Error missing values using .replace(regex) - python-3.x

Question

I'm trying to replace some messy data with regex in a data frame, the column has qualification values, but they are messy. For example, I have 'plastic','plastique','Plasticpackage',or 'Karton','carton','Carton'... in the column 'packaging', but they all mean the same thing, that is 'plastic' or 'Carton', things like that. Therefore Im trying to replace all these values with .replace and Regex. My code looks like this:
dict1={r'[cK]arton':'Carton',r'\W*((?i)plasti(?-i))\W*':'Plastique',r'[cC]onserve':'Conserve'}
df['packaging'].replace(dict1,inplace=True,regex=True)
However, when i execute it gives me the error:missing : at position 18
I have checked, line 1 to line 18 have 17 missing values not only at line 18, so why i have this error? Should I tell python to ignore na values? But the replace() function does not seem to have the ignore na option.
Thank you very much in advance

Answer 1

You cannot use inline modifiers in Python re at a non-initial position in a regex. Besides, it does not support (?-i) notation (to disable the effect of the preceding (?i)).
Instead, you can use an inline modifier group, (?i:...).
So, you need to fix the regex definitions likes this:
dict1={
r'[cK]arton':'Carton',
r'\W*(?i:plasti)\W*':'Plastique',
r'[cC]onserve':'Conserve'
}
Or, r'\W*(?i:plasti)\W*' can also be written as r'(?i)\W*plasti\W*'.