Cannot create a cronJob for every minute from templates openshift - cron

Question

When I give input for schedule parameter * * * * * the oc export fails with invalid character.
Error: YAML parse error on middleware/templates/cyes-rest/timed-out-streams-cron-job.yaml: error converting YAML to JSON: yaml: line 12: did not find expected alphabetic or numeric character
timedOutStreamsCronJob:
enabled: true
schedule: '* * * * *'
timed-out-streams-cron-job.yaml
{{- if and .Values.cyes.enabled .Values.cyes.timedOutStreamsCronJob.enabled -}}
apiVersion: batch/v1beta1
kind: CronJob
metadata:
name: {{ include "middleware.fullname" . }}-timed-out-streams-cron-job
labels:
{{- include "middleware.labels" . | nindent 4 }}
spec:
schedule: {{.Values.cyes.timedOutStreamsCronJob.schedule}}
jobTemplate:
spec:
template:
spec:
containers:
- name: sync-cron
image: {{.Values.cyes.timedOutStreamsCronJob.image.repository}}:{{.Values.cyes.timedOutStreamsCronJob.image.tag}}
args:
- wget
- -O-
- http://{{ .Release.Name }}-{{.Values.cyes.name}}-service:{{.Values.cyes.port}}/checkStreams
restartPolicy: OnFailure
startingDeadlineSeconds: 3600
{{- end -}}

Answer 1

I believe we are looking at a formatting issue regarding the quotes, as CronJobs should look like this:
apiVersion: batch/v1beta1
kind: CronJob
metadata:
name: pi
spec:
schedule: "*/1 * * * *"
[..]
So your spec should likely look like this (note the "):
spec:
schedule: "{{.Values.cyes.timedOutStreamsCronJob.schedule}}"