As a result of this closed topic I started wondering myself the following:
Let's say we have data like this:
A
1
a
2
b
3
c
4
a
5
b
6
c
7
g
8
h
9
i
I want to divide the list into 3 (I used TEXTJOIN) and check which of the 3 of these is unique.
I used a combination of MATCH and COUNTIF (and SEQUENCE) for this.
Question:
I managed to get that correct, but wanted to get the 3 textjoin-results all at once as a spill range.
In the picture below you can see my results of attempts, but I couldn't get the TEXTJOIN to reference the correct column in it's spill-result. What is missing, or what am I doing wrong?
Not sure what you want for output.
If all you want is to determine which is/are unique entries, just use the UNIQUE function. Note the exactly_once argument.
For example:
C1: =OR(B1=UNIQUE($B$1:$B$3,,TRUE))
and fill down, but the formula will fill down automatically.
Edit:
I don't know how to get the TEXTJOIN function to spill down in groups of three like you want. However, to be able to enter the formula just once, and have the results appear in column B, and have that adjust as you add/remove entries from column A, you can use a Table structure.
In that case, row 1 would be the column headers, and the formula in B2 would be:
=IFERROR(TEXTJOIN(",",TRUE,INDEX([Column1],SEQUENCE(3)+(ROW()-ROW(Table2[#Headers]))*3-3)),"")`
No need to fill down.
Edit2:
To create a list of unique (listed only once) values from Column B in Column C, you can use the UNIQUE function. However, due to limitations on SPILL functions within a Table, this column cannot be part of the table.
In the example below, where Column C is NOT part of the table:
B2: =IFERROR(TEXTJOIN(",",TRUE,INDEX([Column1],SEQUENCE(3)+(ROW()-ROW(Table2[#Headers]))*3-3)),"")
C2: =UNIQUE(Table2[Column2],,TRUE)
Edit3:
If you were OK with omitting columnB, and reporting the unique triplets in separate cells instead of concatenated, you could do that with the UNIQUE function:
or, without a table,
=UNIQUE(INDEX($A:$A,SEQUENCE(COUNTA($A:$A)/3,3,2)),,TRUE)
Note that the start argument in the SEQUENCE function represents the first line of data in column A, (2 in this example)
Related
I have 7 columns to choose from and I need to pick 4 of those columns and generate a total for each row. I also need every combination of 4, which means I'll have 35 new columns with the totals for each of those combinations showing in each row. I need the code for this and if it can be done only using Excel. Here is an image of the columns and the grayed ones are the 7 columns I'm talking about. My knowledge of Excel is very limited. There are over 1,500 rows if that matters.
multi step approach that is going to use some helper rows. there may be a more elegant formula that will do this, and much slicker options in VBA, but this is a formula only approach.
Step 1 - Generate List of Column Combination
To generate the list 4 helper rows will need to be insert at the top of your data. either above or below you header row. These 4 rows will represent the column number you are going to pick. To keep the math simpler for me I just assumed the 1 for the first column and 7 for the last column. those numbers will get converted to later to account for column in between in your spreadsheet. For the sake of this example The first combination sum will occur in column AO and the first helper row will be row 1. The first combination will be hard coded and it will seed the pattern for the remainder of column combinations. Enter the following values in the corresponding cells:
AO1 = 1
AO2 = 2
AO3 = 3
AO4 = 4
In the adjacent column a formula will be placed and copied to the right. It will automatically augment the bottom value by 1 until it hits its maximum value at which point the value in the row above will increase by 1 and the the value of the current will be 1 more than the cell above. This will produce a pattern that covers all 35 combinations by the time column BW is reached. Place the formulas below in the appropriate cell and copy to the right:
AP1
=IF(AO2=5,AO1+1,AO1)
AP2
=IF(AO2=5,AP1+1,IF(AO3=6,AO2+1,AO2))
AP3
=IF(AO3=6,AP2+1,IF(AO4=7,AO3+1,AO3))
AP4
=IF(AO4=7,AP3+1,AO4+1)
Step2 - Sum The Appropriate Columns
I was hoping to use a some sort of array type operation to read through the column reference numbers above, but I could not get my head around it. Since it was just 4 entries to worry about I simply added each reference manually in a SUM function. Now the important thing to note is that we will be using the INDEX function over the 13 columns that cover the range of your columns so to convert the index number we figured out above, to something that will work to grab every second row, the number that was calculated will be multiplied by 2 and then 1 will be subtracted. That means 1,2,3,4 for the first column combination becomes 1,3,5,7. You can see this in the following formula. Place the following formula in the appropriate cell and copy down and to the right as needed.
AO5
=INDEX($AB5:$AN5,AO$1*2-1)+INDEX($AB5:$AN5,AO$2*2-1)+INDEX($AB5:$AN5,AO$3*2-1)+INDEX($AB5:$AN5,AO$4*2-1)
pay careful attention to the $ which will lock row or column reference and prevent them from changing as the formula is copied.
Now you may need to adjust the cell references to match your sheet.
I need to automatically obtain a sorted column of values from another given column values, like in the sample:
I have I need A unchanged, and also B obtained from A
A A B
-----------------
1 1 0
0 0 0
3 3 1
8 8 3
0 0 8
I mean if the values from A changes, the B should change accordignly...
Is that possible in MS Excel?
Here a sandbox and sample:
http://1drv.ms/1SkqMhS
If you put The formula =SMALL(A:A,ROW()) in B1 and copy down then the cells in B will be linked to the cells in A in such a way that the numbers in B will be the numbers in A in sorted order. This won't be efficient for larger ranges but will work fine for small to medium size ranges.
If you want the numbers to start in a lower row, say B2 because you have a header in B1, adjust ROW() to something like ROW()-1.
A word of warning: Use of ROW() can make a spreadsheet somewhat fragile in that formulas that involve it can change their meaning if rows are inserted or deleted or the block containing the formula is moved to somewhere else. Rather than using ROW(), there is something to be said for adding a helper column which numbers the data in A (which would then be in e.g. B) and referring to these numbers rather than small. For example, in:
If I put the formula
=SMALL($B$2:$B$5,A2)
In C1 and copy down, it works as intended. In response to a question you raised in the comments, I added still another column which gives an index where the corresponding value occurs. To do this I wrote in D2 (then copied) the formula
=MATCH(C2,$B$2:$B$5,0)
Of course. Highlight your range and in the Data tab, click "Sort", then you can choose how you want to sort your data:
If column B has information that is to be used with Column A (like next to A1 is "Car"), and you want to sort the whole table, based on Column A, then just select Columns A and B, then sort by column A.
Found the answer, thanks to John Coleman !
Just some minor details like cell value fixing (with $, like A$2)and the -1+ROW adjustment for the 1 header row!
Assume I have the following table:
A B C
1 Week 1 Week 2
2 Melissa 114.7 82.8
3 Mike 105.5 122.5
4 Andrew 102.3 87.5
5 Rich 105.3 65.2
The names are in column A, the Week values are in Row 1. (So A1 is blank, B1 = Week 1, and A2 = Melissa.)
I'm trying to build a formula that looks at all the values in a known range (in this example, B2:C5), chooses the highest value of the bunch (here, 122.5) and returns the name of the person from Column A that got that value. If I use this formula, it works for the values in range B2:B5:
=INDEX(A2:A5,MATCH(MAX(B2:B5),B2:B5,0))
That returns Melissa but if I expand the range to include more than just column B's values, I get an #N/A returned:
=INDEX(A2:A5,MATCH(MAX(B2:C5),B2:C5,0))
The weird part (to my simple brain) is that the MATCH portion of the formula works fine, if I just put in this formula, it returns the highest value of 122.5 from C3:
=MAX(B2:C5,B2:C5,0)
So clearly something it going wrong when I'm using either the MATCH or INDEX commands.
Hopefully this makes sense and someone can point out my error?
Try this:
=INDEX(A:A,MAX((B2:C5=MAX(B2:C5))*ROW(B2:C5)))
This is an array formula and must be confirmed with Ctrl+Shift+Enter.
Note: Match can only search one vector at a time. It can be one row or one column or one array. It cannot be two or more rows or columns or a 2D array.
Do it "twice"? Please try:
=INDEX(A2:A5,IFERROR(MATCH(MAX(B2:C5),B2:B5,0),MATCH(MAX(B2:C5),C2:C5,0)))
If you are going to have up to 52/53 weeks to cope with I'd suggest instead inserting a helper column with the MAX for each row. Make that an new (inserted) ColumnA (say =MAX(C2:BC2) etc.) and a simple VLOOKUP should serve, say:
=VLOOKUP(MAX(A:A),A:B,2,0)
I have a data looks like this:
a b c
1 3 4
2 3 3
4 1 2
2 4 2
In another worksheet, I want to do the following calculation:
whenever A1 returns a (header of data worksheet), count number of items that are smaller and equal to 2 in column "a". (result will be 2)
if A1 returns b, count number of items that are smaller and equal to 2 in column "b". (result will be 1).
A1 has already been preset with formula such that it will show a or b or c as conditions changed.
I need the formula to be lean... I actually have 6 headers, so if I keep on using if functions, I will probably have to set 6 if functions in one cell...that can be overwhelming. index match cannot provide a range to work on...Any suggestion? thanks
I don't know vba. If you could provide a workable vba code, i don't mind. but i don't know how to read it...>.< please provide user manual for that. lol, thank you~
If your data is found on Sheet1 and the a is found on column a, b is found on column b etc. enter this formula on then next sheet on b1 when a1 is the column value:
=COUNTIF(INDIRECT("Sheet1!"&a1&":"&a1),"<=2")
The Indirect is for adding text to your reference.
If your data sheet is Sheet1, you could try the array formula:-
=SUM((Sheet1!A1:C1=$A$1)*(Sheet1!A2:C5<=2))
Must be entered with CtrlShiftEnter
(actually there are 3 items less than or equal to 2 in column A)
Or you can use the SUMPRODUCT version if you prefer not to use an array formula:-
=SUMPRODUCT((Sheet1!A1:C1=$A$1)*(Sheet1!A2:C5<=2))
Or you can use this INDEX/MATCH method which is probably more efficient:-
=COUNTIF(INDEX(Sheet1!A2:C5,,MATCH(A1,Sheet1!A1:C1,0)),"<="&2)
I need help searching Column E for value=1 and return the value of column A for the same row. VLOOKUP isn't working because there are many columns being searched and there are several 1's in the lookup, and I couldn't seem to search just 1 column using VLOOKUP. Here's how my spreadsheet looks...
A B C D E
1 Name Weight WeightRank Height HeightRank
2 Mike 170 3 6.3 2
3 Richard 200 1 6.0 3
4 Charles 185 2 7.0 1
So I want to search column E for value=1 and return the corresponding value in column A, which in this example would search "HeightRank" for "value=1" and return "Charles"
I tried using =VLOOKUP(1,E:E,1) but that returns an error.
I tried using =VLOOKUP(1,A1:E3,1) but that returns an error.
INDEX(A:A,MATCH(1,E:E,0))
VLOOKUP doesn't work here -- it always searches in the first column of your table and returns a value of a column a given number of columns to the right.
The INDEX/MATCH combination is more flexible, letting you just choose the two columns you want. It's also easier to read (you don't have to count columns to see what it does) and it doesn't break if you insert or delete columns in between the ones you're using, which VLOOKUP does. If you use the trace-formula features, VLOOKUP also falsely implies that all the columns in between are precedents of your resulting formula. (Can you tell that I don't much like VLOOKUP? I just always use INDEX/MATCH and my life is easier for it.)
The OFFSET solution works but it's volatile, so you'll really bog down your worksheet if many cells depend on the result of your formula.
MATCH(x,E2:E4,0) returns the relative position of x in the range E2:E4. For example, MATCH(1,E2:E4,0) returns 3, because 1 is the value of the third cell in the range E2:E4.
OFFSET(A2,r,c) returns the cell r rows and c columns away from A2.
Thus you can say =OFFSET(A2,MATCH(1,E2:E4,0)-1,0) to return the value from column A corresponding to the cell in column E that contains 1.