In my Excel workbook, I have "November 10th". I want every cell in the column to the right to display a date 3 days later, but it has to be a weekday Monday - Friday, it can't fall on a Saturday or Sunday. So if "November 10th" is a Thursday the date on the cell next to it should state "November 14th".
Having the date in A1, use =WORKDAY(A1,3).
You can also put the third argument to exclude holidays in this function.
Related
Is there a way to put a year into a cell (say A1), then the day of the week you want (say Monday in cell A2) and enter into the 12 cells below it the first monday of each month (or first tuesday, etc, based on whats in cell A2)?
I have been able to figure out how to do it with 1 day but I would like it to be interactive.
=DATE(2022,{1;2;3;4;5;6;7;8;9;10;11;12},7-WEEKDAY(DATE(2022,{1;2;3;4;5;6;7;8;9;10;11;12},1)-5,3))
With Office 365:
=LET(yr,A1,
wkdy,MATCH(PROPER(A2),{"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"},0),
mnt,SEQUENCE(12),
DATE(yr,mnt,1)+MOD(8-WEEKDAY(DATE(yr,mnt,1),10+wkdy),7))
You where pretty close with your formula
=DATE(A1,{1;2;3;4;5;6;7;8;9;10;11;12},7)-WEEKDAY(DATE(A1,{1;2;3;4;5;6;7;8;9;10;11;12},7),A2)
Where
A1 = year string
A2 = day of the week as number (1 = Saturday, 2 = Sunday, etc.)
Imagine that in cell A1 you have the first day of the month. I need a formula that finds if the 16th day of that month falls on a weekend (Saturday or Sunday) and if that is the case, return the date of the following Monday. If the 16th is not on a weekend, it will just return the date of the 16th
=If( (A1 + 15) = Saturday or Sunday, Date of the next Monday, (A1 + 15) )
I apologize in advance for my formula being terrible, I'm at a loss on this one.
For example, if A1 = "10/1/2019" then the forula will return 10/16/2019 because the 16th is not a weekend. However, is A1 = "11/1/2019" then the formula will return 11/18/2019 because the 16th is a Saturday. Thanks!
You can use the WEEKDAY function to determine the day of the week.
=IF(WEEKDAY(A1+15,2)=6,A1+17,IF(WEEKDAY(A1+15,2)=7,A1+16,A1+15))
The workday function is probably the easiest way to do this:
=WORKDAY(A1+14,1)
A1+14 --> the fifteenth of the month
We then add one workday. If that added workday falls on a Sat or Sun (or optional holiday if you want to do that), the weekend days will be skipped, otherwise the 16th will be returned.
I need a formula that returns Friday's date for the previous Thursday - Wednesday. My sales week closes on every Wednesday, but posts on Friday.
Example - If I enter any date between 8/11 and 8/17, I want the formula to return 8/19. A date of 8/18 should roll to the following end of week 8/26.
Use this formula:
=A1+9-WEEKDAY(A1+1,15)
I am trying to get 6th day from the day itself and should repeat for 3 times but I am not able to get the desired output
Column A Column B(Expected output)
Sunday Sunday
Monday Friday
Tuesday Wednesday
Wednesday Monday
Thursday Saturday
Friday Thursday
Saturday Tuesday
Sunday
Wednesday
Monday
Saturday
Thursday
Tuesday
Sunday
Wednesday
Monday
Saturday
Thursday
Tuesday
Sunday
I am using:
=INDEX($E$1:$E$7,6)
and I am getting only Friday and if I do auto fill only Friday is copied to all cells.
Any assistance much appreciated.
If I understand you correctly, you want to show the name of every sixth day from a starting date. There are different approaches to that. The Index() one is a possibility, but not the easiest.
Easier: In the first cell (B1), enter the starting date. Format with custom format "dddd".
In the next cell down use a formula
=B1+5
and format with custom format "dddd". Copy down as far as desired.
OR use
=TEXT($B$1+((ROW()-1)*5),"dddd")
and copy down.
If you want to base this on today's date, you can start in B1 with
=TEXT(TODAY()+((ROW()-1)*5),"dddd")
and copy down.
EDIT: if the cell contents is not about dates and weekdays, but just any text or value, then you can use the Index() approach. For an array with seven values, you want to extract every 6th value, looping through the seven values. That would mean that the values are accessed in the following order:
1
6
4
2
7
5
3
Therfore, you need a formula that delivers this number sequence. This formula, if started in row 1 and copied down, does that:
=(1+((ROW()-1)*5))-((INT((1+((ROW()-1)*5))/7)-IF(MOD((1+((ROW()-1)*5))/7,1),0,1))*7)
Wrap an Index around it and adjust your column references. In B1 and copied down to B21:
=INDEX($A$1:$A$7,(1+((ROW()-1)*5))-((INT((1+((ROW()-1)*5))/7)-IF(MOD((1+((ROW()-1)*5))/7,1),0,1))*7))
I have an excel sheet in which there is a column of data like the one given below
Last day of this week corresponding to Sunday is 41280
Last day of this week corresponding to Sunday is 41287
Last day of this week corresponding to Sunday is 41294
Last day of this week corresponding to Sunday is 41301
Last day of this week corresponding to Sunday is 41308
Last day of this week corresponding to Sunday is 41315
Last day of this week corresponding to Sunday is 41322
This is a file from our client. But we are expecting the last numeric values to be of date format.
Last day of this week corresponding to Sunday is 1/6/2013
I tried changing the format to date, but it is not accepting
How can i achieve the same
Put this formula in the next column along (formula assumes your text is in column A):
=TEXT(RIGHT(A1, 5), "dd/MM/yyyy")
I've dropped in the UK dateformat, but of course you can go for the dateformat that suits you.
Changing the format of the cell should do the job. So changing from Number or General to Short Date or Long Date works for me.
I have a neat function that I use with a date in Excel. If I want text to appear in the same cell as the date, I use the following concatenation function.
What I want to see: Date of Submission: 10/17/2016
What I type in: ="Date of Submission: "&TEXT(NOW(),"MM/DD/YYYY")