Continue After Exception - Python - python-3.x

Question

I am trying to have try and except block in my code to catch an error, then put it to sleep for 5 seconds and then I want to continue where it left off. Following is my code and currently as soon as it catches exception, it does not continue and stops after exception.
from botocore.exceptions import ClientError
tries = 0
try:
for pag_num, page in enumerate(one_submitted_jobs):
if 'NextToken' in page:
print("Token:",pag_num)
else:
print("No Token in page:", pag_num)
except ClientError as exception_obj:
if exception_obj.response['Error']['Code'] == 'ThrottlingException':
print("Throttling Exception Occured.")
print("Retrying.....")
print("Attempt No.: " + str(tries))
time.sleep(5)
tries +=1
else:
raise
How can I make it to continue after exception? Any help would be great.
Note - I am trying to catch AWS's ThrottlingException error in my code.
Following code is for demonstration to #Selcuk to show what I have currently from his answer. Following will be deleted as soon as we agree if I am doing it correct or not.
tries = 1
pag_num = 0
# Only needed if one_submitted_jobs is not an iterator:
one_submitted_jobs = iter(one_submitted_jobs)
while True:
try:
page = next(one_submitted_jobs)
# do things
if 'NextToken' in page:
print("Token: ", pag_num)
else:
print("No Token in page:", pag_num)
pag_num += 1
except StopIteration:
break
except ClientError as exception_obj:
# Sleep if we are being throttled
if exception_obj.response['Error']['Code'] == 'ThrottlingException':
print("Throttling Exception Occured.")
print("Retrying.....")
print("Attempt No.: " + str(tries))
time.sleep(3)
tries +=1

Answer 1

You are not able to keep running because the exception occurs in your for line. This is a bit tricky because in this case the for statement has no way of knowing if there are more items to process or not.
A workaround could be to use a while loop instead:
pag_num = 0
# Only needed if one_submitted_jobs is not an iterator:
one_submitted_jobs = iter(one_submitted_jobs)
while True:
try:
page = next(one_submitted_jobs)
# do things
pag_num += 1
except StopIteration:
break
except ClientError as exception_obj:
# Sleep if we are being throttled