Related
I have two columns in my excel file.
Full ID Expected Result
159473A1 159473
159696A1 159696
160614A1 160614
43293J1A 43293
43293D1A 43293
43293A2B 43293
43293J2B 43293
43293B2B 43293
What i had tried :
=Left(A2,LEN(A2)-2)
159473
159696
160614
43293J
43293D
43293A
43293J
43293B
53202
But has you can see, I cant do that because I still have some characters in the expected results
43293J
43293D
43293A
43293J
43293B
How can I get my expected results in like the top example?
In B2 try:
=LEFT(A2,MATCH(FALSE,INDEX(ISNUMBER(MID(A2,ROW(A$1:INDEX(A:A,LEN(A2))),1)*1),),0)-1)
If you have access to DA-functions (O365), like SEQUENCE:
=LEFT(A2,MATCH(FALSE,ISNUMBER(MID(A2,SEQUENCE(LEN(A2)),1)*1),0)-1)
Note: If you are dealing with integers too, maybe to prevent possible errors through MATCH, you could use =LEFT(A2,MATCH(FALSE,ISNUMBER(MID(A2&"A",SEQUENCE(LEN(A2)+1),1)*1),0)-1)
So, very simple in the first instance:
But you have an issue with line 4... so this will help that:
IF(ISNUMBER(VALUE(LEFT(A3,LEN(A3)-2))),VALUE(LEFT(A3,LEN(A3)-2)),VALUE(LEFT(A3,LEN(A3)-3)))
This formula will work for you , remember to click Ctrl+Shift+Enter after pasting formula as its a matrix based formula
mention your email i can send you my workout
=LEFT(A2,IFERROR(MATCH(1,ISERR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)*1)*1,),)-1)
I am trying to write a formula to evaluate all possible values in three cells and score them in another. Excel says that there is a problem with my formula, but I can't locate it. Your help is appreciated.
I am using IF(AND throughout my spreadsheet, but only with two values. Those formulas are accepted by Excel.
=IF(AND(B2="No",B3="Red",B5="No"),0,
IF(AND(B2="No",B3="Green",B5="No",2,
IF(AND(B2="No",B3="Blue",B5="No",3,
IF(AND(B2="No",B3="Yellow",B5="No",5,5,
IF(AND(B2="No",B3="Red",B5="Yes"),0,
IF(AND(B2="No",B3="Green",B5="Yes"),2,
IF(AND(B2="No",B3="Blue",B5="Yes",3,
IF(AND(B2="No",B3="Yellow",B5="Yes",5,
IF(AND(B2="Yes",B3="Red",B5="Yes",0,
IF(AND(B2="Yes",B3="Green",B5="Yes",1,
IF(AND(B2="Yes",B3="Blue",B5="Yes",2,
IF(AND(B2="Yes",B3="Yellow",B5="Yes",5,
IF(AND(B2="Yes",B3="Red",B5="No",0,
IF(AND(B2="Yes",B3="Green",B5="No",1,
IF(AND(B2="Yes",B3="Blue",B5="No",2,
IF(AND(B2="Yes",B3="Yellow",B5="No",3))))))))))))))))
Excel states "There is a problem with this formula".
You had a 5,5 where you should have had a 5 and where missing many ) to close the ANDs
=IF(AND(B2="No",B3="Red",B5="No"),0,
IF(AND(B2="No",B3="Green",B5="No"),2,
IF(AND(B2="No",B3="Blue",B5="No"),3,
IF(AND(B2="No",B3="Yellow",B5="No"),5,
IF(AND(B2="No",B3="Red",B5="Yes"),0,
IF(AND(B2="No",B3="Green",B5="Yes"),2,
IF(AND(B2="No",B3="Blue",B5="Yes"),3,
IF(AND(B2="No",B3="Yellow",B5="Yes"),5,
IF(AND(B2="Yes",B3="Red",B5="Yes"),0,
IF(AND(B2="Yes",B3="Green",B5="Yes"),1,
IF(AND(B2="Yes",B3="Blue",B5="Yes"),2,
IF(AND(B2="Yes",B3="Yellow",B5="Yes"),5,
IF(AND(B2="Yes",B3="Red",B5="No"),0,
IF(AND(B2="Yes",B3="Green",B5="No"),1,
IF(AND(B2="Yes",B3="Blue",B5="No"),2,
IF(AND(B2="Yes",B3="Yellow",B5="No"),3,""))))))))))))))))
But I think you can do this with a simpler formula:
=IFERROR(IF(B2 = "No",CHOOSE(MATCH(B3,{"Red","Green","Blue","Yellow"},0),0,2,3,5),IF(B5="Yes",CHOOSE(MATCH(B3,{"Red","Green","Blue","Yellow"},0),0,1,2,5),CHOOSE(MATCH(B3,{"Red","Green","Blue","Yellow"},0),0,1,2,3))),"")
You could put your logic in string form in one cell (say, F1):
0NOREDNO 2NOGREENNO 3NOBLUENO 5NOYELLOWNO 0NOREDYES 2NOGREENYES 3NOBLUEYES 5NOYELLOWYES 0YESREDYES 1YESGREENYES 2YESBLUEYES 5YESYELLOWYES 0YESREDNO 1YESGREENNO 2YESBLUENO 3YESYELLOWNO
Then your code reduces to:
=MID(F1, FIND(UPPER(B2&B3&B5),F1)-1, 1)
This would also make it extremely easy to add more conditions in the future.
Try this:
=IF(B3="Red",0,
IF(B3="Green",
IF(B2="Yes",1,
IF(B2="No",2,NA())),
IF(B3="Blue",
IF(B2="Yes",2,
IF(B2="No",3,NA())),
IF(B3="Yellow",
IF(AND(B2="Yes",B5="No"),3,5),
NA()))))
Hope that helps
I'm trying to figure out what I am doing wrong with this formula. It is returning the error "you've entered too many arguments for this function"
=IF(ROUND(d28=0,0,IF(b28<=$B$19,0,IF(AND($B$18="Fixed Balloon",b28=$B$20),d28,G28-f28))))
Thanks for the help
Try it like this, putting ROUND(d28,1)=0 instead of ROUND(d28=0...
=IF(ROUND(d28,1)=0,0,IF(b28<=$B$19,0,IF(AND($B$18="Fixed Balloon",b28=$B$20),d28,G28-f28)))
To make this clearer, showing what is happening, type it out in a text document in an indented format:
=IF(ROUND(d28,1)=0,
0,
IF(b28<=$B$19,
0,
IF(AND($B$18="Fixed Balloon",b28=$B$20),
d28,
G28-f28
)
)
)
Edit: ROUND takes 2 parameters, the first being the number to round, and the second being the number of digits to round to. I choose to make it round to one digit.
This could equally be written like this, which I find makes it easier to understand:
=IF(OR(ROUND(D28,1)=0,B28<=$B$19),
0,
IF(AND($B$18="Fixed Balloon",B28=$B$20),
D28,
G28-F28
)
)
I am trying to write a formula that takes a word and process it through a IF function in excel, The Values are list in the formula. My issue right now is the fact that I have Large, X-Large and 1X-Large text. The X-Large and 1X-Large are unique strings and need the IF function to be able to differentiate the two.
Here is what i have so far.
=if(or(isnumber(search("Small",af2)),ISNUMBER(SEARCH("Medium",AF2)),ISNUMBER(SEARCH("Large",AF2)),,ISNUMBER(SEARCH("X-Large",AF2))),"Small",or(isnumber(search("1X-Large",af2)),isnumber(search("2X-Large",af2)),isnumber(search("3X-Large",af2)),isnumber(search("4X-Large",af2))),"1X-Large")
I cant understand why it's showing an error and only displays small when it works.
All help is appreciated
Your current formula shouldn't work, it should be giving you an error about having too many arguments. A breakdown of your function:
=if(
or(isnumber(search("Small",af2)),ISNUMBER(SEARCH("Medium",AF2)),ISNUMBER(SEARCH("Large",AF2)),,ISNUMBER(SEARCH("X-Large",AF2))),
"Small",
or(isnumber(search("1X-Large",af2)),isnumber(search("2X-Large",af2)),isnumber(search("3X-Large",af2)),isnumber(search("4X-Large",af2))),
"1X-Large"
)
You cannot use 4 parameters in an IF. You need to have a maximum of 3. Maybe what you meant was:
=if(
or(isnumber(search("Small",af2)),ISNUMBER(SEARCH("Medium",AF2)),ISNUMBER(SEARCH("Large",AF2)),,ISNUMBER(SEARCH("X-Large",AF2))),
"Small",
IF(
or(isnumber(search("1X-Large",af2)),isnumber(search("2X-Large",af2)),isnumber(search("3X-Large",af2)),isnumber(search("4X-Large",af2))),
"1X-Large"
)
)
But that doesn't solve your issue about the X-Large part. To cater for that, you can check whether the X-Large series exist first, then the others.
=IF(
OR(ISNUMBER(SEARCH("1X-Large",AF2)),ISNUMBER(SEARCH("2X-Large",AF2)),ISNUMBER(SEARCH("3X-Large",AF2)),ISNUMBER(SEARCH("4X-Large",AF2))),
"1X-Large",
IF(
OR(ISNUMBER(SEARCH("Small",AF2)),ISNUMBER(SEARCH("Medium",AF2)),ISNUMBER(SEARCH("Large",AF2)),ISNUMBER(SEARCH("X-Large",AF2))),
"Small"
)
)
Although you can make it shorter with this:
=IF(
OR(ISNUMBER(SEARCH({"1X-Large","2X-Large","3X-Large","4X-Large"},AF2))),
"1X-Large",
IF(
OR(ISNUMBER(SEARCH({"Small","Medium","Large","X-Large"},AF2))),
"Small"
)
)
In one line...
=IF(OR(ISNUMBER(SEARCH({"1X-Large","2X-Large","3X-Large","4X-Large"},AF2))),"1X-Large",IF(OR(ISNUMBER(SEARCH({"Small","Medium","Large","X-Large"},AF2))),"Small"))
=SUMIFS(L19:L678, J19:J678, ">TEXT", K19:K678, "TEXT")
Is the formula and I want it to look for >TEXT but it thinks I am saying greater than text, how do I get around this?
Try this version with an additional "="
=SUMIFS(L19:L678, J19:J678, "=>TEXT", K19:K678, "TEXT")
Well, you can perhaps use something like that:
=SUMIFS(L19:L678, J19:J678, "*>TEXT", K19:K678, "TEXT")
Though this will sum if you have A>TEXT as well. Otherwise, you might try:
=SUMPRODUCT((J19:J678=">TEXT")*(K19:K678="TEXT")*(L19:L678))