python3 code not running concurrently Asyncio - python-3.x

Question

please help me to find out where is the mistake, I want to run two functions in parallel. THNX
import asyncio
import time
async def test1():
for i in range(10):
print(f"First function {i}")
async def test2():
for i in range(10):
print(f"Second function {i}")
async def main():
print(f"started at {time.strftime('%X')}")
F = asyncio.create_task(test1())
S = asyncio.create_task(test2())
tasks = (F, S)
await asyncio.gather(*tasks)
print(f"finished at {time.strftime('%X')}")
asyncio.run(main())
Instead I get such an output that doesn't have anything relative to the parallel execution :
started at 10:42:53
First function 0
First function 1
First function 2
First function 3
First function 4
First function 5
First function 6
First function 7
First function 8
First function 9
Second function 0
Second function 1
Second function 2
Second function 3
Second function 4
Second function 5
Second function 6
Second function 7
Second function 8
Second function 9
finished at 10:42:53

Answer 1

Ok, finally I've rewrite my code to work with threads, and it works perfectly, but I couldn't figure out how to catch return values from threaded functions, so at first my code looked like this:
import threading
import time
def test1():
for i in range(10):
print(f"First function {i}")
return 11
def test2():
for i in range(10,20):
print(f"Second function {i}")
def main():
t = time.time()
t1 = threading.Thread(target=test1)
t2 = threading.Thread(target=test2)
t1.start()
t2.start()
print(t1.join())
t2.join()
print("Woaahh!! My work is finished..")
print("I took " + str(time.time() - t))
main()
And wwith help of this thread I've changed a bit to handle return values, here
So now my code look like this:
import time
import concurrent.futures
def test1():
for i in range(10):
print(f"First function {i}")
return 11
def test2():
for i in range(10,20):
print(f"Second function {i}")
return 12
def main():
t = time.time()
with concurrent.futures.ThreadPoolExecutor() as executor:
future = executor.submit(test1)
future2 = executor.submit(test2)
return_value = future.result()
rv= future2.result()
print(return_value)
print(rv)
print("Woaahh!! My work is finished..")
print("I took " + str(time.time() - t))
main()

Answer 2

I do not know what is your problem in your code but if you wan to run in parallel i think you can try something like this, by using thread ?
threading.Thread(target=test1).start()
threading.Thread(target=test2).start()
https://docs.python.org/fr/3/library/threading.html

Answer 3

Here is the other example of handling functions output code using Queues
import threading
import time
import queue
def test1(q):
for i in range(10):
print(f"First function {i}")
q.put(1)
def test2(q):
for i in range(10,20):
print(f"Second function {i}")
q.put(2)
def main():
q = queue.Queue()
t = time.time()
t1 = threading.Thread(target=test1, args=(q, ))
t2 = threading.Thread(target=test2, args=(q, ))
t1.start()
t2.start()
print(t1.join())
t2.join()
print("Woaahh!! My work is finished..")
print("I took " + str(time.time() - t))
while not q.empty():
print(q.get())
main()