Check docker-compose services are running or not - linux

Question

I am writing a script which will check docker service but I want check services which are inside the docker-compose without getting into it.
For ex: we have custom services like tass and inception basically we check it's status by this command "service tass status"
Is there any way to check this services in Docker-compose

Answer 1

You can use:
docker-compose ps <name>
docker-compose top <name>
docker-compose logs <name>
To "check" the service with name <name>. You can learn many more commands by doing `docker-compose --help.
Finally, you can run docker-compose exec <name> <shell> and get an interactive shell inside the cont inaner, which with some unix-utilities will allow you to "check" the container further with ease.
Finally, you can extract the name of the running container as in How do I retrieve the exact container name started by docker-compose.yml , and use any of the docker commands mentioned in the other answer to "check". From docker inspect <the container name> you can get the cgroup name and mounted filesystem, which you can "check".

Answer 2

Docker compose is only a tool to build docker images.
You should rely on docker commands in order to check each service health, for example:
docker ps
docker stat
docker inspect
docker container ls
In this How to check if the docker engine and a docker container are running? thread you can find a lot of alternatives about container checking.

Answer 3

Checking for .State.Status, .State.Running, etc. will tell you if it's running, but it's better to ensure that the health of your containers. Below is a script that you can run that will make sure that two containers are in good health before executing a command in the 2nd container. It prints out the docker logs if the wait time/attempts threshold has been reached.
Example taken from npm sql-mdb.
#!/bin/bash
# Wait for two docker healthchecks to be in a "healthy" state before executing a "docker exec -it $2 bash $3"
##############################################################################################################################
# $1 Docker container name that will wait for a "healthy" healthcheck (required)
# $2 Docker container name that will wait for a "healthy" healthcheck and will be used to run the execution command (required)
# $3 The actual execution command that will be ran (required)
attempt=0
health1=checking
health2=checking
while [ $attempt -le 79 ]; do
attempt=$(( $attempt + 1 ))
echo "Waiting for docker healthcheck on services $1 ($health1) and $2 ($health2): attempt: $attempt..."
if [[ health1 != "healthy" ]]; then
health1=$(docker inspect -f {{.State.Health.Status}} $1)
fi
if [[ $health2 != "healthy" ]]; then
health2=$(docker inspect -f {{.State.Health.Status}} $2)
fi
if [[ $health1 == "healthy" && $health2 == "healthy" ]]; then
echo "Docker healthcheck on services $1 ($health1) and $2 ($health2) - executing: $3"
docker exec -it $2 bash -c "$3"
[[ $? != 0 ]] && { echo "Failed to execute \"$3\" in docker container \"$2\"" >&2; exit 1; }
break
fi
sleep 2
done
if [[ $health1 != "healthy" || $health2 != "healthy" ]]; then
echo "Failed to wait for docker healthcheck on services $1 ($health1) and $2 ($health2) after $attempt attempts"
docker logs --details $1
docker logs --details $2
exit 1
fi