This question already has answers here:
how to detect and get url on string javascript [duplicate]
(2 answers)
Closed 1 year ago.
I have been looking for a way to parse URL from a string.
My current goal is to parse
https://example.com/foo.png
from a string like
abcxyz https://example.com/foo.png gibberfish text.
Anyone got a solution or a package that can help me to do the job?
Thanks in advance.
text = "abcxyz https://example.com/foo.png gibberfish text."
console.log(text.split(" ")[1])
.split() splits the string at spaces into an array of words.
You can refer: https://www.w3schools.com/jsref/jsref_split.asp
I recommend this solution. It turns all words into an array and picks out the ones starting with https://
text.split(" ").filter(i => i.startsWith("https://")).toString();
Related
This question already has answers here:
How do I do a case-insensitive string comparison?
(15 answers)
Closed 7 months ago.
I’m new with Python. Just One question.
I try to create a mini quizz game and i want avoid this :
Answer = Input(« « « Who sing : « Thriller » ? » » »)
If answer == « Michael Jackson »:
Print(« Good. »)
Else:
Print(« Wrong. »)
The problem is that if the user answer «michael jackson », the code run with wrong.
How can i fixed that?
Thanks
The way that this is usually done is to just turn all the input to lowercase. This can be done with the .lower() method on the input string. The corrector answer would then be "michael jackson".
This question already has answers here:
Python convert tuple to string
(5 answers)
Closed 2 years ago.
I would like to know how to convert an unknown number of arguments to a string. what I need to do is redirect the output of a function that is supposed to go to print() to a Qt QPlainTextEdit. since it only accepts strings, I need a way to convert the given arguments to a string.
basically what I am looking for is print() but instead of outputting to the terminal, the output is to a string.
If you have an array of elements you can do:
def print_foo(arr,count):
for i in range(0,int(count)):
print(str(arr[i]))
Basically, converting to string is - newstr = str(varriable)
This question already has answers here:
Regular expression to get a string between two strings in Javascript
(13 answers)
Closed 5 years ago.
I have a string with multiple URLs and other content in it.
I have URLs in following format:
http://www.example.com/bla1/bla2/thumb_my-file-name(2).JPG
The part till http://www.example.com/bla1/bla2/thumb_ is fixed.
However, I dont know what will be: my-file-name(2). I know it will be ending with .JPG
So far, I'm using the following regex to detect them:
/http:\/\/www.example.com\/bla1\/bla2\/thumb_/g
and I have also used \.JPG to detect the end.
But how do I capture the middle part as well?
How do I catch this whole URL?
Try this regex pattern:
http://www.example.com/bla1/bla2/thumb_(.*?)\.JPG
Code:
var url = "http://www.example.com/bla1/bla2/thumb_my-file-name(2).JPG";
var myRegexp = /http:\/\/www.example.com\/bla1\/bla2\/thumb_(.*?)\.JPG/g;
var match = myRegexp.exec(url);
console.log(match[1]); // my-file-name(2)
This question already has answers here:
Extraction of data from a simple XML file
(11 answers)
Closed 7 years ago.
Below is the command used for getting the required string from the file.
cat xmlconfig.new |grep "id=\"build\""
< parameter id="build" >v6.0.9< /parameter >
I want the v6.0.9 value from the above result, in such a way that it tokenizes according to the bracket, not according to word position
I do not have xml parser installed on my machine and I do not have admin access
I want to know if it can be done without using XML parser
Use a proper XML parser, e.g. xsh:
open xmlconfig.new ;
echo //parameter[#id='build'] ;
This question already has answers here:
Split string in Lua?
(18 answers)
Closed 9 years ago.
I have one string, that is = s = "Pedro Martinez, Defense"
I want to split the string before the comma and after the comma, store those cuts on 2 variables, for example:
I think that I need to use the string.gmatch function or string.sub
How can I do that?
The accepted answer at How to convert GPS coordinates to decimal in Lua? shows how to use string.match and patterns. Applying the same techniques as mentioned there, you could use
local name, expertise = string.match(s, "(.*),%s*(%a*)")
which would lead to name being "Pedro Martinez" and expertise being "Defense".