Finding regex pattern of date on separate lines and between text - python-3.x

Question

I got the regex pattern of 15 July - 3 September 2022 as
[\d]{1,2} [ADFJMNOS]\w* [\-] [\d]{1,2} [ADFJMNOS]\w* [\d]{4}
My doubts are
What will be the regex pattern if the date is not on a single line
example
15 July - 3 September
2022
22
July
Desired Output
15 July - 3 September 2022
22 July
Also if it is seen as a part of another word
example
delayed15 July – 3 Septemer 2022
Here it is attached with the word "delayed". The word can be anything.
Desired Output
15 July – 3 Septemer 2022
Code i am trying
from selenium import webdriver
from bs4 import BeautifulSoup
import re
url_list = ['https://alabamasymphony.org/event/bachmozart']
headers = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/92.0.4515.131 Safari/537.3"
}
driver = webdriver.Chrome('/home/ubuntu/selenium_drivers/chromedriver')
format_list = ["[\d]{1,2} [ADFJMNOS]\w* [\-] [\d]{1,2} [ADFJMNOS]\w* [\d]{4}"]
for URL in url_list:
date = []
driver.get(URL)
driver.implicitly_wait(2)
data = driver.page_source
cleantext = BeautifulSoup(data, "lxml").text
cleanr = re.compile('<.*?>')
x = re.sub(cleanr, ' ', cleantext)
print(URL)
for pattern in format_list:
all_dates = re.findall(pattern, x)
if all_dates == []:
continue
else:
date.append(all_dates)
for s in date:
print(s)

Answer 1

You can try this regex (Demo):
(\d{1,2})\s*([A-Za-z]+)[ \t]*(?:(-\s*\d{1,2}\s*[A-Za-z]+)\s+(\d{4}))?
The idea is to break down the date and text in 4 groups and print those as needed by you.
source code (run here) :
import re
regex = r"(\d{1,2})\s*([A-Za-z]+)[ \t]*(?:(-\s*\d{1,2}\s*[A-Za-z]+)\s+(\d{4}))?"
test_str = ("15 July - 3 September 2022 as\n\n\n"
"15 July - 3 September \n"
"2022\n"
"22\n"
"July\n\n\n\n"
" Also if it is seen as a part of another word\n\n"
"example\n\n"
"delayed15 July - 3 Septemer 2022\n\n"
"Here it is attached with the word \"delayed\". The word can be anything.\n\n\n")
matches = re.finditer(regex, test_str, re.MULTILINE)
for match in matches:
if match.group(3) is not None :
print(match.group(1)+" "+match.group(2)+match.group(3)+" "+match.group(4))
else:
print(match.group(1)+" "+match.group(2))