experts, i have many folders and inside the folder there are many sub-folders and the sub-folders contain many files.However, in all the sub-folders one file name is same that is input.ps.Now i want to rename the same input.ps with full path plus file name
so input.ps in all directories should be renamed to home_wuan_data_filess_input.ps
i tried
#!/bin/sh
for file in /home/wuan/data/filess/*.ps
do
mv $file $file_
done
But it does not do the same as i expect,i hope experts will help me.Thanks in advance.
so input.ps in all directories should be renamed to home_wuan_data_filess_input.ps
You may use this find solution:
find /home/wuan/data/filess -type f -name 'input*.ps' -exec bash -c '
for f; do fn="${f#/}"; echo mv "$f" "${fn//\//_}"; done' _ {} +
while read line;
do
fil=${line//\//_}; # Converts all / characters to _ to form the file name
fil=${fil:1}; # Remove the first -
dir=${line%/*}; # Extract the directory
echo "mv $line $dir/$fil"; # Echo the move command
# mv "$line" "$dir/$fil"; # Remove the comment to perform the actual command
done <<< "$(find /path/to/dir -name "input.ps")"
Ok, so file will end up being
/home/wuan/data/filess/input.ps
What we need here is the path, and the full, snake-cased name. Let's start by getting the path:
for f in /home/wuan/data/filess/*.ps; do
path="${f%*/}";
This will match the substring of f up until the last occurrence of /, effectively giving us the path.
Next, we want to snake_case all the things, which is even easier:
for f in /home/wuan/data/filess/*.ps; do
path="${f%*/}";
newname="${f//\//_}"
This replaces all instances of / with _, giving the name you want the new file to have. Now let's put all of this together, and move the file f to path/newname:
for f in /home/wuan/data/filess/*.ps; do
path="${f%*/}";
newname="${f//\//_}"
mv "${f}" "${path}/${newname}"
done
That should do the trick
Here's one of many sites listing some of the bash string manipulations you can use.
Sorry for the delayed update, the power in my building just cut out :)
Related
This is the script that I'm using to move files with the string "john" in them (124334_john_rtx.mp4 , 3464r64_john_gty.mp4 etc) to a certain folder
find /home/peter/Videos -maxdepth 1 -type f -iname '*john' -print0 | \
xargs -0 --no-run-if-empty echo mv --target-directory=/home/peter/Videos/john/
Since I have a large amount of videos with various names written in the files, I want to make a bash script which moves videos with a string between the underscores to a folder named based on the string between the underscores. So for example if a file is named 4345655_ben_rts.mp4 the script would identify the string "ben" between the underscores, create a folder named as the string between the underscores which in this case is "ben" and move the file to that folder. Any advice is greatly appreciated !
My way to do it :
cd /home/peter/Videos # Change directory to your start directory
for name in $(ls *.mp4 | cut -d'_' -f2 | sort -u) # loops on a list of names after the first underscore
do
mkdir -p /home/peter/Videos/${name} # create the target directory if it doesn't exist
mv *_${name}_*.mp4 /home/peter/Videos/${name} # Moving the files
done
This bash loop should do what you need:
find dir -maxdepth 1 -type f -iname '*mp4' -print0 | while IFS= read -r -d '' file
do
if [[ $file =~ _([^_]+)_ ]]; then
TARGET_DIR="/PARENTPATH/${BASH_REMATCH[1]}"
mkdir -p "$TARGET_DIR"
mv "$file" "$TARGET_DIR"
fi
done
It'll only move the files if it finds a directory token.
I used _([^_]+)_ to make sure there is no _ in the dir name, but you didn't specify what you want if there are more than two _ in the file name. _(.+)_ will work if foo_bar_baz_buz.mp4 is meant to go into directory bar_baz.
And this answer to a different question explains the find | while logic: https://stackoverflow.com/a/64826172/3216427 .
EDIT: As per a question in the comments, I added mkdir -p to create the target directory. The -p means recursively create any part of the path that doesn't already exist, and will not error out if the full directory already exists.
I'm trying to match two directories and if the file exists in the second directory, I want to move files from the first directory to a third one.
The filenames do not matching exactly, they get a "_ica" at the end of the name and a different extension.
I have tried to write a script that loops through dir1 checks if it's in dir2
and if found move to dir3:
DATA= /home/eegfilesonlyWM/*
PROCESSED= /home/eegfilesonlyWM/icaddata/*
DONE= /home/eegfilesonlyWM/done/
for f in $DATA ; do
fname=${f##*/}
fname=${fname%/}
find /home/eegfilesonlyWM/icaddata/ -iname "${fname*_ica*}" -type f -exec mv {} ./done \;
done
I would like to copy from the first directory those files that already have corresponding files in the second directory.
Thank you for any help
Maybe this will do what you want:
#!/usr/bin/env bash
#Directory paths here
DATA=./DATA
PROCESSED=./PROCESSED
DONE=./DONE
#Do the test and copy here
for f in `ls -1 $DATA`; do
#build output name
p="$PROCESSED/${f/\.xxx/}"; #xxx is the file extension of original
p="${p}_ica.yyy"; #yyy is the file extension of the processed
if [ -f $p ] ; then
cp $DATA/$f $DONE
fi
done
I'm trying to learn bash on Linux, just for fun. I thought it would be pretty useful to have a .sh that would group together similar files. For example, let's say we have the directory
/home/docs/
Inside the directory we have /mathdocs/, /codingdocs/, etc.
Inside those sub-directories we have doc.txt, in all of them. Same name for all the files on the subdirectories.
Let's say I want to group them together, and I want to move all the files to /home/allthedocs/ and rename them after the directories they were in. (mathdocs.txt, codingdocs.txt, etc.)
How could I do that?
I've tried to create a script based on the ls and cp commmands, but I don't know how I can take the name of the directories to rename the files in it after I moved them. I guess it has to be some sort of iterative sentence (for X on Y directories) but I don't know how to do it.
You can move and rename your file in one shot with mv, with a loop that grabs all your files through a glob:
#!/bin/bash
dest_dir=/home/allthedocs
cd /home/docs
for file in */doc.txt; do
[[ -f "$file" ]] || continue # skip if not a regular file
dir="${file%/*}" # get the dir name from path
mv "$file" "$dest_dir/$dir.txt"
done
See this post for more info:
Copying files from multiple directories into a single destination directory
Here is a one liner solution that treats whitespaces in filenames, just as #codeforester 's solution does with the glob.
Note that white spaces are treated with the "-print0" option passed to "find", the internal field separator (IFS) in while loop and the wrapping of file3 variable with quotes.
The parameter substitution from file2 into file3 gets rid of the leading "./".
The parameter substition inside the move command turns the path into a filename (run under /home/docs/):
find . -maxdepth 2 -mindepth 2 -print0 | while IFS= read -r -d '' file; \
do file2=$(printf '%s\n' "$file"); file3=${file2#*\/*}; \
mv "$file2" ../allsil/"${file3//\//}"; done
I am trying to find all text files in my directory and copy a list to text file. I am using a for loop to get the names. Then the output is being placed in the text file. However I am getting an indication of a syntax error near unexpected token$'do\r''`. What would be the best way to do this? Also for the text file name how could I save it with a date/timestamp name?
FILE_PATH="/my_folder/"
for f in $(find $FILE_PATH -type f -name '*.txt'); do
echo "file '$f'" >> "$FILE_PATH"mylist.txt;
done
Don't use for loop. In order for that for loop to execute, it first has to find all of the files that meet your criteria, then substitutes that list into your for loop. It means waiting for that ``findto process before yourfor` loop can even start to process the names. Plus, if there are lots of files, you can overload the command line and lose files you want to see.
Why not:
FILE_PATH="/my_folder"
find $FILE_PATH -type f -name '*.txt' > "$FILE_PATH/mylist.txt"
No need for a loop. No need to echo. Simple and clean.
Plus, you don't have issues with file names that may contain spaces.
You can avoid find using pathname expansion:
FILE_PATH="/my_folder/"
for f in "$FILE_PATH"/* ; do
test -f "$f" || continue # not a regular file
echo "$f"
done >| "$FILE_PATH/mylist.txt" # >| force overwrite
I have a folder with more than 5000 images, all with JPG extension.
What i want to do, is to add recursively the "thumb_" prefix to all images.
I found a similar question: Rename Files and Directories (Add Prefix) but i only want to add the prefix to files with the JPG extension.
One of possibly solutions:
find . -name '*.jpg' -printf "'%p' '%h/thumb_%f'\n" | xargs -n2 echo mv
Principe: find all needed files, and prepare arguments for the standard mv command.
Notes:
arguments for the mv are surrounded by ' for allowing spaces in filenames.
The drawback is: this will not works with filenames what are containing ' apostrophe itself, like many mp3 files. If you need moving more strange filenames check bellow.
the above command is for dry run (only shows the mv commands with args). For real work remove the echo pretending mv.
ANY filename renaming. In the shell you need a delimiter. The problem is, than the filename (stored in a shell variable) usually can contain the delimiter itself, so:
mv $file $newfile #will fail, if the filename contains space, TAB or newline
mv "$file" "$newfile" #will fail, if the any of the filenames contains "
the correct solution are either:
prepare a filename with a proper escaping
use a scripting language what easuly understands ANY filename
Preparing the correct escaping in bash is possible with it's internal printf and %q formatting directive = print quoted. But this solution is long and boring.
IMHO, the easiest way is using perl and zero padded print0, like next.
find . -name \*.jpg -print0 | perl -MFile::Basename -0nle 'rename $_, dirname($_)."/thumb_".basename($_)'
The above using perl's power to mungle the filenames and finally renames the files.
Beware of filenames with spaces in (the for ... in ... expression trips over those), and be aware that the result of a find . ... will always start with ./ (and hence try to give you names like thumb_./file.JPG which isn't quite correct).
This is therefore not a trivial thing to get right under all circumstances. The expression I've found to work correctly (with spaces, subdirs and all that) is:
find . -iname \*.JPG -exec bash -c 'mv "$1" "`echo $1 | sed \"s/\(.*\)\//\1\/thumb/\"`"' -- '{}' \;
Even that can fall foul of certain names (with quotes in) ...
In OS X 10.8.5, find does not have the -printf option. The port that contained rename seemed to depend upon a WebkitGTK development package that was taking hours to install.
This one line, recursive file rename script worked for me:
find . -iname "*.jpg" -print | while read name; do cur_dir=$(dirname "$name"); cur_file=$(basename "$name"); mv "$name" "$cur_dir/thumb_$cur_file"; done
I was actually renaming CakePHP view files with an 'admin_' prefix, to move them all to an admin section.
You can use that same answer, just use *.jpg, instead of just *.
for file in *.JPG; do mv $file thumb_$file; done
if it's multiple directory levels under the current one:
for file in $(find . -name '*.JPG'); do mv $file $(dirname $file)/thumb_$(basename $file); done
proof:
jcomeau#intrepid:/tmp$ mkdir test test/a test/a/b test/a/b/c
jcomeau#intrepid:/tmp$ touch test/a/A.JPG test/a/b/B.JPG test/a/b/c/C.JPG
jcomeau#intrepid:/tmp$ cd test
jcomeau#intrepid:/tmp/test$ for file in $(find . -name '*.JPG'); do mv $file $(dirname $file)/thumb_$(basename $file); done
jcomeau#intrepid:/tmp/test$ find .
.
./a
./a/b
./a/b/thumb_B.JPG
./a/b/c
./a/b/c/thumb_C.JPG
./a/thumb_A.JPG
jcomeau#intrepid:/tmp/test$
Use rename for this:
rename 's/(\w{1})\.JPG$/thumb_$1\.JPG/' `find . -type f -name *.JPG`
For only jpg files in current folder
for f in `ls *.jpg` ; do mv "$f" "PRE_$f" ; done