Countif or sumif function in Excel - excel
I have 2 tables, one which gets populated with results (on the right) and the other is the summary of that results table (on the left). Not even sure if countif is the correct approach but I just wondered if there was a formula I can put into B2:D3 which can add up the number of occurences in the results table. So going forward I'll just need to manually insert another row in columns I and J which would update B2:D3
Use this as shown in image below, going forward when you add more values in column I & J, it shall give you the number of occurrences of L, W, & D respectively as per Name
Enter the formula in cell B2 & Fill Down -- Fill Right
=SUMPRODUCT(($A2=$I$1:$J$1)*(B$1=$I:$J))
What this formula does is creates an array of TRUE's & FALSE's, select the Array 1 & Press F9,
($A2=$I$1:$J$1) {TRUE,FALSE}
likewise for the Array 2 as well
(B$1=$I:$J) {FALSE,FALSE;TRUE,TRUE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,FALSE;FALSE,)
Each Array 1 will be multiplied by corresponding Array 2 and returns the sum of the products, by far this is safest option and can be used in all Excel Versions.
You can add the following formula into B2:
=COUNTIF($H$2:$H$3,B$1)
It will count all 'W' occurrences in the H2:H3 range. You can drag this formula to the right.
For the B3 cell, you need to update the column from H to I.
Related
Counting past occurrence given a classification
I have a Table just like the one in the picture below. I want to count the number of cells in the column Leg since the last entry, given a certain classification on the column Type. For example, for the type KFT only, how many blank entries are there in the column Legendary since the last entry for Leg? I know how to solve this issue creating helper columns. But given that I have too many types, I would have to create a helper column for each type, making my table too big given the amount of rows I have. Is there any way I can create a VBA function to perform this task for me, such that I only need one cell per type to let me know the amount of blank cells since last Leg entry for each type? Here is a short example of how my table looks, using only 2 types: In this example, I need a formula with output 0 for MSG, since it has been 0 entries since the last Leg for MSG, and output 2 for UNG, since it has been 2 entries since the last Leg for UNG. Thanks so much for the help!
Solution 1 Using single scary formula
Alright then. I think best solution to your problem is using helper column or VBA but if you really want to use just one formula, I've something for you. This formula is very very scary and someone might give you better solution also, but this formula does work.
In the below formula I've assumed data to be in range A2:F100. Change 100 to you number of rows of data. (change all 100's, best way will be to copy formula without = in an empty sheet and then FIND 100 and REPLACE ALL to your row number)
If you have listed Types in Column H starting from Cell H2 then in Cell I2 enter the following formul, drag/copy down as required.
=COUNTIFS(INDIRECT("F" & INDEX($A$2:$A$100,MAX(IF(($B$2:$B$100=H2)*($F$2:$F$100=1),ROW($B$2:$B$100)-ROW(INDEX($B$2:$B$100,1,1))+1)))+1 & ":F" & IF(INDEX($A$2:$A$100,MAX(IF(($B$2:$B$100=H2)*($F$2:$F$100=1),ROW($B$2:$B$100)-ROW(INDEX($B$2:$B$100,1,1))+1)))+1>INDEX($A$2:$A$100,MAX(IF(($B$2:$B$100=H2)*($F$2:$F$100=""),ROW($B$2:$B$100)-ROW(INDEX($B$2:$B$100,1,1))+1)))+1,100,INDEX($A$2:$A$100,MAX(IF(($B$2:$B$100=H2)*($F$2:$F$100=""),ROW($B$2:$B$100)-ROW(INDEX($B$2:$B$100,1,1))+1)))+1)),"",INDIRECT("B" & INDEX($A$2:$A$100,MAX(IF(($B$2:$B$100=H2)*($F$2:$F$100=1),ROW($B$2:$B$100)-ROW(INDEX($B$2:$B$100,1,1))+1)))+1 & ":B" & IF(INDEX($A$2:$A$100,MAX(IF(($B$2:$B$100=H2)*($F$2:$F$100=1),ROW($B$2:$B$100)-ROW(INDEX($B$2:$B$100,1,1))+1)))+1>INDEX($A$2:$A$100,MAX(IF(($B$2:$B$100=H2)*($F$2:$F$100=""),ROW($B$2:$B$100)-ROW(INDEX($B$2:$B$100,1,1))+1)))+1,100,INDEX($A$2:$A$100,MAX(IF(($B$2:$B$100=H2)*($F$2:$F$100=""),ROW($B$2:$B$100)-ROW(INDEX($B$2:$B$100,1,1))+1)))+1)),H2)
This is an array formula so commit it by pressing Ctrl+Shift+Enter.
Solution 2 Using Helper Columns
Assuming you listed all Types in Column H starting from Cell H2 then in Cell I2 enter the following array formula to get the last row from data for corresponding Type in Column H and Leg =1
=INDEX($A$2:$A$11,MAX(IF(($B$2:$B$11=H2)*($F$2:$F$11=1),ROW($B$2:$B$11)-ROW(INDEX($B$2:$B$11,1,1))+1)))+1
Then in Cell J2, enter the below array formula to get the last row from data for corresponding Type in Column H and Leg ="" (blank)
=INDEX($A$2:$A$11,MAX(IF(($B$2:$B$11=H2)*($F$2:$F$11=""),ROW($B$2:$B$11)-ROW(INDEX($B$2:$B$11,1,1))+1)))+1
Next, in Cell K2, enter the below formula to set last row if there's no row corresponding to particular type for which leg is blank (for example in my sample data ABC do not have empty Leg)
=IF(I2>J2,11,J2)
Finally, in Cell E2 enter the following formula to get Count
=COUNTIFS(INDIRECT("F" & I2 & ":F" & K2),"",INDIRECT("B" & I2 & ":B" & K2),H2)
I need to find an excel formula that I can use to create a unique list of Item numbers from an array
I need to find an excel formula that I can use to create a unique list of Item numbers from an array. I do not want to count them I just want to make a list of the Item Numbers. These part numbers are actually Alpha Numeric and can have repeating numbers through out the array multiple times. There is one other catch this list will have empty cells in it and could also be the first record in the array. This data is being pulled into Excel through a Jet report add-in for Excel. Example: Starting in cell A1..A9 Item No. <BLANK> 7810042050 783979 7810006045 7810006042 7810006032 <BLANK> 7810006022 7810006032
With values in column A, in C1 enter: =MAX(A1:A10) in C2 enter the array formula: =MAX(IF(A$1:A$10<C1,A$1:A$10,"")) and copy down: Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key. EDIT#1: Chris Neilsen has pointed out that the values in column A are actually Text rather than Numeric. To accommodate this, two changes must be made to the formulas: A1 must be excluded the alphas must be converted to numeric. So we will replace the normal formula: =MAX(A1:A10) with the array formula: =MAX(--(A2:A10)) and replace: =MAX(IF(A$1:A$10<C1,A$1:A$10,"")) with the array formula: =MAX(IF(--(A$2:A$10)<C1,--(A$2:A$10),"")) and then copy down.
If you have alpha characters in the part numbers you can do this in 2 steps. Both are array formulas and you need to use Ctrl-Shift-Enter Col B - sorted list of items in Col A B2 =IFERROR(INDEX($A$2:$A$10,MATCH(COUNTA($A$2:A2),COUNTIF($A$2:$A$10,"<="&$A$2:$A$10),0),1),"") Col C - eliminate the duplicates C2 = IFERROR(INDEX($B$2:$B$10, MATCH(0, COUNTIF($C$1:C1, $B$2:$B$10), 0)),"") Copy both formulas down. I tried to combine the two formulas but nesting an array (results in Col B) with varying row ranges did not work out. I could not find a way but the two formulas together will work.
Enter this Formula Array in B2 and copy to B3:B10
FormulaArrays are entered pressing [Ctrl] + [Shift] + [Enter] simultaneously, you shall see { and } around the formula if entered correctly
=IFERROR(
INDEX($A$2:$A$10,
MATCH(1,1+COUNTIF($B1:$B$1,$A$2:$A$10)+(($A$2:$A$10="")*1),0)*1),"")
Excel Auto number row based on criteria
I'm trying to create a spreadsheet in excel which creates a sequential number in a column (B) depending on the contents of another column. Currently, there are two possibilities of what could be in Column A ("BI" or "GF"). So I want the data to look like this
COL A COLB
BI 1
BI 2
GF 1
BI 3
GF 2
GF 3
BI 4
BI 5
I've tried several attempts to do this but can't seem to find a solution. Any help would be greatly appreciated.
In B2, try this formula: =CountIf(A$2:A2,A2)
Try to use the offset equation. The first cell in COL B will look similar to this: =COUNTIFS(OFFSET(A$1$1:A1,0,0),A1) The second should look like this: =COUNTIFS(OFFSET(A$1$1:A2,0,0),A2) Drag this down in Col B as far as desired. If you are using a table this should autofill. Explanation: Essentially you are using the OFFSET formula to create a dynamic range. The A$1$ serves as the start of your range by making this an absolute reference and the A1 will serve as the end of your range. By making the ending cell a relative reference, the array the COUNTIFS function search will never go beyond the row the of the cell the formula is relative of. In your example, the formula in the first row in Col B would result in 1. The reason is the OFFSET returns the array of A$1$:A1 and the COUNTIFS searches through that array and returns a count of all cells equal to A1 which is "BI". The second row retains the original starting cell for the array of A$1$ however the end of the array is A2. So the COUNTIFS function sees the new array to search through to be A$1$:A2. The COUNTIFS then searchs through each cell equal to A2 which like A1 is "BI". There are two cells equal to "BI" in the new array and thus the reult is 2. How this works like you want is displayed in the third row of Col B. The OFFSET functions simply expands the array size to A$1$:A3. The COUNTIFS will work as it normally does, it takes the array, called the criteriarange in Excel, and performs a count for all items that equal A3. A3 in this case is equal to "GF" and in the array A$1$:A3 there are two cells equal to "BF" and one equal to "GF". Hope this helps!
Excel: Multiply each cell in row X by corresponding cell in row 2, and get sum
I have a table set up as follows: Column 1 - Customer Name Row 1 - Item Name Row 2 - Item Cost Row 3+- Item Quantity How do I set up the last column to calculate the total cost for each customer? I.e, For each customer row, I want to multiply the number in each cell (= quantity) by the corresponding cell in Row 2 (= cost), and add them all up for the final bill. To clarify what I'm saying I'm attaching the following picture so that we can discuss specifics.
Have you tried SUMPRODUCT - it does exactly what you need, gives the sum of 2 or more multiplied ranges? =SUMPRODUCT(A71:C71,$A$2:$C$2) You can extend the ranges as far as you need. If you want to add columns make sure you don't add at the end, e.g. if you retain one blank column (D currently) and include that in the formula, then if you add a column at D the formula will automatically extend to E
You can use sumproduct but specify the ranges, e.g. =sumproduct(B2:B6,C2:C6), the next row would then be =sumproduct(B2:B6,D2:D6) etc. I'm sure there's a way to "fix" your cost row but it's quite quick doing it this way
If, for example, your first data set is in column A (i.e. per unit cost) and the second data set is in column B (i.e. quantity), and you want the total cost for each item for the specified quantity, place the following formula in C1 =A1*B1 Select C1 and drag the fill handle - this is the small black square at the bottom right corner of the cursor as far down the column as you need. The program will automatically replicate the formula with the correct cell numbers for each row.
One way is to use this formula: =SUM(B4:B5)*B2+SUM(C4:C5)*C2 It is not so cool but you still need to expand the formula even with SUMPRODUCT because the range has to be the same as far as I know. The other way I came up will use a matrix function called MMULT and here is the example: With this array (means you have to click Ctrl + Shift + Enter altogether) formula entered into cell D6: =SUM(MMULT(B2:C2,TRANSPOSE(B3:C5))), you will get your expected result without needing all the subtotals. Please note this is a 2 x 1 By 2 x 3 Matrixformula.
How to sort table using function/equation only
How can I sort a table in sheet 1 like A B C D E 3 7 3 6 5 into another table in sheet 2 A C E D B 3 3 5 6 7 by using function only?
One really easy way to do it would be to just have a rank index and then use HLOOKUP to find the corresponding values: =RANK(A4,$A$4:$E$4,1) =IF(COUNTIF($A$1:A$1,A1)>1,RANK(A4,$A$4:$E$4,1)+COUNTIF($A$1:A$1,A1)-1,RANK(A4,$A$4:$E$4,1)) =HLOOKUP(COLUMN(),$A$2:$E$4,2,FALSE) =HLOOKUP(COLUMN(),$A$2:$E$4,3,FALSE)
Okay, here's the "one formula does it all" solution without additional temporary columns: Formula in A6: =INDEX($A$2:$E$2,MATCH(SMALL($A$3:$E$3+COLUMN($A$3:$E$3)/100000000,COLUMN()),$A$3:$E$3+COLUMN($A$3:$E$3)/100000000,0)) Enter it as an array formula, i.e. press Ctrl-Shift-Enter. Then copy it to the adjacent columns. To get also the number, use this formula in A7 (again as array formula): =ROUND(SMALL($A$3:$E$3+COLUMN($A$3:$E$3)/100000000,COLUMN()),6) Both formulas are a bit bloated as they have to also handle the potential duplicates. The solution is to simply add a very tiny fraction of the column before applying the sorting (SMALL function) - and then to remove it again...
I think an easier solution is to use the "Large" function: The Column functions are just an easy way to count from 5 down to 1, but a helper column may be even easier. You can have a similar answer using the "Small" function as well.
Although I have used the "add a small number technique", I think this is the most elegant for a helper row/column: =RANK(B4,$B$4:$F$4,0) + COUNTIF($B$4:$F$4,B4)-1 (copy across the row column) RANK gets you close and the COUNTIF portion handles duplicates by counting the number of duplicates of the cell to that point. Since there is always match (itself) you subtract 1 for the final rank. This "sorts" ties in the order that they appear. Note that an empty cell will generate #N/A and character data as #Values.
It's doable! :-)
Here is the sample file.
Explanation
I assume that your data is in row 1 of Sheet1 and that you want the data sorted starting in column 1 of another sheet - if not, adjust accordingly.
Place this formula in column 1 of the target sheet, say in row 2:
=ROUND(SMALL(Sheet1!$A$1:$E$1+COLUMN(Sheet1!$A$1:$E$1)/100000000,COLUMN()),6)
You need to enter the formula as an array formula, i.e. press Ctrl-Shift-Enter.
In case you place it in another column than column one, you need to replace COLUMN() with COLUMN()-COLUMN($A$2)+1 where $A$2must be a reference to the cell itself.
This formula will return you the lowest number in your range - if you copy it the next 4 columns, you'll get your order list of numbers.
To translate this back to the column number, we need to perform 2 steps:
Figure out the column number:This can be done with with this formula:
=MATCH(SMALL(Sheet1!$A$1:$E$1+COLUMN(Sheet1!$A$1:$E$1)/100000000,COLUMN()),Sheet1!$A$1:$E$1+COLUMN(Sheet1!$A$1:$E$1)/100000000,0)
- again, to be entered as array formula. If the source data does not start in column A, you need to add +COLUMN(Sheet1!$A$1)-1 where $A$1 needs to be replaced with the leftmost cell of the source data.
Convert the column number to a letter:Assuming your column number from step 1 is in cell A6, this formula will do the job:
=LEFT(ADDRESS(1,A6,2),SEARCH("$",ADDRESS(1,A6,2))-1)
Of course, you can also combine step 1&2, this will result in this megaformula:
=LEFT(
ADDRESS(
1,
MATCH(
SMALL(Sheet1!$A$1:$E$1+COLUMN(Sheet1!$A$1:$E$1)/100000000,COLUMN()),
Sheet1!$A$1:$E$1+COLUMN(Sheet1!$A$1:$E$1)/100000000,
0),
2),
SEARCH(
"$",
ADDRESS(
1,
MATCH(
SMALL(Sheet1!$A$1:$E$1+COLUMN(Sheet1!$A$1:$E$1)/100000000,COLUMN()),
Sheet1!$A$1:$E$1+COLUMN(Sheet1!$A$1:$E$1)/100000000,0),
2)
)-1
)
Again, to be entered as array formula.