Using Selenium and Python to Click on a button below searched element - python-3.x

Question

I am trying to test downloading a file from a website using selenium on python.
The website has peculiar design where the file name appears as a text element above the button to download the file. There are no specific names or IDs for these buttons. And they are not known to us. So, I can't specify the ID or element name in the code directly.
Here is the HTML snippet:
<div class="col-xs-12 col-sm-12 col-md-12 col-lg-12 noborderBottom semiBolder-label ">
<span data-bind="text: jurisdictionName, attr: { id: jurisdictionId() + '-guides' }, visible: showInList" id="67-guides">Greece</span>
</div>
<div class="clearfix visible-xs"></div>
<div class="col-xs-6 col-sm-6 col-md-5 col-lg-5 text-center">
<div class="greenPDFIcon cursorPointer align-center" data-bind="event: { click: onHighlightClick.bind($data) }, style: { 'visibility': highLightUrl() ? 'visible' : 'hidden' }" style="visibility: visible;"></div>
<span class="taxGuidesText lg-visible md-visible xs-visible" data-bind="style: { 'visibility': highLightUrl() ? 'visible' : 'hidden' }" style="visibility: visible;">Highlights</span>
<!--<span class="taxGuidesText lg-visible md-visible xs-visible" data-bind="visible:showInList">Highlights</span>-->
</div>
Now, I first need to search for the text "Greece" in the above example.
Get it's location on the webpage:
class="col-xs-12 col-sm-12 col-md-12 col-lg-12 noborderBottom semiBolder-label"
Locate the button right below this text - so in the above example that gives me:
class="col-xs-6 col-sm-6 col-md-5 col-lg-5"
And then click on the button:
class="greenPDFIcon cursorPointer align-center"
The thing is, I do not know this "Greece". That comes through input parameter.
I only know that if the input parameter text is found on the webpage, the button will be right below it. And I have to click it to open the pdf file.
How to do that using selenium on python?
So far I have reached:
s=Service(r"driver_path")
browser = webdriver.Edge(service=s)
browser.get('webpage_url')
country = input('Enter a country name: ')
Also, suggest if I should use anything else rather than selenium to do this, as I understand this is more of web-scrapping than automated testing. I also tried beautifulsoup, but the website is not accessible directly through api. Browser access is required.

Answer 1

To locate the element with the country name e.g. Greece and click on the respective element with text as Highlights you can use the following Locator Strategies:
Using XPATH and "Old Style" String Formatting (% Operator):
browser.get('webpage_url')
country = input('Enter a country name: ')
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//div[contains(#class, 'semiBolder-label')]//span[contains(., '%s')]//following::div[2]//span[contains(., 'Highlights')]" % country))).click()
Using XPATH and "New Style" String Formatting (str.format):
browser.get('webpage_url')
country = input('Enter a country name: ')
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//div[contains(#class, 'semiBolder-label')]//span[contains(., '{}')]//following::div[2]//span[contains(., 'Highlights')]".format(country)))).click()
Using XPATH and String Interpolation / f-Strings (Python 3.6+):
browser.get('webpage_url')
country = input('Enter a country name: ')
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, f"//div[contains(#class, 'semiBolder-label')]//span[contains(., '{country}')]//following::div[2]//span[contains(., 'Highlights')]"))).click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC