Convert timestamp in seconds to a timestamp with current date - python-3.x

Question

I have a pandas dataframe which has a column called timeElapsed in seconds.
I take input from user to get a specific timestamp.
I want to add this specific timestamp with the timeElapsed column value.
For example:
user enters: 2021-07-08 10:00:00.0000
First entry in timeElapsed column is 80.1234.
New Column should be 2021-07-08 10:01:20.1234
so far, this is my code
import time
import pandas as pd
from datetime import datetime
df1 = pd.DataFrame({'userData': [1, 2, 3, 4, 5, 6, 7],
'timeElapsed': [0, 1.6427, 2.5185,5.3293,6.6699,37.4221,67.4378]})
takeDateInput = str(datetime.strptime(input("Enter current timestamp: YYYY-MM-DD HH:MM:SS.MS"),'%Y-%m-%d %H:%M:%S.%f'))
def myfunc2(x):
time.gmtime(x)
print(df1['timeElapsed'].apply(myfunc2))
I am trying to convert the seconds value to get a formatted hh:mm:ss timestamp using the myfun2. But I am not able to convert it. Is this the current approach?
Any direction as to how to achieve my final goal, would be much appreciated. Thank you

Answer 1

The timeElapsed value you're trying to add is best represented with a Timedelta. Keep the inputted timestamp as Datetime object (not a string), then you can just add the seconds as Timedelta:
takeDateInput = datetime.strptime(input("Enter current timestamp: YYYY-MM-DD HH:MM:SS.MS"),'%Y-%m-%d %H:%M:%S.%f')
def myfunc2(x):
return takeDateInput + pd.Timedelta(x, unit='sec')
print(df1['timeElapsed'].apply(myfunc2))