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I process a file content with awk. I would like to pipe the output of awk into netcat, that communicates with a socket.
The awk script is very simple, it just prints $1.
When I pipe the result of awk into netcat, I have no result printed (except the value of addresses_file).
echo "$addresses_file"
echo $(awk -f http-awk-check.awk $addresses_file | netcat -U /home/hduser/socket/rtop12)
Output
../keys/addresses-2021-01-26-17-44.txt
However, I have a result printed when I try with one line by command line:
$ echo 'info' | netcat -U /home/hduser/socket/rtop12
{"jsonrpc":"2.0","id":1,"result":"0x0"}
The awk script:
BEGIN {
FS = ","
}
{
print $1 "\n" # same result with and without \n
}
How can I get a result similar to the manual command line with my little script ?
I must have made a mistake somewhere during my tests.
With the following, it works like a charm (but the netcat connexion is not closed thougH...)
BEGIN {
FS = ","
}
{
print $1
}
awk -f http-awk-check.awk $addresses_file | netcat -U /home/hduser/socket/rtop12 > toto
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This is from a vhost file. This is the output I get
ServerName uat3-dam-something1.prg-dc.brb.com
Hello,
I'm wondering how to cut from this output so only this part remains
something1.prg-dc.brb.com
Keep in mind that "something" could be "something4141411" or "something23". So length operations won't work. Tried with cut command and AWK, but didn't work. I would be happy receive a tips from the bash experts :)
Like this :
grep -o 'something.*' file
or more specific:
grep -oE 'something[0-9]+\..*' file
Output:
something1.prg-dc.brb.com
Could you please try following, written and tested with provided samples only.
awk -F'uat3-dam-' '{print $NF}' Input_file
Description: Making uat3-dam- as field separator and printing last field of it.
2nd solution:
awk 'match($0,/something.*/){print substr($0,RSTART,RLENGTH)}' Input_file
Using:
echo "ServerName uat3-dam-something1.prg-dc.brb.com" |cut -d\- -f3-4
Will return:
something1.prg-dc.brb.com
And if you change the string (as you mention):
echo "ServerName uat3-dam-something111111.prg-dc.brb.com" |cut -d\- -f3-4
It will keep returning:
something111111.prg-dc.brb.com
$ echo 'ServerName uat3-dam-something1.prg-dc.brb.com' | awk -F- '{sub(".*" $2 FS,"")}1'
something1.prg-dc.brb.com
This will work:
echo "ServerName uat3-dam-something1.prg-dc.brb.com" | sed -E 's/.*(something.*)/\1/'
Or, if the string is in a file named file
sed -E 's/.*(something.*)/\1/' file
Explanation:
-E is for extended regex
.*(something.*) means "any char 0 or more times followed by something and any other char 0 or more times".
\1 is used to print only the matching part inside the brackets.
You could also use :
echo ${test#*dam-}
Example :
test="ServerName uat3-dam-something1.prg-dc.brb.com"
echo ${test#*dam-}
which gives:
something1.prg-dc.brb.com
Note that the opposite version would be echo ${test%something*}
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Why did printf didn't WORK for the final command printf "%s,%.2f\n" "$s","$a" and what's that extra 0.00 coming from?
When I ran them individually, they worked as expected but not in the final command.
$ s="giga,fifa"; a="8309.18694444444444444444"; echo "$s"; printf "%s\n" "$s"; echo -e "\n"; echo "$a"; printf "%.2f\n" "$a"; echo -e "\n"; echo "$s,$a"; printf "%s" "$s,"; printf "%.2f\n" "$a";echo;printf "%s,%.2f\n" "$s","$a"
giga,fifa
giga,fifa
8309.18694444444444444444
8309.19
giga,fifa,8309.18694444444444444444
giga,fifa,8309.19
giga,fifa,8309.18694444444444444444,0.00
How can I get this output: giga,fifa,8309.19 with just one printf command showing both variables?
You don't use a , in bash printf, you delimit with space. The 0.00 comes from trying to parse the "$s","$a" at once, and has odd results - everything is considered one argument and printed as the first string, so no argument exists for the second and a 0 is substituted as default. This works as expected:
>printf "%s,%.2f\n" "$s" "$a"
giga,fifa,8309.19
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In my Bash script, I have to change a name to a path address(new address) in a text file:
(MYADDREES) change to ( /home/run1/c1 ) and save it as new file.
I did like this: defined a new variable = new address and tried to replace it in previous address in text file.
I use sed but it has problem.
My script was:
#!/bin/bash
# To debug
set -x
x=`pwd`
echo $x
sed "s/MYADDRESS/$x/g" < sample1.txt > new.txt
exit
The output of pwd is likely to contain / characters, making your sed expression look something like s/MYADDRESS//home/user/somewhere/. This makes it impossible for sed to sort out what should be replaced with what. There are two solutions:
Use a different delimiter for sed:
sed "s,MYADDRESS,$x,g" < sample1.txt > new.txt
...although this will have the same problem if the current path contains a comma character or something else that is a special character for sed, so the more robust approach is to use awk instead:
awk -v curdir="$(pwd)" '{ gsub("MYADDRESS", curdir); print }' < sample1.txt > new.txt
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I am a beginner.. I'd like to use Linux shell to make the following file
1 2 2
2 3 4
4 5 2
4 2 1
....
into
1,2,2
2,3,4
4,5,2
4,2,1
Thank you very much!
Are you looking for something like this:-
sed -e "s/ /,/g" < a.txt
or may be easier like this:
tr ' ' ',' <input >output
or in Vim you can use the Regex:
s/ /,/g
The question asks "line by line". In bash :
while read line; do echo $line | sed 's/ /,/g'; done < file
It will read file line by line into line, print (echo) each line and pipe (|) it to sed which will change spaces into commas. You can add > newfile at the end (but > file won't work) if you need to store it in a file.
But if you don't need anything else than changing characters in the file, processing the whole file at once is easier and probably quicker :
sed -i 's/ /,/g' file
(option -i is for modifying the file directly, as opposed to print modifications to stdout).
Read more about sed to understand its syntax, you'll need it eventually.
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I work with Bash script and I want to get line from big text by special text
for example i have these lines
first fffffffffffffffffffffffffff
.................................
second ssssssssssssssssssssssssss
.................................
third ttttttttttttttttttttttttttt
and I want to get ssssssssssssssssssssssssss string .
Can anybody help me?
Is this what you want?
echo "$longstring" | awk '$1 == "second" { print $2 }'
since you seem to not have any criterion as to which line you want to output, i suggest something like:
echo "ssssssssssssssssssssssssss"
this is pretty robust regarding the content of your input, doesn't depend on a "file", and is a fast solution.
cat filename | grep "^second" | cut -d " " -f 2
Or, if you are ALF:
<filename grep "^second" | cut -d " " -f 2
Or
grep "^second" filename | cut -d " " -f 2