I have some files in my directory named as:
...
asdfab-18-121.csv
asdfab-19-221.csv
gafaac-19-289.csv
asdfax-19-311.csv
aasdfb-20-122.csv
aasdfb-20-220.csv
aberrc-20-281.csv
aasdfb-21-127.csv
aasdfb-21-224.csv
acadff-21-286.csv
...
I need to list the files that have "-19-" OR "-20-" in the middle part of their name (e.g. lines 2-7 above), at the same time. I know if only one character was variable I could use [seq] syntax. I tried
ls *#["-19-"|"-20-"]*
but it doesn't seem to work. Any ideas?
If using bash with the extglob option turned on, or ksh93, or zsh with the KSH_GLOB option turned on:
ls *-#(19|20)-*.csv
Related
Write a wildcard to match all files (does not matter the files are in which directory, just ask for the wildcard) named in the following rule: starts with a string “image”, immediately followed by a one-digit number (in the range of 0-9), then a non-digit char plus anything else, and ends with either “.jpg” or “.png”. For example, image7.jpg and image0abc.png should be matched by your wildcard while image2.txt or image11.png should not.
My folder contained these files imag2gh.jpeg image11.png image1agb.jpg image1.png image2gh.jpg image2.txt image5.png image70.jpg image7bn.jpg Screenshot .png
If my command work it should only display image1agb.jpg image1.png image2gh.jpg image5.png image70.jpg image7bn.jpg
This is the command I used (ls -ad image[0-9][^0-9]*{.jpg,.png}) but I'm only getting this image1agb.jpg image2gh.jpg image7bn.jpg so I'm missing (image1.png image5.png)Kali Terminal and what I did
ls -ad image[0-9][!0-9]*{.jpg,.png}
Info
Character ranges like [0-9] are usually seen in RegEx statements and such. They won't work as shell globs (wildcards) like that.
Possible solution
Pipe output of command ls -a1
to standard input of the grep command (which does support RegEx).
Use a RegEx statement to make grep filter filenames.
ls -a1|grep "image"'[[:digit:]]\+[[:alpha:]]*\.\(png\|jpg\)'
I've created an (makefiles oriented) include file which contains some variables defined to be used on by others makefiles.
# this is myinclude/makevars file
MY_FOLDER:=$(ROOT_FOLDER)/my/folder
ANOTHER_FOLDER:=$(MY_FOLDER)/another/folder
MY_LIB:=$(ANOTHER_FOLDER)/lib
this "include file" works just great if I include it in other makefiles:
include myinclude/makevars
but would be cool if I might include it in some shell script too!.
Currently I've created another file (myinclude/shellvars) very similar but "shell" oriented:
# this is myinclude/shellvars file
MY_FOLDER=$ROOT_FOLDER/my/folder
ANOTHER_FOLDER=$MY_FOLDER/another/folder
MY_LIB=$ANOTHER_FOLDER/lib
clearly by including this in my (shell) scripts anything works but I have a duplicated file with (semantically) the same info!
any idea to have this two files "merged" into one (myinclude/makevars and myinclude/shellvars) ? any special syntax?
any help is clearly appreciated!
-- kasper!
Try this:
eval "$(cat makevars.inc | tr -d '(:)')"
echo "$MY_LIB"
This loads the text of the target include file into memory, erases all colons and parentheses from it and then executes the result.
I have separated some tracks from mp3 mixes using mp3splt.
BASH: (mp3splt -c('**!!***use .cue file***!!**') [cuefile.cue] [nonstopmix.mp3] ~for anyone interested, is in the Ubu repos~)
And I ended up with these filenames: "Antares" - 01 - "Xibalba".mp3 which is not a format I prefer, now I've made it a little project to change them with a shell script but its more difficult than I anticipated.
I want to change the filename from:
"Antares" - 01 - "Xibalba".mp
to:
01-Antares_-_Xibalba.mp3
so far I've used :
for var in *.mp3; do mv $var {var/"/}; done
and I could repeat that until I'm through, delete the 0x number and add one but I'd like to do it more efficient.
Could anyone give me a pointer (!not a script!) ?
I'd still like to write it myself but there's so much options that I'm a bit lost.
so far I thought to use this program flow:
read all the filenames containing .mp3 and declare as variable $var
strip $var from quotes
select 0x number, append delimiter _ (0x_)
move 0x_ to the beginning of the string
select remaining ' - - ' and change to '-'
done
which bash programs to use? especially changing the 0x puzzles me cuz I need a loop which increments this number and test if it is present in the filename variable and then it has to be changed.
It is easy to do in python 2.x. You can use this logic in any language you want.
import string
a=raw_input('Enter the name of song')
a=a.replace('"', "")
a=a.replace('.mp', ' .mp3')
words = a.split()
print words[2]+'-'+words[0]+'_-_'+words[4]+words[5]
Logic:
I removed ", then make .mp to .mp3, then splitted the string, which created a list ( array ) and then printed the elements according to need.
Try doing this :
rename -n 's/"(\w+)"\s+-\s*(\d+)\s*-\s*"(\w+)"\.mp/$2-$1_-_$3.mp3/' *mp
from the shell prompt. It's very useful, you can put some perl tricks like I does in a substitution.
You can remove the -n (dry-run mode switch) when your tests become valids.
There are other tools with the same name which may or may not be able to do this, so be careful.
If you run the following command (linux)
$ file $(readlink -f $(type -p rename))
and you have a result like
.../rename: Perl script, ASCII text executable
then this seems to be the right tool =)
If not, to make it the default (usually already the case) on Debian and derivative like Ubuntu :
$ sudo update-alternatives --set rename /path/to/rename
Last but not least, this tool was originally written by Larry Wall, the Perl's dad.
I am writing a bash script that will output a .tgz file to a specific directory, /tmp/ by default
I would like to provide an option to override this directory and I have chosen to do so using arguments provided at the command line
while getopts d: option
do
case "${option}" in
d) dir=${OPTARG};;
esac
done
As written, this works but I've run into a snag depending on user input
The name of my .tgz file is also a variable and my code that brings this all together is
output="$dir""$name"
The problem that I run into is if the user runs
./script -d /home/user
My resulting path and filename end up as
/home/userfilename.tgz
I need to either enforce a requirement for a trailing / or insert one if the user did not.
While it works, if I change my output variable to
output="$dir"/"$name"
If the user does provide a trailing / I end up with something like this and I am trying to keep my output aesthetic.
/home/user//filename.tgz
Any input would be greatly appreciated.
Add the line
output="${output//\/\///}"
after joining dir and name.
It looks complicated, but what it does is it replaces two slashes with one.
You may find more info in here.
I am experimenting with wildcards in bash and tried to list all the files that start with "xyz" but does not end with ".TXT" but getting incorrect results.
Here is the command that I tried:
$ ls -l xyz*[!\.TXT]
It is not listing the files with names "xyz" and "xyzTXT" that I have in my directory. However, it lists "xyz1", "xyz123".
It seems like adding [!\.TXT] after "xyz*" made the shell look for something that start with "xyz" and has at least one character after it.
Any ideas why it is happening and how to correct this command? I know it can be achieved using other commands but I am especially interested in knowing why it is failing and if it can done just using wildcards.
These commands will do what you want
shopt -s extglob
ls -l xyz!(*.TXT)
shopt -u extglob
The reason why your command doesn't work is beacause xyz*[!\.TXT] which is equivalent to xyz*[!\.TX] means xyz followed by any sequence of character (*) and finally a character in set {!,\,.,T,X} so matches 'xyzwhateveryouwant!' 'xyzwhateveryouwant\' 'xyzwhateveryouwant.' 'xyzwhateveryouwantT' 'xyzwhateveryouwantX'
EDIT: where whateveryouwant does not contain any of !\.TX
I don't think this is doable with only wildcards.
Your command isn't working because it means:
Match everything that has xyz followed by whatever you want and it must not end with sequent character: \, .,T and X. The second T doesn't count as far as what you have inside [] is read as a family of character and not as a string as you thought.
You don't either need to 'escape' . as long as it has no special meaning inside a wildcard.
At least, this is my knowledge of wildcards.