I need a formula that will convert a date and time into a unix timestamp. I suppose a logical starting point could be in the format of the result of =NOW() i.e. 25/10/2021 15:26 or the result thereof split into two cells for convenience but I'm not quite sure about how to proceed.
Thanks in advance!
Since the Unix time stamp is the number of seconds since 1/1/1970, we can simple take the date we want, subtract 1/1/1970 and multiply by the number of seconds in a day:
=(NOW()-"1/1/1970")*60*60*24
Related
How do i calculate time difference in milliseconds between two columns where value of time has milliseconds component ... i.e. 16:33:44:056. Please refer to column E and J in pic .. i want to calculate difference in milli seconds between J and E ...
I have tried using the following formula to alculate difference in milli seconds but its giving incorrect results. =((RIGHT(J1,3))-(RIGHT(E1,3)))
It appears your date/time is a text value.
A "real" time value would normally be seen as 16:11:52.052
But by replacing the last : with a ., excel will see it as a real time and ordinary math can be done.
Excel stores date/time as days and fractions of a day.
So a formula that should work:
=ROUND((SUBSTITUTE(J1,":",".",3)-SUBSTITUTE(E1,":",".",3))*86400000,0)
Format the result as General or as Number with no decimal places
Try
=(J1-E1)*1000*60*60*24
or more concisely
=(J1-E1)*86400000
Then format your formula column to general.
This assumes the data is actually stored as datetime and not a text value.
If you change the format of your time columns, and the column to show the difference, to
hh:mm:ss.000
You can simply use subtraction:
(You'll have to tweak the actual cells to have . before the milliseconds, just formatting won't do it)
If the part of that string corresponding to hours, minutes and seconds is always the same, and time in J is always bigger than time in E, you could do:
=VALUE(RIGHT(J1;3))-VALUE(RIGHT(E1;3))
Trying to convert 1504865618099.00 Unix time into a readable date time.
I tried this:
=(UNIX + ("1/1/1970"-"1/1/1900"+1)*86400) / 86400
But it's not working.
To convert the epoch(Unix-Time) to regular time like for the below timestamp
Ex: 1517577336206
First convert the value with the following function like below
=LEFT(A1,10) & "." & RIGHT(A1,3)
The output will be like below
Ex: 1517577336.206
Now Add the formula like below
=(((B1/60)/60)/24)+DATE(1970,1,1)
Now format the cell like below or required format(Custom format)
m/d/yyyy h:mm:ss.000
Now example time comes like
2/2/2018 13:15:36.206
The three zeros are for milliseconds
=A1/(24*60*60) + DATE(1970;1;1) should work with seconds.
=(A1/86400/1000)+25569 if your time is in milliseconds, so dividing by 1000 gives use the correct date
Don't forget to set the type to Date on your output cell. I tried it with this date: 1504865618099 which is equal to 8-09-17 10:13.
TLDR
=(A1/86400)+25569
...and the format of the cell should be date.
If it doesn't work for you
If you get a number you forgot to format the output cell as a date.
If you get ##### you probably don't have a real Unix time. Check your
timestamps in https://www.epochconverter.com/. Try to divide your input by 10, 100, 1000 or 10000**
You work with timestamps outside Excel's (very extended) limits.
You didn't replace A1 with the cell containing the timestamp ;-p
Explanation
Unix system represent a point in time as a number. Specifically the number of seconds* since a zero-time called the Unix epoch which is 1/1/1970 00:00 UTC/GMT. This number of seconds is called "Unix timestamp" or "Unix time" or "POSIX time" or just "timestamp" and sometimes (confusingly) "Unix epoch".
In the case of Excel they chose a different zero-time and step (because who wouldn't like variety in technical details?). So Excel counts days since 24 hours before 1/1/1900 UTC/GMT. So 25569 corresponds to 1/1/1970 00:00 UTC/GMT and 25570 to 2/1/1970 00:00.
Now if you also note that we have 86400 seconds per day (24 hours x60 minutes x60 seconds) and you will understand what this formula does: A1/86400 converts seconds to days and +25569 adjusts for the offset between what is zero-time for Unix and what is zero-time for Excel.
By the way DATE(1970,1,1) will helpfully return 25569 for you in case you forget all this so a more "self-documenting" way to write our formula is:
=A1/(24*60*60) + DATE(1970,1,1)
P.S.: All these were already present in other answers and comments just not laid out as I like them and I don't feel it's OK to edit the hell out of another answer.
*: that's almost correct because you should not count leap seconds
**: E.g. in the case of this question the number was milliseconds since the the Unix epoch.
If you have ########, it can help you:
=((A1/1000+1*3600)/86400+25569)
+1*3600 is GTM+1
in case the above does not work for you. for me this did not for some reasons;
the UNIX numbers i am working on are from the Mozilla place.sqlite dates.
to make it work : i splitted the UNIX cells into two cells : one of the first 10 numbers (the date) and the other 4 numbers left (the seconds i believe)
Then i used this formula, =(A1/86400)+25569 where A1 contains the cell with the first 10 number; and it worked
You are seeing the date as ######## most likely because by definition the EPOCH times is in seconds - https://en.wikipedia.org/wiki/Unix_time. This means the number should be 10 characters long. Your number has 13 characters (see 1504865618099) and it is most likely in milliseconds (MS). In order to fix the formula just divide the number by 1000. Just keep in mind this way you'll loose the MS precision, but in most cases this is OK. So the final formula should be:
=A1/(86400 * 1000) + DATE(1970,1,1)
Just point and shoot.
Replace the C2 with your cell no. No need to format your Excel cell.
Also, you can use this unixtimestamp website to verify your data.
International format (ISO 8601):
=TEXT(C2/(1000*60*60*24)+25569,"YYYY-MM-DD HH:MM:SS")
2022-10-20 00:04:22
2022-10-20 00:05:20
2022-10-20 00:14:58
US format:
=TEXT(C2/(1000*60*60*24)+25569,"MM/DD/YYYY HH:MM:SS")
10/20/2022 00:04:22
10/20/2022 00:05:20
10/20/2022 00:14:58
Europe format:
=TEXT(C2/(1000*60*60*24)+25569,"DD.MM.YYYY HH:MM:SS")
20.10.2022 00:04:22
20.10.2022 00:05:20
20.10.2022 00:14:58
If you only need the date, remove the 'HH:MM:SS'.
=TEXT(C2/(1000*60*60*24)+25569,"YYYY-MM-DD")
How can I convert duration in excel to text ? I am having 1037:00:00 in a cell, which is the sum of certain durations. I want to extract 1037 alone. Excel returns "hours" when I try to extract with MID or use TEXT function.
If it is really the sum of some durations you can get the amount of hours by multiplying the cell by 24. The internal representation of a date or time cell is the number of days since beginning of the year 1900, so you have to multiply it by 24 to get the number of hours. (The year 1900 is not interesting for you as you just want a time span.) The Hour function does not work here because you get the day hour which is 5 in this case.
Be sure to format your target cell as regular number.
lets assume your cell with 1037:00:00 is in cell L40. You can use the following formula to pull the hours.
=INT(L40)*24+HOURS(L40)
Note this will only pull full hours rounded down. It does not take into account minutes or seconds.
Alternatives:
=Rounddown(L40*24,0)
This alternative is what Fratyx explained in his answer.
I am having an issue with Excel and it’s probably very simple but I need to get a starting time by subtracting a duration from and end time.
For example say I know that an event needs to end at 1:55:23 pm and it will take 0:22:13 what formula would I use to find out what time I should start?
I would like to be able to input the duration in the format h:mm:ss without excel trying to turn it into a time and not a duration as well.
Thank you for any suggestions
You simply subtract them.
For example...
Cell A1 has the end time: 1:55:23 PM
Cell B1 has the duration: 0:22:13 (this is the only 'strange' part because it's actually an AM time, as in minutes after midnight... but if you think about it, that's what you want).
Cell C1 has this formula: =A1-B1
That's it.
NOTE: If your duration is longer than your event start time (for example, a 4-hour event that started at 3:00 in the morning!) then the subtraction would result in a negative time.
A negative time is OK in reality, but Excel will not display it as a formatted time... instead it displays a bunch of ############. In that case, you need to display the calculation as a decimal value, which is the fraction of a day. For example. 0.25 means exactly 6 hours. If you would prefer decimal hours you simply multiply the fractional day figure by 24.
I have an emulator in eclipse.
Did i need another things?
Excel stores time internally the same way as date - i.e. 1 equals one full day, namely January 1st, 1900. Thus, one hour is 1/24. Assuming that only the time was entered into the cell (and not a full date with a time), you could therefore use this formula:
=IF(U7>16/24+50/(24*60),U7-(16/24+50/(24*60)),0)
Alternatively, you could use Excel's TIME function, which converts hours, minutes and seconds into an Excel time:
=IF(U7>TIME(16,50,0),U7-TIME(16,50,0),0)
In case your input cell is a full date with a time, you need to either get rid of the date in the input value - or add the date to the comparison - though I'd recommend the former:
=IF(TIME(HOUR(U7),MINUTE(U7),SECOND(U7))>TIME(16,50,0),U7-TIME(16,50,0),0)
Go through the following article, I hope this will help you.
compare time in excel
You should compare time in following way -
U7>TIME(16,50,0) inside the IF condition.
Please make sure that the column U7 which you use as time input, should be in proper Time format.
Thanks.