I want to calculate the likelihoods instead of log-likelihoods. I know that score gives per sample average log-likelihood and for that I need to multiply score with sample size but the log likelihoods are very large negative numbers such as -38567258.1157 and when I take np.exp(scores) , I get a zero. Any help is appreciated.
gmm=GaussianMixture(covariance_type="diag",n_components=2)
y_pred=gmm.fit_predict(X_test)
scores=gmm.score(X_test)
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im try to study confusion matrix. i know about 2x2 confusion matrix but i still don't understand how to count 5x5 confusion matrix for finding accuracy, precision, recall and, f1 - score. Can anyone help me with this ? i appreciate every help.
See my answer here: Calculating Equal error rate(EER) for a multi class classification problem
In short, one strategy is to split the multiclass problem into a set of binary classification, for each class a "one vs. all others" classification. Then for each binary problem you can calculate F1, precision and recall, and if you want you can average (uniformly or weighted) the scores of each class to get one F1 score which will represent the multiclass problem.
As for confusion matrix larger than 2x2: the rows are the true labels and the columns are predicated labels. Then the number in cell (i,j) is the number of samples from class i which were classified as class j (note that i=j corresponds to correct prediction). The accuracy is the trace of the confusion matrix divided by the number of samples.
i did get to know confidence ellipses during university (but that has been some semesters ago).
In my current project, I'd like to calculate a 3 dimensional confidence ellipse/ellipsoid in which I can set the probability of success to e.g. 90%. The center of the data is shifted from zero.
At the moment i am calculating the variance-covariance matrix of the dataset and from it its eigenvalues and eigenvectors which i then represent as an ellipsoid.
here, however, I am missing the information on the probability of success, which I cannot specify.
What is the correct way to calculate a confidence ellipsoid with e.g. 90% probability of success ?
I am trying to implement VGGNet-16 for depth map prediction from single image. In the training the RMSE loss comes out to be 0.1599.
That loss value, is it in percentage or not?
No, if you want a percentage of a correctly classified data you can look at a value of accuracy.
Definition of RMSE from Wikipedia:
The root-mean-square deviation (RMSD) or root-mean-square error (RMSE) is a frequently used measure of the differences between values (sample and population values) predicted by a model or an estimator and the values actually observed.
It's always non-negative, and values closer to zero are better.
I have constructed a GMM-UBM model for the speaker recognition purpose. The output of models adapted for each speaker some scores calculated by log likelihood ratio. Now I want to convert these likelihood scores to equivalent number between 0 and 100. Can anybody guide me please?
There is no straightforward formula. You can do simple things like
prob = exp(logratio_score)
but those might not reflect the true distribution of your data. The computed probability percentage of your samples will not be uniformly distributed.
Ideally you need to take a large dataset and collect statistics on what acceptance/rejection rate do you have for what score. Then once you build a histogram you can normalize the score difference by that spectrogram to make sure that 30% of your subjects are accepted if you see the certain score difference. That normalization will allow you to create uniformly distributed probability percentages. See for example How to calculate the confidence intervals for likelihood ratios from a 2x2 table in the presence of cells with zeroes
This problem is rarely solved in speaker identification systems because confidence intervals is not what you want actually want to display. You need a simple accept/reject decision and for that you need to know the amount of false rejects and accept rate. So it is enough to find just a threshold, not build the whole distribution.
I have several weighted values for which I am taking a weighted average. I want to calculate a weighted standard deviation using the weighted values and weighted average. How would I modify the typical standard deviation to include weights on each measurement?
This is the standard deviation formula I am using.
When I simply use each weighted value for 'x' and the weighted average for '\bar{x}', the result seems smaller than it should be.
I just found this wikipedia page discussing data of equal significance vs weighted data. The correct way to calculate the biased weighted estimator of variance is
,
though the following, on-the-fly implementation, is more efficient computationally as it does not require calculating the weighted average before looping over the sum on the weighted differences squared
.
Despite my skepticism, I tried both and got the exact same results.
Note, be sure to use the weighted average
.