I've got the following:
Dim dupArray As Variant
dupArray = Array("dup")
For j = LBound(numArray) To UBound(numArray)
If IsInArray(Range(numArray(j)).Text, dupArray) Then
Range(numArray(j)).Interior.ColorIndex = 3
MsgBox "Duplicate value"
ElseIf IsInArray(Range(numArray(j)).Text, keyArray) Then
Application.OnKey Range(numArray(j)).Text, comArray(j)
ReDim Preserve dupArray(j)
Dim cellEntry As String
cellEntry = Range(numArray(j)).Text
MsgBox cellEntry
dupArray(j) = cellEntry
Else
Range(numArray(j)).Interior.ColorIndex = 3
MsgBox "Unrecognized key code in " & numArray(j)
End If
Next j
In essence, I want VBA to read the contents of a cell and append them to an array for comparison. Code to read the contents of a cell is Range(numArray(j)).Text... For some reason, cellEntry and dupArray(j) are not equal. More specifically, for the cell A6, cellEntry is "b" (which is the correct contents), but dupArray(j) is "A6"... any thoughts? There's no error code, it's just not putting the correct value in the array.
Thank you!
(Edit) Code for Function IsInArray:
Function IsInArray(stringToBeFound As String, arr As Variant) As Boolean
IsInArray = Not IsError(Application.Match(stringToBeFound, arr, 0))
End Function
(Edit 2) Don't pay attention to much else... I'm just wondering why cellEntry doesn't match dupArray(j) for all values of j when they should clearly be the same thing.
Your code seems to work, but it depends on keyArray being populated.
I've run this demo code, including populating numArray and keyArray with test values, to illustrate what happens.
If how I've populated these arrays doesn't match your code, please add that info to your Q.
Sub Demo()
Dim dupArray As Variant
Dim numArray As Variant
Dim keyArray As Variant
Dim comArray As Variant
Dim j As Long
' for testing
numArray = Application.Transpose([A1:A6].Value)
ReDim keyArray(1 To 3)
keyArray(1) = "x"
keyArray(2) = "a"
keyArray(3) = "s"
dupArray = Array("dup")
For j = LBound(numArray) To UBound(numArray)
If IsInArray(Range(numArray(j)).Text, dupArray) Then
Range(numArray(j)).Interior.ColorIndex = 3
'MsgBox "Duplicate value"
ElseIf IsInArray(Range(numArray(j)).Text, keyArray) Then
'Application.OnKey Range(numArray(j)).Text, comArray(j)
ReDim Preserve dupArray(j)
Dim cellEntry As String
cellEntry = Range(numArray(j)).Text
'MsgBox cellEntry
dupArray(j) = cellEntry
Else
Range(numArray(j)).Interior.ColorIndex = 4 ' changed to be distinct for testing
'MsgBox "Unrecognized key code in " & numArray(j)
End If
Next j
End Sub
Sheet, before
Sheet, after
Variable values at end of execution
As you can see, dupArray has been populated sparsley, in line with numArray. This is fine for how it's used with IsInArray. If it's used for something else too, you can change how it's populated.
Related
I have a table with strings, and I want to check whether those strings are already stored as elements in a certain array. If not, they're supposed to be added as the last element of the respective array. For some reason, I receive an error stating that the types are incompatible in the line mtch = Application.Match(srch, arr, 0).
Also, I want to work with this approach and not a different one since this is supposed to be the basis for further checks.
Sub Test_4()
Dim i, j, k As Long
Dim arr As Variant
Dim srch, mtch As String
With Worksheets("table1")
For i = 1 To .Range("A1").End(xlDown).Row
srch = .Range("A" & i).Value
mtch = Application.Match(srch, arr, 0)
If Not IsNumeric(mtch) Then
ReDim Preserve arr(UBound(arr) + 1)
arr(UBound(arr)) = mtch
End If
Next i
End With
End Sub
Your base fault is - as Mate wrote - that arr isn't initialized in the first run
You can use this code - it uses the VBA Filter function to test wether a value is already part of an array or not.
Public Function getUniqueValuesFromRange(rg As Range) As Variant
Dim arrResult As Variant
ReDim arrResult(0 To rg.Cells.Count - 1) 'dim arrResult to the max
Dim iCell As Long, iResult As Long
Dim value As Variant
For iCell = 1 To rg.Cells.Count
value = rg.Cells(iCell)
If UBound(Filter(arrResult, value)) = -1 Then 'value is not part of arrResult
arrResult(iResult) = value
iResult = iResult + 1
End If
Next
'it is "cheaper" to redim the array once at the end of the function
ReDim Preserve arrResult(iResult - 1)
getUniqueValuesFromRange = arrResult
End Function
You can call this function like this:
arr = getUniqueValuesFromRange(Worksheets("table1").UsedRange.Columns("A"))
EDIT: you can use
If Not IsNumeric(Application.Match(value, arrResult, 0)) Then
instead of
If UBound(Filter(arrResult, value)) = -1 Then
If you have Excel 365 you can use the UNIQUE function as well
Public Function getUniqueValuesFromRange(rg As Range) As Variant
With Application.WorksheetFunction
getUniqueValuesFromRange= .Transpose(.Unique(rg))
End With
End Function
Be aware: there is no check, that you pass only one column ...
Function test()
Dim result As String
Dim x As Integer
Dim search_value As String
Dim column As Integer
search_value = "esg001"
column = 1
For x = 2 To 3
Sheets(x).Select
Range("B:B").Select
On Error Resume Next
Cells.Find(search_value).Select
ActiveCell.Offset(0, column).Select
result = ActiveCell.Value
If search_value <> "" Then
GoTo ola
Else
End If
Next
ola:
test = result
End Function
as stated in the comments the following formula will do what you want:
=IFERROR(VLOOKUP("esg001",Sheet2!B:C,2,FALSE),VLOOKUP("esg001",Sheet3!B:C,2,FALSE))
Where Sheet2 and Sheet3 are the names of the sheets.
Now a couple of notes on your attempted code.
Do not use .Select. More info on that HERE
when using UDF avoid hardcoding ranges, pass them as parameters. The reason is that the formula would not update when the data updates if it is not a parameter.
This accepts two parameters: Search Value and which column to return. It also accepts as many ranges as desired to search for the value:
Function test(schVal As String, clm As Long, ParamArray schRng() As Variant) As Variant
Dim i As Long
For i = LBound(schRng) To UBound(schRng)
If TypeOf schRng(i) Is Range Then
If schRng(i).Columns.Count > clm Then Exit Function
Dim rngArr() As Variant
rngArr = Intersect(schRng(i), schRng(i).Parent.UsedRange).Value
Dim j As Long
For j = 1 To UBound(rngArr, 1)
If rngArr(j, 1) = schVal Then
test = rngArr(j, clm)
Exit Function
End If
Next j
Else
test = "Parameters 3 and higher should be ranges"
Exit Function
End If
Next i
test = "Not Found"
End Function
Now you would call it (using the formula above as a template):
=TEST("esg001",2,Sheet2!B:C,Sheet3!B:C)
It will first
I am working on a program that needs to read an array of values from cells in another worksheet in the same workbook. I am able to read a single value just fine, but when I try to read multiple, I cannot return an array.
Here is what I am trying to do:
Dim list() As Variant
list = ActiveWorkbook.Worksheets("Sheet2").Range("A2:C2").value
Debug.Print TypeName(list)
Debug.Print UBound(list)
Debug.Print LBound(list)
Debug.Print TypeName(list(UBound(list)))
For which the output is:
Variant()
1
1
Subscript out of range
However, If I try it where I expect a single string, instead of an array of strings
Dim value As String
Let value = ActiveWorkbook.Worksheets("Site IDs and CJONs").Range("A2").value
Debug.Print TypeName(value)
Debug.Print value
for which I get the output
String
Expected Value
According to this question I should be able to simply return an array from the range function (example from the answer below), but it doesn't seem to be working for me. What am I doing wrong?
Dim DirArray As Variant
DirArray = Range("a1:a5").Value
Although it is not obvious, this:
Dim DirArray As Variant
DirArray = Range("a1:a5").Value
actually is like:
Dim DirArray(1 To 5, 1 To 1) As Variant
DirArray(1, 1) = Range("A1").Value
DirArray(2, 1) = Range("A2").Value
DirArray(3, 1) = Range("A3").Value
DirArray(4, 1) = Range("A4").Value
DirArray(5, 1) = Range("A5").Value
Pulling a set of cells into an array usually makes a 2-D array.
NOTE:
If you want to go from array to worksheet cells then, for example:
Sub ytrewq()
Dim DirArray(1 To 5, 1 To 1) As Variant
DirArray(1, 1) = "Larry"
DirArray(2, 1) = "Moe"
DirArray(3, 1) = "Curly"
DirArray(4, 1) = "Shepp"
DirArray(5, 1) = "James"
Range("B9").Resize(5, 1) = DirArray
End Sub
I might as well put my comment as an answer:
Option Explicit
Sub test()
Dim list As Variant
list = Application.Transpose(Application.Transpose(ActiveWorkbook.Worksheets("Sheet1").Range("A2:C2").Value))
Debug.Print TypeName(list)
Debug.Print UBound(list)
Debug.Print LBound(list)
'Debug.Print UBound(list, 2) Error
'Debug.Print LBound(list, 2) Error
Debug.Print TypeName(list(UBound(list)))
Debug.Print list(UBound(list))
End Sub
Gives output:
Variant()
3
1
String
x
where C2 contains letter x.
I am trying to get the values of the visible cells of a range into an array.
My code makes the array carry the values until the first non visible cell then stops.
Public Function ListeMaschinen() As Variant
Dim Auswahl As Range
With Sheets("qry_TechnischesDatenblatt")
Set Auswahl = .Range(.Range("A2:B2"), .Range("A2:B2").End(xlDown)).SpecialCells(xlCellTypeVisible)
End With
ListeMaschinen = Auswahl
End Function
If I select the range it shows all the cells I want marked.
Auswahl.Select
Here I have added the range cells to an array.
Sub examp()
Dim rng As Range, cll As Range, i As Integer, a(100) As Variant
Set rng = Range(Range("A2:B2"), Range("A2:B2").End(xlDown)).SpecialCells(xlCellTypeVisible)
i = 0
For Each cll In rng
a(i) = cll.Value
i = i + 1
Next
End Sub
In your code, you are setting a Variant variable equal to a Range object without using the Set statement.
The following works with the little testing I did. Of course, if you declare the function type and other variables as Range type, it also works.
Option Explicit
Sub test()
Dim myVar As Variant
Set myVar = myList()
Debug.Print myVar.Address
End Sub
Public Function myList() As Variant
Dim myRng As Range
With Sheets("Sheet1")
Set myRng = .Range(.Range("A1:B1"), .Range("A1:B1").End(xlDown)).SpecialCells(xlCellTypeVisible)
End With
Debug.Print myRng.Address
Set myList = myRng
End Function
I think your issue is related to
.SpecialCells(xlCellTypeVisible)
When I do this:
Public Function ListeMaschinen() As Variant
Dim Auswahl As Range
With Sheets("qry_TechnischesDatenblatt")
Set Auswahl = .Range(.Range("A2:B2"), .Range("A2:B2").End(xlDown)).SpecialCells(xlCellTypeVisible)
End With
MsgBox Auswahl.Address
Set ListeMaschinen = Auswahl
'Auswahl.Select
End Function
I get an Address composed of 2 parts: the visible parts!
But when I remove the SpecialCells
Public Function ListeMaschinen() As Variant
Dim Auswahl As Range
With Sheets("qry_TechnischesDatenblatt")
Set Auswahl = .Range(.Range("A2:B2"), .Range("A2:B2").End(xlDown))
End With
MsgBox Auswahl.Address
Set ListeMaschinen = Auswahl
End Function
I get one single part, which Is what I get when using Select too.
I tested!
Sub test()
Dim myVar As Variant
Dim i As Integer
i = 0
Set myVar = ListeMaschinen()
For Each C In myVar
i = i + 1
MsgBox C.Value & C.Address & "-" & i
Next
End Sub
Further to my comments earlier, here is a method that will work subject to some limitations:
You can't have more than 65536 rows of data; and
You can't have really long text (911 chars+), or blank visible cells; and
The data should not contain the string "|~|"
If those conditions are met, you can use something like this:
Dim v
Dim sFormula As String
With Selection
sFormula = "IF(SUBTOTAL(103,OFFSET(" & .Cells(1).Address(0, 0) & ",row(" & .Address(0, 0) & ")-min(row(" & .Address(0, 0) & ")),1))," & .Address(0, 0) & ",""|~|"")"
End With
Debug.Print sFormula
v = Filter(Application.Transpose(Evaluate(sFormula)), "|~|", False)
You can adapt this to work round the third limitation by changing the alternate text in the formula string.
Hello :) I was trying to find a way to loop through visible rows in a table without going through all the rows and checking if they are visible as this was consuming too much time on a large table. Below is the solution I was able to come up with. It is a function that returns an array of the absolute row numbers of visible rows in a given Range.
Function GetVisibleRows(LookupRange As Range) As Integer()
Dim VisibleRange As Range, Index As Integer, Area As Range
Static VisibleRows() As Integer
Set VisibleRange = LookupRange.SpecialCells(xlCellTypeVisible)
ReDim VisibleRows(0)
Index = 0
For Each Area In VisibleRange.Areas
If Index = 0 Then
VisibleRows(Index) = Area.Row
ReDim Preserve VisibleRows(Index + 1)
End If
Index = UBound(VisibleRows())
If VisibleRows(Index - 1) <> Area.Row Then
VisibleRows(Index) = Area.Row
ReDim Preserve VisibleRows(Index + 1)
End If
Next
' Remove last empty item
ReDim Preserve VisibleRows(UBound(VisibleRows()) - 1)
GetVisibleRows = VisibleRows
End Function
If you would like to use this function in a lookup scenario, you need to convert the absolute row numbers returned by the function to relative row numbers of the table. Following worked for me.
RowIndex = ReturnedRowIndex - LookupRange.Rows(1).Row + 1
Good luck!
My sub compares two lists of strings and returns the closest matches. I've found that the sub gets tripped up over some common words such as "the" and "facility". I would like to write a function that would be supplied an array of words to exclude and check each string for these words and exclude them if found.
Here is a sample input:
|aNames | bNames | words to exclude
|thehillcrest |oceanview health| the
|oceanview, the|hillCrest | health
Intended Output:
|aResults |bResuts
|hillcrest |hillcrest
|oceanview |oceanview
So far I have:
Dim ub as Integer
Dim excludeWords() As String
'First grab the words to be excluded
If sheet.Cells(2, 7).Value <> "" Then
For y = 2 To sheet.Range("G:G").End(xlDown).Row
ub = UBound(excludeWords) + 1 'I'm getting a subscript out of range error here..?
ReDim Preserve excludeWords(0 To ub)
excludeWords(ub) = sheet.Cells(y, 7).Value
Next y
End If
Then my comparison function, using a double loop, will compare each string in column A with column B. Before the comparison, the value in column a and b will go through our function which will check for these words to exclude. It's possible that there will be no words to exclude, so the parameter should be optional:
Public Function normalizeString(s As String, ParamArray a() As Variant)
if a(0) then 'How can I check?
for i = 0 to UBound(a)
s = Replace(s, a(i))
next i
end if
normalizeString = Trim(LCase(s))
End Function
There's probably a few parts in this code that won't work. Might you be able to point me in the right direction?
Thank you!
To store the list in the array, you can do this
Sub Sample()
Dim excludeWords As Variant
Dim lRow As Long
With Sheet1 '<~~ Change this to the relevant sheet
'~~> Get last row in Col G
lRow = .Range("G" & .Rows.Count).End(xlUp).Row
excludeWords = .Range("G2:G" & lRow).Value
'Debug.Print UBound(excludeWords)
'For i = LBound(excludeWords) To UBound(excludeWords)
'Debug.Print excludeWords(i, 1)
'Next i
End With
End Sub
And then pass the array to your function. The above array is a 2D array and hence needs to be handled accordingly (see commented section in the code above)
Also like I mentioned in the comments above
How does oceanview, the become Oceanview? You can replace the but that would give you oceanview, (notice the comma) and not Oceanview.
You may have to pass those special characters to Col G in the sheet or you can handle them in your function using a loop. For that you will have to use the ASCII characters. Please see this
Followup from comments
Here is something that I wrote quickly so it is not extensively tested. Is this what you are looking for?
Sub Sample()
Dim excludeWords As Variant
Dim lRow As Long
With Sheet1
lRow = .Range("G" & .Rows.Count).End(xlUp).Row
excludeWords = .Range("G2:G" & lRow).Value
'~~> My column G has the word "habilitation" and "this"
Debug.Print normalizeString("This is rehabilitation", excludeWords)
'~~> Output is "is rehabilitation"
End With
End Sub
Public Function normalizeString(s As String, a As Variant) As String
Dim i As Long, j As Long
Dim tmpAr As Variant
If InStr(1, s, " ") Then
tmpAr = Split(s, " ")
For i = LBound(a) To UBound(a)
For j = LBound(tmpAr) To UBound(tmpAr)
If LCase(Trim(tmpAr(j))) = LCase(Trim(a(i, 1))) Then tmpAr(j) = ""
Next j
Next i
s = Join(tmpAr, " ")
Else
For i = LBound(a) To UBound(a)
If LCase(Trim(s)) = LCase(Trim(a(i, 1))) Then
s = ""
Exit For
End If
Next i
End If
normalizeString = Trim(LCase(s))
End Function
First of all, you cannot call UBound function for the Array that doesn't have a size yet:
Dim excludeWords() As String
ub = UBound(excludeWords) + 1 'there is no size yet
To remove some of the unwanted words use Replace function
String1 = Replace(String1, "the", "")
To do the comparison you described I would use Like function. Here is documentation.
http://msdn.microsoft.com/pl-pl/library/swf8kaxw.aspx