I need to write a program that replaces all inputted values in a string. Thus: the string reads as "[link1], [link2], [link3]", the input is "1, 2", I want to replace both [link1] and [link2] with another text.
I've tried both replace() and re.sub, but these expectedly only change the first occurrence of the pattern. What am I doing wrong?
for i in input:
output = string.replace(f'[link{i}]', '')
# output = re.sub(f'[link{i}]', '', string)
return output
In your code, you are not saving the modified string. It is just changing the raw string every time and saving only one change.
Try like this:
string = "[link1], [link2], [link3]"
INPUT = input('Give the input').split(',')
replacer = {'1' : 'ONE', "2" : 'Two', '3' : 'Three'}
for i in INPUT:
string = string.replace(f'[link{i}]', replacer[i])
print(string)
Related
I have what I think is a basic question in Python:
I have a list that can be variable in length and I need to insert it into a string for later use.
Formatting is simple, I just need a comma between each name up to nameN and parenthesis surrounding the names.
List = ['name1', 'name2' .... 'nameN']
string = "Their Names are <(name1 ... nameN)> and they like candy.
Example:
List = ['tom', 'jerry', 'katie']
print(string)
Their Names are (tom, jerry, katie) and they like candy.
Any ideas on this? Thanks for the help!
# Create a comma-separated string with names
the_names = ', '.join(List) # 'tom, jerry, katie'
# Interpolate it into the "main" string
string = f"Their Names are ({the_names}) and they like candy."
There are numerous ways to achieve that.
You could use print + format + join similar to the example from #ForceBru.
Using format would make it compatible with both Python2 and Python3.
names_list = ['tom', 'jerry', 'katie']
"""
Convert the list into a string with .join (in this case we are separating with commas)
"""
names_string = ', '.join(names_list)
# names_string == "tom, katie, jerry"
# Now add one string inside the other:
string = "Their Names are ({}) and they like candy.".format(names_string)
print(string)
>> Their Names are (tom, jerry, katie) and they like candy.
how may I be able to take from a string in python a value that is in a given text but is inside it, it's between 2 letters that I want it to copy from inside.
e.g.
"Kahoot : ID:1234567 Name:RandomUSERNAME"
I want it to receive the 1234567 and the RandomUSERNAME in 2 different variables.
a way I found to catch is to get it between the "ID:"COPYINPUT until the SPACE., "Name:"COPYINPUT until the end of the text.
How do I code this?
if I hadn't explained correctly tell me, I don't know how to ask/format this question! Sorry for any inconvenience!.
If the text always follows the same format you could just split the string. Alternatively, you could use regular expressions using the re library.
Using split:
string = "Kahoot : ID:1234567 Name:RandomUSERNAME"
string = string.split(" ")
id = string[2][3:]
name = string[3][5:]
print(id)
print(name)
Using re:
import re
string = "Kahoot : ID:1234567 Name:RandomUSERNAME"
id = re.search(r'(?<=ID:).*?(?=\s)', string).group(0)
name = re.search(r'(?<=Name:).*', string).group(0)
print(id)
print(name)
I'm a novice in python programming and i'm trying to split full name to first name and last name, can someone assist me on this ? so my example file is:
Sarah Simpson
I expect the output like this : Sarah,Simpson
You can use the split() function like so:
fullname=" Sarah Simpson"
fullname.split()
which will give you: ['Sarah', 'Simpson']
Building on that, you can do:
first=fullname.split()[0]
last=fullname.split()[-1]
print(first + ',' + last)
which would give you Sarah,Simpson with no spaces
This comes handly : nameparser 1.0.6 - https://pypi.org/project/nameparser/
>>> from nameparser import HumanName
>>> name = "Sarah Simpson"
>>> name = HumanName(name)
>>> name.last
'Simpson'
>>> name.first
'Sarah'
>>> name.last+', '+name.first
'Simpson, Sarah'
you can try the .split() function which returns a list of strings after splitting by a separator. In this case the separator is a space char.
first remove leading and trailing spaces using .strip() then split by the separator.
first_name, last_name=fullname.strip().split()
Strings in Python are immutable. Create a new String to get the desired output.
You can use split() method of string class.
name = "Sarah Simpson"
name.split()
split() by default splits on whitespace, and takes separator as parameter. It returns a list
["Sarah", "Simpson"]
Just concatenate the strings. For more reference https://docs.python.org/3.7/library/stdtypes.html?highlight=split#str.split
Output = "Sarah", "Simpson"
name = "Thomas Winter"
LastName = name.split()[1]
(note the parantheses on the function call split.)
split() creates a list where each element is from your original string, delimited by whitespace. You can now grab the second element using name.split()[1] or the last element using name.split()[-1]
split() is obviously the function to go for-
which can take a parameter or 0 parameter
fullname="Sarah Simpson"
ls=fullname.split()
ls=fullname.split(" ") #this will split by specified space
Extra Optional
And if you want the split name to be shown as a string delimited by coma, then you can use join() or replace
print(",".join(ls)) #outputs Sarah,Simpson
print(st.replace(" ",","))
Input: Sarah Simpson => suppose it is a string.
Then, to output: Sarah, Simpson. Do the following:
name_surname = "Sarah Simpson".split(" ")
to_output = name_surname[0] + ", " + name_surname[-1]
print(to_output)
The function split is executed on a string to split it by a specified argument passed to it. Then it outputs a list of all chars or words that were split.
In your case: the string is "Sarah Simpson", so, when you execute split with the argument " " -empty space- the output will be: ["Sarah", "Simpson"].
Now, to combine the names or to access any of them, you can right the name of the list with a square brackets containing the index of the desired word to return. For example: name_surname[0] will output "Sarah" since its index is 0 in the list.
I have the input s of string. I want to print string s in which all the occurrences of WUB are replaced with a white space.
s = input()
print(s.split("WUB"))
Input : WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
but the output I am getting is like this
: ['', 'WE', 'ARE', '', 'THE', 'CHAMPIONS', 'MY', 'FRIEND', '']
instead I need output in string format, like this : WE ARE THE CHAMPIONS MY FRIEND
You can join the strings in the list produced by split with a space:
print(" ".join(s.split("WUB")))
You can also just use replace instead of split + join:
print(s.replace("WUB", " "))
You can apply the input in the print statement like this
s = input()
print(*s.split("WUB"))
Notice * before s.split("WUB") this gives the desired output.
WE ARE THE CHAMPIONS MY FRIEND
Just join all elements from your list. See it below:
print(" ".join("WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB".split("WUB")).strip())
I have a number of files in a directory with the following file format:
roll_#_oe_yyyy-mm-dd.csv
where # is a integer and yyyy-mm-dd is a date (for example roll_6_oe_2008-02-12).
I am trying to use the split function so I can return the number on its own. So for example:
roll_6_oe_2008-02-12 would yield 6
and
roll_14_oe_2008-02-12 would yield 14
I have tried :
filename.split("_")
but cannot write the number to a variable. What can I try next?
Supposing that: filename = 'roll_14_oe_2008-02-12'
print(filename.split('_')) evaluates to ['roll', '14', 'oe', '2008-02-12']
The number you want to retrieve is in the 2nd position of the list:
my_number = filename.split('_')[1]
You could also extract the number using regex:
import re
filename = 'roll_134_oe_2008-02-12'
number_match = re.match("roll_*(\d+)", filename)
if number_match:
print number_match.group(1)
Working example for both methods: http://www.codeskulptor.org/#user41_jEFOv5N5GN_2.py