I want to create a script that automatically inputs password to ssh client to do reboot on /etc/rc.local - linux

The code manually is:
ssh -fNv -L 3049:localhost:2049 ubuntu#20.115.5.61
Now I have in /etc/rc.local:
#!/bin/bash
remote_host=ubuntu#20.115.5.61
remote_port=3049
local_port=2049
cmd="ssh -fN -R ${remote_port}:localhost:${local_port} ${remote_host}"
while true; do
pgrep -fx "$cmd" >/dev/null 2>&1 || $cmd
sleep 10
done
¿Help me?

Related

How to pass IF statement into SSH in UNIX?

I have the following bash script:
#!/bin/bash
set command "pgrep -x 'gedit' "
ssh -t test#192.168.94.139 $command
Now, I want to include this as well in the other device:
if pgrep -x "gedit" > /dev/null
then
echo "Running"
else
echo "Not Running"
fi
How can I make the IF Statement run on the other device? I wasn't able to include it in the ssh.
I tried this:
set command "pgrep -x 'gedit' "
ssh -t test#192.168.94.139 '
if pgrep -x "gedit" > /dev/null
then
echo "Running"
else
echo "Not Running"
fi'
But it didn't work! maybe because there is no command at the beginning?
Thanks.
Invoke bash with heredoc:
ssh -t test#192.168.94.139 bash <<EOF
if pgrep -x "gedit" > /dev/null
then
echo "Running"
else
echo "Not Running"
fi
EOF

How do I set up a port such that when someone netcats to it, a script is run

So for example, when a user netcats to port 7896, a script which asks for a user input will run.
Try like this. Create listener script
$ cat listener
#!/bin/bash
port=7896
input=$(nc -l -p $port) || exit $?
./test ${input:-empty}
Create test script
$ cat test
#!/bin/bash
echo $1
./listener
Run listener
./listener
And in another terminal run
port=7896
nc -q0 localhost $port 2> /dev/null <<< "hello"
Here's a server that executes foo.sh when someone connects.
server.sh
#!/bin/bash
while [[ 1 ]]; do
ncat -l -p 7896 -e foo.sh
done
foo.sh
#!/bin/bash
echo -n 'prompt> '
while IFS= read -r cmd
do
echo "got >$cmd<"
echo -n 'prompt> '
done
A sample session:
$ ncat localhost 7896
prompt> Hello world
got >Hello world<
prompt> <CTRL-D>
$

Working around sudo in shell script child process

So the reason I am asking this is because I'm running two programs simultaneously that are persistent, on the child process a programm is running that requires sudo rights.
#!/bin/bash
echo "Name the file:"
read filename
while [[ 1 -lt 2 ]]
do
if [ -f /home/max/dump/$filename.eth ]; then
echo "File already exist."
read filename
else
break
fi
done
#Now calling a new terminal for dumping
gnome-terminal --title="tcpdump" -e "sh /home/max/dump/dump.sh $filename.eth"
ping -c 1 0 > /dev/null **Waiting for tcpdump to create file**
#Packet analysis program is being executed
Script dump.sh
#!/bin/bash
filename=$1
echo password | sudo tcpdump -i 2 -s 60000 -w /home/max/dump/$filename -U
host 192.168.3.2
#Sudo still asks me for my password though password is piped into stdin

How to log non-interactive bash command sent through ssh

I'm sending a command through ssh:
ssh server.org 'bash -s' << EOF
ls -al
whoami
uptime
EOF
How to log it in the system (remote server)? I'd like to log those commands in some file (.bash_history or /tmp/log).
I've tried to add the line below to sshd_config:
ForceCommand if [[ -z $SSH_ORIGINAL_COMMAND ]]; then bash; else echo "$SSH_ORIGINAL_COMMAND" >> .bash_history; bash -c "$SSH_ORIGINAL_COMMAND"; fi
But it logs "bash -s" only.
I'll appreciate any help.
When bash shell exits, bash reads and executes commands from the ~/.bash_logout file. Probably you can run the history command at the end in the .bash_logout(of the server) and save it to some location.
If it suffices to work with the given command, we can put the necessary additions to enable and log command history at the beginning and end, e. g.
ssh server.org bash <<EOF
set -o history
ls -al
whoami
uptime
history|sed 's/ *[0-9]* *//' >>~/.bash_history
EOF
Or we could put them into the awfully long ForceCommand line:
… if [[ "$SSH_ORIGINAL_COMMAND" == bash* ]]; then echo "set -o history"; cat; echo "history|sed 's/ *[0-9]* *//' >>~/.bash_history"; else cat; fi | bash -c "$SSH_ORIGINAL_COMMAND"; fi

shell script ssh command not working

I have a small list of servers, and I am trying to add a user on each of these servers. I can ssh individually to each server and run the command.
sudo /usr/sbin/useradd -c "Arun" -d /home/amurug -e 2014-12-12 -g users -u 1470 amurug
I wrote a script to loop through the list and run this command but I get some errors.
#!/bin/bash
read -p "Enter server list: " file
if [[ $file == *linux* ]]; then
for i in `cat $file`
do
echo "creating amurug on" $i
ssh $i sudo /usr/sbin/useradd -c "Arun" -d /home/amurug -e 2014-12-12 -g users -u 1470 amurug
echo "==============================================="
sleep 5
done
fi
When I run the script it does not execute the command.
creating amurug on svr102
Usage: useradd [options] LOGIN
Options:
What is wrong with my ssh crommand in my script?
Try this script:
#!/bin/bash
read -p "Enter server list: " file
if [[ "$file" == *linux* ]]; then
while read -r server
do
echo "creating amurug on" "$server"
ssh -t -t "$server" "sudo /usr/sbin/useradd -c Arun -d /home/amurug \
-e 2014-12-12 -g users -u 1470 amurug"
echo "==============================================="
sleep 5
done < "$file"
fi
As per man bash:
-t
Force pseudo-tty allocation. This can be used to execute arbitrary screen-based programs on a remote which can be very useful, e.g. when implementing menu services. Multiple -t options force tty allocation, even if ssh has no local tty.

Resources