write specific file name in specific list in python - python-3.x

Question

I have folder contain multiple .txt files ,the names of files(one.txt,two.txt,three.txt,...) I need to read the one.txt and then write the content of this file in list has name onefile[], then read two.txt and write the content in list twofile[] and so on. how can do this?
Update! Iam try this code, now how can print the values in each list ?
def writeinlist(file_path,i):
multilist = {}
output = open(file_path,'r')
globals()['List%s' % i] = output
print('List%s' % i)
input_path = Path(Path.home(), "Desktop", "NN")
index=1
for root, dirs, files in os.walk(input_path):
for file in files:
file_path = Path(root, file)
writeinlist(file_path,index)
index+=1
Update2: how can delete \n from values?
value_list1 = files_dict['file1']
print('Values of file1 are:')
print(value_list1)

Answer 1

I used the following to create a dictionary with dynamic keys (with the names of the files) and the respective values being a list with elements the lines of the file.
First, contents of onefile.txt:
First file first line
First file second line
First file third line
Contents of twofile.txt:
Second file first line
Second file second line
My code:
import os
import pprint
files_dict = {}
for file in os.listdir("/path/to/folder"):
if file.endswith(".txt"):
key = file.split(".")[0]
full_filename = os.path.join("/path/to/folder", file)
with open(full_filename, "r") as f:
files_dict[key] = f.readlines()
pprint.pprint(files_dict)
Output:
{'onefile': ['First file first line\n',
'First file second line\n',
'First file third line'],
'twofile': ['Second file first line\n', 'Second file second line']}
Another way to do this that's a bit more Pythonic:
import os
import pprint
files_dict = {}
for file in [
f
for f in os.listdir("/Users/itroulli/Downloads/data_eng_challenge3/files")
if f.endswith(".txt")
]:
with open(os.path.join("/path/to/folder", file), "r") as fo:
files_dict[file.split(".")[0]] = fo.readlines()
pprint.pprint(files_dict)