Maybe it is ordinary issue regarding iterating thru a dict. Please find below imovel.txt file, whose content is as follows:
{'Andar': ['primeiro', 'segundo', 'terceiro'], 'Apto': ['101','201','301']}
As you can see this is not a ordinary dictionary, with a key value pair; but a key with a list as key and another list as value
My code is:
#/usr/bin/python
def load_dict_from_file():
f = open('../txt/imovel.txt','r')
data=f.read()
f.close()
return eval(data)
thisdict = load_dict_from_file()
for key,value in thisdict.items():
print(value)
and yields :
['primeiro', 'segundo', 'terceiro'] ['101', '201', '301']
I would like to print a key,value pair like
{'primeiro':'101, 'segundo':'201', 'terceiro':'301'}
Given such txt file above, is it possible?
You should use the builtin json module to parse but either way, you'll still have the same structure.
There are a few things you can do.
If you know both of the base key names('Andar' and 'Apto') you can do it as a one line dict comprehension by zipping the values together.
# what you'll get from the file
thisdict = {'Andar': ['primeiro', 'segundo', 'terceiro'], 'Apto': ['101','201','301']}
# One line dict comprehension
newdict = {key: value for key, value in zip(thisdict['Andar'], thisdict['Apto'])}
print(newdict)
If you don't know the names of the keys, you could call next on an iterator assuming they're the first 2 lists in your structure.
# what you'll get from the file
thisdict = {'Andar': ['primeiro', 'segundo', 'terceiro'], 'Apto': ['101','201','301']}
# create an iterator of the values since the keys are meaningless here
iterator = iter(thisdict.values())
# the first group of values are the keys
keys = next(iterator, None)
# and the second are the values
values = next(iterator, None)
# zip them together and have dict do the work for you
newdict = dict(zip(keys, values))
print(newdict)
As other folks have noted, that looks like JSON, and it'd probably be easier to parse it read through it as such. But if that's not an option for some reason, you can look through your dictionary this way if all of your lists at each key are the same length:
for i, res in enumerate(dict[list(dict)[0]]):
ith_values = [elem[i] for elem in dict.values()]
print(ith_values)
If they're all different lengths, then you'll need to put some logic to check for that and print a blank or do some error handling for looking past the end of the list.
Related
How to check if a specific type exists in a dictionary? No matter what level this is in. I want to do the search both in the keys and values set.
For example, I want to find out the dictionary key that is a np.int64.
I'd loop over the dict with a for loop and check one-by-one:
some_dict = {1:"one",
2:"Two",
3:"Three",}
for key, value in some_dict.items():
if isinstanceof(value, np.int64):
print("Found one! it is {}:{}".format(key, value))
This wil check every one, one-by-one. Here is a list of sources to look into. That way you'll know why it works:
Iterating over dictionaries using 'for' loops
https://pynative.com/python-isinstance-explained-with-examples/#:~:text=The%20Python%E2%80%99s%20isinstance%20%28%29%20function%20checks%20whether%20the,Also%2C%20Solve%3A%20Python%20Basic%20Exercise%20and%20Beginners%20Quiz
You can use recursion for nested dicts
def recur(dct, type_ref):
for k,v in dct.items():
if isinstance(v, type_ref) or isinstance(k, type_ref):
print(k,v)
return True
if isinstance(v, dict):
return recur(v, type_ref)
return False
# dct = input dict, type_ref = type you want to match
Not sure if this is exactly what you want since you haven't provided much information
I am scraping data with scrapetube to get the video IDs of all the videos from a YouTube channel. The scrape code returns a generator object which I have converted to a list of dictionaries containting other dictionaries, lists and string. The scraping code works, but here still some sample data. I am only interested in the string video Id --> see picture for illustration purposes
How to iterate through all the video IDs in the string videoId and save them in a new variable (list or dataframe) for further processing?
import scrapetube
vid = scrapetube.get_channel('UC_zxivooFdvF4uuBosUnJxQ')
type(vid) #generator file
video = next(vid) #extract values from generator & then convert it
videoL = list(vid) #convert it to a list
#code not working
for item in videoL['videoId']:
entry = {}
videoId = item['videoId']
for i in range(len(videoId)):
entry.append(int(videoId[i][0:10]))
#error message: TypeError: list indices must be integers or slices, not str
I used code snippet from this post but can't seem to make it work.
It's helpful when you know the terminology so let's go through it step by step.
What is a generator?
A generator, like it's name implies, generates values on demand.
Their usefulness in this case is that if you don't want to have all the data in memory, you only iterate over one generated value at a time and only extract what you need.
Consider this:
def gen_one_million():
for i in range(0, 1_000_000):
yield i
for i in gen_one_million():
# do something with i
Rather than having a million elements in a list or some container in memory, you only get one at a time. If you want them all in a list it's very easy to do with list(gen_one_million()) but you're not tied to having them all in memory if you don't need them.
What is a list and how do I use them?
A list in python is a container represented by brackets []. To access elements in a list you can index into it i = my_list[0] or iterate over it.
for i in my_list:
# do something with i
What is a dict and how do I use them?
A dict is a python key/value container type represented by curly braces and a colon between the key and value. {key: value}
To access values in a dict you can reference the key who's value you want i = my_dict[key] where key is a string or integer or some other hashable type. You can also iterate over it.
for key in my_dict:
# do something with the key
for value in my_dict.values():
# do something with the key
for key, value in my_dict.items():
# do something with the key and value
How does my case fit into all this?
Looking at your sample data it looks like you already have it converted from a generator to a list.
[
{
'videoId': '8vCvSmAIv1s',
'thumbnail': {
'thumbnails': [
{
'url': 'https://i.ytimg.com/vi/8vCvSmAIv1s/hqdefault.jpg?sqp=-oaymwEbCKgBEF5IVfKriqkDDggBFQAAiEIYAXABwAEG&rs=AOn4CLDn3-yb8BvctGrMxqabxa_nH-UYzQ',
'width': 168,
'height': 94}, # etc..
}
]
}
}
]
However, since you just need to iterate over it and access the 'videoID' key in each generated dict, there's no reason to convert.
Just iterate directly over the generator and access the key of each generated dict.
video_ids = []
for item in vid:
video_ids.append(item['videoId'])
Or even better, as a list comprehension.
video_ids = [item['videoId'] for item in vid]
I have a large dictionary and I am trying to remove values from keys if they start with certain values. Below is a small example of the dictionary.
a_data = {'78567908': {'26.01.17', '02.03.24', '26.01.12', '04.03.03', '01.01.13', '02.03.01', '01.01.10', '26.01.21'}, '85789070': {'26.01.02', '09.01.04', '02.05.04', '02.03.17', '02.05.01'}, '87140110': {'03.15.25', '03.15.24', '03.15.19'}, '87142218': {'26.17.13', '02.11.01', '02.03.22'}, '87006826': {'28.01.03'}}
After I read in the dictionary, I want to remove values from all keys that start with '26.' or '02.' It is possible that would leave a key with no values (an empty set).
I do have code that works:
exclude = ('26.', '02.')
f_a_data = {}
for k, v in a_data.items():
f_a_data.setdefault(k,[])
for code in v:
print (k, code, not code.startswith(exclude))
if not code.startswith(exclude):
f_a_data[k].append(code)
print('Filtered dict:')
print(f_a_data)
This returns a filtered dict:
Filtered dict:
{'78567908': ['04.03.03', '01.01.13', '01.01.10'], '85789070': ['09.01.04'], '87140110': ['03.15.25', '03.15.24', '03.15.19'], '87142218': [], '87006826': ['28.01.03']}
Question 1: Is this the best way to filter a dictionary?
Question 2: How could i modify the above snippet to return values in a set like the original dict?
Your code is quite all right in complexity terms but can be "pythonized" a little and still remain readable.
My proposal: you can rebuild a dictionary using nested comprehensions and all to test if you should include the values:
a_data = {'78567908': {'26.01.17', '02.03.24', '26.01.12', '04.03.03', '01.01.13', '02.03.01', '01.01.10', '26.01.21'}, '85789070': {'26.01.02', '09.01.04', '02.05.04', '02.03.17', '02.05.01'}, '87140110': {'03.15.25', '03.15.24', '03.15.19'}, '87142218': {'26.17.13', '02.11.01', '02.03.22'}, '87006826': {'28.01.03'}}
exclude = ('26.', '02.')
new_data = {k:{x for x in v if all(s not in x for s in exclude)} for k,v in a_data.items()}
result:
>>> new_data
{'78567908': {'01.01.10', '01.01.13', '04.03.03'},
'85789070': {'09.01.04'},
'87006826': {'28.01.03'},
'87140110': {'03.15.19', '03.15.25', '03.15.24'},
'87142218': set()}
(here using a dictionary comprehension embedding a set comprehension (since you need a set) using a generator comprehension in all)
I'm very new in python (I usually write in php). I want to understand how to store information in an associative array, and if you can explain me whats the difference of "tuples", "arrays", "dictionary" and "list" will be wonderful (I tried to read different source but I still not caching it).
So This is my code:
#!/usr/bin/python3.4
import csv
import string
nidless_keys = dict()
nidless_keys = ['test_string1','test_string2'] #this contain the string to
# be searched in linesreader
data = {'type':[],'id':[]} #here I want to store my information
with open('path/to/csv/file.csv',newline="") as csvfile:
linesreader = csv.reader(csvfile,delimiter=',',quotechar="|")
for row in linesreader: #every line in this csv have a url like
#www.test.com/?test_string1&id=123456
current_row_string = str(row)
for needle in nidless_keys:
current_needle = str(needle)
if current_needle in current_row_string:
data[current_needle[current_row_string[-8:]]) += 1 # also I
#need to count per every id how much rows there are.
In conclusion:
my_data_stored = [current_needle][current_row_string[-8]]
current_row_string[-8] is a url which the last 8 digit of the url is an ID.
So the array should looks like this at the end of the script:
test_string1 = 123456 = 20
= 256468 = 15
test_string2 = 123155 = 10
Edit 1:
Which type I need here to store the information?
Can you tell me how to resolve this script?
It seems you want to count how many times an ID in combination with a test string occurs.
There can be multiple ID/count combinations associated with every test string.
This suggests that you should use a dictionary indexed by the test strings to store the results. In that dictionary I would suggest to store collections.Counter objects.
This way, you would have to add a special case when a key in the results dictionary isn't found to add an empty Counter. This is a common problem, so there is a specialized form of dictionary in the collections module called defaultdict.
import collections
import csv
# Using a tuple for the keys so it cannot be accidentally modified
keys = ('test_string1', 'test_string2')
result = collections.defaultdict(collections.Counter)
with open('path/to/csv/file.csv',newline="") as csvfile:
linesreader = csv.reader(csvfile,delimiter=',',quotechar="|")
for row in linesreader:
for key in keys:
if key in row:
id = row[-6:] # ID's are six digits in your example.
# The first index is into the dict, the second into the Counter.
result[key][id] += 1
There is an even easier way, by using regular expressions.
Since you seem to treat every row in a CSV file as a string, there is little need to use the CSV reader, so I'll just read the whole file as text.
import re
with open('path/to/csv/file.csv') as datafile:
text = datafile.read()
pattern = r'\?(.*)&id=(\d+)'
The pattern is a regular expression. This is a large topic in and of itself, so I'll only cover briefly what it does. (You might also want to check out the relevant HOWTO) At first glance it looks like complete gibberish, but it is actually a complete language.
In looks for two things in a line. Anything between ? and &id=, and a sequence of digits after &id=.
I'll be using IPython to give an example.
(If you don't know it, check out IPython. It is great for trying things and see if they work.)
In [1]: import re
In [2]: pattern = r'\?(.*)&id=(\d+)'
In [3]: text = """www.test.com/?test_string1&id=123456
....: www.test.com/?test_string1&id=123456
....: www.test.com/?test_string1&id=234567
....: www.test.com/?foo&id=234567
....: www.test.com/?foo&id=123456
....: www.test.com/?foo&id=1234
....: www.test.com/?foo&id=1234
....: www.test.com/?foo&id=1234"""
The text variable points to the string which is a mock-up for the contents of your CSV file.
I am assuming that:
every URL is on its own line
ID's are a sequence of digits.
If these assumptions are wrong, this won't work.
Using findall to extract every match of the pattern from the text.
In [4]: re.findall(pattern, test)
Out[4]:
[('test_string1', '123456'),
('test_string1', '123456'),
('test_string1', '234567'),
('foo', '234567'),
('foo', '123456'),
('foo', '1234'),
('foo', '1234'),
('foo', '1234')]
The findall function returns a list of 2-tuples (that is key, ID pairs). Now we just need to count those.
In [5]: import collections
In [6]: result = collections.defaultdict(collections.Counter)
In [7]: intermediate = re.findall(pattern, test)
Now we fill the result dict from the list of matches that is the intermediate result.
In [8]: for key, id in intermediate:
....: result[key][id] += 1
....:
In [9]: print(result)
defaultdict(<class 'collections.Counter'>, {'foo': Counter({'1234': 3, '123456': 1, '234567': 1}), 'test_string1': Counter({'123456': 2, '234567': 1})})
So the complete code would be:
import collections
import re
with open('path/to/csv/file.csv') as datafile:
text = datafile.read()
result = collections.defaultdict(collections.Counter)
pattern = r'\?(.*)&id=(\d+)'
intermediate = re.findall(pattern, test)
for key, id in intermediate:
result[key][id] += 1
This approach has two advantages.
You don't have to know the keys in advance.
ID's are not limited to six digits.
A brief summary of the python data types you mentioned:
A dictionary is an associative array, aka hashtable.
A list is a sequence of values.
An array is essentially the same as a list, but limited to basic datatypes. My impression is that they only exists for performance reasons, don't think I've ever used one. If performance is that critical to you, you probably don't want to use python in the first place.
A tuple is a fixed-length sequence of values (whereas lists and arrays can grow).
Lets take them one by one.
Lists:
List is a very naive kind of data structure similar to arrays in other languages in terms of the way we write them like:
['a','b','c']
This is a list in python , but seems very similar to array structure.
However there is a very large difference in the way lists are used in python and the usual arrays.
Lists are heterogenous in nature. This means that we can store any kind of data simultaneously inside it like:
ls = [1,2,'a','g',True]
As you can see, we have various kinds of data within a list and is a valid list.
However, one important thing about them is that we can access the list items using zero based indices. So we can write:
print ls[0],ls[3]
output: 1 g
Dictionary:
This datastructure is similar to a hash map data structure. It contains a (key,Value) pair. An empty dictionary looks like:
dc = {}
Now, to store a key,value pair, e.g., ('potato',3),(tomato,5), we can do as:
dc['potato'] = 3
dc['tomato'] = 5
and we saved the data in the dictionary dc.
The important thing is that we can even store another data structure element like a list within a dictionary like:
dc['list1'] = ls , where ls is the list defined above.
This shows the power of using dictionary.
In your case, you have difined a dictionary like this:
data = {'type':[],'id':[]}
This means that your dictionary will consist of only two keys and each key corresponds to a list, which are empty for now.
Talking a bit about your script, the expression :
current_row_string[-8:]
doesn't make a sense. The index should have been -6 instead of -8 that would give you the id part of the current row.
This part is the id and should have been stored in a variable say :
id = current_row_string[-6:]
Further action can be performed as seen the answer given by Roland.
I want to add string dictionary keys like this:
x = "%s-%s-%s %s:%s:00"%(dt.year,dt.month,dt.day,dt.hour,dt.minute)
dict[x] +=a1
But it gives me an error like this:
KeyError: '2015-11-26 8:47:00'
If I try print type(x) it prints str
But if i try this:
dict = {}
x = "abc"
dict[x] = 1
print dict
it print to this:
{'abc': 1}
I don't understand what is the difference.
First error is that you named your dictionary dict. That name's
already being used; it's the name of the dictionary type. Overwriting an
existing name like this is called "shadowing". Don't do it, it will mess
you up.
You're using +=. This implies that there's already a value associated
with the key, which can be incremented. If that key isn't in the dict
yet, you get a KeyError.
You probably want to set a default value of zero. This can be done in
various ways. The simplest is:
d[x] = d.get(x, 0) + a1
Also see the collections standard library, which has a defaultdict
type.