Pass in bash terminal variables to a bash script - linux

If I am in a Linux terminal and I start setting variables such as export AGE=45.
Then I have a script to read user data from terminal variables and process it, is this possible to do?
IE:
user#linux$ export AGE=45
user#linux$ ./age.sh
#script asks for input
read -p "what is your age?" scriptAGE
#user inputs variable set in terminal
$AGE
#echo output
echo "your age is: " $scriptAGE"
#should say your age is: 45

There is no such thing as a terminal variable. read just assigns a string to your variable scriptAGE.
If this string contains some $NAME you want to expand, you could apply eval to it, but this is of course extremely dangerous because of possible code injection.
A safer way to do this is using envsubst, but this requires that the variables to be substituted must be environment variables. In your case, AGE is in the environment, so this condition is met.
In your case, you would have to do therefore a
envsubst <<<"$scriptAGE"
which would print on stdout the content of scriptAGE with all environment variables in it substituted.

Variables are not expanded in input, only in the script itself.
You could use eval to force it to process the variable value as shell syntax.
eval "echo 'your age is:' $scriptAGE"
But this will also process other shell syntax. If they enter $AGE; rm * it will say their age is 45 and then delete all their files.

you could just do
age=$1
echo "Your age is $1"
where $1, $2, $3, .., $N are the passed arguments by order
And then run your script
bash script sh Noureldin
For more Info read this:
passing names args

Related

What does the linux operator $ do?

I've seen many examples where $USER and similar commands are used but I could never figure out what it meant.
Whenever I search $ on Google, it doesn't recognise the symbol.
it is used to access system variable.
for example:
if you type in linux and/or unix shell
...$ my_var="some value"
...$ echo my_var
will print "some value"
...$ echo $USER
will print the name of shell user
...$ echo $?
will print the result of the previous command when successfully will print 0
in other word the result of "exit (num)" of you shell.
"$" also can indicate you are logged as no-root user for some shells the root will be indicated "#"
The $ is a special character that tells the shell interpreter to interpret the contents following as a value for a variable. It is also called variable substitution.
In the case of commands or command output, it can be used to call a shell command and store it's output as a variable's value. For example:
VAR_1="$(ip link show)"
Calling the variable VAR_1 will print the output of the command ip link show.
This is called command substitution.
You can find out more information on special characters Here
as well as information on wildcards, keywords and more.

Strange behavior of shell output file ( Linux )

Do you know why below shell script just generates the output file named 'Loading_EMP.sql' instead of 'Loading_1_EMP.sql'?
#!/bin/bash
JOBID="1"
TABLE="EMP"
echo 'test' > Loading_$JOBID_$TABLE.sql;
# Output
Loading_EMP.sql
# Expected Output
Loading_1_EMP.sql
echo 'test' > Loading_${JOBID}_${TABLE}.sql;
should do it, or better
echo 'test' > "Loading_${JOBID}_${TABLE}.sql" # to avoid word splitting
In Loading_$JOBID_$TABLE, shell trates $JOBID_ as a single variable and since it is not set, it substitutes $JOBID_ with nothing resulting in Loading_EMP.sql
This [ answer ] must read for you.
_ is not a special character in shell. So the shell sees this as you echoing a $JOBID_ variable, which is undefined, and thus empty. Instead, you should explicitly show the shell what your variables are by using {}:
echo 'test' > Loading_${JOBID}_${TABLE}.sql;
# Here -----------------^-----^--^-----^
The interpreter thinks you are referring to a variable named JOBID_. Enclose the name with {}.
echo 'test' > Loading_${JOBID}_$TABLE.sql

Using "read" to set variables

In bash from the CLI I can do:
$ ERR_TYPE=$"OVERLOAD"
$ echo $ERR_TYPE
OVERLOAD
$ read ${ERR_TYPE}_ERROR
1234
$ echo $OVERLOAD_ERROR
1234
This works great to set my variable name dynamically; in a script it doesn't work. I tried:
#!/bin/env bash
ERR_TYPE=("${ERR_TYPE[#]}" "OVERLOAD" "PANIC" "FATAL")
for i in "${ERR_TYPE[#]}"
do
sh -c $(echo ${i}_ERROR=$"1234")
done
echo $OVERLOAD_ERROR # output is blank
# I also tried these:
# ${i}_ERROR=$(echo ${i}_ERROR=$"1234") # command not found
# read ${i}_ERROR=$(echo ${i}_ERROR=$"1234") # it never terminates
How would I set a variable as I do from CLI, but in a script? thanks
When you use dynamic variables names instead of associative arrays, you really need to question your approach.
err_type=("OVERLOAD" "PANIC" "FATAL")
declare -A error
for type in "${err_type[#]}"; do
error[$type]=1234
done
Nevertheless, in bash you'd use declare:
declare "${i}_error=1234"
Your approach fails because you spawn a new shell, passing the command OVERLOAD_ERROR=1234, and then the shell exits. Your current shell is not affected at all.
Get out of the habit of using ALLCAPSVARNAMES. One day you'll write PATH=... and then wonder why your script is broken.
If the variable will hold a number, you can use let.
#!/bin/bash
ERR_TYPE=("OVERLOAD" "PANIC" "FATAL")
j=0
for i in "${ERR_TYPE[#]}"
do
let ${i}_ERROR=1000+j++
done
echo $OVERLOAD_ERROR
echo $PANIC_ERROR
echo $FATAL_ERROR
This outputs:
1000
1001
1002
I'd use eval.
I think this would be considered bad practice though (it had some thing to do with the fact that eval is "evil" because it allows bad input or something):
eval "${i}_ERROR=1234"

Unix: What does cat by itself do?

I saw the line data=$(cat) in a bash script (just declaring an empty variable) and am mystified as to what that could possibly do.
I read the man pages, but it doesn't have an example or explanation of this. Does this capture stdin or something? Any documentation on this?
EDIT: Specifically how the heck does doing data=$(cat) allow for it to run this hook script?
#!/bin/bash
# Runs all executable pre-commit-* hooks and exits after,
# if any of them was not successful.
#
# Based on
# http://osdir.com/ml/git/2009-01/msg00308.html
data=$(cat)
exitcodes=()
hookname=`basename $0`
# Run each hook, passing through STDIN and storing the exit code.
# We don't want to bail at the first failure, as the user might
# then bypass the hooks without knowing about additional issues.
for hook in $GIT_DIR/hooks/$hookname-*; do
test -x "$hook" || continue
echo "$data" | "$hook"
exitcodes+=($?)
done
https://github.com/henrik/dotfiles/blob/master/git_template/hooks/pre-commit
cat will catenate its input to its output.
In the context of the variable capture you posted, the effect is to assign the statement's (or containing script's) standard input to the variable.
The command substitution $(command) will return the command's output; the assignment will assign the substituted string to the variable; and in the absence of a file name argument, cat will read and print standard input.
The Git hook script you found this in captures the commit data from standard input so that it can be repeatedly piped to each hook script separately. You only get one copy of standard input, so if you need it multiple times, you need to capture it somehow. (I would use a temporary file, and quote all file name variables properly; but keeping the data in a variable is certainly okay, especially if you only expect fairly small amounts of input.)
Doing:
t#t:~# temp=$(cat)
hello how
are you?
t#t:~# echo $temp
hello how are you?
(A single Controld on the line by itself following "are you?" terminates the input.)
As manual says
cat - concatenate files and print on the standard output
Also
cat Copy standard input to standard output.
here, cat will concatenate your STDIN into a single string and assign it to variable temp.
Say your bash script script.sh is:
#!/bin/bash
data=$(cat)
Then, the following commands will store the string STR in the variable data:
echo STR | bash script.sh
bash script.sh < <(echo STR)
bash script.sh <<< STR

Shell script for setting environment variable

I am writing a shell script to set the environment variables whose values are available in a file. Below is the shell script I wrote,
VARIABLE_FILE=env-var.dat
if [ -f ${VARIABLE_FILE} ] ; then
. ${VARIABLE_FILE}
if [ ! -z "${TEST_VAR1}" ] ; then
export TEST_VAR1="${TEST_VAR1}"
fi
if [ ! -z "${TEST_VAR2}" ] ; then
export TEST_VAR2="${TEST_VAR2}"
fi
fi
The above code works only in bash shell, since I have used export command to set the environment variable and it fails if I used it with any other shell. Is there is any command to set the environment variable which works in any shell ?
"Fancier" shells like bash and zsh permit you to set a variable and export it as an environment variable at the same time like so:
export FOO=bar
With a standard POSIX bourne shell, the equivalent is achieved by doing it in two commands:
FOO=bar
export FOO
Note that once you've exported a variable, you can reset it to a different value later in the script and it's still exported (you don't need to export it again). Also, you can export several variables at a time:
FOO=bar
BAZ=quux
export FOO BAZ
You mentioned tcsh in your comment, but csh and derivatives are completely different from bourne-based shells (and not recommended for use!). You can rarely make a shell script compatible with both sh and csh at the same time. For csh, look into setenv
If you really want this to happen, it can be done, but it's tricky. One way to do it is to use awk to output the correct syntax and evaluate the text coming back from awk. To share a single environment variable value file between major sh and csh flavors, the following command in a file will import a variable value file to the environment: (yes, yes, it's one huge line, due to the inflexible way that some shells treat the backticks. If you didn't mind having a .awk file too, you could use awk -f...)
eval `awk '{ var = $1; $1=""; val=substr($0,2); if ( ENVIRON["SHELL"] ~ /csh$/) { print "setenv", var, " \"" val "\";" } else { print var "=\"" val "\"" ; print "export", var }}' $HOME/env_value_file`
The variable value file is in this format:
FOO value for foo
BAR foo bar
BAZ $BAR plus values $FOO
Design notes for educational purposes:
In awk, there's no easy way of accessing fields 2-NF, so if there
could be spaces in our variable values we need to modify $1 to get
$0 to be close to get the value we want.
To get this to work, since a SHELL variable is always set, but not as an
environment variable and not with a consistent capitalization, you have to wet
a SHELL environment variable from the shell's value as below.
as an environment variable before you use the script.
Also, if you want the new environment values to be present after the import
environment script you need to source the environment script.
If a shell doesn't do eval well, you'll have to tweak the script.
For bourne shell flavors (bash, sh, ksh, zsh):
export SHELL
. import_environment
For csh flavors: (shell variable tends to be lower case in csh shells)
setenv SHELL "$shell"
source import_environment

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