Moving circles - like bouncing - geometry

Just another question! I'm trying to make the circle bounce around, but it's not working I even tried the most basic way, of just adding a value (from a 'step' int) to the circle x, but it's not working. What's the approach I should follow?
I know it's a basic question, but I'm knew to this :)
float time;
PFont font1;
/*float posX, posY, velX, velY, raio;
int dirX = 1;
int dirY = -1;*/
int passo = 2;
color c1 = color (253, 196, 80, 40);
color c2 = color(254, 127, 168, 40);
color c3 = color (53, 63, 114, 80);
color c4 = color (206, 186, 221, 80);
void setup() {
size(600, 800);
smooth();
background (#F6C4C7);
ellipseMode(RADIUS);
noStroke();
time = 17;
}
//make gradient
void desenhar_grad(float posX, float posY, int raio, color color1, color color2) {
pushStyle();
noStroke();
for (int r = raio; r > 0; r--) {
int tom = lerpColor(color1, color2, map(r, 0, raio, 0.0, 1.0)); // os últimos dois valores são as cores. o primeiro é o centro, o segundo é o exterior
fill(tom);
circle(posX, posY, r * 2);
}
popStyle();
}
/*void move() {
posY+=velY*dirY;
if (posY>height-raio || posY<raio)
dirY*=-1;
posX+=velX*dirX;
if (posX>width-raio || posX<raio)
dirX*=-1;
}*/
void draw () {
smooth();
for (int linha = 0; linha < 3; linha++) {
for (int coluna = 0; coluna < 3; coluna++) {
if (time <= 19) {
desenhar_grad(150 + coluna * 150, 200 + linha * 150, 30, c1, c2);
} else
desenhar_grad(150 + coluna * 150, 200 + linha * 150, 30, c4, c3);
}
}
}
} ```
Also, should I create a class for the circles in order to optimize the code?
Thank you!

I see your attempt with using the move() function (and related variables).
Again, close, but there are a few gotchas:
the values used in move() should be initialised: otherwise they'll default to 0 and any number multiplied by 0 is 0 which will result in no movement at all
once you have computed the correct posX, posY you could use those to translate() everything (i.e. the gradients): once everything is translated the 150, 200 offsets could be removed (and used as posX, posY initial values)
it's unclear with the "pivot" of the 3x3 gradient grid should be at the centre or the top left corner of the grid. Let's start with the simpler top left option. This can easily be changed later to centre simply by adding had the grid size to posX and posY
Here's a modified version of your sketch using the notes above:
float time;
// initialise movement variables
float posX = 150, posY = 200, velX = 1, velY = 1;
int raio = 30;
int dirX = 1;
int dirY = -1;
color c1 = color (253, 196, 80, 40);
color c2 = color(254, 127, 168, 40);
color c3 = color (53, 63, 114, 80);
color c4 = color (206, 186, 221, 80);
void setup() {
size(600, 800);
smooth();
ellipseMode(RADIUS);
smooth();
noStroke();
time = 17;
}
//make gradient
void desenhar_grad(float posX, float posY, int raio, color color1, color color2) {
pushStyle();
noStroke();
for (int r = raio; r > 0; r--) {
int tom = lerpColor(color1, color2, map(r, 0, raio, 0.0, 1.0)); // os últimos dois valores são as cores. o primeiro é o centro, o segundo é o exterior
fill(tom);
circle(posX, posY, r * 2);
}
popStyle();
}
void move() {
posY += velY * dirY;
if (posY > height - raio || posY < raio)
dirY *= -1;
posX += velX * dirX;
if (posX > width - raio || posX < raio)
dirX *= -1;
// for testing only:
println("posX",posX, "width", width, "posY", posY, "height", height);
}
void draw () {
if(!mousePressed) background (#F6C4C7);
// update posX, posY taking sketch borders into account
move();
// translate everything to the updated position
translate(posX, posY);
for (int linha = 0; linha < 3; linha++) {
for (int coluna = 0; coluna < 3; coluna++) {
if (time <= 19) {
desenhar_grad(coluna * 150, linha * 150, raio, c1, c2);
} else
desenhar_grad(coluna * 150, linha * 150, raio, c4, c3);
}
}
}
I've removed unused variables for clarity and added a few comments.
There are still a few confusing, perhaps unrelated items:
should the screen be cleared or should the grid leave trails ? (for now you can leave trails by holding the mouse pressed, but you can easily choose when to call background() based on the look you're going for)
how should the time variable be updated ? Currently it's set to 17 in setup() and doesn't change making the if/else condition inside the nested for loops redundant. Perhaps you meant to update in draw() based on some conditions ?
should the grid move as a whole or should each gradient move on its own ? my assumption is you're trying move the grid altogether however if you want to move each gradient on its own bare in mind you will need to use an array for each variable used in move() so it can be updated independently for each gradient (e.g. float[] posX, posY, velX, velY).)
Side note: If the movement is this simple you could get away with pos and
vel variables and not use dir variables:
void move() {
posY += velY;
if (posY > height - raio || posY < raio)
velY *= -1;
posX += velX;
if (posX > width - raio || posX < raio)
velY *= -1;
}
Manually updating each x,y variable is a great way to learn.
At a later date you might find PVector useful for movement.

Related

Processing: how to make box() appear solid (non-transparent) in 3d mode

I'm trying to create layers of 3d boxes in Processing. I want them to appear solid, so that you can't see the boxes "behind" other boxes, but the way they're displaying makes them seem transparent; you can see the stroke of boxes behind other boxes. How do I make them appear solid?
// number of boxes
int numBox = 300;
// width of each box
int boxWidth = 30;
// number of boxes per row
float numPerRow;
void setup() {
size(800, 800, P3D);
pixelDensity(1);
colorMode(HSB, 360, 100, 100, 100);
background(40, 6, 85);
stroke(216, 0, 55);
smooth(4);
fill(0, 0, 90, 100);
numPerRow = width / boxWidth;
}
void draw() {
background(40, 6, 85);
translate((boxWidth / 2), 100);
rotateX(-PI/6);
rotateY(PI/8);
for (int i = 0; i < numBox; i++) {
drawBox(i);
if (i == numBox - 1) {
noLoop();
}
}
}
void drawBox(int i) {
if ((i % 2) == 0) {
pushMatrix();
translate(((boxWidth / 2) * i) % width, 20 * floor(i / (2 * numPerRow)));
translate(0, -((i % 30) / 2));
box(boxWidth, i % 30, boxWidth);
popMatrix();
};
}
Close-up of how the boxes are being displayed:
The issue is that the boxes are intersecting and the strokes of these intersecting boxes are what give the appearance of "see through".
I'm noticing you are using x and y translation, but not z.
If you don't plan to increase x, y spacing to avoid intersections, you can easily offset rows on the z axis so rows of boxes appear in front of each other.
Here's a slightly modified version of your code illustrating this idea:
// number of boxes
int numBox = 300;
// width of each box
int boxWidth = 30;
// number of boxes per row
float numPerRow;
void setup() {
size(800, 800, P3D);
pixelDensity(1);
colorMode(HSB, 360, 100, 100, 100);
background(40, 6, 85);
stroke(216, 0, 55);
smooth(4);
fill(0, 0, 90, 100);
numPerRow = width / boxWidth;
}
void draw() {
background(40, 6, 85);
translate((boxWidth / 2), 100);
if(mousePressed){
rotateX(map(mouseY, 0, height, -PI, PI));
rotateY(map(mouseX, 0, width, PI, -PI));
}else{
rotateX(-PI/6);
rotateY(PI/8);
}
for (int i = 0; i < numBox; i++) {
drawBox(i);
//if (i == numBox - 1) {
// noLoop();
//}
}
}
void drawBox(int i) {
if ((i % 2) == 0) {
pushMatrix();
float x = ((boxWidth / 2) * i) % width;
float y = 20 * floor(i / (2 * numPerRow));
float z = y * 1.5;
translate(x, y, z);
translate(0, -((i % 30) / 2));
box(boxWidth, i % 30, boxWidth);
popMatrix();
};
}
(Click and drag to rotate and observe the z offset.
Feel free to make z as interestersting as you need it it.
Nice composition and colours!
(framing (window size) could use some iteration/tweaking, but I'm guessing this is WIP))

How to draw this circle instead of Bresenham's Circle Algorithm

int main()
{
const auto console = ::GetConsoleWindow();
const auto context = ::GetDC(console);
constexpr auto red = RGB(255, 0, 0);
constexpr auto yellow = RGB(255, 255, 0);
RECT rectClient, rectWindow;
GetClientRect(console, &rectClient);
GetWindowRect(console, &rectWindow);
int posx, posy;
posx = GetSystemMetrics(SM_CXSCREEN) / 2 - (rectWindow.right - rectWindow.left) / 2;
posy = GetSystemMetrics(SM_CYSCREEN) / 2 - (rectWindow.bottom - rectWindow.top) / 2;
const int radius = 150;
for (int y = -radius; y <= radius; y++)
for (int x = -radius; x <= radius; x++)
if (x * x + y * y <= radius * radius)
SetPixel(context, posx + x, posy + y, red);
}
It gives me this result img
it looks good but i saw this weird pixels at sides (up, down, right, left)
img
and this is what I want (I added some pixels at the top so it looks better)
enter image description here
Your "what I want" looks anti-aliased. So draw anti-aliased.
If the original condition is not met, but x*x + y*y <= (radius+1)*(radius+1) is met then you need a partially-shaded pixel.
Another way to do anti-aliasing is to test not the center of each pixel but the four corners (x \plusminus 0.5, y \plusminus 0.5). If more than zero but fewer than four corners are inside the circle, you need a partially-shaded pixel.

How to center this grid of squares?

I am trying to simply produce a grid of 5 rotated rectangles. But the grid will not come out centered. Can anyone help me out?
int margin = 150; //padding to sides and top/bottom
int rectH = 60; // height of rectangle
int rectW = 20; // width of rectangle
int n_rectangles = 5; // 5 rectangles to draw
size(800,800);
for (int x = margin+rectW; x <= width - margin; x += (width-2*(margin+rectW))/n_rectangles) {
for (int y = margin+rectH; y <= height - margin; y += (height-2*(margin+rectH))/n_rectangles) {
fill(255);
//now rotate matrix 45 degrees
pushMatrix();
translate(x, y);
rotate(radians(45));
// draw rectangle at x,y point
rect(0, 0, rectW, rectH);
popMatrix();
}
}
I recommend to draw single "centered" rectangles, the origin of the rectangle is (-rectW/2, -rectH/2):
rect(-rectW/2, -rectH/2, rectW, rectH);
Calculate the distance of the first rectangle center tor the last rectangle center, for row and column:
int size_x = margin * (n_rectangles-1);
int size_y = margin * (n_rectangles-1);
Translate to the center of the screen (width/2, height/2),
to the position of the upper left rectangle (-size_x/2, -size_y/2)
and finally each rectangle to its position (i*margin, j*margin):
translate(width/2 - size_x/2 + i*margin, height/2 - size_y/2 + j*margin);
See the final code:
int margin = 150; //padding to sides and top/bottom
int rectH = 60; // height of rectangle
int rectW = 20; // width of rectangle
int n_rectangles = 5; // 5 rectangles to draw
size(800,800);
int size_x = margin * (n_rectangles-1);
int size_y = margin * (n_rectangles-1);
for (int i = 0; i < n_rectangles; ++i ) {
for (int j = 0; j < n_rectangles; ++j ) {
fill(255);
pushMatrix();
translate(width/2 - size_x/2 + i*margin, height/2 -size_y/2 + j*margin);
rotate(radians(45));
rect(-rectW/2, -rectH/2, rectW, rectH);
popMatrix();
}
}

How to get the average color of a specific area in a webcam feed (Processing/JavaScript)?

I'm using Processing to get a webcam feed from my laptop. In the top left corner, I have drawn a rectangle over the displayed feed. I'm trying to get the average color of the webcam, but only in the region contained by that rectangle.
I keep getting color (0, 0, 0), black, as the result.
Thank you all!
PS sorry if my code seems messy..I'm new at Processing and so I don't know if this might be hard to read or contain bad practices. Thank you.
import processing.video.*;
Capture webcam;
Capture cap;
PImage bg_img;
color bgColor = color(0, 0, 0);
int rMargin = 50;
int rWidth = 100;
color input = color(0, 0, 0);
color background = color(255, 255, 255);
color current;
int bgTolerance = 5;
void setup() {
size(1280,720);
// start the webcam
String[] inputs = Capture.list();
if (inputs.length == 0) {
println("Couldn't detect any webcams connected!");
exit();
}
webcam = new Capture(this, inputs[0]);
webcam.start();
}
void draw() {
if (webcam.available()) {
// read from the webcam
webcam.read();
image(webcam, 0,0);
webcam.loadPixels();
noFill();
strokeWeight(2);
stroke(255,255, 255);
rect(rMargin, rMargin, rWidth, rWidth);
int yCenter = (rWidth/2) + rMargin;
int xCenter = (rWidth/2) + rMargin;
// rectMode(CENTER);
int rectCenterIndex = (width* yCenter) + xCenter;
int r = 0, g = 0, b = 0;
//for whole image:
//for (int i=0; i<bg_img.pixels.length; i++) {
// color c = bg_img.pixels[i];
// r += c>>16&0xFF;
// g += c>>8&0xFF;
// b += c&0xFF;
//}
//r /= bg_img.pixels.length;
//g /= bg_img.pixels.length;
//b /= bg_img.pixels.length;
//CALCULATE AVG COLOR:
int i;
for(int x = 50; x <= 150; x++){
for(int y = 50; y <= 150; y++){
i = (width*y) + x;
color c = webcam.pixels[i];
r += c>>16&0xFF;
g += c>>8&0xFF;
b += c&0xFF;
}
}
r /= webcam.pixels.length;
g /= webcam.pixels.length;
b /= webcam.pixels.length;
println(r + " " + g + " " + b);
}
}
You're so close, but missing out one important aspect: the number of pixels you're sampling.
Notice in the example code that is commented out for a full image you're dividing by the full number of pixels (pixels.length).
However, in your adapted version you want to compute the average colour of only a subsection of the full image which means a smaller number of pixels.
You're only sampling an area that is 100x100 pixels meaning you need to divide by 10000 instead of webcam.pixels.length (1920x1000). That is why you get 0 as it's integer division.
This is what I mean in code:
int totalSampledPixels = rWidth * rWidth;
r /= totalSampledPixels;
g /= totalSampledPixels;
b /= totalSampledPixels;
Full tweaked sketch:
import processing.video.*;
Capture webcam;
Capture cap;
PImage bg_img;
color bgColor = color(0, 0, 0);
int rMargin = 50;
int rWidth = 100;
int rHeight = 100;
color input = color(0, 0, 0);
color background = color(255, 255, 255);
color current;
int bgTolerance = 5;
void setup() {
size(1280,720);
// start the webcam
String[] inputs = Capture.list();
if (inputs.length == 0) {
println("Couldn't detect any webcams connected!");
exit();
}
webcam = new Capture(this, inputs[0]);
webcam.start();
}
void draw() {
if (webcam.available()) {
// read from the webcam
webcam.read();
image(webcam, 0,0);
webcam.loadPixels();
noFill();
strokeWeight(2);
stroke(255,255, 255);
rect(rMargin, rMargin, rWidth, rHeight);
int yCenter = (rWidth/2) + rMargin;
int xCenter = (rWidth/2) + rMargin;
// rectMode(CENTER);
int rectCenterIndex = (width* yCenter) + xCenter;
int r = 0, g = 0, b = 0;
//for whole image:
//for (int i=0; i<bg_img.pixels.length; i++) {
// color c = bg_img.pixels[i];
// r += c>>16&0xFF;
// g += c>>8&0xFF;
// b += c&0xFF;
//}
//r /= bg_img.pixels.length;
//g /= bg_img.pixels.length;
//b /= bg_img.pixels.length;
//CALCULATE AVG COLOR:
int i;
for(int x = 0; x <= width; x++){
for(int y = 0; y <= height; y++){
if (x >= rMargin && x <= rMargin + rWidth && y >= rMargin && y <= rMargin + rHeight){
i = (width*y) + x;
color c = webcam.pixels[i];
r += c>>16&0xFF;
g += c>>8&0xFF;
b += c&0xFF;
}
}
}
//divide by just the area sampled (x >= 50 && x <= 150 && y >= 50 && y <= 150 is a 100x100 px area)
int totalSampledPixels = rWidth * rHeight;
r /= totalSampledPixels;
g /= totalSampledPixels;
b /= totalSampledPixels;
fill(r,g,b);
rect(rMargin + rWidth, rMargin, rWidth, rHeight);
println(r + " " + g + " " + b);
}
}
Bare in mind this is averaging in the RGB colour space which is not the same as perceptual colour space. For example, if you average red and yellow you'd expect orange, but in RGB, a bit of red and green makes yellow.
Hopefully the RGB average is good enough for what you need, otherwise you may need to convert from RGB to CIE XYZ colour space then to Lab colour space to compute the perceptual average (then convert back to XYZ and RGB to display on screen). If that is something you're interested in trying, you can find an older answer demonstrating this in openFrameworks (which you'll notice can be similar to Processing in simple scenarios).

Generate a n-color rainbow palette

I'm trying to generate a rainbow with 15 different colors with (runnable code here):
size(360,100);
colorMode(HSB, 360, 100, 100); // Hue in degrees in [0, 360],
// saturation/brightness in [0, 100]
// like in Photoshop
noStroke();
for (int i = 0; i < 15; i++)
{
fill(i*24, 100, 100); // 24*15 = 360
rect(i*24, 0, 25, 100);
}
but it doesn't produce a rich 15 rainbow-color palette, instead some colors are missing (vivid yellow for example).
Is there a well known algorithm to produce a vivid rainbow color palette?
To understand what's going on, try creating a program that shows a line for each value 0-360:
size(360,100);
colorMode(HSB, 360, 100, 100);
noStroke();
for (int i = 0; i < 360; i++)
{
fill(i, 100, 100);
rect(i, 0, 1, 100);
}
You'll see this:
Notice that the "vivid yellow" band is much more narrow than, for example, the green or blue bands. That's why simply sampling every X values doesn't generate a yellow color.
The yellow color is around value 60, so you could modify your increment so it lands on 60. Drawing 12 rectangles with a width of 30 lets you land on the yellow:
size(360,100);
colorMode(HSB, 360, 100, 100);
noStroke();
for (int i = 0; i < 360; i++)
{
fill(i*30, 100, 100);
rect(i*30, 0, 30, 100);
}
Or you could come up with the values you want ahead of time and put them in an array instead of using an even distribution:
int[] hueValues = {0, 15, 30, 60, 90, 120, 150, 180, 210, 225, 240, 270, 300, 330, 360};
size(360,100);
colorMode(HSB, 360, 100, 100);
noStroke();
for (int index = 0; index < hueValues.length; index++)
{
float rectWidth = width/hueValues.length;
fill(hueValues[index], 100, 100);
rect(index*rectWidth, 0, rectWidth, height);
}
I created a function that generates N colors (rainbow) and outputs a list of strings (Hex values). This is in C# but logic can be converted. In order to understand what's going on I graphed the red, blue, and green values vs n. Doing that you'll see the three graphs each are piecewise functions with points of interest at n=0, n=1/4, n=1/2 and n=3/4.
List<string> GenerateRainbowPalette(int numColors)
{
var toRet = new List<SKColor>();
var n = (float)numColors;
for(var i = 0; i< numColors; i++)
{
int red = 255;
int green = 0;
int blue = 0;
//red: (first quarter)
if (i <= n / 4)
{
red = 255;
green = (int)(255 / (n / 4) * i);
blue = 0;
}
else if (i <= n / 2) //2nd quarter
{
red = (int)((-255)/(n/4)*i + 255 * 2);
green = 255;
blue = 0;
}
else if (i <= (.75)*n)
{ // 3rd quarter
red = 0;
green = 255;
blue = (int)(255 / (n / 4) * i + (-255 * 2));
}
else if(i > (.75)*n)
{
red = 0;
green = (int)(-255 * i / (n / 4) + (255 * 4));
blue = 255;
}
//generate hex string:
var redHex = red.ToString("X2");
var greenHex = green.ToString("X2");
var blueHex = blue.ToString("X2");
var color = $"#{redHex}{greenHex}{blueHex}";
toRet.Add(color);
}
return toRet;
}

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