I'm looking for a script that could tell me all possible combinations
input (9)
output (8+1)(7+2)(6+3)(5+4)(9)
input (10)
output (9+1)(8+2)(7+3)(6+4)(5+5)(10)
I would still appreciate the ability to select as many digits as possible
in the example it is 2 to 1 (even if only two is enough)
something this way
there should be an exit at three
input (10)
output (7+1+2)(6+3+1)(5+4+1)(4+4+2)(3+6+2)(1+6+3)
here is at least part of the possible results
I'm a beginner and the only thing I can do is combine all the words but this is at another level thank you for your help
word = ""
word_array = []
for c in word:
word_array.append(c)
import itertools
results = list(itertools.permutations(word_array))
o = ""
for r in results:
o += "".join(r)+"\r\n"
print("".join(r))
f = open(""+str(word)+".txt", "a")
f.write(o)
f.close()
exit()
Related
i'm a beginner programmer, and i want to ask about count the many letters in a sentence.
For the example program like this :
data = "Hello World"
s = input() # Try to input L
Output :
L = 3
So the output is just what i input, not with other letters like w, o, r, d, h, e. I wrote some code but i dont know why the output sometimes None or 11 or 0. Here the code i write with output 0
data = "Hello World"
s = input()
sum = 0
for s in data :
if s == data :
sum += 1
print(sum)
Any suggestion for what i can do to write the program like i want ?
If I am not wrong, what I understood from your problem is that you wish to count the total number of times an alphabet appears in a string and then print the total number of times it occurred in the sentence.
In order to achieve this, I can show you two methods:
Method 1:
Naive approach:
data="Hello World"
s=input() # Assume you put 'l'
count = 0
for i in data:
if i == s:
count = count + 1
print(count)
Doing so, you will get output as 3
Method 2:
Using count():
data="Hello World"
counter = data.count('l')
print("Count of l in data is : " + str(counter))
Hope this answered you query.
Writing a Python program (ver. 3) to count strings in a specified field within each line of one or more csv files.
Where the csv file contains:
Field1, Field2, Field3, Field4
A, B, C, D
A, E, F, G
Z, E, C, D
Z, W, C, Q
the script is executed, for example:
$ ./script.py 1,2,3,4 file.csv
And the result is:
A 10
C 7
D 2
E 2
Z 2
B 1
Q 1
F 1
G 1
W 1
ERROR
the script is executed, for example:
$ ./script.py 1,2,3,4 file.csv file.csv file.csv
Where the error occurs:
for rowitem in reader:
for pos in field:
pos = rowitem[pos] ##<---LINE generating error--->##
if pos not in fieldcnt:
fieldcnt[pos] = 1
else:
fieldcnt[pos] += 1
TypeError: list indices must be integers or slices, not str
Thank you!
Judging from the output, I'd say that the fields in the csv file does not influence the count of the string. If the string uniqueness is case-insensitive please remember to use yourstring.lower() to return the string so that different case matches are actually counted as one. Also do keep in mind that if your text is large the number of unique strings you might find could be very large as well, so some sort of sorting must be in place to make sense of it! (Or else it might be a long list of random counts with a large portion of it being just 1s)
Now, to get a count of unique strings using the collections module is an easy way to go.
file = open('yourfile.txt', encoding="utf8")
a= file.read()
#if you have some words you'd like to exclude
stopwords = set(line.strip() for line in open('stopwords.txt'))
stopwords = stopwords.union(set(['<media','omitted>','it\'s','two','said']))
# make an empty key-value dict to contain matched words and their counts
wordcount = {}
for word in a.lower().split(): #use the delimiter you want (a comma I think?)
# replace punctuation so they arent counted as part of a word
word = word.replace(".","")
word = word.replace(",","")
word = word.replace("\"","")
word = word.replace("!","")
if word not in stopwords:
if word not in wordcount:
wordcount[word] = 1
else:
wordcount[word] += 1
That should do it. The wordcount dict should contain the word and it's frequency. After that just sort it using collections and print it out.
word_counter = collections.Counter(wordcount)
for word, count in word_counter.most_common(20):
print(word, ": ", count)
I hope this solves your problem. Lemme know if you face problems.
First question here.
I am picking up Python and have a question that may be quite basic.
I am trying to create this pattern with a nested loop:
x
x
x
xxx
With the code:
numbers = [1,1,1,3]
for count_x in numbers:
output = ""
for count in range(count_x):
output +=x
print(output)
My question is - why does my output change when I move the position of print(output).
The code above works but when I align print(output) with the for count_x in numbers:, I only get "xxx", when I align print(output) to output +=x, I get the following:
x
x
x
x
xx
xxx
which is very odd because there are only 4 items in the list and it shows me 6 lines of output.
Could someone please help? Really puzzled. Thank yall very much.
There's a difference between these two bits of code (fixing the x/"x" problem along the way - your code won't actually work as is unless you have a variable x):
# First:
numbers = [1,1,1,3]
for count_x in numbers:
output = ""
for count in range(count_x):
output += "x"
print(output)
# Second:
numbers = [1,1,1,3]
for count_x in numbers:
output = ""
for count in range(count_x):
output += "x"
print(output)
In the second, the print is done inside the loop that creates the string, meaning you print it out multiple times while building it. That's where your final three lines come from: *, ** and ***. This doesn't matter for all the previous lines since there's no functional difference. Printing a one character string at the end or after adding each of the one characters has the same effect.
In the first, you only print the string after fully constructing it.
You can see this effect by using a slightly modified version that outputs different things for each outer loop:
numbers = [1,1,1,3]
x = 1
for count_x in numbers:
output = ""
for count in range(count_x):
output += str(x)
print(output)
x += 1
This shows that the final three lines are part of a single string construction (comments added):
1 \
2 >- | Each is one outer/inner loop.
3 /
4 \ | A single outer loop, printing
44 >- | string under construction for
444 / | each inner loop.
In any case, there are better ways to do what you want, such as:
numbers = [1,1,1,3]
for count_x in numbers:
print('x' * count_x)
You could probably also do it on one line with a list comprehension but that's probably overkill.
I have a simple question that I need help on. My code,I believe, is almost complete but im having trouble with the a specific line of code.
I have an assignment question (2 parts) that asks me to find whether a protein (string), has the specified motif (substring) at that particular location (location). This is the first part, and the function and code looks like this:
function output = Motif_Match(motif,protein,location)
%This code wil print a '1' if the motif occurs in the protein starting
at the given location, else it wil print a '0'
for k = 1:location %Iterates through specified location
if protein(1, [k, k+1]) == motif; % if the location matches the protein and motif
output = 1;
else
output = 0;
end
end
This part I was able to get correctly, and example of this is as follows:
p = 'MGNAAAAKKGN'
m = 'GN'
Motif_Match(m,p,2)
ans =
1
The second part of the question, which I am stuck on, is to take the motif and protein and return a vector containing the locations at which the motif occurs in the protein. To do this, I am using calls to my previous code and I am not supposed to use any functions that make this easy such as strfind, find, hist, strcmp etc.
My code for this, so far, is:
function output = Motif_Find(motif,protein)
[r,c] = size(protein)
output = zeros(r,c)
for k = 1:c-1
if Motif_Match(motif,protein,k) == 1;
output(k) = protein(k)
else
output = [];
end
end
I belive something is wrong at line 6 of this code. My thinking on this is that I want the output to give me the locations to me and that this code on this line is incorrect, but I can't seem to think of anything else. An example of what should happen is as follows:
p = 'MGNAAAAKKGN';
m = 'GN';
Motif_Find(m,p)
ans =
2 10
So my question is, how can I get my code to give me the locations? I've been stuck on this for quite a while and can't seem to get anywhere with this. Any help will be greatly appreciated!
Thank you all!
you are very close.
output(k) = protein(k)
should be
output(k) = k
This is because we want just the location K of the match. Using protien(k) will gives us the character at position K in the protein string.
Also the very last thing I would do is only return the nonzero elements. The easiest way is to just use the find command with no arguments besides the vector/matrix
so after your loop just do this
output = find(output); %returns only non zero elements
edit
I just noticed another problem output = []; means set output to an empty array. this isn't what you want i think what you meant was output(k) = 0; this is why you weren't getting the result you expected. But REALLY since you already made the whole array zeros, you don't need that at all. all together, the code should look like this. I also replaced your size with length since your proteins are linear sequences, not 2d matricies
function output = Motif_Find(motif,protein)
protein_len = length(protein)
motif_len = length(motif)
output = zeros(1,protein_len)
%notice here I changed this to motif_length. think of it this way, if the
%length is 4, we don't need to search the last 3,2,or 1 protein groups
for k = 1:protein_len-motif_len + 1
if Motif_Match(motif,protein,k) == 1;
output(k) = k;
%we don't really need these lines, since the array already has zeros
%else
% output(k) = 0;
end
end
%returns only nonzero elements
output = find(output);
http://www.cs.uni.edu/~diesburg/courses/cs1510_sp15/homework/PA04/index.htm
So I have this assignment. I have been trying to work out the code to find the additive and multiplicative roots of a user given input. I am new to python and know how to work the problem out, but without the tools (coding know how) have been just running in circles for quite a while now. So if anyone could be so kind as to help me figure out the coding. I have tried slicing the list, but keep getting an error if I try to make the string an int and if I leave it as an string it just doesn't seem to run. I know there is probably a way using modulous as well, but have yet to quite master it.
Thank you for any help any of you are able to leave me.
Edit
Here is the code I have so far.
import sys
userStr = input("What number should I use for my \
calculations? ")
userInt = int (userStr)
original = userStr #Save Copy of original value
originalTwo = userStr #Save second Copy of original value
addCount = 0
mulCount = 0
#Stop the program if the integer is less than or equal to 0
while userInt <= 0:
print ("Thanks for playing along!")
sys.exit()
#Use a while loop to repeat the process of splitting an integer into single digits and then adding the individual digits.
print = ("Addition")
while userInt > 9:
userInt = sum(map(int, userStr))
print("New Value: ",userStr)
addCount = addCount + 1
#Use a while loop to repeat the process of splitting an integer into single digits and then multiplying the individual digits.
print = ("Multiplication")
while original > 9:
original = (map (int, original))
print("New Value: ",original)
mulCount = mulCount + 1
#Print the outputs to the screen for the user.
print("For the Integer: ",userInt)
print(" Additive Persistence= ",addCount,", Additive Root= ", userInt)
print(" Multiplicative Persistence= ",mulCount,",
Multiplicative Root= ", original)