function first(){
console.log('first')
}
function second(){
console.log('second')
}
let interval = async ()=>{
await setInterval(first,2000)
await setInterval(second,2000)
}
interval();
Imagine that I have this code above.
When I run it, first() and second() will be called at the same time; how do I call second() after first)() returns some data, for example, if first() is done, only then call second()?
Because first() in my code will be working with a big amount of data and if this 2 functions will be calling at the same time, it will be hard for the server.
How do I call second() each time when first() will return some data?
As mentioned above setInterval does not play well with promises if you do not stop it. In case you clear the interval you can use it like:
async function waitUntil(condition) {
return await new Promise(resolve => {
const interval = setInterval(() => {
if (condition) {
resolve('foo');
clearInterval(interval);
};
}, 1000);
});
}
Later you can use it like
const bar = waitUntil(someConditionHere)
You have a few problems:
Promises may only ever resolve once, setInterval() is meant to call the callback multiple times, Promises do not support this case well.
Neither setInterval(), nor the more appropriate setTimeout() return Promises, therefore, awaiting on them is pointless in this context.
You're looking for a function that returns a Promise which resolves after some times (using setTimeout(), probably, not setInterval()).
Luckily, creating such a function is rather trivial:
async function delay(ms) {
// return await for better async stack trace support in case of errors.
return await new Promise(resolve => setTimeout(resolve, ms));
}
With this new delay function, you can implement your desired flow:
function first(){
console.log('first')
}
function second(){
console.log('second')
}
let run = async ()=>{
await delay(2000);
first();
await delay(2000)
second();
}
run();
setInterval doesn't play well with promises because it triggers a callback multiple times, while promise resolves once.
It seems that it's setTimeout that fits the case. It should be promisified in order to be used with async..await:
async () => {
await new Promise(resolve => setTimeout(() => resolve(first()), 2000));
await new Promise(resolve => setTimeout(() => resolve(second()), 2000));
}
await expression causes async to pause until a Promise is settled
so you can directly get the promise's result without await
for me, I want to initiate Http request every 1s
let intervalid
async function testFunction() {
intervalid = setInterval(() => {
// I use axios like: axios.get('/user?ID=12345').then
new Promise(function(resolve, reject){
resolve('something')
}).then(res => {
if (condition) {
// do something
} else {
clearInterval(intervalid)
}
})
}, 1000)
}
// you can use this function like
testFunction()
// or stop the setInterval in any place by
clearInterval(intervalid)
You could use an IFFE. This way you could escape the issue of myInterval not accepting Promise as a return type.
There are cases where you need setInterval, because you want to call some function unknown amount of times with some interval in between.
When I faced this problem this turned out to be the most straight-forward solution for me. I hope it help someone :)
For me the use case was that I wanted to send logs to CloudWatch but try not to face the Throttle exception for sending more than 5 logs per second. So I needed to keep my logs and send them as a batch in an interval of 1 second. The solution I'm posting here is what I ended up using.
async function myAsyncFunc(): Promise<string> {
return new Promise<string>((resolve) => {
resolve("hello world");
});
}
function myInterval(): void {
setInterval(() => {
void (async () => {
await myAsyncFunc();
})();
}, 5_000);
}
// then call like so
myInterval();
Looked through all the answers but still didn't find the correct one that would work exactly how the OP is asked. This is what I used for the same purpose:
async function waitInterval(callback, ms) {
return new Promise(resolve => {
let iteration = 0;
const interval = setInterval(async () => {
if (await callback(iteration, interval)) {
resolve();
clearInterval(interval);
}
iteration++;
}, ms);
});
}
function first(i) {
console.log(`first: ${i}`);
// If the condition below is true the timer finishes
return i === 5;
}
function second(i) {
console.log(`second: ${i}`);
// If the condition below is true the timer finishes
return i === 5;
}
(async () => {
console.log('start');
await waitInterval(first, 1000);
await waitInterval(second, 1000);
console.log('finish');
})()
In my example, I also put interval iteration count and the timer itself, just in case the caller would need to do something with it. However, it's not necessary
In my case, I needed to iterate through a list of images, pausing in between each, and then a longer pause at the end before re-looping through.
I accomplished this by combining several techniques from above, calling my function recursively and awaiting a timeout.
If at any point another trigger changes my animationPaused:boolean, my recursive function will exit.
const loopThroughImages = async() => {
for (let i=0; i<numberOfImages; i++){
if (animationPaused) {
return;
}
this.updateImage(i);
await timeout(700);
}
await timeout(1000);
loopThroughImages();
}
loopThroughImages();
Async/await do not make the promises synchronous.
To my knowledge, it's just a different syntax for return Promise and .then().
Here i rewrote the async function and left both versions, so you can see what it really does and compare.
It's in fact a cascade of Promises.
// by the way no need for async there. the callback does not return a promise, so no need for await.
function waitInterval(callback, ms) {
return new Promise(resolve => {
let iteration = 0;
const interval = setInterval(async () => {
if (callback(iteration, interval)) {
resolve();
clearInterval(interval);
}
iteration++;
}, ms);
});
}
function first(i) {
console.log(`first: ${i}`);
// If the condition below is true the timer finishes
return i === 5;
}
function second(i) {
console.log(`second: ${i}`);
// If the condition below is true the timer finishes
return i === 5;
}
// async function with async/await, this code ...
(async () => {
console.log('start');
await waitInterval(first, 1000);
await waitInterval(second, 1000);
console.log('finish');
})() //... returns a pending Promise and ...
console.log('i do not wait');
// ... is kinda identical to this code.
// still asynchronous but return Promise statements with then cascade.
(() => {
console.log('start again');
return waitInterval(first, 1000).then(() => {
return waitInterval(second, 1000).then(() => {
console.log('finish again');
});
});
})(); // returns a pending Promise...
console.log('i do not wait either');
You can see the two async functions both execute at the same time.
So using promises around intervals here is not very useful, as it's still just intervals, and promises changes nothing, and make things confusing...
As the code is calling callbacks repeatedly into an interval, this is, i think, a cleaner way:
function first(i) {
console.log(`first: ${i}`);
// If the condition below is true the timer finishes
return i === 5;
}
function second(i) {
console.log(`second: ${i}`);
// If the condition below is true the timer finishes
return i === 5;
}
function executeThroughTime(...callbacks){
console.log('start');
let callbackIndex = 0; // to track current callback.
let timerIndex = 0; // index given to callbacks
let interval = setInterval(() =>{
if (callbacks[callbackIndex](timerIndex++)){ // callback return true when it finishes.
timerIndex = 0; // resets for next callback
if (++callbackIndex>=callbacks.length){ // if no next callback finish.
clearInterval(interval);
console.log('finish');
}
}
},1000)
}
executeThroughTime(first,second);
console.log('and i still do not wait ;)');
Also, this solution execute a callback every secondes.
if the callbacks are async requests that takes more than one sec to resolve, and i can't afford for them to overlap, then, instead of doing iterative call with repetitive interval, i would get the request resolution to call the next request (through a timer if i don't want to harass the server).
Here the "recursive" task is called lTask, does pretty much the same as before, except that, as i do not have an interval anymore, i need a new timer each iteration.
// slow internet request simulation. with a Promise, could be a callback.
function simulateAsync1(i) {
console.log(`first pending: ${i}`);
return new Promise((resolve) =>{
setTimeout(() => resolve('got that first big data'), Math.floor(Math.random()*1000)+ 1000);//simulate request that last between 1 and 2 sec.
}).then((result) =>{
console.log(`first solved: ${i} ->`, result);
return i==2;
});
}
// slow internet request simulation. with a Promise, could be a callback.
function simulateAsync2(i) {
console.log(`second pending: ${i}`);
return new Promise((resolve) =>{
setTimeout(() => resolve('got that second big data'), Math.floor(Math.random()*1000) + 1000);//simulate request that last between 1 and 2 sec.
}).then((result) =>{ // promise is resolved
console.log(`second solved: ${i} ->`,result);
return i==4; // return a promise
});
}
function executeThroughTime(...asyncCallbacks){
console.log('start');
let callbackIndex = 0;
let timerIndex = 0;
let lPreviousTime = Date.now();
let lTask = () => { // timeout callback.
asyncCallbacks[callbackIndex](timerIndex++).then((result) => { // the setTimeout for the next task is set when the promise is solved.
console.log('result',result)
if (result) { // current callback is done.
timerIndex = 0;
if (++callbackIndex>=asyncCallbacks.length){//are all callbacks done ?
console.log('finish');
return;// its over
}
}
console.log('time elapsed since previous call',Date.now() - lPreviousTime);
lPreviousTime = Date.now();
//console.log('"wait" 1 sec (but not realy)');
setTimeout(lTask,1000);//redo task after 1 sec.
//console.log('i do not wait');
});
}
lTask();// no need to set a timer for first call.
}
executeThroughTime(simulateAsync1,simulateAsync2);
console.log('i do not wait');
Next step would be to empty a fifo with the interval, and fill it with web request promises...
As far as I understand, in ES7/ES2016 putting multiple await's in code will work similar to chaining .then() with promises, meaning that they will execute one after the other rather than in parallel. So, for example, we have this code:
await someCall();
await anotherCall();
Do I understand it correctly that anotherCall() will be called only when someCall() is completed? What is the most elegant way of calling them in parallel?
I want to use it in Node, so maybe there's a solution with async library?
EDIT: I'm not satisfied with the solution provided in this question: Slowdown due to non-parallel awaiting of promises in async generators, because it uses generators and I'm asking about a more general use case.
You can await on Promise.all():
await Promise.all([someCall(), anotherCall()]);
To store the results:
let [someResult, anotherResult] = await Promise.all([someCall(), anotherCall()]);
Note that Promise.all fails fast, which means that as soon as one of the promises supplied to it rejects, then the entire thing rejects.
const happy = (v, ms) => new Promise((resolve) => setTimeout(() => resolve(v), ms))
const sad = (v, ms) => new Promise((_, reject) => setTimeout(() => reject(v), ms))
Promise.all([happy('happy', 100), sad('sad', 50)])
.then(console.log).catch(console.log) // 'sad'
If, instead, you want to wait for all the promises to either fulfill or reject, then you can use Promise.allSettled. Note that Internet Explorer does not natively support this method.
const happy = (v, ms) => new Promise((resolve) => setTimeout(() => resolve(v), ms))
const sad = (v, ms) => new Promise((_, reject) => setTimeout(() => reject(v), ms))
Promise.allSettled([happy('happy', 100), sad('sad', 50)])
.then(console.log) // [{ "status":"fulfilled", "value":"happy" }, { "status":"rejected", "reason":"sad" }]
Note: If you use Promise.all actions that managed to finish before rejection happen are not rolled back, so you may need to take care of such situation. For example
if you have 5 actions, 4 quick, 1 slow and slow rejects. Those 4
actions may be already executed so you may need to roll back. In such situation consider using Promise.allSettled while it will provide exact detail which action failed and which not.
TL;DR
Use Promise.all for the parallel function calls, the answer behaviors not correctly when the error occurs.
First, execute all the asynchronous calls at once and obtain all the Promise objects. Second, use await on the Promise objects. This way, while you wait for the first Promise to resolve the other asynchronous calls are still progressing. Overall, you will only wait for as long as the slowest asynchronous call. For example:
// Begin first call and store promise without waiting
const someResult = someCall();
// Begin second call and store promise without waiting
const anotherResult = anotherCall();
// Now we await for both results, whose async processes have already been started
const finalResult = [await someResult, await anotherResult];
// At this point all calls have been resolved
// Now when accessing someResult| anotherResult,
// you will have a value instead of a promise
JSbin example: http://jsbin.com/xerifanima/edit?js,console
Caveat: It doesn't matter if the await calls are on the same line or on different lines, so long as the first await call happens after all of the asynchronous calls. See JohnnyHK's comment.
Update: this answer has a different timing in error handling according to the #bergi's answer, it does NOT throw out the error as the error occurs but after all the promises are executed.
I compare the result with #jonny's tip: [result1, result2] = Promise.all([async1(), async2()]), check the following code snippet
const correctAsync500ms = () => {
return new Promise(resolve => {
setTimeout(resolve, 500, 'correct500msResult');
});
};
const correctAsync100ms = () => {
return new Promise(resolve => {
setTimeout(resolve, 100, 'correct100msResult');
});
};
const rejectAsync100ms = () => {
return new Promise((resolve, reject) => {
setTimeout(reject, 100, 'reject100msError');
});
};
const asyncInArray = async (fun1, fun2) => {
const label = 'test async functions in array';
try {
console.time(label);
const p1 = fun1();
const p2 = fun2();
const result = [await p1, await p2];
console.timeEnd(label);
} catch (e) {
console.error('error is', e);
console.timeEnd(label);
}
};
const asyncInPromiseAll = async (fun1, fun2) => {
const label = 'test async functions with Promise.all';
try {
console.time(label);
let [value1, value2] = await Promise.all([fun1(), fun2()]);
console.timeEnd(label);
} catch (e) {
console.error('error is', e);
console.timeEnd(label);
}
};
(async () => {
console.group('async functions without error');
console.log('async functions without error: start')
await asyncInArray(correctAsync500ms, correctAsync100ms);
await asyncInPromiseAll(correctAsync500ms, correctAsync100ms);
console.groupEnd();
console.group('async functions with error');
console.log('async functions with error: start')
await asyncInArray(correctAsync500ms, rejectAsync100ms);
await asyncInPromiseAll(correctAsync500ms, rejectAsync100ms);
console.groupEnd();
})();
Update:
The original answer makes it difficult (and in some cases impossible) to correctly handle promise rejections. The correct solution is to use Promise.all:
const [someResult, anotherResult] = await Promise.all([someCall(), anotherCall()]);
Original answer:
Just make sure you call both functions before you await either one:
// Call both functions
const somePromise = someCall();
const anotherPromise = anotherCall();
// Await both promises
const someResult = await somePromise;
const anotherResult = await anotherPromise;
There is another way without Promise.all() to do it in parallel:
First, we have 2 functions to print numbers:
function printNumber1() {
return new Promise((resolve,reject) => {
setTimeout(() => {
console.log("Number1 is done");
resolve(10);
},1000);
});
}
function printNumber2() {
return new Promise((resolve,reject) => {
setTimeout(() => {
console.log("Number2 is done");
resolve(20);
},500);
});
}
This is sequential:
async function oneByOne() {
const number1 = await printNumber1();
const number2 = await printNumber2();
}
//Output: Number1 is done, Number2 is done
This is parallel:
async function inParallel() {
const promise1 = printNumber1();
const promise2 = printNumber2();
const number1 = await promise1;
const number2 = await promise2;
}
//Output: Number2 is done, Number1 is done
I've created a gist testing some different ways of resolving promises, with results. It may be helpful to see the options that work.
Edit: Gist content as per Jin Lee's comment
// Simple gist to test parallel promise resolution when using async / await
function promiseWait(time) {
return new Promise((resolve, reject) => {
setTimeout(() => {
resolve(true);
}, time);
});
}
async function test() {
return [
await promiseWait(1000),
await promiseWait(5000),
await promiseWait(9000),
await promiseWait(3000),
]
}
async function test2() {
return {
'aa': await promiseWait(1000),
'bb': await promiseWait(5000),
'cc': await promiseWait(9000),
'dd': await promiseWait(3000),
}
}
async function test3() {
return await {
'aa': promiseWait(1000),
'bb': promiseWait(5000),
'cc': promiseWait(9000),
'dd': promiseWait(3000),
}
}
async function test4() {
const p1 = promiseWait(1000);
const p2 = promiseWait(5000);
const p3 = promiseWait(9000);
const p4 = promiseWait(3000);
return {
'aa': await p1,
'bb': await p2,
'cc': await p3,
'dd': await p4,
};
}
async function test5() {
return await Promise.all([
await promiseWait(1000),
await promiseWait(5000),
await promiseWait(9000),
await promiseWait(3000),
]);
}
async function test6() {
return await Promise.all([
promiseWait(1000),
promiseWait(5000),
promiseWait(9000),
promiseWait(3000),
]);
}
async function test7() {
const p1 = promiseWait(1000);
const p2 = promiseWait(5000);
const p3 = promiseWait(9000);
return {
'aa': await p1,
'bb': await p2,
'cc': await p3,
'dd': await promiseWait(3000),
};
}
let start = Date.now();
test().then((res) => {
console.log('Test Done, elapsed', (Date.now() - start) / 1000, res);
start = Date.now();
test2().then((res) => {
console.log('Test2 Done, elapsed', (Date.now() - start) / 1000, res);
start = Date.now();
test3().then((res) => {
console.log('Test3 Done, elapsed', (Date.now() - start) / 1000, res);
start = Date.now();
test4().then((res) => {
console.log('Test4 Done, elapsed', (Date.now() - start) / 1000, res);
start = Date.now();
test5().then((res) => {
console.log('Test5 Done, elapsed', (Date.now() - start) / 1000, res);
start = Date.now();
test6().then((res) => {
console.log('Test6 Done, elapsed', (Date.now() - start) / 1000, res);
});
start = Date.now();
test7().then((res) => {
console.log('Test7 Done, elapsed', (Date.now() - start) / 1000, res);
});
});
});
});
});
});
/*
Test Done, elapsed 18.006 [ true, true, true, true ]
Test2 Done, elapsed 18.009 { aa: true, bb: true, cc: true, dd: true }
Test3 Done, elapsed 0 { aa: Promise { <pending> },
bb: Promise { <pending> },
cc: Promise { <pending> },
dd: Promise { <pending> } }
Test4 Done, elapsed 9 { aa: true, bb: true, cc: true, dd: true }
Test5 Done, elapsed 18.008 [ true, true, true, true ]
Test6 Done, elapsed 9.003 [ true, true, true, true ]
Test7 Done, elapsed 12.007 { aa: true, bb: true, cc: true, dd: true }
*/
In my case, I have several tasks I want to execute in parallel, but I need to do something different with the result of those tasks.
function wait(ms, data) {
console.log('Starting task:', data, ms);
return new Promise(resolve => setTimeout(resolve, ms, data));
}
var tasks = [
async () => {
var result = await wait(1000, 'moose');
// do something with result
console.log(result);
},
async () => {
var result = await wait(500, 'taco');
// do something with result
console.log(result);
},
async () => {
var result = await wait(5000, 'burp');
// do something with result
console.log(result);
}
]
await Promise.all(tasks.map(p => p()));
console.log('done');
And the output:
Starting task: moose 1000
Starting task: taco 500
Starting task: burp 5000
taco
moose
burp
done
(async function(){
function wait(ms, data) {
console.log('Starting task:', data, ms);
return new Promise(resolve => setTimeout(resolve, ms, data));
}
var tasks = [
async () => {
var result = await wait(1000, 'moose');
// do something with result
console.log(result);
},
async () => {
var result = await wait(500, 'taco');
// do something with result
console.log(result);
},
async () => {
var result = await wait(5000, 'burp');
// do something with result
console.log(result);
}
]
await Promise.all(tasks.map(p => p()));
console.log('done');
})();
await Promise.all([someCall(), anotherCall()]); as already mention will act as a thread fence (very common in parallel code as CUDA), hence it will allow all the promises in it to run without blocking each other, but will prevent the execution to continue until ALL are resolved.
another approach that is worth to share is the Node.js async that will also allow you to easily control the amount of concurrency that is usually desirable if the task is directly linked to the use of limited resources as API call, I/O operations, etc.
// create a queue object with concurrency 2
var q = async.queue(function(task, callback) {
console.log('Hello ' + task.name);
callback();
}, 2);
// assign a callback
q.drain = function() {
console.log('All items have been processed');
};
// add some items to the queue
q.push({name: 'foo'}, function(err) {
console.log('Finished processing foo');
});
q.push({name: 'bar'}, function (err) {
console.log('Finished processing bar');
});
// add some items to the queue (batch-wise)
q.push([{name: 'baz'},{name: 'bay'},{name: 'bax'}], function(err) {
console.log('Finished processing item');
});
// add some items to the front of the queue
q.unshift({name: 'bar'}, function (err) {
console.log('Finished processing bar');
});
Credits to the Medium article autor (read more)
You can call multiple asynchronous functions without awaiting them. This will execute them in parallel. While doing so, save the returned promises in variables, and await them at some point either individually or using Promise.all() and process the results.
You can also wrap the function calls with try...catch to handle failures of individual asynchronous actions and provide fallback logic.
Here's an example:
Observe the logs, the logs printed at the beginning of execution of the individual asynchronous functions get printed immediately even though the first function takes 5 seconds to resolve.
function someLongFunc () {
return new Promise((resolve, reject)=> {
console.log('Executing function 1')
setTimeout(resolve, 5000)
})
}
function anotherLongFunc () {
return new Promise((resolve, reject)=> {
console.log('Executing function 2')
setTimeout(resolve, 5000)
})
}
async function main () {
let someLongFuncPromise, anotherLongFuncPromise
const start = Date.now()
try {
someLongFuncPromise = someLongFunc()
}
catch (ex) {
console.error('something went wrong during func 1')
}
try {
anotherLongFuncPromise = anotherLongFunc()
}
catch (ex) {
console.error('something went wrong during func 2')
}
await someLongFuncPromise
await anotherLongFuncPromise
const totalTime = Date.now() - start
console.log('Execution completed in ', totalTime)
}
main()
// A generic test function that can be configured
// with an arbitrary delay and to either resolve or reject
const test = (delay, resolveSuccessfully) => new Promise((resolve, reject) => setTimeout(() => {
console.log(`Done ${ delay }`);
resolveSuccessfully ? resolve(`Resolved ${ delay }`) : reject(`Reject ${ delay }`)
}, delay));
// Our async handler function
const handler = async () => {
// Promise 1 runs first, but resolves last
const p1 = test(10000, true);
// Promise 2 run second, and also resolves
const p2 = test(5000, true);
// Promise 3 runs last, but completes first (with a rejection)
// Note the catch to trap the error immediately
const p3 = test(1000, false).catch(e => console.log(e));
// Await all in parallel
const r = await Promise.all([p1, p2, p3]);
// Display the results
console.log(r);
};
// Run the handler
handler();
/*
Done 1000
Reject 1000
Done 5000
Done 10000
*/
Whilst setting p1, p2 and p3 is not strictly running them in parallel, they do not hold up any execution and you can trap contextual errors with a catch.
This can be accomplished with Promise.allSettled(), which is similar to Promise.all() but without the fail-fast behavior.
async function Promise1() {
throw "Failure!";
}
async function Promise2() {
return "Success!";
}
const [Promise1Result, Promise2Result] = await Promise.allSettled([Promise1(), Promise2()]);
console.log(Promise1Result); // {status: "rejected", reason: "Failure!"}
console.log(Promise2Result); // {status: "fulfilled", value: "Success!"}
Note: This is a bleeding edge feature with limited browser support, so I strongly recommend including a polyfill for this function.
I create a helper function waitAll, may be it can make it sweeter.
It only works in nodejs for now, not in browser chrome.
//const parallel = async (...items) => {
const waitAll = async (...items) => {
//this function does start execution the functions
//the execution has been started before running this code here
//instead it collects of the result of execution of the functions
const temp = [];
for (const item of items) {
//this is not
//temp.push(await item())
//it does wait for the result in series (not in parallel), but
//it doesn't affect the parallel execution of those functions
//because they haven started earlier
temp.push(await item);
}
return temp;
};
//the async functions are executed in parallel before passed
//in the waitAll function
//const finalResult = await waitAll(someResult(), anotherResult());
//const finalResult = await parallel(someResult(), anotherResult());
//or
const [result1, result2] = await waitAll(someResult(), anotherResult());
//const [result1, result2] = await parallel(someResult(), anotherResult());
I vote for:
await Promise.all([someCall(), anotherCall()]);
Be aware of the moment you call functions, it may cause unexpected result:
// Supposing anotherCall() will trigger a request to create a new User
if (callFirst) {
await someCall();
} else {
await Promise.all([someCall(), anotherCall()]); // --> create new User here
}
But following always triggers request to create new User
// Supposing anotherCall() will trigger a request to create a new User
const someResult = someCall();
const anotherResult = anotherCall(); // ->> This always creates new User
if (callFirst) {
await someCall();
} else {
const finalResult = [await someResult, await anotherResult]
}