im working on small project and i need to display date from api , api uses millisecounds and i cant really find a way to get date without time.
So far i didnt find anything usefull on internet.
Code i was using for this is:
ts= millisecounds im using
date = datetime.datetime.fromtimestamp(ts / 1000, tz=datetime.timezone.utc)
print(date)
But it prints something like 2010-10-10 10:10:10.100000+00:00
only thing i want from this is first part (2010-10-10)
how can i get date?
1. Naive Solution:
If you just want the date, you can try using the split method:
Code:
year_month_day = date.split(" ")[0]
print(year_month_day)
Output:
2010-10-10
2. Using strftime():
# using strftime
ts = 1588234567899 # Unix time in milliseconds
ts /= 1000 # Convert millisecondsto seconds
datetime_object = datetime.utcfromtimestamp(ts) # Create datetime object
date = datetime_object.strftime('%Y-%m-%d') # Strip just the date part out
print(date)
Output:
2020-04-30
Related
How do I Convert "1561994754" number to "2019-07-01T15:25:54.000000"
I have used :
import datetime
datetime.datetime.fromtimestamp(x['date'] / 1000.0).strftime('%Y-%m-%d %H:%M:%S.%f')
But I am getting 1970-01-18 19:53:14.754000, can you please guide me to correct function?
Thanks,
Aditya
Removing the / 1000 gives me '2019-07-01 08:25:54.000000', It seems like there was a unit mismatch in your expression. To exactly match the format you're asking for, datetime.datetime.fromtimestamp(x['date'], tz=datetime.timezone.utc).strftime('%Y-%m-%dT%H:%M:%S.%f') produces '2019-07-01T15:25:54.000000 (leaving the timezone argument blank defaults to using local time, but the human-readable date in your question uses UTC)
You can try like this!
String myString = String.valueOf(1561994754);
DateFormat format = new SimpleDateFormat("yyyy-MM-ddTHH:mm:ssZ");
Date date = format.parse(myString);
I have a code which I have it's performance timestamped, and I want to measure the average of time it took to run it on multiple computers, but I just cant figure out how to use the datetime module in python.
Here is how my procedure looks:
1) I have the code which simply writes into a text file the log, where the timestamp looks like
t1=datetime.datetime.now()
...
t2=datetime.datetime.now()
stamp= t2-t1
And that stamp variable is just written in say log.txt so in the log file it looks like 0:07:23.160896 so it seems like it's %H:%M:%S.%f format.
2) Then I run a second python script which reads in the log.txt file and it reads the 0:07:23.160896 value as a string.
The problem is I don't know how to work with this value because if I import it as a datetime it will also append and imaginary year and month and day to it, which I don't want, I simply just want to work with hours and minutes and seconds and microseconds to add them up or do an average.
For example I can just open it in Libreoffice and add the 0:07:23.160896 to 0:00:48.065130 which will give 0:08:11.226026 and then just divide by 2 which will give 0:04:05.613013, and I just can't possibly do that in python or I dont know how to do it.
I have tried everything, but neither datetime.datetime, nor datetime.timedelta allows simply multiplication and division like that. If I just do a y=datetime.datetime.strptime('0:07:23.160896','%H:%M:%S.%f') it will just give out 1900-01-01 00:07:23.160896 and I can't just take a y*2 like that, it doesnt allow arithmetic operations, plus if if I convert it into a timedelta it will also multiply the year,which is ridiculous. I simply just want to add and subtract and multiply time.
Please help me find a way to do this, and not just for 2 variables but possibly even a way to calculate the average of an entire list of timestamps like average(['0:07:23.160896' , '0:00:48.065130', '0:00:14.517086',...]) way.
I simply just want a way to calculate the average of many timestamps and give out it's average in the same format, just as you can just select a column in Libreoffice and take the AVERAGE() function which will give out the average timestamp in that column.
As you have done, you first read the string into a datetime-object using strptime: t = datetime.datetime.strptime(single_time,'%H:%M:%S.%f')
After that, convert the time part of your datestring into a timedelta, so you can easily calculate with times: tdelta = datetime.timedelta(hours=t.hour, minutes=t.minute, seconds=t.second, microseconds=t.microsecond)
Now you can easily calculate with the timedelta object, and convert at the end of the calculations back into a string by str(tdsum)
import datetime
times = ['0:07:23.160896', '0:00:48.065130', '0:12:22.324251']
# convert times in iso-format into timedelta list
tsum = datetime.timedelta()
count = 0
for single_time in times:
t = datetime.datetime.strptime(single_time,'%H:%M:%S.%f')
tdelta = datetime.timedelta(hours=t.hour, minutes=t.minute, seconds=t.second, microseconds=t.microsecond)
tsum = tsum + tdelta
count = count + 1
taverage = tsum / count
average_time = str(taverage)
print(average_time)
Hi I have a date format that i am getting from my Jira Sprint Environment 2019-03-29T06:56:00.000-04:00
I am using groovy Script.
I have tried to use multiple format to make similar format like the above .
But Unable to do it.
Here are the below solution i have tried.
1 --
`def sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'")
sdf.setTimeZone(TimeZone.getTimeZone("GMT"))
log.debug("Printing Current time stamp date : "+sdf)
solution 1 is printing text only.
2 --
def now = new Date()
println now.format("yyyy-MM-dd'T'HH:mm:ss'Z'",TimeZone.getTimeZone('UTC'))
this one is printing
Printing Current time stamp date : Thu Sep 26 08:00:35 EDT 2019"
Can anyone help me on this?
So, the goal is to have date in format
2019-03-29T06:56:00.000-04:00
the following code does the formatting with timezone GMT-4
def now=new Date().format("yyyy-MM-dd'T'HH:mm:ss.SSSXXX",TimeZone.getTimeZone('GMT-4'))
println now
prints
2019-09-26T16:33:18.462-04:00
note that the variable now will contain String with formatted date
Check for all available date & time patterns:
https://docs.oracle.com/javase/8/docs/api/java/text/SimpleDateFormat.html
Given that you’ve got a Java 8 or newer underneath, all you need is
OffsetDateTime.now(ZoneId.systemDefault()).toString()
In my time zone (Europe/Copenhagen) I just got
2019-09-27T21:46:53.336204+02:00
If your default time zone is America/Montreal or America/New_York, you will get the time at offset -04:00 as long as summer time (Daylight Saving Time) is in effect, then -05:00.
And you can easily parse.
OffsetDateTime.parse( "2019-09-27T21:46:53.336204+02:00" )
See this code running at IdeOne.com.
def currentDate = new Date()
def date = currentDate.format('yyyy-MM-dd')
def time = currentDate.format('HH:mm:ss.SSS')
def dateTime = date.toString() + 'T' + time.toString() + 'Z'
i have this problem with milliseconds or microseconds data from api im not totally sure. I am trying to convert this to a readable date time. below is an example. The web app has a dashboard which you i can check the date time. but i do not know exactly how to convert it to a readable date time.
Example 1:
FROM API
"start":1542243678,
FROM Dashboard
11/15/2018 9:01 am
Example 2:
FROM API
"end":1542330078,
FROM Dashboard
11/16/2018 9:01 am
When i try to convert to python date time it gives me wrong info.
import datetime
import time
milliseconds = 1542243678
date = datetime.datetime.fromtimestamp(milliseconds/1000.0)
date = date.strftime('%Y-%m-%d %H:%M:%S')
print(date)
Output:
1970-01-19 04:24:03
Sorry if I don't understand your question correctly, but is this what you want?
import datetime
import time
milliseconds = 1542243678
date = datetime.datetime.fromtimestamp(milliseconds)
date = date.strftime('%m/%d/%Y %I:%M %p')
print(date)
Output: 11/14/2018 05:01 PM
You don't need to divide by 1000 before passing to datetime.datetime.fromtimestamp.
Try datetime.datetime.fromtimestamp(1542243678). It should work.
Thats a code a friend of mine helped me with in order to get files from diferent measurement systems, timestamps and layout into on .csv file.
You enter the timeperiod or like in the case below 1 day and the code looks for this timestamps in different files and folders, adjusts timestamps (different Timezone etc.) and puts everything into one .csv file easy to plot. Now I need to rewrite that stuff for different layouts. I managed to get everything working but now I don't want to enter every single day manually into the code :-( , cause I'd need to enter it 3 times in a row --> in order to get the day for one day into one file, dateFrom and dateTo needs to be the same and in the writecsv...section you'd have to enter the date again.
here's the code:
from importer import cloudIndices, weatherall, writecsv,averagesolar
from datetime import datetime
from datetime import timedelta
dateFrom = datetime.strptime("2010-06-21", '%Y-%m-%d')
dateTo = datetime.strptime("2010-06-21", '%Y-%m-%d')
....
code
code
....
writecsv.writefile("data_20100621", header, ciData)
what can I change here so that I get an automatic loop for all data between e.g 2010-06-21 to 2011-06-21
p.s. if i'd entered 2010-06-21in dataFromand 2011-06-21 in dateTo i'd get a huge cvs. file with all the data in it ..... I thought that would be a great idea but it's not really good for plotting so I enden up manually entering day after day which isn't bad if you do it on a regular basis for 2 or 3 days but now a dates showed up and I need to rund the code over it :-(
Generally speaking you should be using datetime.datetime and datetime.timedelta, here is an example of how:
from datetime import datetime
from datetime import timedelta
# advance 5 days at a time
delta = timedelta(days=5)
start = datetime(year=1970, month=1, day=1)
end = datetime(year=1970, month=2, day=13)
print("Starting from: %s" % str(start))
while start < end:
print("advanced to: %s" % str(start))
start += delta
print("Finished at: %s" % str(start))
This little snippet creates a start and end time and a delta to advance using the tools python provides. You can modify it to fit your needs or apply it in your logic.