I want to integrate Spark GraphX with Neo4j using 1
I tried to follow the steps in 2 but it doesn't work.
What should I do exactly with the neo4j-connector-apache-spark_2.12-4.0.0.jar file ? I put it in the jar files in the Spark folder.
in bash I write:
C:>Spark\spark-3.1.1-bin-hadoop2.7\bin\spark-shell --jars neo4j-connector-apache-spark_2.12-4.0.0.jar
Any suggestions please?
Update no. 1
I tried this C:\Spark\spark-3.1.1-bin-hadoop2.7\bin\spark-shell --packages neo4j-contrib:neo4j-connector-apache-spark_2.12:4.0.0
I think it work. but when I want to write the DataFrame to nodes of type Person in spark-shell:
import org.apache.spark.sql.{SaveMode, SparkSession}
val spark = SparkSession.builder().getOrCreate()
import spark.implicits._
val df = Seq(
("John Doe"),
("Jane Doe")
).toDF("name")
df.write.format("org.neo4j.spark.DataSource")
.mode(SaveMode.ErrorIfExists)
.option("url", "bolt://localhost:7687")
.option("authentication.basic.username", "neo4j")
.option("authentication.basic.password", "neo4j")
.option("labels", ":Person")
.save()
It raises errors. what should I do?
Update no. 2
I follow the steps in the 3 and it gives error when entering this:
val neo = Neo4j(sc)
as follow:
error: not found: value Neo4j
Use:
$SPARK_HOME\bin\spark-shell --conf spark.neo4j.password=<password> --packages neo4j-contrib:neo4j-spark-connector:2.4.5-M2
instead of:
$SPARK_HOME\bin\spark-shell --conf spark.neo4j.bolt.password=<password> --packages neo4j-contrib:neo4j-spark-connector:2.4.5-M2
Just remove the bolt word.
Update'
Now I want to use the following package:
$SPARK_HOME/bin/spark-shell --packages neo4j-contrib:neo4j-connector-apache-spark_2.12:4.0.1_for_spark_3
As mentioned in 1
The only one that works is the following (the old version):
$SPARK_HOME/bin/spark-shell --packages neo4j-contrib:neo4j-spark-connector:2.4.5-M2
But using it, the Neo4jGraph.saveGraph is not working. The error is : Writing in read access mode not allowed.
Thanks for your help.
Related
After looking at the other answers i still cant figure it out.
I am able to use kafkaProducer and kafkaConsumer to send and receive a messages from within my notebook.
producer = KafkaProducer(bootstrap_servers=['127.0.0.1:9092'],value_serializer=lambda m: json.dumps(m).encode('ascii'))
consumer = KafkaConsumer('hr',bootstrap_servers=['127.0.0.1:9092'],group_id='abc' )
I've tried to connect to the stream with both spark context and spark session.
from pyspark.streaming.kafka import KafkaUtils
sc = SparkContext("local[*]", "stream")
ssc = StreamingContext(sc, 1)
Which gives me this error
Spark Streaming's Kafka libraries not found in class path. Try one
of the following.
1. Include the Kafka library and its dependencies with in the
spark-submit command as
$ bin/spark-submit --packages org.apache.spark:spark-streaming-
kafka-0-8:2.3.2 ...
It seems that i needed to add the JAR to my
!/usr/local/bin/spark-submit --master local[*] /usr/local/Cellar/apache-spark/2.3.0/libexec/jars/spark-streaming-kafka-0-8-assembly_2.11-2.3.2.jar pyspark-shell
which returns
Error: No main class set in JAR; please specify one with --class
Run with --help for usage help or --verbose for debug output
What class do i put in?
How do i get Pyspark to connect to the consumer?
The command you have is trying to run spark-streaming-kafka-0-8-assembly_2.11-2.3.2.jar, and trying to find pyspark-shell as a Java class inside of that.
As the first error says, you missed a --packages after spark-submit, which means you would do
spark-submit --packages ... someApp.jar com.example.YourClass
If you are just locally in Jupyter, you may want to try Kafka-Python, for example, rather than PySpark... Less overhead, and no Java dependencies.
I set up a spark-yarn cluster environment, and try spark-SQL with spark-shell:
spark-shell --master yarn --deploy-mode client --conf spark.yarn.archive=hdfs://hadoop_273_namenode_ip:namenode_port/spark-archive.zip
One thing to mention is the Spark is in Windows 7. After spark-shell starts up successfully, I execute the commands as below:
scala> val sqlContext = new org.apache.spark.sql.SQLContext(sc)
scala> val df_mysql_address = sqlContext.read.format("jdbc").option("url", "jdbc:mysql://mysql_db_ip/db").option("driver", "com.mysql.jdbc.Driver").option("dbtable", "ADDRESS").option("user", "root").option("password", "root").load()
scala> df_mysql_address.show
scala> df_mysql_address.write.format("parquet").saveAsTable("address_local")
"show" command returns result-set correctly, but the "saveAsTable" ends in failure. The error message says:
java.io.IOException: Mkdirs failed to create file:/C:/jshen.workspace/programs/spark-2.2.0-bin-hadoop2.7/spark-warehouse/address_local/_temporary/0/_temporary/attempt_20171018104423_0001_m_000000_0 (exists=false, cwd=file:/tmp/hadoop/nm-local-dir/usercache/hduser/appcache/application_1508319604173_0005/container_1508319604173_0005_01_000003)
I expect and guess the table is to be saved in the hadoop cluster, but you can see that the dir (C:/jshen.workspace/programs/spark-2.2.0-bin-hadoop2.7/spark-warehouse) is the folder in my Windows 7, not in hdfs, not even in the hadoop ubuntu machine.
How could I do? Please advise, thanks.
The way to get rid of the problem is to provide "path" option prior to "save" operation as shown below:
scala> df_mysql_address.write.option("path", "/spark-warehouse").format("parquet").saveAsTable("address_local")
Thanks #philantrovert.
I'd like to run a Spark application using Structured Streaming with PySpark.
I use Spark 2.2 with Kafka 0.10 version.
I fail with the following error:
java.lang.IncompatibleClassChangeError: Implementing class
spark-submit command used as below:
/bin/spark-submit \
--packages org.apache.spark:spark-streaming-kafka-0-10_2.11:2.2.0 \
--master local[*] \
/home/umar/structured_streaming.py localhost:2181 fortesting
structured_streaming.py code:
from pyspark.sql import SparkSession
spark = SparkSession.builder.appName("StructuredStreaming").config("spark.driver.memory", "2g").config("spark.executor.memory", "2g").getOrCreate()
raw_DF = spark.readStream.format("kafka").option("kafka.bootstrap.servers", "localhost:2181").option("subscribe", "fortesting").load()
values = raw_DF.selectExpr("CAST(value AS STRING)").as[String]
values.writeStream.trigger(ProcessingTime("5 seconds")).outputMode("append").format("console").start().awaitTermination()
You need spark-sql-kafka for structured streaming:
--packages org.apache.spark:spark-sql-kafka-0-10_2.11:2.2.0
Also make sure that you use the same versions of Scala (2.11 above) and Spark (2.2.0) as you use on your cluster.
Please reference This
You're using spark-streaming-kafka-0-10 which currently not support python.
I have the following as the command line to start a spark streaming job.
spark-submit --class com.biz.test \
--packages \
org.apache.spark:spark-streaming-kafka_2.10:1.3.0 \
org.apache.hbase:hbase-common:1.0.0 \
org.apache.hbase:hbase-client:1.0.0 \
org.apache.hbase:hbase-server:1.0.0 \
org.json4s:json4s-jackson:3.2.11 \
./test-spark_2.10-1.0.8.jar \
>spark_log 2>&1 &
The job fails to start with the following error:
Exception in thread "main" java.lang.IllegalArgumentException: Given path is malformed: org.apache.hbase:hbase-common:1.0.0
at org.apache.spark.util.Utils$.resolveURI(Utils.scala:1665)
at org.apache.spark.deploy.SparkSubmitArguments.parse$1(SparkSubmitArguments.scala:432)
at org.apache.spark.deploy.SparkSubmitArguments.parseOpts(SparkSubmitArguments.scala:288)
at org.apache.spark.deploy.SparkSubmitArguments.<init>(SparkSubmitArguments.scala:87)
at org.apache.spark.deploy.SparkSubmit$.main(SparkSubmit.scala:105)
at org.apache.spark.deploy.SparkSubmit.main(SparkSubmit.scala)
I've tried removing the formatting and returning to a single line, but that doesn't resolve the issue. I've also tried a bunch of variations: different versions, added _2.10 to the end of the artifactId, etc.
According to the docs (spark-submit --help):
The format for the coordinates should be groupId:artifactId:version.
So what I have should be valid and should reference this package.
If it helps, I'm running Cloudera 5.4.4.
What am I doing wrong? How can I reference the hbase packages correctly?
A list of packages should be separated using commas without whitespaces (breaking lines should work just fine) for example
--packages org.apache.spark:spark-streaming-kafka_2.10:1.3.0,\
org.apache.hbase:hbase-common:1.0.0
I found it worthy to use SparkSession in spark version 3.0.0 for mysql and postgres
from pyspark.sql import SparkSession
spark = SparkSession.builder.appName('mysql-postgres').config('spark.jars.packages', 'mysql:mysql-connector-java:8.0.20,org.postgresql:postgresql:42.2.16').getOrCreate()
#Mohammad thanks for this input. This worked for me too. I had to load the Kafka and msql packages in a single sparksession. I did something like this:
spark = (SparkSession .builder ... .appName('myapp') # Add kafka and msql package .config("spark.jars.packages", "org.apache.spark:spark-sql-kafka-0-10_2.12:3.1.2,mysql:mysql-connector-java:8.0.26") .getOrCreate())
I have Spark running on a Cloudera CDH5.3 cluster, using YARN as the resource manager. I am developing Spark apps in Python (PySpark).
I can submit jobs and they run succesfully, however they never seem to run on more than one machine (the local machine I submit from).
I have tried a variety of options, like setting --deploy-mode to cluster and --master to yarn-client and yarn-cluster, yet it never seems to run on more than one server.
I can get it to run on more than one core by passing something like --master local[8], but that obviously doesn't distribute the processing over multiple nodes.
I have a very simply Python script processing data from HDFS like so:
import simplejson as json
from pyspark import SparkContext
sc = SparkContext("", "Joe Counter")
rrd = sc.textFile("hdfs:///tmp/twitter/json/data/")
data = rrd.map(lambda line: json.loads(line))
joes = data.filter(lambda tweet: "Joe" in tweet.get("text",""))
print joes.count()
And I am running a submit command like:
spark-submit atest.py --deploy-mode client --master yarn-client
What can I do to ensure the job runs in parallel across the cluster?
Can you swap the arguments for the command?
spark-submit --deploy-mode client --master yarn-client atest.py
If you see the help text for the command:
spark-submit
Usage: spark-submit [options] <app jar | python file>
I believe #MrChristine is correct -- the option flags you specify are being passed to your python script, not to spark-submit. In addition, you'll want to specify --executor-cores and --num-executors since by default it will run on a single core and use two executors.
Its not true that python script doesn't run in cluster mode. I am not sure about previous versions but this is executing in spark 2.2 version on Hortonworks cluster.
Command : spark-submit --master yarn --num-executors 10 --executor-cores 1 --driver-memory 5g /pyspark-example.py
Python Code :
from pyspark import SparkConf, SparkContext
from pyspark.sql import SQLContext
conf = (SparkConf()
.setMaster("yarn")
.setAppName("retrieve data"))
sc = SparkContext(conf = conf)
sqlContext = SQLContext(sc)
parquetFile = sqlContext.read.parquet("/<hdfs-path>/*.parquet")
parquetFile.createOrReplaceTempView("temp")
df1 = sqlContext.sql("select * from temp limit 5")
df1.show()
df1.write.save('/<hdfs-path>/test.csv', format='csv', mode='append')
sc.stop()
Output : Its big so i am not pasting. But it runs perfect.
It seems that PySpark does not run in distributed mode using Spark/YARN - you need to use stand-alone Spark with a Spark Master server. In that case, my PySpark script ran very well across the cluster with a Python process per core/node.