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I want to add lines '{"index":{"_id":$number_of_id}}' to my file name ss.josn before each json object (which is a line)
cat ss.json
input example:
{"msisdn":"255742005249","subscription_date":"2021-05-26T16:41:40.467Z","optout_date":"2022-01-03T19:12:59.808Z","total_charged_amount":1300}
{"msisdn":"255742009077","subscription_date":"2019-12-31T22:00:00.000Z","optout_date":"2022-01-09T14:08:00.282Z","total_charged_amount":3370}
{"msisdn":"255742009703","subscription_date":"2019-12-31T22:00:00.000Z","optout_date":"2022-01-01T12:34:02.104Z","total_charged_amount":400}
Desired output:
{"index":{"_id":1}}
{"msisdn":"255742005249","subscription_date":"2021-05-26T16:41:40.467Z","optout_date":"2022-01-03T19:12:59.808Z","total_charged_amount":1300}
{"index":{"_id":2}}
{"msisdn":"255742009077","subscription_date":"2019-12-31T22:00:00.000Z","optout_date":"2022-01-09T14:08:00.282Z","total_charged_amount":3370}
{"index":{"_id":3}}
{"msisdn":"255742009703","subscription_date":"2019-12-31T22:00:00.000Z","optout_date":"2022-01-01T12:34:02.104Z","total_charged_amount":400}
If you can ensure that each line is a json struct and you don't have multiline case, a script like this should do the job:
#!/bin/bash
_id=0
while read -r line; do
echo "{"index":{"_id":$_id}}" >> result.json
echo $line >> result.json
_id=$((_id+1))
done < ss.json
Maybe not the most elegant option, but you will have a result.json file with your desired output.
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I'm trying to create a shell script that creates an excel output file and add data in it.
I don't know how to add rows in this excel file. The goal being that the data will be added in separate cells.
I tried many instruction that i found in the web, but none worked for me.
the file after my script would be like below:
Is there an instruction to do this please?
Thanks for your help
This code worked for me:
touch Output.xls
chmod 777 Output.xls
printf "Date\tTotal number\tSuccessful number\tFailed numbe\n" >> Output.xls
printf "2016_05_11\t20\t5\t15\n" >> Output.xls
printf "2016_06_30\t30\t16\t14\n" >> Output.xls
The output file is as below:
enter image description here
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Write a program to open the file and delete a specific line from a text file. The line number of the line to be replaced is asked as input. A new file is opened in write mode named output.txt. The input file name should be input.txt and output file name should be output.txt.
someone please help me through it
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i have a file which contains few lines of code
identifier = "bi-us-rds-15september"
i have to change "bi-us-rds-15september" with "bi-us-rds-current date & current month " .
For example - "bi-us-rds-15september" with "bi-us-rds-18september .
I want to accomplish this using task shell script but i am not good with scripting .
Just use the date format
$ identifier="bi-us-rds-`date +%d%B`"
$ echo $identifier
bi-us-rds-18September
I'd suggest maybe using https://www.tutorialkart.com/bash-shell-scripting/bash-date-format-options-examples/
Also fyi your question is a bit unhelpful - I'd suggest next time at least offer your current script so we can be more precise with the assistance.
edit: removed the extra hyphen just so it matches your exact output required
edit: re: your comment...
$replace=Hi
$replacewith="Hey"
$ echo "Hi how are you?" | sed -e "s/$replace/$replacewith/g"
Hey how are you?
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I want to print the line which has below value in my text file(ex: file.txt).
I have tried multiple ways but no luck. Can someone please help me the right command.
selector="((Source IN ('VPS','VPSLegacy')) OR (JMS_TIBCO_SENDER='rig'))"
Please note that i need to use entire above value to check in the file.
The easiest way to assign a literal (potentially containing quotes or other shell syntax) to a variable, even though it comes with a performance penalty, is to use a quoted heredoc:
content=$(cat <<'EOF'
selector="((Source IN ('VPS','VPSLegacy')) OR (JMS_TIBCO_SENDER='rig'))"
EOF
)
echo "Value is: <$content>"
...correctly emits as output:
Value is: <selector="((Source IN ('VPS','VPSLegacy')) OR (JMS_TIBCO_SENDER='rig'))">
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I have log file for checking transactions, and I have error lines, so I need those error lines to be exported to a .csv file? is there any code using linux bash shell script can do this?
suppose your error lines consists ERROR.
then
grep "ERROR" errorfile.txt | tr -s '[:blank:]' ',' >> errorfile.csv
csv conversion is based on blank spaces to each cell.you can replace blank filter with anything