_in+'.'+middle_in+'.' )

Answer 1

You can use an if else statement to check how long broken_name is.
Try:
your_name = input()
broken_name = your_name.split()
if len(broken_name) > 2:
first_name = broken_name[0]
middle_name = broken_name[1]
last_name = broken_name[2]
middle_in = middle_name[0]
first_in = first_name[0]
print(last_name+', ',first_in+'. '+middle_in+'.'
else:
first_name = broken_name[0]
last_name = broken_name[1]
first_in = first_name[0]
print(last_name+', ',first_in+'.')

Answer 2

Another option:
def get_pretty_name_str(names):
splited_names = names.split()
last_name = splited_names.pop(-1)
result = f'{last_name},'
while splited_names:
n = splited_names.pop(0)
result += f'{n}.'
return result
print(get_pretty_name_str('First Middle Last')) # Last,First.Middle.
print(get_pretty_name_str('First Last')) # Last,First.