I'm working on an assignment where I need to create a jackpot game. But I'm having trouble driving the register that controls the win condition and I can't figure out why. As far as I know, the always#(posedge zero) block should be able to run whenever I flip my switch to the up position. Then, so long as the right hot register value happens in the same instant, it should be able to set the win register. However, this is not the case. Nothing seems to happen, and I'm not sure why. I've tried running the always block from different sensitivities but nothing seems to effect it. Maybe I'm just mis-understanding how always blocks work or how the switch works, any help is appreciated.
module jackpot(
input [3:0] SWITCHES,
output [3:0] LEDS,
input CLOCK,
input reset
);
reg [3:0] hot = 4'd1;
reg win;
wire clk, zero, one, two, three;
Clock_Div CDD (CLOCK, clk);
assign LEDS[2:0] = hot[2:0];
assign zero = SWITCHES[0];
assign one = SWITCHES[1];
assign two = SWITCHES[2];
assign three = SWITCHES[3];
assign LEDS[3] = zero;
initial begin
win <= 1'b0;
end
always #(posedge zero) begin
if(hot[0] && zero)
win <= 1'd1;
end
always #(posedge clk) begin
if (reset == 1'b1) begin
hot <= 4'd1;
win <= 1'd0;
end
else if(win == 1'b1) begin
hot <= 4'b1111;
end
else begin
if(hot == 4'b1000) begin
hot <= 4'b0001;
end
else begin
hot <= hot << 1;
end
end
end
endmodule
Thanks to Serge's comment I've realized the issue. Like his comment says, driving a register from multiple always blocks throws a critical warning, and Vivado picks one of the blocks to use over the other. Once I made sure to isolate a reg to an always block the behavior started to look like I expected. This must just be something that got glossed over during class, or maybe I wasn't paying attention enough.
Related
module clks(
input clk,
output [15:0] led
);
wire div2, div4, div8;
reg [2:0] count = 0;
assign div2 = count[0];
assign div4 = count[1];
assign div8 = count[2];
always #(posedge clk) count = count + 1;
endmodule
How can I turn on each led (I have 15 leds) using clock?
I'm really having trouble finding helpful resources online
initial begin
case({count})
2'b00:
led = 15'b000000000000001;
2'b01:
led = 15'b000000000000010;
...
endcase
end
This didn't work.
Or could I do something like this?
led = led + 1;
In your sample code above, you defined count as 3 bits, but your case statements are 2 bits wide. Also, you don't want the initial statement, rather use an always statement.
always # (count)
begin
case(count)
3'b000 : led = 15'b000_0000_0001;
3'b001 : led = 15'b000_0000_0010;
...
endcase
end
I guess that 'by using clock' means changing the led every clock cycle, right? Also it looks like you are trying to encode the led sequentially. In this case you can do the following:
you need to reset your lead to an initial value, sey 15'b1;
every clock cycle you can just shift it left by one. You should not do it in an initial block (though there is a technical way to do so). Use always blocks:
Here is an example:
module clks(
input clk,
input reset,
output reg [15:0] led
);
always #(posedge clk) begin
if (reset == 1)
led <= 15'b1;
else
led <= led << 1;
end
endmodule
In the above case '1' will travel through all bits of led over 15 clock cycles once. 'led' will become '0' after this. You have to make sure that it becomes '1' again if you want to continue in cycles.
Another possibility is to initialize 'led' in the always block, but it is not always synthesizable. YOu do not need a reset signal here.
initial led = 15'b1;
always #(posedge clk) led <= led << 1;
I'm trying to make a morse code display using an led. I need a half second pulse of the light to represent a dot and a 1.5 second pulse to represent a dash.
I'm really stuck here. I have made a counter using an internal 50MHz clock on my FPGA. The machine I have to make will take as input a 3 bit number and translate that to a morse letter, A-H with A being 000, B being 001 and so on. I just need to figure out how to tell the FPGA to keep the led on for the specified time and then turn off for about a second (that would be the delay between a dot pulse and a dash pulse).
Any tips would be greatly appreciated.
Also, it has to be synthesizable.
Here is my code. It's not functioning yet. The error message it keeps giving me is:
Error (10028): Can't resolve multiple constant drivers for net "c3[0]"
at part4.v(149)
module part4 (SELECT, CLK, CLOCK_50, RESET, led);
input [2:0]SELECT;
input RESET, CLK, CLOCK_50;
output reg led=0;
reg [26:0] COUNT=0; //register that keeps track of count
reg [1:0] COUNT2=0; //keeps track of half seconds
reg halfsecflag=0; //goes high every time half second passes
reg dashflag=0; //goes high every time 1 and half second passes
reg [3:0] code; //1 is dot and 0 is dash. There are 4 total
reg [1:0] c3; //keeps track of the index we are on in the code.
reg [3:0] STATE; //register to keep track of states in the state machine
reg done=0; //a flag that goes up when one morse pulse is done.
reg ending=0; //another flag that goes up when a whole morse letter has flashed
reg [1:0] length; //This is the length of the morse letter. It varies from 1 to 4
wire i; // if i is 1, then the state machine goes to "dot". if 0 "dash"
assign i = code[c3];
parameter START= 4'b000, DOT= 4'b001, DASH= 4'b010, DELAY= 4'b011, IDLE=
4'b100;
parameter A= 3'b000, B=3'b001, C=3'b010, D=3'b011, E=3'b100, F=3'b101,
G=3'b110, H=3'b111;
always #(posedge CLOCK_50 or posedge RESET) //making counter
begin
if (RESET == 1)
COUNT <= 0;
else if (COUNT==8'd25000000)
begin
COUNT <= 0;
halfsecflag <= 1;
end
else
begin
COUNT <= COUNT+1;
halfsecflag <=0;
end
end
always #(posedge CLOCK_50 or posedge RESET)
begin
if (RESET == 1)
COUNT2 <= 0;
else if ((COUNT2==2)&&(halfsecflag==1))
begin
COUNT2 = 0;
dashflag=1;
end
else if (halfsecflag==1)
COUNT2= COUNT2+1;
end
always #(RESET) //asynchronous reset
begin
STATE=IDLE;
end
always#(STATE) //State machine
begin
done=0;
case(STATE)
START: begin
led = 1;
if (i) STATE = DOT;
else STATE = DASH;
end
DOT: begin
if (halfsecflag && ~ending) STATE = DELAY;
else if (ending) STATE= IDLE;
else STATE=DOT;
end
DASH: begin
if ((dashflag)&& (~ending))
STATE = DELAY;
else if (ending)
STATE = IDLE;
else STATE = DASH;
end
DELAY: begin
led = 0;
if ((halfsecflag)&&(ending))
STATE=IDLE;
else if ((halfsecflag)&&(~ending))
begin
done=1;
STATE=START;
end
else STATE = DELAY;
end
IDLE: begin
c3=0;
if (CLK) STATE=START;
else STATE=IDLE;
end
default: STATE = IDLE;
endcase
end
always #(posedge CLK)
begin
case (SELECT)
A: length=2'b01;
B: length=2'b11;
C: length=2'b11;
D: length=2'b10;
E: length=2'b00;
F: length=2'b11;
G: length=2'b10;
H: length=2'b11;
default: length=2'bxx;
endcase
end
always #(posedge CLK)
begin
case (SELECT)
A: code= 4'b0001;
B: code= 4'b1110;
C: code= 4'b1010;
D: code= 4'b0110;
E: code= 4'b0001;
F: code= 4'b1011;
G: code= 4'b0100;
H: code= 4'b1111;
default: code=4'bxxxx;
endcase
end
always #(posedge CLK)
begin
if (c3==length)
begin
c3<=0; ending=1;
end
else if (done)
c3<= c3+1;
end
endmodule
I have been reading your code and there are many issues:
The code is not formatted.
You did not provide a test-bench. Did you write one?
"Can't resolve multiple constant drivers for net" Search on stack exchange for the error message. It has been asked many times.
Use always #(*) not e.g. always #(STATE) you are missing signals like i, halfsecflag, ending. But see point 6: You want the STATE in a clocked section.
Where you use always #(posedge CLK) you must use non-blocking assignments: <=.
There are many places where you use always #(posedge CLK) where you want to use always #(*) (e.g. where you set length and code) Opposite you want to use a posedge CLK where you work with your STATE.
Use one clock and one clock only. Do not use CLK and CLOCK_50. Use either one or the other.
Take care of your vector sizes. This 8'd25000000 is wrong as you can no fit 25000000 in 8 bits.
Your usage of halfsecflag is excellent! I have see many times where people think they can use always #(halfsecflag) which is a recipe for disaster!
Below you find a small piece of your code which I have re-written.
All assignments are non-blocking <=
halfsecflag is essential to operate the code only every half a second, so I put that by itself in a separate if at the top. I would use that throughout the code.
All register are reset, both COUNT2 and dashflag.
dashflag was set to 1 but never set back to 0. I fixed that.
I specified the vector sizes. It makes the code "Lint proof".
Here is it:
always #(posedge CLOCK_50 or posedge RESET)
begin
if (RESET == 1'b1)
begin
COUNT2 <= 2'd00;
dashflag <= 1'b0;
end // reset
else if (halfsecflag) // or if (halfsecflag==1'b1)
begin
if (COUNT2==2'd2))
begin
COUNT2 <= 2'd0;
dashflag <=1'b1;
end
else
begin
COUNT2 <= COUNT2+2'd1;
dashflag <=1'b0;
end
end // clocked
end // always
Start fixing the rest of your code the same way. Write a test-bench, simulate and trace on a waveform display where things go wrong.
Normally you would build the finite state machine to produce the output. That machine would have some stages, like reading the input, mapping it to a sequence of morse code element, shifting out the elements to output buffer, waiting for conditions to move to the next morse element. You will need some timer that would produce one morse time unit intervals, and depending on the FSM stage you will wait one, three or seven time units. The FSM will spin in the waiting stage, it doesn't "magically" sleeps in some fpga-produced delay, there's no such things.
Okay a year later, I know exactly what one should do if they want to create a delay in their verilog program! Essentially, what you should do is create a timer using one of the clocks on your FPGA. For me on my Altera DE1-SoC, the timer I could use is the 50MHz clock known as CLOCK_50. What you do is make a timer module that triggers on the positive (or negative, doesn't matter) edge of the 50MHz clock. Set up a count register that holds a constant value. For example, reg [24:0] timer_limit = 25'd25000000; This is a register that can hold 25 bits. I've set this register to hold the number 25 million. The idea is to flip a bit every time the value in this register is exceeded. Here's some pseudocode to help you understand:
//Your variable declarations
reg [24:0] timer_limit = 25'd25000000; //defining our timer limit register
reg [25:0] timer_count = 0; //See note A
reg half_sec_clock;
always#(posedge of CLOCK_50) begin
if timer_count >= timer_limit then begin
reset timer_count to 0;
half_sec_clock = ~half_sec_clock; //toggle your half_sec_clock
end
Note A: Setting it to zero may or may not initialize count, it's always best to include a reset function that clears your count to zero because you don't know what the initial state is when you're dealing with hardware.
This is the basic idea of how to introduce timing into your hardware. You need to use an onboard clock on your device, trigger on the edge of that clock and create your own slower clock to measure things like seconds. The example above will give you a clock that triggers periodically every half second. For me, this allowed me to easily make a morse code light that could flash on either 1 half second count, or 3 half seconds. My best advice to you beginners is to work in a modular fashion. For example build your half second clock and then test it out to see if you can get a light on your FPGA to toggle once every half second (or whatever interval you want). :) I really hope this is the answer that helps you. I know this is what I was looking for when I originally posted this question so long ago.
I am trying to implement the I2S Transmitter in verilog. The datasheet for it is at: https://www.sparkfun.com/datasheets/BreakoutBoards/I2SBUS.pdf
I wrote the code, but my SD line is delayed 1 clock cycle when i test it.
Can someone check my implementation?
module Transmiter(
input signed [23:0] DLeft, input signed [23:0] DRight, input WS, input CLK,
output reg SD
);
wire PL;
reg Q1,Q2;
reg [23:0] shift_reg;
reg [23:0] Tdata;
assign PL = Q1^Q2;
always #(posedge CLK)
begin
Q1 <= WS;
Q2 <= Q1;
end
always #( Q1) begin
if (Q1)
begin
Tdata <= DRight;
end
else
begin
Tdata <= DLeft;
end
end
always #(negedge CLK)
begin
if(PL)
begin
shift_reg <= Tdata;
end
else begin
SD <= shift_reg[23];
shift_reg <= {shift_reg[22:0],1'b0};
end
end
endmodule
EDIT: here is a image of waveform image
TEST BENCH CODE:
module Transmitter_tb(
);
reg CLK, WS;
reg [23:0] dataL;
reg [23:0] dataR;
wire SDout;
Transmiter UT(dataL, dataR, WS, CLK, SDout);
initial begin
dataL = 24'hF0F0FF; #2;
dataR = 24'h0000F0; #2;
end
always begin
CLK=0; #20;
CLK=1; #20;
end;
always begin
WS=0; #1000;
WS=1; #1000;
end;
endmodule
Your negedge block contains an if-else construct and will only ever compute one or the other on a single clock edge. SD will therefore not change value when PL is high.
Furthermore you are using non-blocking assignments(<=) in your code. This roughly means that changes won't be evaluated until the end of the always block. So even if SD <= shift_reg[23] after shift_reg <= Tdata it will not take on the new value in shift_reg[23] but use the previous value. If you want SD to change immediately when shift_reg[23] changes you need to do this combinatorically.
This should work:
always #(negedge CLK)
begin
if(PL)
begin
shift_reg <= Tdata;
end
else
shift_reg <= {shift_reg[22:0],1'b0};
end
assign SD = shift_reg[23];
Working example: https://www.edaplayground.com/x/4bPv
On a side note I am still not convinced that DRight and DLeft are in fact constants, I can see that they are in your TB but it doesn't make sense that the data for your I2S is constant. Your current construct will probably generate a latch(instead of a MUX), and we generally don't want those in our design.
You should clean up your use of blocking versus non-blocking statements:
Always use non-blocking assigments, meaning "<=", in clocked statements.
Always use blocking assigments, meaning "=", in combinational (non-clocked) statements.
This is a industry-wide recommendation, not a personal opinion. You can find this recommendation many places, see for instance:
http://web.mit.edu/6.111/www/f2007/handouts/L06.pdf
The sensitivtity list being incomplete (as pointed out by #Hida) may also cause issues.
Try to correct these two things, and see if it starts working more as expected.
Also note that you are using Q1 (among other signals) to generate your PL signal. If the WS input is not synchronous to your local clock (as I assume it is not), you need to put one more flop (i.e. two in series) before starting to use the output, to avoid metastability-issues. But you won't see this in an RTL simulation.
I wrote a behavioral program for booth multiplier(radix 2) using state machine concept. I am getting the the results properly during the program simulation using modelsim, but when I port it to fpga (spartan 3) the results are not as expected.
Where have I gone wrong?
module booth_using_statemachine(Mul_A,Mul_B,Mul_Result,clk,reset);
input Mul_A,Mul_B,clk,reset;
output Mul_Result;
wire [7:0] Mul_A,Mul_B;
reg [7:0] Mul_Result;
reg [15:0] R_B;
reg [7:0] R_A;
reg prev;
reg [1:0] state;
reg [3:0] count;
parameter start=1 ,add=2 ,shift=3;
always #(state)
begin
case(state)
start:
begin
R_A <= Mul_A;
R_B <= {8'b00000000,Mul_B};
prev <= 1'b0;
count <= 3'b000;
Mul_Result <= R_B[7:0];
end
add:
begin
case({R_B[0],prev})
2'b00:
begin
prev <= 1'b0;
end
2'b01:
begin
R_B[15:8] <= R_B[15:8] + R_A;
prev <= 1'b0;
end
2'b10:
begin
R_B[15:8] <= R_B[15:8] - R_A;
prev <= 1'b1;
end
2'b11:
begin
prev <=1'b1;
end
endcase
end
shift:
begin
R_B <= {R_B[15],R_B[15:1]};
count <= count + 1;
end
endcase
end
always #(posedge clk or posedge reset)
begin
if(reset==1)
state <= start;
else
begin
case(state)
start:
state <= add;
add:
state <= shift;
shift:
begin
if(count>7)
state <= start;
else
state <=add;
end
endcase
end
end
endmodule
You have an incomplete sensitivity list in your combinational always block. Change:
always #(state)
to:
always #*
This may be synthesizing latches.
Use blocking assignments in your combinational always block. Change <= to =.
Good synthesis and linting tools should warn you about these constructs.
Follow the following checklist if something does work in the simulation but not in reality:
Did you have initialized every register? (yes)
Do you use 2 registers for one working variable that you transfer after each clock (no)
(use for state 2 signals/wires, for example state and state_next and transfer after each clock state_next to state)
A Example for the second point is here, you need the next stage logic, the current state logic and the output logic.
For more informations about how to proper code a FSM for an FPGA see here (go to HDL Coding Techniques -> Basic HDL Coding Techniques)
You've got various problems here.
Your sensitivity list for the first always block is incomplete. You're only looking at state, but there's numerous other signals which need to be in there. If your tools support it, use always #*, which automatically generates the sensitivity list. Change this and your code will start to simulate like it's running on the FPGA.
This is hiding the other problems with the code because it's causing signals to update at the wrong time. You've managed to get your code to work in the simulator, but it's based on a lie. The lie is that R_A, R_B, prev, count & Mul_Result are only dependent on changes in state, but there's more signals which are inputs to that logic.
You've fallen into the trap that the Verilog keyword reg creates registers. It doesn't. I know it's silly, but that's the way it is. What reg means is that it's a variable that can be assigned to from a procedural block. wires can't be assigned to inside a procedural block.
A register is created when you assign something within a clocked procedural block (see footnote), like your state variable. R_A, R_B, prev and count all appear to be holding values across cycles, so need to be registers. I'd change the code like this:
First I'd create a set of next_* variables. These will contain the value we want in each register next clock.
reg [15:0] next_R_B;
reg [7:0] next_R_A;
reg next_prev;
reg [3:0] next_count;
Then I'd change the clocked process to use these:
always #(posedge clk or posedge reset) begin
if(reset==1) begin
state <= start;
R_A <= '0;
R_B <= '0;
prev <= '0;
count <= '0;
end else begin
R_A <= next_R_A;
R_B <= next_R_B;
prev <= next_prev;
count <= next_count;
case (state)
.....
Then finally change the first process to assign to the next_* variables:
always #* begin
next_R_A <= R_A;
next_R_B <= R_B;
next_prev <= prev;
next_count <= count;
case(state)
start: begin
next_R_A <= Mul_A;
next_R_B <= {8'b00000000,Mul_B};
next_prev <= 1'b0;
next_count <= 3'b000;
Mul_Result <= R_B[7:0];
end
add: begin
case({R_B[0],prev})
2'b00: begin
next_prev <= 1'b0;
end
.....
Note:
All registers now have a reset
The next_ value for any register defaults to it's previous value.
next_ values are never read, except for the clocked process
non-next_ values are never written, except in the clocked process.
I also suspect you want Mul_Result to be a wire and have it assign Mul_Result = R_B[7:0]; rather than it being another register that's only updated in the start state, but I'm not sure what you're going for there.
A register is normally a reg, but a reg doesn't have to be a register.
I want to use if-else and for loop inside an always block. I don't want those if-else to be executed again and again, so I don't want to connect always with either posedge clkor negedge clk.
I want them to be executed only once. I not only want to simulate but I want to synthesize on to Spartan Board aswell.
always # (**what I should add here**)
begin
if(condition)
else
end
For simulations to execute some thing once you can use initial but this is not a synthesizable:
reg x;
initial begin
if(condition) begin
x = 1'b0 ;
end
else begin
x = 1'b1 ;
end
end
To answer the general question always #(**what I should add here**) Most modern verilog simulators will allow the use of * which will trigger the block (always begin to end) when any right hand side argument changes of any condition of selection logic.
always #* begin
if(condition)
x = y ;
else
x = ~y ;
end
older simulators would require you to list the variables you needed to trigger on, in a list. always #(condition, y)
If there is only 1 variable being selected an assign on a wire type might be better, but this can not be limited to being 'executed once', but would be a suitable choice from your question. Not sure about suitability for FPGA's though
wire [3:0] x ; //4 bit wire
//(condition) ? value if true : value if false ;
assign x = (condition) ? 4'b1010 : 4'b0100 ;
module oneShot(in, out, enable, reset);
input in;
input enable;
input reset;
output reg out;
reg once_only;
always # (posedge enable) begin
if (reset) begin
once_only <= 0;
end
else if (once_only == 0) begin
out <= calc_out; // or whatever processing you want
once_only <= 1;
end
end
always #(*) begin
// calculate ouput here always
calc_out = 1 + 7 +100+ in;
end
endmodule
You can't have those if statements calculate only once. It's hardware, it'll always calculate. But you can hold the output steady after it's been calculated once. You are still trying to write a software function and put it in to hardware rather than describe hardware which will solve your problem. I can't see that you'll get a decent design this way. Sure you'll be able to make some small pieces and synthesise them (eventually), but a full design??