I want to get the result of the below query using PyGithub. Is there a way to set accept header in pygithub? I want the output in diff format and I don't want to use github compare API.
So is there a way to make below request using pygithub?
curl \
-H "Accept: application/vnd.github.diff" \
http(s)://{hostname}/api/v3/repos/octocat/hello-world/commits/REF
Related
I need to make a POST request via cURL from the command line. Data for this request is located in a file. I know that via PUT this could be done with the --upload-file option.
curl host:port/post-file -H "Content-Type: text/xml" --data "contents_of_file"
You're looking for the --data-binary argument:
curl -i -X POST host:port/post-file \
-H "Content-Type: text/xml" \
--data-binary "#path/to/file"
In the example above, -i prints out all the headers so that you can see what's going on, and -X POST makes it explicit that this is a post. Both of these can be safely omitted without changing the behaviour on the wire. The path to the file needs to be preceded by an # symbol, so curl knows to read from a file.
I need to make a POST request via Curl from the command line. Data for this request is located in a file...
All you need to do is have the --data argument start with a #:
curl -H "Content-Type: text/xml" --data "#path_of_file" host:port/post-file-path
For example, if you have the data in a file called stuff.xml then you would do something like:
curl -H "Content-Type: text/xml" --data "#stuff.xml" host:port/post-file-path
The stuff.xml filename can be replaced with a relative or full path to the file: #../xml/stuff.xml, #/var/tmp/stuff.xml, ...
If you are using form data to upload file,in which a parameter name must be specified , you can use:
curl -X POST -i -F "parametername=#filename" -F "additional_parm=param2" host:port/xxx
Most of answers are perfect here, but when I landed here for my particular problem, I have to upload binary file (XLSX spread sheet) using POST method, I see one thing missing, i.e. usually its not just file you load, you may have more form data elements, like comment to file or tags to file etc as was my case. Hence, I would like to add it here as it was my use case, so that it could help others.
curl -POST -F comment=mycomment -F file_type=XLSX -F file_data=#/your/path/to/file.XLSX http://yourhost.example.com/api/example_url
I was having a similar issue in passing the file as a param. Using -F allowed the file to be passed as form data, but the content type of the file was application/octet-stream. My endpoint was expecting text/csv.
You are able to set the MIME type of the file with the following syntax:
-F 'file=#path/to/file;type=<MIME_TYPE>
So the full cURL command would look like this for a CSV file:
curl -X POST -F 'file=#path/to/file.csv;type=text/csv' https://test.com
There is good documentation on this and other options here: https://catonmat.net/cookbooks/curl/make-post-request#post-form-data
I had to use a HTTP connection, because on HTTPS there is default file size limit.
https://techcommunity.microsoft.com/t5/IIS-Support-Blog/Solution-for-Request-Entity-Too-Large-error/ba-p/501134
curl -i -X 'POST' -F 'file=#/home/testeincremental.xlsx' 'http://example.com/upload.aspx?user=example&password=example123&type=XLSX'
I am trying to get the response from a curl url only for a particular value. For example
i am using the command
URLS=$(curl -g -H "Authorization: ${abc}" "https://api.buildkite.com/v2/organizations/org/agents?meta_data=[queue=dev]")
echo "${URLS}"
The metadata is actually as below:
"meta_data": [
"queue=dev"
]
The above curl command is giving the response for all agents in all queues and not able to get the required ones specific to queue=dev.
What is the correct way to pass url with brackets?
I have a scenario in which I call multiple API requests with the same headers.
Headers would usually have:
Authorization: Bearer ASADFW&YUWFIANDJDDAjd8sa87sad7sa8dhsahdusabhdw
Content-Type: text/html;charset=UTF-8
etc...
I need to set these headers key-value pair as a default so whenever I curl the APIs these get picked.
Is there a way to do this?
I usually just keep a text file open with the Curl command, something like:
curl -X POST -H "Authorization: Bearer ASADFW&YUWFIANDJDDAjd8sa87sad7sa8dhsahdusabhdw"
-H "Content-Type: text/html;charset=UTF-8" -d 'blah'
http://some_url.com:8080
Then, just copy and paste the above into a terminal and make the changes you want. Note that I have formatted the above on multiple lines for reading purposes only. In practice, the entire Curl command should be on a single line.
EDIT 2:
It's working I have added raw parameter Thanks a lot to Arty-chan.
curl --insecure --request GET --header 'PRIVATE-TOKEN: Y_F8YP3nUnFbzhxkQvgo' https://gitlabxxxxxxxxxxxxxxx/api/v4/projects/98/repository/files/src%2Fmain%2Fscript%2Fdeploiement%2Fsettings%2Frci%2Fsesameweb2.sh/raw?ref=master >> setting.sh
EDIT:
Thanks to Arty-chan.
I cannot download the file but I have long output. How can I download my sesameweb2.sh file please ?
The sh file should contain some export variable and if I check the content it's not the content of my actual file :(
{"file_name":"sesameweb2.sh","file_path":"src/main/script/deploiement/settings/rci/sesameweb2.sh","size":792,"encoding":"base64","content_sha256":"0ef870c1ebf9e0be5a5a976a4d3e5424a0b5752a75c67fe4b7744eb8fd6279d3","ref":"master","blob_id":"e3937fb8a25edd7a73bbbe5d6b2e267a4e404ef5","commit_id":"577c6c9ba661eb2726b5cd2095bc93bbd7eb3302","last_commit_id":"6921e0acd61d24066a3d680a5d77bd68f880e4d1","content":"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"}
Cannot understand how using api to download with curl my file on gitlab.
here my url:
https://gitlabxxxxxxx/administration/gitlab/raw/master/src/main/script/deploiement/settings/rci/setting.sh
I have checked official website but cannot understand how it's works and which part I should replace:
curl --request GET --header 'PRIVATE-TOKEN: <your_access_token>' 'https://gitlab.example.com/api/v4/projects/13083/repository/files/app%2Fmodels%2Fkey%2Erb/raw?ref=master'
I have tried but it's not working
curl --insecure --request GET --header 'PRIVATE-TOKEN: Y_F8YP3nUnFbzhxkQvgo' 'https://gitlabxxxxxxxxxx/api/v4/administration/gitlab/98/src/main/script/deploiement/settings/rci/sesameweb2.sh/app%2Fmodels%2Fkey%2Erb/raw?ref=master'
My project ID is : 98
I would like to download this setting.sh, I'am using gitlab-ce 12.6.4.
Thanks for help
When following the docs, you need to follow the /projects/:id/repository/files/:file_path format for the link, so don't replace everything, just the pieces with : in front.
You also need to make sure that the file path is using URI encoding.
With the information that you have, it would look something like this:
https://gitlabxxxxxxxxxx/api/v4/projects/98/repository/files/src%2Fmain%2Fscript%2Fdeploiement%2Fsettings%2Frci%2Fsetting.sh?ref=master
curl -k --request GET --header PRIVATE-TOKEN:"<PRIVATE-TOKEN>" https://<gitlab_url>/api/v4/projects/<id>/repository/files/<path_url_encoded>/raw?ref=master > <destination_path>
OR
refer official example:
curl --header "PRIVATE-TOKEN: <your_access_token>" "https://gitlab.example.com/api/v4/projects/13083/repository/files/app%2Fmodels%2Fkey%2Erb?ref=master"
Here:
PRIVATE-TOKEN - enter your private token
path_url_encoded = Check here
destination_path - path where you want to download the file with filename
Check the Official Doc
I can create an annotated tag using the GitHub v3 API by following their directions. I create the tag object, then the ref object. Everything good there.
I can delete the reference like this:
curl -X DELETE -i -u 'myuser:mypassword' https://api.github.com/repos/:user/:repo/git/refs/tags/ben-test-310
Unfortunately this doesn't seem to be sufficient. How do I fully delete the tag using the API?
The API supports this now. It's called "deleting a ref" (delete_ref):
https://docs.github.com/en/rest/reference/git#delete-a-reference
Here it is in the Ruby SDK also, just for example:
https://octokit.github.io/octokit.rb/Octokit/Client/Refs.html
Had to figure out that I needed to prepend /tags before the tag I wanted to delete but it's not mentioned in https://docs.github.com/en/rest/reference/git#delete-a-reference.
Here's the full command for reference:
curl \
-X DELETE \
-H "Accept: application/vnd.github+json" \
-H "Authorization: Bearer {GITHUB_TOKEN}" \
"https://api.github.com/repos/{username}/{repo}/git/refs/tags/{tag}"