I am trying to tar a file and get it's output store in a variable.
I tried this but it is not working:
resulting_tar=$(tar -zcf "$(date '+%Y-%m-%d').tar.gz" folder)
Any idea how do I go about it?
By default, tar does not report the name of the file created. In fact, it doesn't say anything unless you tell it to, and the options given don't tell it to say anything.
Note that tar doesn't tell you what file it created. You tell tar what file to create.
You'll need to capture the name of the file in a variable and report it yourself:
file="$(date '+%Y-%m-%d').tar.gz"
tar -czf "$file" folder
echo "$file"
Try running tar -czf /dev/null folder; you won't see anything from (most implementations of) tar — and that's not because I specified /dev/null. Specify a name if you prefer: tar -czf junk.tar.gz folder and watch the (lack of) output — and remember to remove junk.tar.gz.
You might want to think about including the folder name in the tar file name, too.
folder="…whatever…"
file="$folder-$(date +'%Y-%m-%d').tar.gz"
tar -czf "$file" "$folder"
echo "$file"
EDIT: No longer applicable after further clarification. Leaving for posterity.
You're likely looking for both stdout and stderr. You can combine the two output streams by appending 2>&1 to your command:
resulting_tar=$(tar -zcf "$(date '+%Y-%m-%d').tar.gz" folder 2>&1)
Related
The problem is like this :
I need to extract the logs from a tar archive using user input/argument for the file name (cubelog_457890.tar)
In the archive there is just one folder named tftpboot that I need to rename to the original user input.
After that I need to open and view the log files.
#!/bin/bash
fname=$1
if [ -f $fname ]; then
tar -xvzf $fname
fi
mv tftpboot $fname
If I try to use the script with the argument cubelog_457890.tar I have the problem that the MV line will not work.
Starting the script again and using cubelog_457890 will do the job.
How can I make the MV command take cubelog_457890 from user input without the tar extension?
./extract.sh cubelog_457890.tar - will extract but not rename
./extract.sh cubelog_457890 - will rename the folder
try this:
#!/bin/bash
fname=$1
if [[ -f "${fname}.tar" ]]; then
tar -xvf "${fname}.tar"
fi
mv tftpboot $fname
then ./extract.sh cubelog_457890
#!/bin/bash
source="/home/user/work/tar/deneme"
source2="/home/user/work/tar/deneme1"
for i in {1..5}
do
tar -czvf $source2/$i/$i.tar.gz $source/$i/
done
I get this error message.
tar: Removing leading/' from member names`
this is my script and error. there are a lot of questions here but my problem doesn't solve. I run script than script create .tar.gz file. But if I unzip with tar -xzvf 1.tar.gzthis command, my file created in full path like home/user/work/tar/deneme/1/1-1.txt.
Do you have any idea?
I try some of ways.
For examle
Find /SED to convert absolute path to relative path within a single line tar statement for crontab
https://unix.stackexchange.com/questions/59243/tar-removing-leading-from-member-names/59244
This is because GNU tar remove leading / (by default). To avoid it you can rewrite your script on this way:
#!/bin/bash
cd /home/user/work/tar
source="deneme"
source2="deneme1"
for i in {1..5}
do
mkdir -p ${source2}/${i}
tar -czvf ${source2}/${i}/${i}.tar.gz ${source}/${i}/
done
Thank you for all your comments and answer.
I find the solution. I change some of codes. which is inside for loop
mkdir $source2/$i
cd $source/
tar -czvf $source2/$i/$i.tar.gz $i/*
I know it is the basic question but please do help me .I compressed and archived my server log file using tar command
for i in server.log.2016-07-05 server.log.2016-07-06 ; do tar -zcvf server2.tar.gz $i; done
The output of the above loop is:
server.log.2016-07-05
server.log.2016-07-06
But while listing the file using tar -tvf server2.tar.gz the output obtained is:
rw-r--r-- root/root 663643914 2016-07-06 23:59 server.log.2016-07-06
i.e., I archived two files but only one file was displayed which means archive doesnt have both files right?? Please help on this.
I just tested with these two files but my folder has multiple files. Since I didn't get expected output I was not proceeded with all the files in my folder. The exact loop I am going to use is:
Previousmonth=$(date "+%b" --date '1 month ago')
for i in $(ls -l | awk '/'$Previousmonth'/ && /server.log./ {print $NF}');do;tar -zcvf server2.tar.gz $i;done
I am trying to compress and archive multiple files but while listing the files using tar -tvf it doesn't shows all the files.
You don't need a loop here. Just list all the files you want to add as command line parameter:
tar -zcvf server2.tar.gz server.log.2016-07-05 server.log.2016-07-06
The same goes for your other example too:
tar -zcvf server2.tar.gz $(ls -l | awk '/'$Previousmonth'/ && /server.log./ {print $NF}')
Except that parsing the output of ls -l is awful and strongly not recommended.
But since the filenames to backup contain the month number,
a much simpler and better solution is to get the year + month number using the date command, and then use shell globbing:
prefix=$(date +%Y-%m -d 'last month')
tar -zcvf server2.tar.gz server.log.$prefix-??
Possible Duplicate:
gzipping up a set of directories and creating a tar compressed file
This post describes how to gzip each file individually within a directory structure. However, I need to do something slightly different. I need to produce one big gzip file for all files under a certain directory. I also need to be able to specify the output filename for the compressed file (e.g., files.gz) and overwrite the old compressed file file if one already exists.
tar -zcvf compressFileName.tar.gz folderToCompress
everything in folderToCompress will go to compressFileName
Edit: After review and comments I realized that people may get confused with compressFileName without an extension. If you want you can use .tar.gz extension(as suggested) with the compressFileName
there are lots of compression methods that work recursively command line and its good to know who the end audience is.
i.e. if it is to be sent to someone running windows then zip would probably be best:
zip -r file.zip folder_to_zip
unzip filenname.zip
for other linux users or your self tar is great
tar -cvzf filename.tar.gz folder
tar -cvjf filename.tar.bz2 folder # even more compression
#change the -c to -x to above to extract
One must be careful with tar and how things are tarred up/extracted, for example if I run
cd ~
tar -cvzf passwd.tar.gz /etc/passwd
tar: Removing leading `/' from member names
/etc/passwd
pwd
/home/myusername
tar -xvzf passwd.tar.gz
this will create
/home/myusername/etc/passwd
unsure if all versions of tar do this:
Removing leading `/' from member names
#amitchhajer 's post works for GNU tar. If someone finds this post and needs it to work on a NON GNU system, they can do this:
tar cvf - folderToCompress | gzip > compressFileName
To expand the archive:
zcat compressFileName | tar xvf -
I have a script that I need to run on a large number of files with the extension **.tar.gz*.
Instead of uncompressing them and then running the script, I want to be able to uncompress them as I run the command and then work on the uncompressed folder, all with a single command.
I think a pipe is a good solution for this but i haven't used it before. How would I do this?
The -v orders tar to print filenames as it extracts each file:
tar -xzvf file.tar.gz | xargs -I {} -d\\n myscript "{}"
This way the script will contain commands to deal with a single file, passed as a parameter (thanks to xargs) to your script ($1 in the script context).
Edit: the -I {} -d\\n part will make it work with spaces in filenames.
The following three lines of bash...
for archive in *.tar.gz; do
tar zxvf "${archive}" 2>&1 | sed -e 's!x \([^/]*\)/.*!\1!' | sort -u | xargs some_script.sh
done
...will iterate over each gzipped tarball in the current directory, decompress it, grab the top-most directories of the decompressed contents and pass those as arguments to somescript.sh. This probably uses more pipes than you were expecting but seems to do what you are asking for.
N.B: tar xf can only take one file per invocation.
You can use a for loop:
for file in *.tar.gz; do tar -xf "$file"; your commands here; done
Or expanded:
for file in *.tar.gz; do
tar -xf "$file"
# your commands here
done