I'm trying to play sound files (.wav) with pygame but when I start it I never hear anything.
This is the code:
import pygame
pygame.init()
pygame.mixer.init()
sounda= pygame.mixer.Sound("desert_rustle.wav")
sounda.play()
I also tried using channels but the result is the same
For me (on Windows 7, Python 2.7, PyGame 1.9) I actually have to remove the pygame.init() call to make it work or if the pygame.init() stays to create at least a screen in pygame.
My example:
import time, sys
from pygame import mixer
# pygame.init()
mixer.init()
sound = mixer.Sound(sys.argv[1])
sound.play()
time.sleep(5)
sounda.play() returns an object which is necessary for playing the sound. With it you can also find out if the sound is still playing:
channela = sounda.play()
while channela.get_busy():
pygame.time.delay(100)
I had no sound from playing mixer.Sound, but it started to work after i created the window, this is a minimal example, just change your filename, run and press UP key to play:
WAVFILE = 'tom14.wav'
import pygame
from pygame import *
import sys
mixer.pre_init(frequency=44100, size=-16, channels=2, buffer=4096)
pygame.init()
print pygame.mixer.get_init()
screen=pygame.display.set_mode((400,400),0,32)
while True:
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
if event.type == KEYDOWN:
if event.key==K_ESCAPE:
pygame.quit()
sys.exit()
elif event.key==K_UP:
s = pygame.mixer.Sound(WAVFILE)
ch = s.play()
while ch.get_busy():
pygame.time.delay(100)
pygame.display.update()
What you need to do is something like this:
import pygame
import time
pygame.init()
pygame.mixer.init()
sounda= pygame.mixer.Sound("desert_rustle.wav")
sounda.play()
time.sleep (20)
The reason I told the program to sleep is because I wanted a way to keep it running without typing lots of code. I had the same problem and the sound didn't play because the program closed immediately after trying to play the music.
In case you want the program to actually do something just type all the necessary code but make sure it will last long enough for the sound to fully play.
import pygame, time
pygame.mixer.init()
pygame.init()
sounda= pygame.mixer.Sound("beep.wav")
sounda.play()
pygame.init() goes after mixer.init(). It worked for me.
I had the same problem under windows 7. In my case I wasn't running the code as Administrator. Don't ask me why, but opening a command line as administrator fixed it for me.
I think what you need is pygame.mixer.music:
import pygame.mixer
from time import sleep
pygame.mixer.init()
pygame.mixer.music.load(open("\windows\media\chimes.wav","rb"))
pygame.mixer.music.play()
while pygame.mixer.music.get_busy():
sleep(1)
print "done"
You missed to wait for the sound to finish. Your application will start playing the sound but will exit immediately.
If you want to play a single wav file, you have to initialize the module and create a pygame.mixer.Sound() object from the file. Invoke play() to start playing the file. Finally, you have to wait for the file to play.
Use get_length() to get the length of the sound in seconds and wait for the sound to finish:
(The argument to pygame.time.wait() is in milliseconds)
import pygame
pygame.mixer.init()
sounda = pygame.mixer.Sound('desert_rustle.wav')
sounda.play()
pygame.time.wait(int(sounda.get_length() * 1000))
Alternatively you can use pygame.mixer.get_busy to test if a sound is being mixed. Query the status of the mixer continuously in a loop.
In the loop, you need to delay the time by either pygame.time.delay or pygame.time.Clock.tick. In addition, you need to handle the events in the application loop. See pygame.event.get() respectively pygame.event.pump():
For each frame of your game, you will need to make some sort of call to the event queue. This ensures your program can internally interact with the rest of the operating system.
import pygame
pygame.init()
pygame.mixer.init()
sounda = pygame.mixer.Sound('desert_rustle.wav')
sounda.play()
while pygame.mixer.get_busy():
pygame.time.delay(10)
pygame.event.poll()
Your code plays desert_rustle.wav quite fine on my machine (Mac OSX 10.5, Python 2.6.4, pygame 1.9.1). What OS and Python and pygame releases are you using? Can you hear the .wav OK by other means (e.g. open on a Mac's terminal or start on a Windows console followed by the filename/path to the .wav file) to guarante the file is not damaged? It's hard to debug your specific problem (which is not with the code you give) without being able to reproduce it and without having all of these crucial details.
Just try to re-save your wav file to make sure its frequency info. Or you can record a sound to make sure its frequency,bits,size and channels.(I use this method to solve this problem)
I've had something like this happen. Maybe you have the same problem? Try using an absolute path:
import pygame
pygame.init()
pygame.mixer.init()
sounda= pygame.mixer.Sound("/absolute_path/desert_rustle.wav")
sounda.play()
Where abslute_path is obviously replaced with your actual absolute path ;)
good luck.
import pygame
pygame.init()
sound = pygame.mixer.Sound("desert_rustle.wav")
pygame.mixer.Sound.play(sound)
This will work on python 3
5 years late answer but I hope I can help someone.. :-)
Firstly, you dont need the "pygame.init()"-line.
Secondly, make a loop and play the sound inside that, or else pygame.mixer will start, and stop playing again immediately.
I got this code to work fine on my Raspberry pi with Raspbian OS.
Note that I used a while-loop that continues to loop the sound forver.
import pygame.mixer
pygame.mixer.init()
sounda = pygame.mixer.Sound("desert_rustle.wav")
while True:
sounda.play()
Just try:
import pygame.mixer
from time import sleep
pygame.mixer.init()
pygame.mixer.music.load(open("\windows\media\chimes.wav","rb"))
print ""
pygame.mixer.music.play()
while pygame.mixer.music.get_busy():
sleep(1)
print "done"
This should work. You just need to add print ""and the sound will have
had time to load its self.
Many of the posts are running all of this at toplevel, which is why the sound may seem to close. The final method will return while the sound is playing, which closes the program/terminal/process (depending on how called).
What you will eventually want is a probably a class that can call either single time playback or a looping function (both will be called, and will play over each other) for background music and single sound effects.
Here is pattern, that uses a different event loop / run context other than Pygame itself, (I am using tkinter root level object and its init method, you will have to look this up for your own use case) once you have either the Pygame.init() runtime or some other, you can call these methods from your own logic, unless you are exiting the entire runtime, each file playback (either single use or looping)
this code covers the init for ONLY mixer (you need to figure our your root context and where the individual calls should be made for playback, at least 1 level inside root context to be able to rely on the main event loop preventing premature exit of sound files, YOU SHOULD NOT NEED TIME.SLEEP() AT ALL (very anti-pattern here).... ALSO whatever context calls the looping forever bg_music, it will probably be some 'level' or 'scene' or similar in your game/app context, when passing from one 'scene' to the next you will probably want to immediately replace the bg_music with the file for next 'scene', and if you need the fine-grained control stopping the sound_effect objects that are set to play once (or N times)....
from pygame import mixer
bg_music = mixer.Channel(0)
sound_effects = mixer.Channel(1)
call either of these from WITHIN your inner logic loops
effect1 = mixer.Sound('Sound_Effects/'+visid+'.ogg')
sound_effects.play(effect1, 0)
sound1 = mixer.sound('path to ogg or wav file')
bg_music.play(sound1, -1) # play object on this channel, looping forever (-1)
do this:
import pygame
pygame.mixer.init()
pygame.mixer.music.load("desert_rustle.wav")
pygame.mixer.music.play(0)
I think that your problem is that the file is a WAV file.
It worked for me with an MP3. This will probably work on python 3.6.
Related
I have a QMediaPlayer object, which if I try to get the duration of before letting the file buffer enough, will return -1. To my understanding, this is because the file is loaded asynchronously and duration (and subsequently position) cannot be known since it is unknown if the file is fully loaded yet.
My initial idea to solve this was to run media.play(), immediately followed by media.stop(). This does absolutely nothing. Then, I considered running media.play() and media.pause(). This does not work either. I imagine this is because the media needs to buffer for a significant period of time before the duration can be obtained. Also, this "solution" would not have been ideal regardless.
How can I get the duration of a QMediaPlayer object before the file has been played?
One possible solution is to use the durationChanged signal:
from PyQt5 import QtCore, QtMultimedia
if __name__ == '__main__':
import sys
app = QtCore.QCoreApplication(sys.argv)
player = QtMultimedia.QMediaPlayer()
#QtCore.pyqtSlot('qint64')
def on_durationChanged(duration):
print(duration)
player.stop()
QtCore.QCoreApplication.quit()
player.durationChanged.connect(on_durationChanged)
file = "/path/of/small.mp4"
player.setMedia(QtMultimedia.QMediaContent(QtCore.QUrl.fromLocalFile(file)))
player.play()
sys.exit(app.exec())
from gtts import *
import os
import vlc
def sauvegarde(text,i):
tts = gTTS(text, lang='fr')
tts.save("text"+str(i)+".mp3")
def play(file):
p = vlc.MediaPlayer(file)
p.play()
text = "Salut Santo c\'est Alexis, ton maitre qui te parle"
text2="Bonjour Santo"
sauvegarde(text,1)
sauvegarde(text2,2)
play("text1.mp3")
play("text2.mp3")
os.system("pause")
When I run this code the two .mp3 files that I created previously are being played at the same time. Any ideas how to play the second one after the first is finished?
vlc doesn't seem to have a blocking version of play as far as I can tell, so probably the easiest way to accomplish this is to manually wait for the first mp3 to finish. So to make a blocking version of your play function, try something like this:
import time
def play(file):
p = vlc.MediaPlayer(file)
p.play()
while(p.is_playing()):
time.sleep(0.1)
This will check is p is still playing every 100ms. Only when it is done playing, the play function will return.
Alternatively, you can use vlc.MediaListPlayer and vlc.MediaList to create a playlist containing your mp3's.
I'm using Python 3.5 and Pyglet 1.2.4 on OS X 10.11.5. I am very new to this setup.
I am trying to see if I can use event handling to capture keystrokes (without echoing them to the screen) and return them to the main program one at a time by separate invocations of the pyglet.app.run method. In other words I am trying to use Piglet event handling as if it were a callable function for this purpose.
Below is my test program. It sets up the Pyglet event mechanism and then calls it four times. It works as desired but causes the system messages shown below.
import pyglet
from pyglet.window import key
event_loop = pyglet.app.EventLoop()
window = pyglet.window.Window(width=400, height=300, caption="TestWindow")
#window.event
def on_draw():
window.clear()
#window.event
def on_key_press(symbol, modifiers):
global key_pressed
if symbol == key.A:
key_pressed = "a"
else:
key_pressed = 'unknown'
pyglet.app.exit()
# Main Program
pyglet.app.run()
print(key_pressed)
pyglet.app.run()
print(key_pressed)
pyglet.app.run()
print(key_pressed)
pyglet.app.run()
print(key_pressed)
print("Quitting NOW!")
Here is the output with blank lines inserted for readability. The first message is different and appears even if I comment out the four calls to piglet.app.run. The double release messages do not occur after every call to event handling and do not appear in a consistent manner from one test run to the next.
/Library/Frameworks/Python.framework/Versions/3.5/bin/python3.5 "/Users/home/PycharmProjects/Test Event Handling/.idea/Test Event Handling 03B.py"
2016-07-28 16:49:59.401 Python[11419:4185158]ApplePersistenceIgnoreState: Existing state will not be touched. New state will be written to /var/folders/8q/bhzsqtz900s742c17gkj_y740000gr/T/org.python.python.savedState
a
2016-07-28 16:50:02.841 Python[11419:4185158] *** -[NSAutoreleasePool drain]: This pool has already been drained, do not release it (double release).
2016-07-28 16:50:03.848 Python[11419:4185158] *** -[NSAutoreleasePool drain]: This pool has already been drained, do not release it (double release).
a
a
2016-07-28 16:50:04.632 Python[11419:4185158] *** -[NSAutoreleasePool drain]: This pool has already been drained, do not release it (double release).
a
Quitting NOW!
Process finished with exit code 0
Basic question: Why is this happening and what can I do about it?
Alternate question: Is there a better way to detect and get a users keystrokes without echoing them to the screen. I will be using Python and Pyglet for graphics so I was trying this using Pyglet's event handling.
Try to play with this simple example. It uses the built-in pyglet event handler to send the key pressed to a function that can then handle it. It shows that pyglet.app itself is the loop. You don't need to create any other.
#!/usr/bin/env python
import pyglet
class Win(pyglet.window.Window):
def __init__(self):
super(Win, self).__init__()
def on_draw(self):
self.clear()
# display your output here....
def on_key_press(self, symbol, modifiers):
if symbol== pyglet.window.key.ESCAPE:
exit(0)
else:
self.do_something(symbol)
# etc....
def do_something(symbol):
print symbol
# here you can test the input and then redraw
window = Win()
pyglet.app.run()
I'm making a program that displays a messagebox and plays a .wav file through a thread at the same time. The problem is, the sound file is big, and I would like it to stop playing after I press 'OK'. Any help would be appreciated. I'm using Python 3.3 on Windows 7. Here's my code for the box and audio:
t1 = threading.Thread(target=winsound.PlaySound, args=("C:/Interactive Program/LIP Source Files/skyisup.wav", 2))
t1.start()
lipgui.msgbox("The sky is up!")
I fixed it. What I needed to do was pass winsound.SND_ASYNC to winsound.PlaySound() instead of '2'. Then stop the audio by passing winsound.PlaySound(None, 0)!
For background, I'm running
Debian Lenny, and have tried this with both GNOME and Fluxbox.
Anyway, I've been looking at how to draw on the desktop, and I found and tried this code here:
http://blog.prashanthellina.com/2007/08/24/drawing-on-your-desktop/
It worked fine, except upon terminating it (by hitting control C), X loses it's ability to create new windows.
I had thought that maybe the problem was pygame not releasing some resource, so I added in a block of code to trap the kill signal, giving me the following:
"""
Run the following command in the shell before executing this script
export SDL_WINDOWID=`xwininfo -root|grep "id:"|sed 's/^.*id: //'|sed 's/ (.*$//'`
"""
import pygame
import sys
import random
import time
import signal
pygame.init()
window = pygame.display.set_mode((1280, 1024))
screen = pygame.display.get_surface()
def handle_sigint(signum, frame):
"""I want to ensure resources are released before bailing."""
print("SIGINT received.");
pygame.display.quit()
pygame.quit()
sys.exit(0)
# Set handler to catch C^C Interupts
signal.signal(signal.SIGINT, handle_sigint)
while 1:
for event in pygame.event.get():
if event.type == pygame.QUIT: sys.exit(0)
x = random.choice(range(640))
y = random.choice(range(480))
radius = random.choice(range(100))
col_r = random.choice(range(255))
col_g = random.choice(range(255))
col_b = random.choice(range(255))
time.sleep(.03)
rect = pygame.draw.circle(screen, (col_r, col_g, col_b), (x,y), radius)
pygame.display.update(rect)
And so I tried again. The print statement in the interrupt handler tells me that the handler does run when I quit, but I still have the same problem. And even more interestingly, X has no problems while it's running. It's only after terminating it.
Might anybody out there have any idea what's happening, and what I can do to fix the code so it doesn't wreck my X session? Thanks in advance.
Questions, ideas & things to try:
If you have a terminal up before you try a -c, can you still type in it after? If yes, there's likely a problem in your session or window manager, not the x server.
Have you tried Ctrl-Alt-Backspace? Does this fix your problem?
Are gtk-window-decorator and x-session-manager still running?
pygame is typically run out of a window and is normally going to try to cleanup after itself. You've added an explicit call to pygame.display.quit(), but I don't think this changes anything - pygame tries to delete the window referred to by the SDL_WINDOWID variable. Actually succeeding in deleting your root window is probably a bad thing. I'm going to guess that the guy you got this from, running ubuntu, pygame fails to delete the window because he doesn't have permission. You might on your OS.
Since killing your root window is bad, how about just restoring control of the root window back to nautilus (gnome)? something like gconftool-2 --type bool --set /apps/nautilus/preferences/show_desktop true?