Excel is converting the date 03/11/2021 to value 44535, which seems to be days since 1900. I´m trying to figure out a way to calculate this using my own golang libs. Does anyone have this kind of problem?
Thank you a lot for your help
A not so fency workaround for this problem would be addDays
d := time.Date(1900, 1, 1, 0, 0, 0, 0, time.UTC)
fmt.Println(d) // 1900-01-01 00:00:00 +0000 UTC
d2 := d.AddDate(0, 0, 44503)
fmt.Println(d2) // 2021-11-05 00:00:00 +0000 UTC
Would print: 05/11/2021 witch is 2 days more than what we desire.
Here we can see the same using JavaScript:
date = new Date(1900, 0, 1)
// Mon Jan 01 1900 00:00:00 GMT-0338 (Amazon Standard Time)
date.setDate(date.getDate() + 44503)
// Fri Nov 05 2021 00:00:00 GMT-0400 (Amazon Standard Time)
After some research about this 2 days I found this in a comment by #chux-reinstate-monica:
If you choose to use MS Excel to check your work note 2 things: 1) Jan 1, 1900 is day 1 (not the number of days since Jan 1, 1900) and 2) according to Excel Feb 29, 1900 exists(a bug in their code they refuse to fix.)
So we can substract 2 days from that to have: 03/11/2021.
Related
System: WIN10
IDE: MS Visual Studio COde
Language: Python version 3.7.3
Library: pandas version 1.0.1
Data source: supplied in the example below
Dataset: supplied in the example below
Ask:
I need to split the date and time string out of a column from a data frame that has rows of uneven delimiters i.e. some with three and some with four commas.
I am trying to figure out how to strip the date and time values: 'Nov 11 2013 12:00AM', and 'Apr 11 2013 12:00AM' respectively off the back of these two records in one column into a new column given the second row in the example below has fewer commas.
Code:
df['sample field'].head(2)
4457-I need, this, date, Nov 11 2013 12:00AM ,
2359-I need this, date, Apr 11 2013 12:00AM ,
While the below method expands the data into different columns and staggers which column houses the date, this does not work. I need the date and time (or even just date) information in one column so that I can use the date values in further analysis (for example time-series).
Code:
df['sample field'].str.split(",", expand=True)
Data
df=pd.DataFrame({'Text':['4457-I need, this, date, Nov 11 2013 12:00AM ,','2359-I need this, date, Apr 11 2013 12:00AM ,']})
df
Use df.extract with a regex epression
df['Date']= df.Text.str.extract('([A-Za-z]+\s+\d+\s+\d+\s+\d+:[0-9A-Z]+(?=\s+\,+))')
df
#df.Date=pd.to_datetime(df.Date).dt.strftime('%b %d %Y %H:%M%p')
#df['date'] = pd.to_datetime(df['date'] ,format='%b %d %Y %H:%M%p')
df['Date']=pd.to_datetime(df['Date'])#This or even df['Date']=pd.to_datetime(df['Date'], format=('%b %d %Y %I:%M%p')) could work. Just remmeber because your time is 12AM use 12 clock hour system %I not %H and also hour 00.00 likely to be trncated, If have say11.00AM, the time will appear
IIUC you need str.extract with a regular expression.
Regex Demo Here
print(df)
0
0 4457-I need, this, date, Nov 11 2013 12:00AM
1 2359-I need this, date, Apr 11 2013 12:00AM
df['date'] = df[0].str.extract('(\w{3}\s\d.*\d{4}\s\d{2}:\d{2}\w{2})')
df['date'] = pd.to_datetime(df['date'] ,format='%b %d %Y %H:%M%p')
print(df)
0 date
0 4457-I need, this, date, Nov 11 2013 12:00AM 2013-11-11 12:00:00
1 2359-I need this, date, Apr 11 2013 12:00AM 2013-04-11 12:00:00
I'll use #wwnde's data :
df=pd.DataFrame({'Text':['4457-I need, this, date, Nov 11 2013 12:00AM ,','2359-I need this, date, Apr 11 2013 12:00AM ,']})
df['Date'] = df.Text.str.strip(',').str.split(',').str[-1].str.strip()
df['Date_formatted'] = pd.to_datetime(df.Date, format = '%b %d %Y %H:%M%p')
Text Date Date_formatted
0 4457-I need, this, date, Nov 11 2013 12:00AM , Nov 11 2013 12:00AM 2013-11-11 12:00:00
1 2359-I need this, date, Apr 11 2013 12:00AM , Apr 11 2013 12:00AM 2013-04-11 12:00:00
Is it possible to convert a date/time in Excel such as Mon Nov 11 2019 22:12:22 UTC time to and EST date/time value? Essentially subtract 5 hours from it? Some of the formulas I've been playing with are:
=C2-5/24
=(SUBSTITUTE(LEFT(A1,27),"T"," "))+(MID(A1,28,3)/24)
I need to run a particular script starting from Jan 1st of 2019 at 12 AM and next it should run on Jan 1st 2021 at 12 AM, then on Jan 1st 2023 at 12 AM and soon.
You can create and/or check the cron expression format with http://www.cronmaker.com/
0 0 0 1 1 ? 2019/2
This should work. It will run the task on
1. Tuesday, January 1, 2019 12:00 AM
2. Friday, January 1, 2021 12:00 AM
3. Sunday, January 1, 2023 12:00 AM
4. Wednesday, January 1, 2025 12:00 AM
5. Friday, January 1, 2027 12:00 AM
I have thousands of rows of these two columns worth of data that looks exactly to this. The date and time of an event is listed inside a single cell. I need to be able to subtract the time in one cell from the other, but I'm not sure exactly how to go about doing this.
For instance, I would need to somehow pull 4:00am and subtract the difference of 6:00am - leaving me an answer of 2 hours. Thank you ahead of time!
Nov 25, 2016 4:00:00 AM Nov 25, 2016 6:00:00 AM
Nov 25, 2016 4:00:00 AM Nov 25, 2016 6:00:00 AM
Nov 25, 2016 4:00:00 AM Nov 25, 2016 5:15:00 AM
Nov 25, 2016 4:00:00 AM Nov 25, 2016 6:00:00 AM
Nov 25, 2016 4:00:00 AM Nov 25, 2016 6:00:00 AM
In C1:
=24*(B1-A1)
and fill down.
Dates in Excel are managed such that subtracting A1 from B1 gives a fraction of a day, so multiply by 24 to get number of hours.
How to get next year period based on current month and year, for example:
Jan 2014 - Dec 2014
Feb 2014 - Jan 2015
Mar 2014 - Feb 2015
Apr 2014 - Mar 2015
May 2014 - Apr 2015
Jun 2014 - May 2015
Jul 2014 - Jun 2015
Aug 2014 - Jul 2015
Sep 2014 - Aug 2015
Oct 2014 - Sep 2015
Nov 2014 - Oct 2015
Dec 2014 - Nov 2015
Next period
Jan 2015 - Dec 2015
Feb 2015 - Jan 2016
etc.
I have tried with the following formula:
=UPPER(TEXT(NOW();"MMM")) &" "& TEXT(NOW();"YY")-1
It works fine for Jan 2014 but can't figure out how to get Dec 2014; Feb 2014 - Jan 2015 and so on?
I think you need the EOMonth formula.
=EOMONTH(NOW(),-13) +1 and =EOMONTH(NOW(),-2) +1 should give give you JAN 2014 to DEC 2014
from the MS Excel documentation
Microsoft Excel stores dates as sequential serial numbers so they can
be used in calculations. By default, January 1, 1900 is serial number
1, and January 1, 2008 is serial number 39448 because it is 39,448
days after January 1, 1900.
To get the text formatting you are after, I would suggest that you stick with formatting the cell/column as #Makyen has suggested. Having said that this is the formula that you can use to format the text.
=UPPER(TEXT(EOMONTH(NOW(),-13) +1, "MMM YY"))
Assuming that the date (as a date serial number) for which you desire to find the year period is in cell A1, the following should provide the next year period starting from that day:
=EOMONTH(A1,11) +DAY(A1) -1
Examples:
Input Output
1/18/2014 1/17/2015
2/18/2014 2/17/2015
3/18/2014 3/17/2015
4/18/2014 4/17/2015
5/18/2014 5/17/2015
6/18/2014 6/17/2015
7/18/2014 7/17/2015
8/18/2014 8/17/2015
9/18/2014 9/17/2015
10/18/2014 10/17/2015
11/18/2014 11/17/2015
12/18/2014 12/17/2015
1/18/2015 1/17/2016
2/18/2015 2/17/2016
3/18/2015 3/17/2016
4/18/2015 4/17/2016
5/18/2015 5/17/2016
6/18/2015 6/17/2016
7/18/2015 7/17/2016
8/18/2015 8/17/2016
9/18/2015 9/17/2016
10/18/2015 10/17/2016
11/18/2015 11/17/2016
12/18/2015 12/17/2016
1/18/2016 1/17/2017
If you want the year period to start from the current day:
=EOMONTH(NOW(),11) + DAY(NOW()) -1
If you want the year period to start from the first day of the current month:
=EOMONTH(EOMONTH(NOW(),-1) + 1,11)
or
=EOMONTH(NOW() - DAY(NOW()) + 1,11)
The EOMONTH() function:
EOMONTH(start_date,months)
Returns the serial number for the last day of the month that is the
indicated number of months before or after start_date. Use EOMONTH to
calculate maturity dates or due dates that fall on the last day of the
month.
If this function is not available, and returns the #NAME? error,
install and load the Analysis ToolPak add-in.