find all substring between two char (...) delimiters using shell script [closed] - string

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I want find all substring between '(' and ')' delimiters using shell script
ex: a string (123).....(abc)...(0000).....
123
abc
0000
I want to extract all substring from the string and use grep like this:
grep -o -P "(?<=()(.*?)(?=))"
and how to assign the output values that match the conditions to the variables
x=123
y=abc
...
Thanks

Answer 1

As your question is confusing regarding the language to use, using bash:
echo "a string (123).....(abc)...(0000)..... <br/>" | grep -P "(?<=\()(.*?)(?=\))" -o
The same logic can be used in Python
import re
data = "a string (123).....(abc)...(0000)..... <br/>"
print(re.findall("(?<=\\()(.*?)(?=\\))", data))
Output
123
abc
0000
Explanation
(?<=\() : positive lookbehind for (
(.*?) : match everything in a non-greedy way and capture it.
(?=\)) : positive lookahead for )

Answer 2

strr='a string (123).....(abc)...(0000)..... <br/>'
strr=strr.split('(')
plist=[]
for s in range(1,len(strr)):
plist.append(strr[s].split(')')[0])
print(plist)