group dictionaries and get count - python-3.x

Question

I have a list of dictionaries like this:
list1 = [{'name': 'maik','is_payed': 1, 'brand': 'HP', 'count': 1, 'items': [{'device': 'mouse', 'count': 110}]},{'name': 'milanie','is_payed': 0, 'brand': 'dell', 'count':10, 'items': [{'device': 'bales', 'count': 200}]}]
list2 = [{'name': 'maik','is_payed': 0, 'brand': 'HP', 'count': 20, 'items': [{'device': 'mouse', 'count': 1}]},{'name': 'nikola','is_payed': 1, 'brand': 'toshiba', 'count':10, 'items': [{'device': 'hard', 'count': 20}]}]
my_list= list1 + list2
count = pd.DataFrame(my_list).groupby(['name', 'is_payed'])
final_list_ = []
for commande, group in count:
print(commande)
records = group.to_dict("records")
final_list_.append({"name": commande[0],
"payed": commande[1],
"occurrence": len(group),
"items": pd.DataFrame(records).groupby('device').agg(
occurrence=('device', 'count')).reset_index().to_dict('records')})
I don't know how can I get it like this:
the 'payed' field is like this payed/total_commands
for example lets take maik he has two commands one is payed and the other one is not, so the final result will be like this:
{'name': 'maik','payed': 1/2, 'brand': 'HP', 'count': 21, 'items': [{'device': 'mouse', 'count': 111}]}

Answer 1

Since you just want to group by "name" and are only interested in the "played" values, let's concentrate on that and ignore the other data.
So for our purposes, your starting data looks like:
my_list = [
{'name': 'maik', 'is_payed': 1},
{'name': 'milanie', 'is_payed': 0},
{'name': 'maik', 'is_payed': 0},
{'name': 'nikola', 'is_payed': 1}
]
Now let's take a first pass over this data and count up the number of times we see a name and the number of times that name corresponds to an "is_payed" flag
results = {}
for item in my_list:
key = item["name"]
results.setdefault(key, {"sum": 0, "count": 0})
results[key]["count"] += 1
results[key]["is_payed"] += item["is_payed"]
At this point we have a dictionary that will look like:
{
'maik': {'is_payed': 1, 'count': 2},
'milanie': {'is_payed': 0, 'count': 1},
'nikola': {'is_payed': 1, 'count': 1}
}
Now we will take a pass over this dictionary and create our true final result:
results = [
{"name": key, "payed": f"{value['is_payed']}/{value['count']}"}
for key, value in results.items()
]
Giving us:
[
{'name': 'maik', 'payed': '1/2'},
{'name': 'milanie', 'payed': '0/1'},
{'name': 'nikola', 'payed': '1/1'}
]