Pivot String Values in Snowflake - pivot

Question

How can I pivot this table
ID
attribute_name
attribute_value
1
Name
John
1
Country
UK
1
City
London
into structure?
ID
Name
Country
City
1
John
UK
London
According to the documentation pivot requires a aggregate function
SELECT ...
FROM ...
PIVOT ( <aggregate_function> ( <pivot_column> )
FOR <value_column> IN ( <pivot_value_1> [ , <pivot_value_2> ... ] ) )
How can I apply this to string values?

Answer 1

The aggregating function can be max(). For example:
select *
from (
select xx.seq, xx.value:"#id" id, xx.value:"$" title
from BooksXML, table(flatten(xml:"$":"$")) xx
)
pivot(max(title) for id in ('bk101', 'bk102', 'bk103', 'bk104', 'bk105')) as p
order by seq
With the table:
CREATE temp TABLE BooksXML
as
select parse_xml('<catalog issue="spring">
<Books>
<book id="bk101">The Good Book</book>
<book id="bk102">The OK Book</book>
<book id="bk103">The NOT Ok Book</book>
<book id="bk104">All OK Book</book>
<book id="bk105">Every OK Book</book>
</Books>
</catalog>') xml
union all select parse_xml('
<catalog issue="spring">
<Books>
<book id="bk102">The OK Book1</book>
<book id="bk103">The NOT Ok Book1</book>
<book id="bk104">All OK Book1</book>
</Books>
</catalog>')
union all select parse_xml('
<catalog issue="spring">
<Books>
<book id="bk101">The Good Book2</book>
<book id="bk103">The NOT Ok Book2</book>
<book id="bk104">All OK Book2</book>
<book id="bk105">Every OK Book2</book>
</Books>
</catalog>');