I was trying to make a lcm finder but i failed can some one give me and idea for it
so this was wat i was able to create
class math:
def lcm_finder(self, number1, number2):
if number1 > number2:
grater = number1
elif number1 < number2:
grater = number2
please tell me its ahead code
You can do something like this
def find_lcm(x, y):
# choose the higher number
if x > y:
greater = x
else:
greater = y
while(True):
if((greater % x == 0) and (greater % y == 0)):
lcm = greater
break
greater += 1
return lcm
num1 = 22 # You can input the numbers if u want
num2 = 56
# call the function
print("L.C.M :", find_lcm(num1, num2))
Related
The condition is simple. If sum<=20 then print sum or else loop the starting from the input. However, this is looping even if the input is valid. How should I fix this? My code is in the picture
code in the picture
You need to specify that you wish to update the global variable.
invalid_input = True
def start():
x = int(input("number1: "))
y = int(input("number2: "))
z = int(input("number3: "))
sum = x + y + z
if (sum <= 20):
global invalid_input
invalid_input = False
print(sum)
else:
print("return and give valid input")
while invalid_input:
start()
Alternatively, you could return a boolean from the function.
def start():
x = int(input("number1: "))
y = int(input("number2: "))
z = int(input("number3: "))
sum = x + y + z
if (sum <= 20):
print(sum)
return True
else:
print("return and give valid input")
while True:
if start(): break
Related post: python-function-global-variables
def get_nearest_multiple(minnum, factor):
"""
function get_nearest_multiple will calculate the nearest multiple that is greater than the min. value,
Parameters are the minimum value and factor,
Will return the ans - the nearest multiple
"""
ans = 0
x = 1
while ans < minnum:
if minnum == 0:
ans = 0
else:
ans = x * factor
x += 1
return ans
get_nearest_multiple(0, 1)
if __name__ == '__main__':
get_nearest_multiple(0, 1)
Can't seem to figure out why my function doesn't print out anything. The output doesn't even show up as an error. Just blank.
Nowhere in your code do you have a print() statement which is required to produce an output in the console
I have created the below script to find out the prime factors of a number :
def check_if_no_is_prime(n):
if n <= 3:
return True
else:
limit = int(math.sqrt(n))
for i in range(2,limit + 1):
if n % i == 0:
return False
return True
def find_prime_factors(x):
prime_factors = []
if check_if_no_is_prime(x):
prime_factors.append(1)
prime_factors.append(x)
else:
while x % 2 == 0 and x > 1:
prime_factors.append(2)
x = x // 2
for i in range(3,x+1,2):
while x % i == 0 and x > 1:
if check_if_no_is_prime(i):
prime_factors.append(i)
x = x // i
if x <= 1:
return prime_factors
return prime_factors
no = int(input())
check = find_prime_factors(no)
print (check)
I am not sure whether this is the best and efficient way to do this ?
Can someone please point out any better way to do this ?
using sieve of erathnostanes to get all prime numbers from 2 to whatever limit inputted
def sieve(N):
from math import floor,sqrt
A=[1 for x in range(N+1)]
for count in range(2):
A[count]=0
for i in range(floor(sqrt(N))+1):
if A[i]==1:
for k in range(i*i,N+1,i):
A[k]=0
ans=list(enumerate(A))
res=[]
for (i,j) in ans:
if j==1:
res+=[i]
return res
print(sieve(100))
#my code
I am doing an assignment and the answers are coming back correctly but I would need them to say 5! = 120 instead of just = 120. How would I go about that?
def getInt():
getInt = int
done = False
while not done:
print("This program calcultes N!")
# get input for "N
N = int(input("Please enter a non-negative value for N: "))
if N < 0:
print("Non-Negative integers, please!")
else:
done = True
return N
def main():
n = getInt()
for i in range(n-1):
n = n * (i+1)
print("=" ,n)
main()
I hope this code will help.
print('Enter a positive integer')
a = int(input())
def factorial(n):
if n == 0:
return(1)
if n == 1:
return(1)
if n > 1:
return(n * factorial(n-1))
if a < 0:
print('Non-Negative integers, please!')
if a >= 0:
print(str(a) + '! = ' + str(factorial(a)))
In the for i in range(n-1)you could use another integer instead of n just to be sure things don't mess up and you can print like joel said print(i,"!=", n) but instead of n the integer you will use.
can you show me your homework instructions?
i'm not sure what the first value is in your example.. the current iteration or the original number entered?
# declare getInt()
def getInt():
getInt = int
done = False
while not done:
# write "this program calculates N!"
print("This program calcultes N!")
# get input for "N
N = int(input("Please enter a non-negative value for N: "))
# if N < 0 then
if N < 0:
print("Non-Negative integers, please!")
# else
else:
# done = true
done = True
# return N
return N
# main
def main():
n = entry = getInt()
for i in range(n-1):
n = n * (i+1)
print("{0}! = {1}".format(entry, n))
main()
results:
/*
This program calcultes N!
Please enter a non-negative value for N: 5
5! = 120
*/
I am working on the following problem.
Write a program that continually prompts for positive integers and stops when the sum of numbers entered exceeds 1000.
But my code stop early if a negative integer is entered.
The numbers will not sum.
My code:
x = int(input("Enter an integer:"))
total = 0
sum = 0
while (0 <= x):
if sum <= 1000:
x += 1
sum += (int(input("Enter an integer:")))
elif sum >= 1000:
break
x = 0
total = 0
sum = 0
while sum <= 1000:
x = int(input("Enter an integer:"))
if x<0:
print("Invalid negative value given")
break
sum += x
First:
if sum >= 1000:
...
elif sum < 1000:
...
is redundant, because if you chek for sum >= 1000, and the elif is reached, you aready know, that the condition was False and therefore sum < 1000 has to be true. So you could replace it with
if sum >= 1000:
...
else:
...
Second:
You want to use x to check, whether the input is negative. Until now, you were simpy increasing it by one each time. Instead, you should first assing the input to x, and then add this to sum. So do it like this:
x = int(input("Enter an integer:"))
if x<0:
break
sum += x
In case you want to stop as soon as you encounter the negative number.
x = 0
total = 0
sum = 0
while (sum <= 1000):
x = (int(input("Enter an integer:"))
if (x < 0):
break
else:
sum += x