I have the following aggregation and It does not return the user profiles properly
const newConverSation = await Messenger.Messenger.aggregate([
{ $match: {
users: mongoose.Types.ObjectId("6084036ad4d4cd40a47afba4")}},
{ $sort: { updatedAt: -1 } },
{
$group: {
_id: { $setUnion: "$users" },
message: { $first: "$$ROOT" }
}
},
{
$lookup: {
from: 'users',
localField: 'users',
foreignField: '_id',
as: 'users'
}
}
])
In the outcome, there is an users array like this
"users" : [
ObjectId("60841d03f6ccad2b0400f619"),
ObjectId("6084036ad4d4cd40a47afba4")
],
and I just want to fetch user profiles depending on these two Id's but it does not return profiles in the current way.
Try adding the .populate after the .find property where you want to show this data.
Related
I have a schema
const membershipsSchema = new Schema({
spaceId: {
type: Schema.Types.ObjectId,
ref: 'Space',
},
member: {
type: Schema.Types.ObjectId,
ref: 'User',
},
....
);
mongoose.model('Membership', membershipsSchema);
I want to use join statement like
Select * from membershipPlans as plans join User as users on plans.member=users._id
where plans.spaceId=id and users.status <> 'archived'; // id is coming from function arguments
I tried the aggregate pipeline like
const memberships = await Memberships.aggregate([
{
$match: {
spaceId: id
}
},
{
$lookup: {
from: 'User',
localField: 'member',
foreignField: '_id',
as: 'users',
},
},
{
$match: {
'users.status': {$ne: 'archived'}
}
},
]);
But on console.log(memberships); I am getting an empty array. If I try return Memberships.find({ spaceId: id }) it returns populated memberships of that space. But when I try
const memberships = await Memberships.aggregate([
{
$match: {
spaceId: id
}
},
]}
It still returns an empty array. Not sure if I know how to use an aggregate pipeline.
There are two things that you need to do:
Cast id to ObjectId.
Instead of using $match, just filter the contents of the users array using $filter.
Try this:
const memberships = await Memberships.aggregate([
{
$match: {
spaceId: new mongoose.Types.ObjectId(id)
}
},
{
$lookup: {
from: 'User',
localField: 'member',
foreignField: '_id',
as: 'users',
},
},
{
$project: {
users: {$filter: {
input: "$users",
as: "user",
cond: {
$ne: ["$$user.status", "archived"]
}
}}
}
},
]);
I have a collection of users like this
[
{ _id: ObjectId("61a6d586e56ea12d6b63b68e"), fullName: "Mr A" },
{ _id: ObjectId("6231a89b009d3a86c788bf39"), fullName: "Mr B" },
{ _id: ObjectId("6231a89b009d3a86c788bf3a"), fullName: "Mr C" }
]
And a collection of complains like this
[
{ _id: ObjectId("6231aaba2a038b39d992099b"), type: "fee", postedBy: ObjectId("61a6d586e56ea12d6b63b68e" },
{ _id: ObjectId("6231aaba2a038b39d992099b"), type: "fee", postedBy: ObjectId("6231a89b009d3a86c788bf3c" },
{ _id: ObjectId("6231aaba2a038b39d992099b"), type: "fee", postedBy: ObjectId("6231a89b009d3a86c788bf3b" },
]
I want to check if the postedBy fields of complains are not existed in users, then update by using the updateMany query
By the way, I have an optional way to achieve the goal but must use 2 steps:
const complains = await Complain.aggregate()
.lookup({
from: "users",
localField: "postedBy",
foreignField: "_id",
as: "postedBy",
})
.match({
$expr: {
$eq: [{ $size: "$postedBy" }, 0],
},
});
complains.forEach(async (complain) => {
complain.type = "other";
await complain.save();
});
Therefore, can I combine 2 steps into a single updateMany query? Like $match and $lookup inside updateMany query?
With MongoDB v4.2+, you can use $merge to perform update at last stage of aggregation.
db.complains.aggregate([
{
"$lookup": {
from: "users",
localField: "postedBy",
foreignField: "_id",
as: "postedByLookup"
}
},
{
$match: {
postedByLookup: []
}
},
{
"$addFields": {
"type": "other"
}
},
{
"$project": {
postedByLookup: false
}
},
{
"$merge": {
"into": "complains",
"on": "_id",
"whenMatched": "replace"
}
}
])
Here is the Mongo playground for your reference.
I am currently working on a project that has the following schema using mongoose.
User schema
const userSchema = {
name: string
email: string
medicalVisits: [{type: Schema.ObjectId, ref: "records"}]
createdAt: Date
}
Records schema
const recordSchema = {
medication: [String],
rating: Number
user: [{type: Schema.ObjectId, ref: "user"}]
tests: [{type: Schema.ObjectId, ref: "tests"}]
createdAt: Date
}
Tests schema
testScore: Number
answers: Object
user: [{type: Schema.ObjectId, ref: "user"}]
createdAt: Date
From the little schema above, I have a setup where a patient can take tests multiple times and their respective tests are saved in the Tests collection. Also, the date is recorded for all tests they take. A doctor can request to see a patient's record, in this case, the patient has only one record document that has their tests records embedded in them. Currently, I am faced with the problem of getting a patient's newest and oldest test score alongside their initial details.
I can do a mongoose populate to get all information regarding a user, e.g
await User.findById(userId).populate({
path: "medicalVisits"
model: "records"
populate: {
path: "tests"
model: "test"
}
})
And that operation returns the patient's record and all the tests they have taken since they signed up to date. But when I make such a call to the Database, I just want to retrieve the patient's newest and oldest score. In other words, I want to get the patients, Initial test score, and their most recent test score. I am new to Mongoose aggregation, I tried to use the Mongoose aggregate function, but it returns an empty array, I guess I am missing something.
Currently, this is what my aggregate pipeline looks like.
const user = await Doctor.aggregate([
{ $match: { _id: docId } },
{
$lookup: {
from: "users",
localField: "patients",
foreignField: "_id",
as: "patients",
},
},
{ $unwind: "$patients" },
{ $unwind: "$patients.medicalVisits" },
{
$lookup: {
from: "records",
localField: "patients.user",
foreignField: "_id",
as: "patientRecord",
},
},
{ $unwind: "$patientRecord" },
// { $sort: { createdAt: 1 } },
{
$group: {
_id: docId,
user: { $last: "$patients" },
record: { $last: "$patientRecord"}
},
},
]);
return user[0];
From the above snippet, my intention is:
given a doctor Id, they can see a list of their patients and also see their newest and oldest test score.
Expected Output
const output = {
userId: 6e12euido....
name: "John doe"
email: "john#john.com"
rating: 2
initialTestScore: 10
recentTestScore: 30
}
How do I go about this? Or what could be a better alternative? Thank you very much.
tried my best to understand your case, and I think your aggregation pipeline should be like:
const patientsWithNewestRecord = await Doctor.aggregate([
{ $match: { _id: docId } },
{
$lookup: {
from: "users",
localField: "patients",
foreignField: "_id",
as: "patients",
},
},
// one patient, per doc
{ $unwind: "$patients" },
// one patient with all his/her visit records, per doc
{
$lookup: {
from: "records",
localField: "patients.medicalVisits",
foreignField: "_id",
as: "patientRecords",
},
},
// one patient with one visit record, per doc
{ $unwind: "$patientRecords" },
// sort by patient first, createdAt second
{ $sort: { 'patientRecords.user': 1, 'patientRecords.createdAt': 1 } },
{
$group: {
_id: { patient: '$patientRecords.user' },
user: { $last: "$patients" },
record: { $last: "$patientRecords"}
},
},
]);
this pipeline return a list of a doctor's patients and also see their newest test record. Oldest test record should be in similar war.
Based on these collections (as I understand them from your question):
// doctor collection:
{ _id: "doc1", patients: ["user1"] }
// user collection:
{
_id: "user1", name: "John", email: "john#gmail.com",
medicalVisits: ["record1", "record2"]
}
// record collection:
{ _id: "record1", rating: 2, tests: ["test1", "test2"] }
{ _id: "record2", rating: 4, tests: ["test3"] }
// test collection:
{ _id: "test1", testScore: 12, createdAt: ISODate("2021-12-04") }
{ _id: "test2", testScore: 9, createdAt: ISODate("2021-12-05") }
{ _id: "test3", testScore: 15, createdAt: ISODate("2021-12-24") }
we can apply:
db.doctor.aggregate([
{ $match: { _id: "doc1" } }
{ $lookup: {
from: "user",
localField: "patients", foreignField: "_id",
as: "patients"
}},
{ $unwind: "$patients" }, { $unwind: "$patients.medicalVisits" },
{ $lookup: {
from: "record",
localField: "patients.medicalVisits", foreignField: "_id",
as: "records"
}},
{ $unwind: "$records" }, { $unwind: "$records.tests" },
{ $lookup: {
from: "test",
localField: "records.tests", foreignField: "_id",
as: "tests"
}},
{ $unwind: "$tests" },
{ $sort: { "tests.createdAt": 1 } },
{ $group: {
_id: "$patients._id",
name: { $first: "$patients.name" },
email: { $first: "$patients.email" },
rating: { $first: "$records.rating" },
initialTestScore: { $first: "$tests.testScore" },
recentTestScore: { $last: "$tests.testScore" }
}},
{ $set: { "userId": "$_id" } }, { $unset: "_id" }
])
in order to extract:
{
userId: "user1",
name: "John",
email: "john#gmail.com",
rating: 2,
initialTestScore: 12,
recentTestScore: 15
}
Differences compared to your query:
I $lookup the test collection as it seems you information from there to get both test dates and test scores.
I $sort by test date (createdAt) before the $group by user such that we'll be able to define the right order for selecting the $first and $last test scores.
I extract user's information by using a $first on each group on user's field (since all unwind records for a given user have the same user information): for instance email: { $first: "$patients.email" }
I extract the $first and $last test scores for a user as defined by the $sort order: initialTestScore: { $first: "$tests.testScore" } and recentTestScore: { $last: "$tests.testScore" }.
I finally $set/$unset to rename the _id field into userId
I would suggest to do the following once you have the userId / patientId:
Get their tests (all) from the database in a sorted order
Take the first and last element of the array for your initial and final test report based on the sorting order you have applied (ascending or descending)
If you can just retrieve the user details and all the tests without any sorting, then you can proceed the following way:
Run a loop through all the tests and sort the tests according to test date.
Take the first and last element of the array for your initial and final test report based on the sorting order you have applied (ascending or descending)
You will not be performing the operations on DB end, so there might be a minor speed issue, but the difference would still come out to be in milliseconds unless a user takes a billion tests.
Let me know if this helps, let me know if it doesn't
I have the following schema:
const UserQualificationSchema = new Schema(
{
user: {
type: mongoose.Schema.Types.ObjectId,
ref: 'User',
},
qualification: {
type: mongoose.Schema.Types.ObjectId,
ref: 'Qualification',
},
expiry_date: {
type: Date
}
}
const QualificationSchema = new Schema(
{
fleet: {
type: [String], // Eg ["FleetA", "FleetB", "FleetC"]
required: true,
}
}
I am searching the UserQualifications with filters in a table, to search them by fleet, qualification or expiry date. I so far have the following aggregate:
db.UserQualifications.aggregate([{
{
$lookup: {
from: 'qualifications',
localField: 'qualification',
foreignField: '_id',
as: 'qualification',
},
},
{
$unwind: '$qualification',
},
{
$match: {
$and: [
'qualification.fleet': {
$in: ["Fleet A", "Fleet C"], // This works
},
expiry_date: {
$lt: req.body.expiry_date, // This works
},
qualification: { // Also tried 'qualification._id'
$in: ["6033e4129070031c07fbbf29"] // Adding this returns blank array
}
]
},
}
}])
Filtering by fleet, and expiry date both work, independently and in combination, however when adding by the qualification ID, it returns blank despite the ID's being sent in being valid.
Am i missing something here?
Looking at your schema I can infer that qualification in ObjectId and in the query you are passing only the string value of ObjectId. You can pass the ObjectId to get your expected output
db.UserQualifications.aggregate([
{
$lookup: {
from: "Qualifications",
localField: "qualification",
foreignField: "_id",
as: "qualification",
},
},
{
$unwind: "$qualification",
},
{
$match: {
"qualification.fleet": {
$in: [
"FleetA",
"FleetC"
],
},
expiry_date: {
$lt: 30 // some dummy value to make it work
},
"qualification._id": {
$in: [
// some dummy value to make it work
ObjectId("5a934e000102030405000000")
]
}
},
}
])
I have created a playground with some dummy data to test the query: Mongo Playground
Also, In $match stage there is no need to combine query explicitly in $and as by default behaviour will be same as $and only so I have remove that part in my query
How to to get distinct values in mongodb. I am using mongodb aggregation. How to use distinct in aggregation query. I am using it in node.js
below is my query in model
const criteria = [
{ $match: { $and: [{ $text: { $search: search } }, { $or: [publicData, { $and: [publisherId, { $or: [unListedData, privateData] }] }] }] } },
{ $lookup: { from: 'user', localField: 'userId', foreignField: 'id', as: 'publisherDetails' } },
{ $addToSet: '$_id' },
{ $sort: { created_at: -1 } }
];
Here I have used $addToset, but it did not work.
I have followed the doc's
distinct,
addToset,
but still coud not get proper solution