Append the columns and put one after other - python-3.x

Question

I have the following dataframe:
a1
p1
a2
p2
a3
p3
...
1
2
3
4
5
6
...
7
8
9
10
11
12
...
And, I want to create a dataframe like this:
a
p
1
2
7
8
3
4
9
10
5
6
11
12
...
...

Answer 1

Do you need something like this?
import pandas as pd
import random
a = [random.randint(1,100) for i in range(178) ]
b = [random.randint(1,100) for i in range(178) ]
#Original DF
df = pd.DataFrame({"0": a, "1": b})
#New DF
cf = pd.DataFrame()
cf["Actual Value"] = df["0"]
cf["Predicted Value"] = df["1"]
cf["Error Value"] = df["0"] - df["1"]
cf["Id"] = ["Bin" + str(i + 1) for i in range(178) ]
I misunderstand you with previous one.
This should fit you:
import pandas as pd
import random
#Original DF
d = {}
for i in range(int(178)):
a = [random.randint(1,100) for i in range(10) ]
b = [random.randint(1,100) for i in range(10) ]
d["Bin " + str(i+1)] = pd.DataFrame({"0": a, "1": b})
con = pd.concat(d, axis=1)
colum = []
for i in range(178*2):
if i%2 == 0:
colum.append("0")
else:
colum.append("1")
con.columns = colum
#New DF
result = []
count = 0
for i in range(0,178*2,2):
a = con.iloc[:,[i,i+1]]
a["Error"] = a["0"] - a["1"]
a["Bucked"] = "Bin: " + str(count)
result.append(a)
count = count + 1
result = pd.concat(result)
result
Result image: