I have 20TB file and I want to repartition it in spark with each partition = 128MB.
But after calculating n=20TB/128mb= 156250 partitions.
I believe 156250 is a very big number for
df.repartition(156250)
how should I approach repartitiong in this?
or should I increase the block size from 128mb to let's say 128gb.
but 128 gb per task will explode executor.
Please help me with this.
Divide and conquer it. You don’t need to load all the dataset in one place cause it would cost you huge amount resources and also network pressure because of shuffle exchanging.
The block size that you are referring to here is an HDFS concept related to storing the data by breaking it into chunks (say 128M default) & replicating thereafter for fault tolerance. In case you are storing your 20TB file on HDFS, it will automatically be broken into 20TB/128mb=156250 chunks for storage.
Coming to the Spark dataframe repartition, firstly it is a tranformation rather than an action (more information on the differences between the two: https://spark.apache.org/docs/latest/rdd-programming-guide.html#rdd-operations). Which means merely calling this function on the dataframe does nothing unless the dataframe is eventually used in some action.
Further, the repartition value allows you to define the parallelism level of your operation involving the dataframe & should mostly be though upon in those terms rather than the amount of data being processed per executor. The aim should be to maximize parallelism as per the available resources rather than trying to process certain amount of data per executor. The only exception to this rule should be in cases where the executor either needs to persist all this data in memory or collect some information from this data which is proportional to the data size being processed. And the same applies to any executor task running on 128GB of data.
Related
1.) I understand that "Spark's operators spills data to disk if it does not fit memory allowing it to run well on any sized data".
If this is true, why do we ever get OOM (Out of Memory) errors?
2.) Increasing the no. of executor cores increases parallelism. Would that also increase the chances of OOM, because the same memory is now divided into smaller parts for each core?
3.) Spark is much more susceptible to OOM because it performs operations in memory as compared to Hive, which repeatedly reads, writes into disk. Is that correct?
There is one angle that you need to consider there. You may get memory leaks if the data is not properly distributed. That means that you need to distribute your data evenly (if possible) on the Tasks so that you reduce shuffling as much as possible and make those Tasks to manage their own data. So if you need to perform a join, if data is distributed randomly, every Task (and therefore executor) will have to:
See what data they have
Send data to other executors (and tasks) to provide the same keys they need
Request the data that is needed by that task to the others
All that data exchange may cause network bottlenecks if you have a large dataset and also will make every Task to hold their data in memory plus whatever has been sent and temporary objects. All of those will blow up memory.
So to prevent that situation you can:
Load the data already repartitioned. By that I mean, if you are loading from a DB, try Spark stride as defined here. Please refer to the partitionColumn, lowerBound, upperBound attributes. That way you will create a number of partitions on the dataframe that will set the data on different tasks based on the criteria you need. If you are going to use a join of two dataframes, try similar approach on them so that partitions are similar (for not to say same) and that will prevent shuffling over network.
When you define partitions, try to make those values as evenly distributed among tasks as possible
The size of each partition should fit on memory. Although there could be spill to disk, that would slow down performance
If you don't have a column that make the data evenly distributed, try to create one that would have n number of different values, depending on the n number of tasks that you have
If you are reading from a csv, that would make it harder to create partitions, but still it's possible. You can either split the data (csv) on multiple files and create multiple dataframes (performing a union after they are loaded) or you can read that big csv and apply a repartition on the column you need. That will create shuffling as well, but it will be done once if you cache the dataframe already repartitioned
Reading from parquet it's possible that you may have multiple files but if they are not evenly distributed (because the previous process that generated didn't do it well) you may end up on OOM errors. To prevent that situation, you can load and apply repartition on the dataframe too
Or another trick valid for csv, parquet files, orc, etc. is to create a Hive table on top of that and run a query from Spark running a distribute by clause on the data, so that you can make Hive to redistribute, instead of Spark
To your question about Hive and Spark, I think you are right up to some point. Depending on the execute engine that Hive uses in your case (map/reduce, Tez, Hive on Spark, LLAP) you can have different behaviours. With map/reduce, as they are mostly disk operations, the chance to have a OOM is much lower than on Spark. Actually from Memory point of view, map/reduce is not that affected because of a skewed data distribution. But (IMHO) your goal should be to find always the best data distribution for the Spark job you are running and that will prevent that problem
Another consideration is if you are testing in a dev environment that doesn't have same data as in a prod environment. I suppose the data distribution should be similar although volumes may differ a lot (I am talking from experience ;)). In that case, when you assign Spark tuning parameters on the spark-submit command, they may be different in prod. So you need to invest some time on finding the best approach on dev and fine tune in prod
Huge majority of OOM in Spark are on the driver, not executors. This is usually a result of running .collect or similar actions on a dataset that won't fit in the driver memory.
Spark does a lot of work under the hood to parallelize the work, when using structured APIs (in contrast to RDDs) the chances of causing OOM on executor are really slim. Some combinations of cluster configuration and jobs can cause memory pressure that will impact performance and cause lots of garbage collection to happen so you need to address it, however spark should be able to handle low memory without explicit exception.
Not really - as above, Spark should be able to recover from memory issues when using structured APIs, however it may need intervention if you see garbage collection and performance impact.
I am looking through spark partitioning and I see different answers for the question.
Is spark partition size is equal to HDFS block size or depends on the number of cores available on all executors?, and Does the performance improves by repartitioning the data in skewed data case? (I assume the data related to the same join key is again shuffled back to a single executor during the join). Please help me understand this. Thanks!
It really depends on your data where from you are reading. If you are reading from HDFS, then one block will be one partition. But if you are reading a parquet file, then one parquet file is one partition as it is not splittable, so depending on the block in case of HDFS and files count in case of parquet, it creates partitions.
Regarding the skewed data, the more data one partition has, the more time it takes to finish the execution. The other tasks will finished quickly as they have less data so the resources are not being utilized properly. Therefore, it is always better to repartition the skewed data properly, so all executors can evenly do the execution.
You can look here for all the available RDDs, and how they are creating partitions:
https://github.com/apache/spark/tree/master/core/src/main/scala/org/apache/spark/rdd
I'm getting confused about spill to disk and shuffle write. Using the default Sort shuffle manager, we use an appendOnlyMap for aggregating and combine partition records, right? Then when execution memory fill up, we start sorting map, spilling it to disk and then clean up the map for the next spill(if occur), my questions are :
What is the difference between spill to disk and shuffle write? They consist basically in creating file on local file system and also record.
Admit are different, so Spill records are sorted because the are passed through the map, instead shuffle write records no because they don't pass from the map.
I have the idea that the total size of the spilled file, should be equal to the size of the Shuffle write, maybe I'm missing something, please help to understand that phase.
Thanks.
Giorgio
spill to disk and shuffle write are two different things
spill to disk - Data move from Host RAM to Host Disk - is used when there is no enough RAM on your machine, and it place part of its RAM into disk
http://spark.apache.org/faq.html
Does my data need to fit in memory to use Spark?
No. Spark's operators spill data to disk if it does not fit in memory,
allowing it to run well on any sized data. Likewise, cached datasets
that do not fit in memory are either spilled to disk or recomputed on
the fly when needed, as determined by the RDD's storage level.
shuffle write - Data move from Executor(s) to another Executor(s) - is used when data needs to move between executors (e.g. due to JOIN, groupBy, etc)
more data can be found here:
https://0x0fff.com/spark-architecture-shuffle/
http://blog.cloudera.com/blog/2015/05/working-with-apache-spark-or-how-i-learned-to-stop-worrying-and-love-the-shuffle/
An edge case example which might help clearing this issue:
You have 10 executors
Each executor with 100GB RAM
Data size is 1280MB, and is partitioned into 10 partitions
Each executor holds 128MB of data.
Assuming that the data holds one key, Performing groupByKey, will bring all the data into one partition. Shuffle size will be 9*128MB (9 executors will transfer their data into the last executor), and there won't be any spill to disk as the executor has 100GB of RAM and only 1GB of data
Regarding AppendOnlyMap :
As written in the AppendOnlyMap code (see above) - this function is
a low level implementation of a simple open hash table optimized for
the append-only use case, where keys are never removed, but the value
for each key may be changed.
The fact that two different modules uses the same low-level function doesn't mean that those functions are related in hi-level.
I have an Spark application that keeps running out of memory, the cluster has two nodes with around 30G of RAM, and the input data size is about few hundreds of GBs.
The application is a Spark SQL job, it reads data from HDFS and create a table and cache it, then do some Spark SQL queries and writes the result back to HDFS.
Initially I split the data into 64 partitions and I got OOM, then I was able to fix the memory issue by using 1024 partitions. But why using more partitions helped me solve the OOM issue?
The solution to big data is partition(divide and conquer). Since not all data could be fit into the memory, and it also could not be processed in a single machine.
Each partition could fit into memory and processed(map) in relative short time. After the data is processed for each partition. It need be merged (reduce). This is tradition map reduce
Splitting data to more partitions means that each partition getting smaller.
[Edit]
Spark using revolution concept called Resilient Distributed DataSet(RDD).
There are two types of operations, transformation and acton
Transformations are mapping from one RDD to another. It is lazy evaluated. Those RDD could be treated as intermediate result we don't wanna get.
Actions is used when you really want get the data. Those RDD/data could be treated as what we want it, like take top failing.
Spark will analysed all the operation and create a DAG(Directed Acyclic Graph) before execution.
Spark start compute from source RDD when actions are fired. Then forget it.
(source: cloudera.com)
I made a small screencast for a presentation on Youtube Spark Makes Big Data Sparking.
Spark's operators spill data to disk if it does not fit in memory,
allowing it to run well on any sized data". The issue with large
partitions generating OOM
Partitions determine the degree of parallelism. Apache Spark doc says that, the partitions size should be atleast equal to the number of cores in the cluster.
Less partitions results in
Less concurrency,
Increase memory pressure for transformation which involves shuffle
More susceptible for data skew.
Many partitions might also have negative impact
Too much time spent in scheduling multiple tasks
Storing your data on HDFS, it will be partitioned already in 64 MB or 128 MB blocks as per your HDFS configuration When reading HDFS files with spark, the number of DataFrame partitions df.rdd.getNumPartitions depends on following properties
spark.default.parallelism (Cores available for the application)
spark.sql.files.maxPartitionBytes (default 128MB)
spark.sql.files.openCostInBytes (default 4MB)
Links :
https://spark.apache.org/docs/latest/tuning.html
https://databricks.com/session/a-deeper-understanding-of-spark-internals
https://spark.apache.org/faq.html
During Spark Summit Aaron Davidson gave some tips about partitions tuning. He also defined a reasonable number of partitions resumed to below 3 points:
Commonly between 100 and 10000 partitions (note: two below points are more reliable because the "commonly" depends here on the sizes of dataset and the cluster)
lower bound = at least 2*the number of cores in the cluster
upper bound = task must finish within 100 ms
Rockie's answer is right, but he does't get the point of your question.
When you cache an RDD, all of his partitions are persisted (in term of storage level) - respecting spark.memory.fraction and spark.memory.storageFraction properties.
Besides that, in an certain moment Spark can automatically drop's out some partitions of memory (or you can do this manually for entire RDD with RDD.unpersist()), according with documentation.
Thus, as you have more partitions, Spark is storing fewer partitions in LRU so that they are not causing OOM (this may have negative impact too, like the need to re-cache partitions).
Another importante point is that when you write result back to HDFS using X partitions, then you have X tasks for all your data - take all the data size and divide by X, this is the memory for each task, that are executed on each (virtual) core. So, that's not difficult to see that X = 64 lead to OOM, but X = 1024 not.
Say I have lots data in a couple of s3 files, about 5 GB each, which I read in using sc.textFile
I need to join the data from the two files, therefore, I opt to use the HashPartitioner technique, and I set a partition count of 20. The submitted job to 8 worker nodes fails without any meaningful messages. Now I am thinking maybe I need to pick a proper number of partitions.
Obviously, the idea for spark to partition up all the data based on a chosen key. In order to load them up into 20 partitions, I imagine spark will have to read thru every line of data, compute its hash, and load into the memory of the matching partition, which resides in one of the 8 worker nodes. If there is enough collective memory in the worker nodes, I assume this goes smoothly. At the end of the read, all the data is in the proper partition, in the right node's memory. Am I right so far?
However, if the total memory can not fit all the data, I imagine Spark will work on certain partitions first. And after processing these first partitions, it flushes the original partitions and reads from the source files again, loading remaining data into new partitions. This would mean reading the same file as many time as necessary to process all partitions using available memory. Is this also correct?
Should I should calculate the number of partitions so that at least one full partition would fit into a single node's memory. Are there other guidelines to follow?