In Groovy -How to fill empty fields in version with number zero? - groovy

I have a version like below and I want to add zero (0) in versionB after 2 decimal. How can I achieve this in groovy?
versionA=1.12.14
versionB=1.11
Expected OutPut:-
versionA=1.12.14
VersionB=1.11.0

Solution
The term you are are looking for is Semantic Versioning ( semver ). This is not the prettiest solution but it will work
//def semver = "1"
def semver = "1.13"
def split = semver.split("\\.");
if(split.size() == 1) {
semver+=".0.0"
} else if(split.size()==2) {
semver+=".0"
}
println semver
In your example you have the variables typed as numbers but they must be strings

A generic variant for version strings of variable lengths:
String getFormattedVersion( String raw, int maxPositions = 3 ){
def parts = raw.split( /\./ )
(0..<maxPositions).collect{ it < parts.size() ? parts[ it ] : '0' }.join '.'
}
assert '1.2.3' == getFormattedVersion( '1.2.3' )
assert '1.2.0' == getFormattedVersion( '1.2' )
assert '1.0.0' == getFormattedVersion( '1' )
assert '1.2.3.0.0' == getFormattedVersion( '1.2.3', 5 )

Related

How to parse a string of version numbers in Groovy?

I have a string containing a version number like major.minor.patch.build but I only want to keep major.minor.patch where each number can have 1-3 digits.
How can I do this in groovy?
Examples for a result:
1.20.30.44 -> 1.20.30
or
1.21.1.1 -> 1.21.1
This will work for provided examples.
def majorMinorPatchBuild = '1.20.30.44'
def majorMinorPatch
if (majorMinorPatchBuild.toList().count('.') < 3) {
majorMinorPatch = majorMinorPatchBuild
} else {
majorMinorPatch = majorMinorPatchBuild.split('\\.')[0..-2].join('.')
}
assert majorMinorPatch == '1.20.30'
Note, you'll have to implement some error handling if the input data will have some format deviations.
Test on more data:
[
'1.2.3',
'1.2.3.4',
'11.22.33.44',
'111.222.333.444'
].each {
def majorMinorPatchBuild = it
def majorMinorPatch
if (majorMinorPatchBuild.toList().count('.') < 3) {
majorMinorPatch = majorMinorPatchBuild
} else {
majorMinorPatch = majorMinorPatchBuild.split('\\.')[0..-2].join('.')
}
println("major.minor.patch: '$it' -> '$majorMinorPatch'")
}
Output:
major.minor.patch: '1.2.3' -> '1.2.3'
major.minor.patch: '1.2.3.4' -> '1.2.3'
major.minor.patch: '11.22.33.44' -> '11.22.33'
major.minor.patch: '111.222.333.444' -> '111.222.333'
That should be essentially one-liners in Groovy. To start with 2:
String listBased = '1.20.30.44'.split( /\./ ).take 3 join '.'
String regexBased = '1.20.30.44'.replaceFirst( /(.+)\.[^.]+/, '$1' )
assert listBased == '1.20.30'
assert regexBased == '1.20.30'
This expression returns the substring of an versionString before the last dot - and so results exactly what you have specified in your question:
versionString = '1.20.30.44'
println versionString[0..versionString.lastIndexOf('.')-1]
// => 1.20.30

In Groovy - How to Iterate the versions in the list?

I am performing below task in jenkinsfile using groovy. where i have below variables
list C=[1.1,1.2,1.3]
String A=1.1
String B=1.3
if ("${A}" == "${B}") {
echo "No Action needed"
} else if ("${A}" != "${B}") {
then check in the variable list C and then iterate the list in sequential order.
}
Need Help in this condition. I am newbie in groovy.
When the A is != to B then it check the version from list C
Expected Output:-
1.1 == 1.3
then check in list C [1.1,1.2,1.3]
Iterate
1.2 ==1.3
print "still need iteration"
1.3 == 1.3
print " Matched"
I have Tried below code but its not doing iteration in for loop for If condition.
def C = ['1.1', '1.2', '1.3']
A=1.1
B=1.3
if ('${A}' == '${B}') {
println "equal"
}
else if ('${A}' != '${B}') {
println "not equal"
for (i = 0; i < C.size(); i++) {
println C[i]
if ('C[i]' == '${B}') {
println "equal"
}
}
}
there are several issues in your code
A,B are numeric and C is array of strings. to compare objects you need same type.
'C[i]' == '${B}' is incorrect because you are comparing literal string 'C[i]' to B converted to GString "1.3"
better to avoid this kind of comparison '${A}' == '${B}' - result could be tricky. better to use A == B
so, your code with changes
def C = ['1.1', '1.2', '1.3']
A='1.1'
B='1.3'
if (A == B) {
println "equal"
} else {
println "not equal"
for (i = 0; i < C.size(); i++) {
println C[i]
if (C[i] == B) {
println "equal"
}
}
}
result:
not equal
1.1
1.2
1.3
equal

Remove elements in a string separated by commas in groovy

I am building a string in this way:
def presentationType = "${feedDisplayType}, ${moduleType}, ${cellType}"
What happens is that sometimes the variables has null values, and the resulting string is showing this null values, I have to avoid show null values.
I want to know if there is some way to remove this possible null values in the string or avoid add this when they will be presented.
I know that it is possible and more easy to do with arrays, but I want to do it with strings in a more direct way.
Thanks for any help in advance.
There are 3 options:
1. GString interpolation
def presentationType = "${feedDisplayType != null && !feedDisplayType.isEmpty() ? feedDisplayType + ', ' : ''}${moduleType != null && !moduleType.isEmpty() ? moduleType + ', ' : ''}${cellType != null && !cellType.isEmpty() ? cellType : ''}".toString()
2. Using StringBuilder
def sb = new StringBuilder()
if (feedDisplayType != null && !feedDisplayType.isEmpty()) {
sb.append(feedDisplayType)
sb.append(', ')
}
if (moduleType != null && !moduleType.isEmpty()) {
sb.append(moduleType)
sb.append(', ')
}
if (cellType != null && !cellType.isEmpty()) {
sb.append(cellType)
}
def presentationType = sb.toString()
3. Joining a list with , as a delimiter
def presentationType = [feedDisplayType, moduleType, cellType].findAll { str -> str != null && !str.isEmpty() }.join(', ')
Benchmark
Before going into conclusion let's benchmark all 3 methods using GBench tool:
#Grab(group='org.gperfutils', module='gbench', version='0.4.3-groovy-2.4')
def feedDisplayType = 'test'
def moduleType = null
def cellType = ''
def r = benchmark {
'GString method' {
def presentationType = "${feedDisplayType != null && !feedDisplayType.isEmpty() ? feedDisplayType + ', ' : ''}${moduleType != null && !moduleType.isEmpty() ? moduleType + ', ' : ''}${cellType != null && !cellType.isEmpty() ? cellType : ''}".toString()
}
'StringBuilder method' {
def sb = new StringBuilder()
if (feedDisplayType != null && !feedDisplayType.isEmpty()) {
sb.append(feedDisplayType)
sb.append(', ')
}
if (moduleType != null && !moduleType.isEmpty()) {
sb.append(moduleType)
sb.append(', ')
}
if (cellType != null && !cellType.isEmpty()) {
sb.append(cellType)
}
def presentationType = sb.toString()
}
'Join list method' {
def presentationType = [feedDisplayType, moduleType, cellType].findAll { str -> str != null && !str.isEmpty() }.join(', ')
}
}
r.prettyPrint()
Output
Environment
===========
* Groovy: 2.4.12
* JVM: OpenJDK 64-Bit Server VM (25.171-b10, Oracle Corporation)
* JRE: 1.8.0_171
* Total Memory: 236 MB
* Maximum Memory: 3497 MB
* OS: Linux (4.16.5-200.fc27.x86_64, amd64)
Options
=======
* Warm Up: Auto (- 60 sec)
* CPU Time Measurement: On
user system cpu real
GString method 265 2 267 268
StringBuilder method 72 4 76 77
Join list method 484 3 487 495
Conclusion
If you aim towards highest throughput, StringBuilder method is the best one (77 nanoseconds mean time).
GString method is a few times slower than StringBuilder and it is much less readable due to all condition statements inside a single GString. It is also pretty error prone - it's easy to make a mistake when interpolating String in this case.
Joining list method is the slowest one (only 2 times slower approximately than GString method), but it is the cleanest one. And it is still pretty fast - 495 nanoseconds is acceptable in most cases. Of course optimization depends on specific use case - if you have to execute this part of code million times per second, then using StringBuilder instead makes much more sense.
Benchmark corner cases
To make this example complete let's also take a look at corner cases in benchmarking. We use the same code with different input.
Input:
def feedDisplayType = 'lorem ipsum'
def moduleType = 'dolor sit amet'
def cellType = '123456789'
Output:
user system cpu real
GString method 387 1 388 390
StringBuilder method 170 0 170 175
Join list method 847 6 853 859
Input:
def feedDisplayType = ''
def moduleType = ''
def cellType = ''
Output:
user system cpu real
GString method 237 5 242 242
StringBuilder method 44 0 44 44
Join list method 441 0 441 446
Edit: This answer has been changed as there is a requirement to not print "," for null terms.
Consider:
def feedDisplayType = 'abc'
def moduleType = null
def cellType = 'ijk'
def f = { s, isLast = false ->
def token = s ?: ''
def seperator = (!s || isLast) ? '' : ','
"${token}${seperator}"
}
def presentationType = "${f feedDisplayType}${f moduleType}${f cellType,true}"
assert 'abc,ijk' == presentationType
Note that in function calls, parens are optional in Groovy so ${f x} is equivalent to ${f(x)}. f was originally field in an earlier version, but I've shortened it for brevity.

How to get last 2 digit from a String

I have a problem to get last two digit from a string.
example :
String texter = "5793231309"
how to get '09' ?
so when Iprintln "texter : "+texter.
It will be Groovy<<09
I try split but it not successful ?
Use this to split your first String:
static main(args) {
String texter = "5793231309"
String texter2 = texter[-2..-1]
println(texter2)
}
Here's a one liner that's also a safe alternative:
assert "5793231309".reverse().take(2).reverse() == "09"
In groovy you can substring via negative indices.
String last2 = texter[-2..-1] // Last 2 symbols
Its an analogue of substring, and it uses Ranges.
http://groovy.codehaus.org/Collections see 'Slicing with the subscript operator'
Inspired by tim_yates:
It may be safer to use some function, to extract last n characters, as tim suggested. But I think his solution, with regexp is a big overhead, and may be hard to understand by novices.
There is an easier and faster way to do this, using size() check, and then range substring:
def lastN(String input, int n){
return n > input?.size() ? null : n ? input[-n..-1] : ''
}
assert lastN("Hello", 2) == 'lo'
assert lastN("Hello", 3) == 'llo'
assert lastN("Hello", 0) == ''
assert lastN("Hello", 13) == null
assert lastN(null, 3) == null
Be careful though, if your unit is less than 2 characters long, s[ -2..-1 ] will fail.
Might be better to do:
String lastN( String input, int n ) {
input == null ?
null :
( input =~ /^.+(\S{$n})$/ ).with { m -> m.matches() ?
m[ 0 ][ 1 ] :
null }
}
assert lastN( "5793231309", 2 ) == '09'
assert lastN( "5793231309", 3 ) == '309'
assert lastN( "5793231309", 0 ) == ''
assert lastN( '', 2 ) == null
assert lastN( null, 2 ) == null
Or:
String lastN( String input, int n ) {
if( input == null || input.length() < n ) null
else if( n == 0 ) ''
else input[ -n..-1 ]
}
assert lastN( "5793231309", 2 ) == '09'
assert lastN( "5793231309", 3 ) == '309'
assert lastN( "5793231309", 0 ) == ''
assert lastN( '', 2 ) == null
assert lastN( null, 2 ) == null
The most readable solution is probably just to drop() all but the last two characters:
def texter = "5793231309"
println texter.drop(texter.size() - 2) //result: "09"
Or as a reusable closure:
def lastTwo = { it.drop(it.size() - 2) }
println lastTwo("ABC") //result: "BC"
println lastTwo("AB") //result: "AB"
println lastTwo("A") //result: "A" (no exception thrown)
println lastTwo("") //result: "" (no exception thrown)
Fiddle with the code:
https://groovyconsole.appspot.com/script/5768158526832640
More examples of Groovy goodness:
http://mrhaki.blogspot.com/2011/09/groovy-goodness-take-and-drop-items.html
Another safe alternative using size() and substring() methods:
s?.size() < 2 ? s : s.substring(s.size() - 2)
Note the above takes care of nulls and strings that are less than two characters long.
In Java use
String texter = "5793231309";
String val=texter.substring(texter.length()-2,texter.length());
System.out.println("val-->"+val);
In Groovy you don’t need the above stuff just,
String value= texter[-2..-1]

Is There a Groovier Way To Add Dashes to a String?

I have the following code, which works, but I'm wondering if there is a "groovier" way of doing this:
/**
* 10 digit - #-######-##-#
* 13 digit - ###-#-######-##-#
* */
private formatISBN(String isbn) {
if (isbn?.length() == 10) {
def part1 = isbn.substring(0, 1)
def part2 = isbn.substring(1, 7)
def part3 = isbn.substring(7, 9)
def part4 = isbn.substring(9, 10)
return "${part1}-${part2}-${part3}-${part4}"
} else if (isbn?.length() == 13) {
def part1 = isbn.substring(0, 3)
def part2 = isbn.substring(3, 4)
def part3 = isbn.substring(4, 10)
def part4 = isbn.substring(10, 12)
def part5 = isbn.substring(12, 13)
return "${part1}-${part2}-${part3}-${part4}-${part5}"
} else {
return isbn
}
}
You could first use the [] string operator to get the substrings instead of substring and drop the intermediate variables. For example in the case for length == 10:
"${isbn[0]}-${isbn[1..6]}-${isbn[7..8]}-${isbn[9]}"
Now, there is a bit of repetition there. You can get instead first get all the isbn segments and then .join them with '-':
[isbn[0], isbn[1..6], isbn[7..8], isbn[9]].join('-')
And, even further, instead of referencing isbn every time, you can make a list of the ranges you want to get and then get them all the same time using collect:
[0, 1..6, 7..8, 9].collect { isbn[it] }.join('-')
If you're going for code golfing, you can also do:
('-'+isbn)[1, 0, 2..7, 0, 8..9, 0, 10]
I'll leave it to you to figure out how that works, but i guess it's probably not a good idea to leave that on production code, unless you want to surprise future maintainers hehe.
Also, notice that the format when length == 13 is the same as for length == 10 but with a different prefix, you can then reuse the same function in that case. The whole function (with a couple of tests) would be:
/**
* 10 digit - #-######-##-#
* 13 digit - ###-#-######-##-#
**/
def formatIsbn(isbn) {
switch (isbn?.length()) {
case 10: return [0, 1..6, 7..8, 9].collect { isbn[it] }.join('-')
case 13: return isbn.take(3) + '-' + formatIsbn(isbn.drop(3))
default: return isbn
}
}
assert formatIsbn('abcdefghij') == 'a-bcdefg-hi-j'
assert formatIsbn('abcdefghijklm') == 'abc-d-efghij-kl-m'
Now, i think there are some bad smells in that code. Can isbn be null? At least to me, this doesn't look like a function that needs to bother about the nullity of its argument, or at least that's not clear by reading its name (it should be called something like formatIsbnOrNull instead if both ISBN strings and null values are accepted). If null values are not valid, then let it blow up with a NullPointerException when accessing isbn.length() so the caller know they have passed a wrong argument, instead of silently returning the same null.
The same goes for the return ISBN at the end. Is it expected for that function to receive a string that's neither 10 nor 13 characters long? If not, better throw new IllegalArgumentException() and let the caller know they have called it wrongly.
Finally, i'm not sure if this is the most "readable" solution. Another possible solution is having a string for the format, like '###-#-######-##-#' and then replace the #s by the isbn characters. I think it might be more self-documenting:
def formatIsbn(isbn) {
def format = [
10: '#-######-##-#',
13: '###-#-######-##-#'
][isbn.length()]
def n = 0
format.replaceAll(/#/) { isbn[n++] }
}
Consider adding the method to the String class, as shown here. Note that this answer is a spin on a clever suggestion in epidemian's answer (re: collect).
Note:
This code augments String with asIsbn().
The range [0..2] does not need the call to asIsbn(), but the symmetry of using collect twice is irresistable.
Groovy returns the last expression in if/else, so 'return' is not necessary
/**
* 10 digit - #-######-##-#
* 13 digit - ###-#-######-##-#
**/
String.metaClass.asIsbn = { ->
if (delegate.length() == 10) {
[0, 1..6, 7..8, 9].collect { delegate[it] }.join('-')
} else if (delegate.length() == 13) {
[0..2, 3..12].collect { delegate[it].asIsbn() }.join('-')
} else {
delegate
}
}
assert "abcdefghij".asIsbn() == 'a-bcdefg-hi-j'
assert "abcdefghijklm".asIsbn() == 'abc-d-efghij-kl-m'
assert "def".asIsbn() == "def"
String s = null
assert s?.asIsbn() == null
I would try using Regex... I think it's pretty much readable if you know how to use regex, and it's javascript inspired syntax in groovy is pretty cool also.
One more thing: it's pretty clear, looking at the capture groups, what your string looks like for the desired formatting.
private formatISBN(String isbn) {
if (isbn?.length() == 10) {
m = isbn =~ /(\d{1})(\d{6})(\d{2})(\d{1})/
return "${m[0][1]}-${m[0][2]}-${m[0][3]}-${m[0][4]}"
} else if (isbn?.length() == 13) {
m = isbn =~ /(\d{3})(\d{1})(\d{6})(\d{2})(\d{1})/
return "${m[0][1]}-${m[0][2]}-${m[0][3]}-${m[0][4]}-${m[0][5]}"
} else {
return isbn
}
}
Btw, #epidemian suggestion using backreferences is great! I think the code would look like:
private formatISBN(String isbn) {
if (isbn?.length() == 10) {
return isbn.replaceAll(/(\d{1})(\d{6})(\d{2})(\d{1})/, '$1-$2-$3-$4')
} else if (isbn?.length() == 13) {
return isbn.replaceAll(/(\d{3})(\d{1})(\d{6})(\d{2})(\d{1})/, '$1-$2-$3-$4-$5')
} else {
return isbn
}
}
Dunno if I like this any better. I'd make the position map a static final, too.
private isbnify(String isbn) {
def dashesAt = [ 10: [[0,1], [1,7], [7,9], [9,10]],
13: [[0,3], [3,4], [4,10], [10,12], [12,13]]]
def dashes = dashesAt[isbn?.length()]
(dashes == null) ? isbn
: dashes.collect { isbn.substring(*it) }.join('-')
}
Ranges make for a bit less clutter, IMO:
private isbnify3(String isbn) {
def dashesAt = [ 10: [0, 1..6, 7..8, 9],
13: [0..2, 3, 4..9, 10..11, 12]]
def dashes = dashesAt[isbn?.length()]
dashes == null ? isbn : dashes.collect { isbn[it] }.join("-")
}
With an inject-with-two-accumulators it should be easy to do a list-of-dash-positions version, too.
This should be a comment to #everton, but I don't have the 50 reputation needed to do that yet. So this answer is really just a suggested variation on #everton's answer.
One less regex by making the first 3 digits optional. The downside is having to remove a leading '-' if the ISBN is 10 characters. (I also prefer \d over \d{1}.)
private formatISBN(String isbn) {
String result = isbn.replaceAll(/^(\d{3})?(\d)(\d{6})(\d{2})(\d)$/,
'$1-$2-$3-$4-$5')
if (result) {
return result.startsWith('-') ? result[1..-1] : result
} else {
return isbn // return value unchanged, pattern didn't match
}
}
println formatISBN('1234567890')
println formatISBN('9991234567890')
println formatISBN('123456789') // test an ISBN that's too short
println formatISBN('12345678901234') // test an ISBN that's too long

Resources