We can find different approaches to determining the week of the month, and even though there are many pages on 1:4 and/or 1:5, there is very few around 1:6 approach.
So to give you a bit of the context, I am working with a pivot table in Excel which gets its values from a Power Query source.
In Power Query, there is a function Date.WeekOfMonth which takes in the date and returns a number between 1 and 6.
In this definition, weeks start from Sunday and ends on Saturday.
So, for example, the first two days of October 2021 -i.e. Fri & Sat- fall in the 1st week of Oct, while the 3rd day of Oct 2021 starts the second week, and then the last day of October 2021,i.e. Oct 31, is the only day in the 6th week.
I had an automation task on hand in which I needed to pull data from the Power Query-generated pivot, so I had to implement a piece of code in VBA which calcs weeks the same.
Unfortunately, I couldn't find any prepared snippet, so after implementing I though it might worth sharing.
(Any comments and suggestions appreciated)
The DatePart function is perfect for this. Using DatePart with the interval set to "weeks" you can find the week of a given date. Then you subtract the number of weeks before the first day of that month (which sets the first day to week = 1).
Function WeekNumOfDate(D As Date) As Integer
WeekNumOfDate = DatePart("ww", D) - DatePart("ww", DateSerial(Year(D), Month(D), 1)) + 1
End Function
Here is a second version of the function that has the ability to set the FirstDayOfWeek argument:
Function WeekNumOfDate(D As Date, Optional FirstDayOfWeek As VbDayOfWeek = vbSunday) As Integer
WeekNumOfDate = DatePart("ww", D, FirstDayOfWeek) - DatePart("ww", DateSerial(Year(D), Month(D), 1), FirstDayOfWeek) + 1
End Function
As an example for using FirstDayOfWeek: With FirstDayOfWeek set to vbThursday, the date "Nov 5th, 2021" will return as Week 2, whereas it would by default be counted as Week 1. November 1st to 3rd of 2021 will be week 1, and then 4th to 10th will be week 2.
Its implementation in VBA is:
Function WeekOfMonth(My_Date As Date)
If Day(My_Date) > Day(My_Date - 1) And Weekday(My_Date) > Weekday(My_Date - 1) Then
WeekOfMonth = WeekOfMonth(My_Date - 1)
ElseIf Day(My_Date) > Day(My_Date - 1) And Weekday(My_Date) < Weekday(My_Date - 1) Then
WeekOfMonth = WeekOfMonth(My_Date - 1) + 1
Else
WeekOfMonth = 1
End If
End Function
Note that even though the above function is recursive, its time and space complexity is an expression of order N, which here cannot exceed 31.
Related
I have a data set which includes dates.
I need to split this out by week number for reporting purposes.
What I have so far is:
startDate variable containing 03/01/2015 (populated from data in spreadsheet)
startDay = Day(startDate)
startMonth = Month(startDate)
startYear = Year(startDate)
startWeek = Application.WorksheetFunction.WeekNum(DateSerial(startYear, startMonth, startDay))
which gives me week 1 in startWeek
However I know need to know how far into week 1 the date is.
So for this example, as the date is the 3rd of January, it includes 3 days of week 1
Meaning the reporting I'm putting together will only report on 3 days (as opposed to the full week)
The only way I've figured to do this so far is to calculate which day of the year the date is and the use a MOD calculation (basically divide by 7 and the remainder is how far into the week it is)
dayNumber = DateDiff("d", DateSerial(startYear, 1, 1), DateSerial(startYear, startMonth, startDay)) + 1
dayOfWeek = dayNumber Mod 7
This does work, but I was wondering if there was a nicer solution than this.
You could use a loop to determine how many days before startDate the week number changed:
Public Sub FindDaysInWeekNo()
Dim startDate As Date
startDate = DateSerial(2015, 1, 3)
Dim startWeek As Integer
startWeek = Application.WorksheetFunction.WeekNum(startDate)
Dim i As Integer
Do While startWeek = Application.WorksheetFunction.WeekNum(DateAdd("d", -i, startDate))
i = i + 1
Loop
Debug.Print i '= 3rd day in this week number
End Sub
The following table shows my comparison to the other suggested formulas and why I think that (refered to =WEEKNUM) my calculation is correct.
Note that if you assume 1st to 7th January will be week 1 (days 1 to 7) you cannot use the WeekNum function because this will give you a different result (see table above and note that the first week has only 6 days according to the WeekNum function). Also you cannot name this week number (as what everybody calls week number is defined as https://en.wikipedia.org/wiki/Week#Week_numbering).
Instead you will need to use …
Public Function AlternativeWeekNum(startDate As Date) As Integer
AlternativeWeekNum = WorksheetFunction.Days(startDate, DateSerial(Year(startDate), 1, 1)) \ 7 + 1 'note that this no normal division but a integer division and uses a backslash instead
End Function
to calculate the week number your alternative way, and …
Public Function AlternativeWeekNumDay(startDate As Date) As Integer
AlternativeWeekNumDay = WorksheetFunction.Days(startDate, DateSerial(Year(startDate), 1, 1)) Mod 7 + 1
End Function
to calculate the day in the alternative week.
You can use the Weekday() function for this:
=WEEKDAY(B4;2)
The second parameter mentions how you want your days to be counted (starting from Sunday or Monday, counting starting from 0 or from 1, ...).
dayOfWeek = (8 + Weekday(startDate) - Weekday(DateSerial(startYear, 1, 1))) mod 7
Just take the positive mod 7 of the difference between the current Day-Of-Week and the Day-Of-Week for the 1st January of whatever the year is
I have a date which I will need to increment the date by a day, month or year from the actual date. This is based of a list of fields below and is different per the input. Also each resultant date has to be a business day i.e not a weekend day or a bank holiday. Also if the resultant date is either Dec 25 or Jan 1st the day needs to move forward to the next business day (not a weekend day).
I have created this in Excel using a couple of formulas though it is a bit clunky.
Below is my data set
Business Date 15/05/2018
Tenor Settlement Value Settlement Period
ON 1 Day
TN 2 Day
SP 2 Day
SN 3 Day
1W 7 Day
2W 14 Day
3W 21 Day
1M 1 Month
2M 2 Month
3M 3 Month
In column E - I am using formula
=IF(D4="Day",$B$1+C4,IF(D4="Month",EDATE($B$1,C4),(TEXT($B$1,"dd/mm/")&(YEAR($B$1)+C4))+0))
In column F - I am using formula
=E4+LOOKUP(WEEKDAY(E4),{1,2,3,4,5,6,7},{1,0,0,0,0,0,2})
In column G - I am using formula
=F4+IF(AND(OR(TEXT(F4,"ddmm")="2512",TEXT(F4,"ddmm")="0101"),WEEKDAY(F4)>=2,WEEKDAY(F4)<=6),LOOKUP(WEEKDAY(F4),{1,2,3,4,5,6,7},{0,1,1,1,1,3,0}),LOOKUP(WEEKDAY(F4),{1,2,3,4,5,6,7},{1,0,0,0,0,0,2}))
In H I format the date in mm/dd/yyyy and I have my desired result.
storax has kindly created a function for me which replicates my excel formula in column E - on this thread Increment a date by a number of days, months or years
Function IncDate(ByVal dt As Date, ByVal add As Long, ByVal dmy As String) As Date
Select Case UCase(dmy)
Case "DAY"
IncDate = DateAdd("d", add, dt)
Case "MONTH"
IncDate = DateAdd("m", add, dt)
Case "YEAR"
IncDate = DateAdd("yyyy", add, dt)
Case Else
IncDate = dt
End Select
Could use some advise on how I could incorporate my formulas in columns F & G to make the process less clunky.
Manipulating the DATE function (DateSerial in vba) with the WORKDAY.INTL function seems to produce the correct business dates.
Put this in E4 and fill down.
=WORKDAY.INTL(DATE(YEAR(B$1)+(D4="year")*C4, MONTH(B$1)+(D4="month")*C4, DAY(B$1)+(D4="day")*C4)-1, 1, 1, holidays)
[holidays] is a named range (Formulas, Defined Names, Defined Name) with a Refers To: of,
=Sheet10!$Z$2:INDEX(Sheet10!$Z:$Z, MATCH(1E+99, Sheet10!$Z:$Z))
I am trying to find the week number for a fiscal year which is starts on first sunday of February. I have got it to a point where I can get the week number which starts on first of every year (in my case feb).
Not able to start it from First Sunday. Below is what I've come up with.
=IF(AND(MONTH($E2)=2,DAY($E2)=1),1,ROUNDUP(($E2-DATE(YEAR($E2)-IF(MONTH($E2)<2,1,0),2,0)+WEEKDAY(DATE(YEAR($E2)-IF(MONTH($E2)<2,1,0),2,0)))/7,0))
I would also like it to end on Saturday of last week of the year.
For example: in Feb 2016, the week count should start from 7thFeb2016 and the count should end on 4thFeb2017.
Use this formula to find week number of given date:
=IF(A1>=IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1),2,1),DATE(YEAR(A1),2,7-WEEKDAY(DATE(YEAR(A1),2,1),1)+2)),ROUNDUP((A1-IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1),2,1),DATE(YEAR(A1),2,7-WEEKDAY(DATE(YEAR(A1),2,1),1)+2))+1)/7,0),ROUNDUP((A1-IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1)-1,2,1),DATE(YEAR(A1)-1,2,7-WEEKDAY(DATE(YEAR(A1)-1,2,1),1)+2))+1)/7,0))
I hope you want this.
UPDATED
If you want week number of fiscal quarter, use this:
=ROUNDUP(MOD(=IF(A1>=IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1),2,1),DATE(YEAR(A1),2,7-WEEKDAY(DATE(YEAR(A1),2,1),1)+2)),ROUNDUP((A1-IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1),2,1),DATE(YEAR(A1),2,7-WEEKDAY(DATE(YEAR(A1),2,1),1)+2))+1)/7,0),ROUNDUP((A1-IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1)-1,2,1),DATE(YEAR(A1)-1,2,7-WEEKDAY(DATE(YEAR(A1)-1,2,1),1)+2))+1)/7,0)),13.01),0)
I just chucked this together (no doubt there is a more elegant way to do this). You can use it by putting it into a Module in your VBA editor and then on the worksheet use the function =AltWeekNumber(E2)
Function AltWeekNumber(endDate As Range) As Date
Dim startDate As Date
startDate = FirstFebruarySunday(year(endDate.Value))
If startDate > endDate Then
startDate = FirstFebruarySunday(year(endDate.Value) - 1)
End If
AltWeekNumber = DateDiff("w", startDate, endDate.Value, vbSunday)
End Function
Private Function FirstFebruarySunday(year As Integer) As Date
For i = 1 To 7
If Weekday(DateSerial(year, 2, i)) = 1 Then
FirstFebruarySunday = DateSerial(year, 2, i)
Exit Function
End If
Next i
End Function
I need a formula which calculates the End Date (with Time) when total Man Hours and Start Date are given. [Excel 2010]
Criteria:
1 Man Day = 8 Hours (1 hour is break time)
Work Start Time = 10:00
Work End Time = 19:00
1 Man Week = Mon - Fri
Holidays, if any, should not be counted
For example:
Cell E7 = Man Hours = 10 Hrs
Cell F7 = Start Date = 26-Jun-15 13:00
Cell G7 = End Date = ???? (Ideally 29-Jun-15 14:00)
*27th and 28th are weekends
Thank you!
margin of error for the estimate of duration from estimate of effort is too big for an hourly granularity to make any sense as long as real people and realistic plans are concerned
however, if we have an estimate of duration in working hours on the input (as opposed to calendar days/weeks/months which are more common units of duration estimates) and we need to calculate the end date-time, we could:
compute helper column with the would-be end hour if there were no closing hours (e.g. in cell H7, in Excel Date units = fractions of a day)
=MOD(F7, 1) + MOD(E7, 8)/24
check if the would-be hour is before the closing hours and adjust the end day + end time accordingly. If it's after, move to the next workday and adjust time, e.g. for simplicity assume all breaks are at the beginning of a day, so we can subtract the number of hours in a workday:
=IF(H7 <= 19/24,
WORKDAY(F7, E7/8, holidays) + H7,
WORKDAY(F7, E7/8 + 1, holidays) + H7 - 8/24)
assume you saved your national holidays on column I, you can try below in cell H7:
=IF(HOUR(F7+E7/24)>19,((F7+E7/24)-INT(F7+E7/24)-0.792)+(WORKDAY(F7,1,I:I))+0.417,F7+E7/24)
I have a date with this format : 14w01 (year : 2014 week number : 1)
I want to convert this date in month like this : 14m01
Is there a function which converts a week number in a month number ?
Maybe something like this (in vba, not in formula) :
Format(weekNumber, "mm")
Thank you
It depends on how the weeks are defined. One way is to say that the first day of week#1 of a year is 1 January of that year. For this definition, a typical UDF is:
Public Function MonthFromDt(s As String) As Integer
Dim yr As Integer, wk As Integer, d As Date
ary = Split(s, "w")
yr = CInt(ary(0)) + 2000
wk = ary(1)
MonthFromDt = Month(DateSerial(yr, 1, 1) + 7 * (wk - 1))
End Function
There are other definitions of week number.
The DateFormat function is quiet comfortable, however the DateValue function, which parses a date, won't probably support your week format.
I suggest a trick with DateAdd, as DateAdd can handle weeks.
First split your date in year and week number:
Dim parts
parts = Split("2014w33", "w")
Dim year
Dim week
year = CInt(parts(0))
week = CInt(parts(1))
Then, add both to a "zero-date" to add up to the final date. Note that if you give "0" as year for DateAdd, VBA compiler interprets 2000.
dim DateResult
DateResult = dateAdd("yyyy", (year - 2000), DateValue("Jan 1, 0"))
Debug.Print dateResult
DateResult = dateAdd("ww", week, dateResult)
Debug.Print dateResult
Then show the result reformatted:
Debug.Print Format(DateResult, "yyyy\mm")
This prints on my side:
01.01.2014
20.08.2014
2014m08
August 2014, there is week 33 if I look up in the calendar. Seems correct.
I found a way to do it without VBA (and only using Formulas). This assumes A1 contains the "14w01" format
=LEFT(A1,2)&"m"&TEXT(MONTH(DATE(20&LEFT(A1,2),1,1)+(RIGHT(A1,2)*7)),"00")
Heres a breakdown of what the code does..
LEFT(A1,2) returns "14" (year)
MONTH(DATE(20&LEFT(A1,2),1,1)+(RIGHT(A1,2)*7)) converts the week # to the month # and it takes in the year 20&LEFT(A1,2) as well as week # RIGHT(A1,2)
TEXT(...,"00") pads the month # with a 0 if necessary (i.e. 3 becomes 03)
Then we just combine everything together to get "14m01"