i have a data sheet where there are 5 entries of gate passes in a single row. now to evaluate the rows, i need the data to be divided into rows for the same single row of 5 items.
picture 1
Picture 2
plz help.
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I have exported a list of items from a website, this data all sits in row one with different 'types' of data in every 8th row.
For example The name of the first item item is in row 1, with its date in row 2 and a barcode in row 3 etc
The second product name is in row 8 with its corresponding date in row 9 and its barcode in row 10 etc
I would like to rearrange this into columns so that every 8th row goes into a column. Does anyone know how to do this please?
I have tried transposing the data but this does not work.
See the current data format from my sheet below:
The format I would like is as below:
You can use INDIRECT and ADDRESS functions:
=INDIRECT(ADDRESS(COLUMN(A1)+(7*(ROW(A2)-2)) - COLUMN($A$1) + ROW($A$1); ROW(A$1) - ROW($A$1) + COLUMN($A$1)))
I have a spreadsheet with sales data for a given month for a number of different stores. There are approximately 450 rows (stores) to go through. The days of the month are in row 1, starting in column B, with the store numbers in column A, starting in row 2. What I need to find are the rows that are missing data for different days. I can use conditional formatting to highlight the cells that are empty, but that is still a lot to look at. What I am trying to do is reduce the amount of cells to look at by deleting any rows that are not missing data. So if a row is not missing any days of data, then I don't need to look at it, and can delete it. But if it is missing data, then keep the row.
I'm stuck on figuring out the actual code, but I have come up with pseudo code for what I want:
foreach row in range ($B$2:$AB$450)
foreach cell in row
if cell < 1
delete row
end foreach
end foreach
Here is an example of the spreadsheet:
A B C D
1 12/1/2019 12/2/2019 12/3/2019
2 Site 1 1000 2000
3 Site 2 5000 5000 3000
4 Site 3 6000 4000 3000
In this example, rows 4 and 4 would be deleted because they are not missing any data.
Thanks
**assuming that you have 4 columns and they start in column B:
with an array formula you can see the length of characters in each row.
=MIN(LEN(B2:E2))
for example, you can use the above formula in row 2 (remember: ctrl+shift+enter to use it)
So, if you apply that formula per row, you should be able to know if you have missing value per row (all of them that have length 0 per row); then, use that column to filter. E.g. Filter anything that is not 0.
how can I merge two columns of data into one like the following:
Col1 Col2 Col3
========================
A 1 A
B 2 1
C 3 B
2
C
3
You can use the following formula in column D as per my example. Keep in mind to increase the $A$1:$B$6 range according to your data.
=INDEX($A$1:$B$6,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
Result:
Thank you to #Koby Douek for the answer. Just an addition--if you are using Open Office Calc, you replace the commas with semi-colons.
=INDEX($A$1:$B$6;INT((ROWS(D$2:D2)-1)/2)+1;MOD(ROWS(D$2:D2)-1;2)+1)
Expanding #koby Douek's answer to more columns and explaining some of the terms
Original Code for 2 columns to 1 alternating
=INDEX($A$1:$B$6,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
$A$1:$B$6 Defines the columns and rows to source the final set of data from, the $s are only present to keep the formula from changing the columns and rows selects if it is copied and pasted or dragged.
To extend to work on any values you dump into the columns instead of having to expand the range every time it should be amended to $A:$B or A:B so you can easily copy it to other sets of columns and create new merges, but it will also give the 1st value in every column as one of the alternating values so if you instead have headers you would be able to do this by instead using a large number so $A$1:$B$99999 or A$1:B$99999 if you want to past and move the columns ymmv which is better by situation.
lets assume you are fine including the values in the 1st row
This changes the formula to
=INDEX($A:$B,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
Now on to D$2:D2
This is the row that is being used to calculate the difference between the current row the formula is in (D2) and the reference row (D$2) The important thing to make sure you do is to set the reference row number to the 1st row you will be putting values in, so if your 1st row is a header in the sort column you will use the 2nd row as the reference, if your values in the combined column D begin on the 3rd row then the reference row would be D$3
Since I like the more general form where the 1st row isn't a header row I'll use D$1:D1 but you could still mix source rows without headers into a combined row with a header of as many rows as you like just by incrementing that reference row number to be the 1st row where your values should begin.
This changes the formula to
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/2)+1,MOD(ROWS(D$1:D1)-1,2)+1)
Now INT((ROWS(D$1:D1)-1)/2)+1 and MOD(ROWS(D$1:D1)-1,2)+1
INT returns an integer value so any decimal places are dropped, it essentially functions like rounding down to the nearest whole number
MOD functions by returning the remainder of a division, it's result will be a whole number between 0 and n-1 where n is the number we are dividing by. (eg: 0/3=0; 1/3=1; 2/3=2; 3/3=0; 4/3=1 ... etc)
So -1)/2)+1 and -1,2)+1
the first value is again the difference between the current row and the reference row. but D$1:D1 is going to be the count of the rows, which is 1 so we have to correct for the rows count starting at 1 instead of 0 which would throw off our calculations, so both are using the -1 to reduce the count of the rows by 1
in the case of /2 and ,2 both are because we are dividing by 2 in the first statement it's a normal division by 2 /2 in the modulus statement it's an argument of the Mod function so ,2
finally we need to add 1 using +1 to correct for the index's need to have a value series which begins at 1.
INT((ROWS(D$2:D2)-1)/2)+1 is finding the row number to select the value from.
MOD(ROWS(D$1:D1)-1,2)+1 is finding the column number to select the value from
Thus we can change /2 and ,2 to /3 and ,3 to do this with 3 columns
This yields:
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/3)+1,MOD(ROWS(D$1:D1)-1,3)+1)
So maybe that's the confusing way to look at it but it's closer to how my mind works on it. Here is an alternative view:
=INDEX([RANGE],[ROW_#],[COLUMN_#]) returns the value from a range of rows and columns
Using the example:
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/3)+1,MOD(ROWS(D$1:D1)-1,3)+1)
[RANGE] = $A:$B this is the range of source columns.
[ROW_#] = INT((ROWS(D$1:D1)-1)/3)+1
INT([VALUE_A])+1 returns an integer value so any decimal places are dropped. Then adds one to it. we add one to the value because the result of the next steps will be 1 less than the value we need.
[Value_A] = (ROWS(D$1:D1)-1)/3
ROWS(D$1:D1) returns the number of rows in the Range to the current row in the results column, we use D$1 to designate the row number where the values in the results column begin. D1 is the current row in the results column giving us a range from the source row, allowing us to count the rows. we have to subtract 1 from this value using -1 to get the difference between the source and current. This is then divided by /3 because we have three columns we want to look through in this example so we only change rows when the result is divisible by 3. the INT drops any decimal places as mentioned so it only increments when cleanly divisible by 3.
[COLUMN_#] = MOD(ROWS(D$1:D1)-1,3)+1
MOD([VALUE],[Divisor])+1 returns the remainder of the value when divided by the divisor.
Using the example:
MOD(ROWS(D$1:D1)-1,3)+1
In this case we still divide by 3 but it's an argument to the MOD function, we still need to count the number of rows and subtract 1 before dividing it, this will return a 0, 1, or 2 for the column, but as above we are shifted backwards by 1 as the column numbers begin with the number 1, so as before we must add 1
And here we add column A and D
two different formulas depending on if you add the formula to an odd row or an even row.
https://1drv.ms/x/s!AncAhUkdErOkguUaToQkVkl5Qw-l_g?e=5d9gVM
Odd Start row
=INDEX($A$2:$D$9;ROUND(ROW(A1)/2;0);IF(MOD(ROW()-ROW($A$2);2)=1;4;1))
Even Start row
=INDEX($A$2:$D$9;ROUND(ROW(A1)/2;0);IF(MOD(ROW()-ROW($A$1);2)=1;4;1))
What is A1 in the picture is the cell directly above your first data cell.
If you want to place it on a different sheet you just add the sheet name:
=INDEX(MySheet!$A$2:$D$9;ROUND(ROW(MySheet!A1)/2;0);IF(MOD(ROW()-ROW(MySheet!$A$2);2)=1;4;1))
=INDEX(MySheet!$A$2:$D$9;ROUND(ROW(MySheet!A1)/2;0);IF(MOD(ROW()-ROW(MySheet!$A$1);2)=1;4;1))
I have data in an excel spreadsheet. It is arranged as follows: 6 rows with 15 columns. Then a 7th row with 8 columns. Then 6 rows with 15 columns and a 7th row with 8 columns. This repeats down the spreadsheet. There are 441 'blocks' of this pattern.
There are two options that I have for this data.
Option 1: I would like it to be in a single column, so the values from the first row are now the first 15 values in column 1, then the values from the second row are now the next 15 values in column 1, and so on.
Option 2: I would like the values to be formatted in a grid that is 98 columns ad 441 rows. The data from the first 'block' would be the first row. the data from the second 'block' would be the second row.
Is there any way that this can be done?
Option 1 is possible with unpivoting. Assuming your data starts in A1, insert a new row at the top and a new column at the left and apply the steps detailed here. From the Table delete the left-hand two columns and filter the remaining column to delete blank rows.
For Option 2 consider OFFSET.
I have searched through many similar topics but could find nothing that will do what I need.
I am trying to create a worksheet that will track scores for a darts game.
On Sheet 1 I have two columns that simply tracks each players throws from 501 down to 0
Row 25 is the amount remaining for each player.
In Sheet 2 I have 2 columns. The Column A contains scores that you can check out on, and Column B contains the checkout e.g. (T20, T20, D18). So if the value in row 25 of Sheet 1 matches any of the values in Column A of sheet 2, the I want to display the Value of Column B in the matching row on Sheet 2 Underneath the remaining score on Sheet 1.
Can anyone point me in the right direction?
not sure what you mean exactly, but this formula in row 26 should do the trick:
=index('Sheet 2'!$B:$B;match(A25;'Sheet 2'!$A:$A;0))
if your list separator is comma ,, use that instead of semicolon ;
you might want to use 1 as the third argument of match function, if you want to display the checkout according to the nearest match that is bigger than the number in row 25 and the column A in Sheet 2 is sorted in ascending order (1-9)
or -1 if you want the nearest match that is smaller and column A is sorted in descending order (9-1)
You can use this:
=IFERROR(VLOOKUP(A4, Sheet2!$C$2:$E$65535, 3, FALSE),0)