I want to use find to find files with _101_ in the name and not .jpg or .wsq extensions, but I cannot get this to work.
I tried things like this:
find . -type f -name '*_101_*' -o -not -name *.jpg -o -name *.wsq
but it doesn't work.
What am I doing wrong?
Your attempt does "matches _101_, or does not end in .jpg, or does not end in .wsq". That'll match every single file, based on the two extensions alone, as a file can only have one.
You have to group differently:
find . -type f -name '*_101_*' -not -name '*.jpg' -not -name '*.wsq'
This applies all rules (logical AND is implied).
You also should quote the parameters to -name, or they might be expanded by the shell instead of find.
You need to use parenthesis (or #Benjamin's solution)
otherwise a or not b or c is evaluated as (a or not b) or c.
And you need and instead of or to filter only files that satisfy both conditions (pass both tests). a and not (b or c)
find -name '*_101_*' -not \( -name '*.jpg' -o -name '*.wsq' \)
Related
I'm creating a cron job, that will find all *.log* files (it will be used to remove them later, when it works).
The find command looks like this:
find /data/dg \( -path /data/dg/kf/data -o -path /data/dg/pg/data \) -prune -o -name "*.log*" -type f
And it should find all files with name ".log" that are not in directories /data/dg/kf/data and /data/dg/pg/data
However the output this command gives contains also the directories.
...
/data/dg/kf/log/controller.log.2019-09-08-22
/data/dg/kf/log/server.log.2019-09-09-07
/data/dg/kf/data
/data/dg/pg/log/postgresql-2019-09-27_000000.log
/data/dg/pg/log/postgresql-2019-09-27_100859.log
/data/dg/pg/log/postgresql-2019-09-27_102411.log
/data/dg/pg/data
/data/dg/sim/log/sim_2019-09-27-11.0.log
/data/dg/sim/log/sim_2019-09-27-12.0.log
...
It seems that -type f doesn't work. What's wrong?
put -type f right after /data/dg
find /data/dg -type f -not -path "/data/dg/kf/data*" -not -path "/data/dg/pg/data*" -name "*.log*"
I want to write a cleanup routine for my make file that removes every thing except the necessary source files in my folder. For example, my folder contains files with the following extensions: .f .f90 .F90 .F03 .o .h .out .dat .txt .hdf .gif.
I know I can accomplish this with:
find . -name \( '*.o' '*.out' '*.dat' '*.txt' '*.hdf' '*.gif' \) -delete
Using negation, I can do this:
find . -not -name '*.f*' -not -name '*.F*' -not -name '*.h' -delete
But, when I try to do this:
find . -not -name \( '*.f*' '*.F*' '*.h' \)
I get an error:
find: paths must exceed expression: [first expression in the above list]
(In this case, I would get:
find: paths must exceed expression: *.f*
)
Can you explain why this happens, and how to do what I am trying to do? I just hate writing -not -name every time I want to add a file extension to the list. Also, I want to find out why this is giving me an error so that I can learn Linux better.
Thanks!
find . -not -name \( '*.f' '*.F' '*.h' \)
is interpreted as
find
. # path to search
-not # negate next expression
-name \( # expression for files named "("
'*.f' '*.F' .'*.h' \) # more paths to search?
leading to the error.
Since these are single-letter extensions, you can collapse them to a single glob:
find . -not -name '*.[fFh]'
but if they are longer, you have to write out the globs
find . -not -name '*.f' -not -name '*.F' -not -name '*.h'
or
find . -not \( -name '*.f' -o -name '*.F' -o -name '*.h' \)
or switch to using regular expressions.
find . -not -regex '.*\.(f|F|h)$'
Note that regular expressions in find is not part of the POSIX standard and might not be available in all implementations.
I would like to recursively find all files contained into a directory that has name “name1” or name “name2”
for instance:
structure/of/dir/name1/file1.a
structure/of/dir/name1/file2.b
structure/of/dir/name1/file3.c
structure/of/dir/name1/subfolder/file1s.a
structure/of/dir/name1/subfolder/file2s.b
structure/of/dir/name2/file1.a
structure/of/dir/name2/file2.b
structure/of/dir/name2/file3.c
structure/of/dir/name2/subfolder/file1s.a
structure/of/dir/name2/subfolder/file2s.b
structure/of/dir/name3/name1.a ←this should not show up in the result
structure/of/dir/name3/name2.a ←this should not show up in the result
so when I start my magic command the expected output should be this and only this:
structure/of/dir/name1/file1.a
structure/of/dir/name1/file2.b
structure/of/dir/name1/file3.c
structure/of/dir/name2/file1.a
structure/of/dir/name2/file2.b
structure/of/dir/name2/file3.c
I scripted something but it does not work because it search within the files and not only folder names:
for entry in $(find $SEARCH_DIR -type f | grep 'name1\|name2');
do
echo "FileName: $(basename $entry)"
done
If you can use the -regex option, avoiding subfolders with [^/]:
~$ find . -type f -regex ".*name1/[^/]*" -o -regex ".*name2/[^/]*"
./structure/of/dir/name2/file1.a
./structure/of/dir/name2/file3.c
./structure/of/dir/name2/subfolder
./structure/of/dir/name2/file2.b
./structure/of/dir/name1/file1.a
./structure/of/dir/name1/file3.c
./structure/of/dir/name1/file2.b
I'd use -path and -prune for this, since it's standard (unlike -regex which is GNU specific).
find . \( -path "*/name1/*" -o -path "*/name2/*" \) -prune -type f -print
But more importantly, never do for file in $(find...). Use finds -exec or a while read loop instead, depending on what you really need to with the matching files. See UsingFind and BashFAQ 20 for more on how to handle find safely.
I need to find all the iplanets on one server and I was thinking to use this command:
find / type d -name https-* | uniq
But at the same time I need to ignore some directories/file. I've been trying to use !, but it not always work. I have a command like this:
find / type d -name https-* ! -name https-admserv* ! -name conf_bk* ! -name alias* ! -name *db* ! -name ClassCache* | uniq
I need to ignore all that. The directories admserv, conf_bk, alias and tmp and the files *.db*
Basically I need find this:
/opt/mw/iplanet/https-daniel.com
/opt/https-daniel1.com
/apps/https-daniel2.com
I only need to find the directory name. How can I ignore all the other stuff?
Use -prune to keep from recursing into directories:
find / \( -type d \( -name 'https-admserv*' -o -name 'conf_bk*' -o -name 'alias*' -o -name 'tmp' \) -prune -o -type d -name 'https-*' -print
There's no need to ignore any files. You're only selecting https-* directories, so everything else is ignored.
And there's no need to pipe to uniq, since find never produces duplicates.
I am trying to find all files ending in .jar, but it is picking up folders that ends in .jar which is something I do not want.
My command so far
find . -name ".*jar"
I need it so it ignores directories ending in .jar
Additional request.
I now need to ignore a specific folder when looking, is this possible?
Thanks.
just add -type f:
find . -name "*.jar" -type f
Others have already shown, how to pick up files named ending in .jar. As an answer to your comment "How to ignore a specific folder". You use -prune for that
find . -name 'specific/folder' -type d -prune -o -type f -name '*.jar'
that's what you want
find . -type f -name "*.jar"
see man page:
-type Type
Evaluates to the value True if the Type variable specifies one of the following values:
b
Block special file
c
Character special file
d
Directory
f
Plain file
l
Symbolic link
p
FIFO (a named pipe)
s
Socket