predict_proba() Logistic Regression when predicting a single value - python-3.x

I want to use Logistic Regression to predict a class (-1 or +1) given a data set which I split as follows (only a single entry is to be predicted in the test set):
x_train, x_test = loc_indep[:-1], loc_indep[-1:]
y_train, y_test = loc_target[:-1], loc_target[-1:]
Then I use the following to train the model:
regr = LogisticRegression()
regr.fit(x_train, y_train)
predictions = regr.predict(x_test)
probabilities = regr.predict_proba(x_test)
print(probabilities) # prints probabilities
Given the above, the probabilities always prints either [1. 0.] or [0. 1.], meaning that either class +1 or class -1 are picked with the probability 100%. Why is this the case? I expected that the probabilities sum to 1, but that the model picks, say, class +1 with probability 54%.

Your code seems to be correct. So this means you have a supper accurate model (which makes me suspect that something is wrong...). I will recommend check your training data, maybe you have some variable, by error, that explains too much (for example the same output).
Also try to output the train an test accuracy. If train accuracy is 100% and test accuracy is much lower, you are over fitting. Then you will have to change some hyperparameters to avoid it.
To conclude, try to understand your data, maybe it's super easy to differentiate both classes, and maybe for this reason you obtain such a good model.

Related

Custom loss for single-label, multi-class problem

I have a single-label, multi-class classification problem, i.e., a given sample is in exactly one class (say, class 3), but for training purposes, predicting class 2 or 5 is still okay to not penalise the model that heavily.
For example, the ground truth for 1 sample is [0,1,1,0,1] of 5 classes, instead of a one-hot vector. This implies that, the model predicting any one (not necessarily all) of the above classes (2,3 or 5) is fine.
For every batch, the predicted output dimension is of the shape bs x n x nc, where bs is the batch size, n is the number of samples per point and nc is the number of classes. The ground truth is also of the same shape as the predicted tensor.
For every batch, I'm expecting my loss function to compare n tensors across nc classes and then average it across n.
Eg: When dimensions are 32 x 8 x 5000. There are 32 batch points in a batch (for bs=32). Each batch point has 8 vector points, and each vector point has 5000 classes. For a given batch point, I wish to compute loss across all (8) vector points, compute their average and do so for the rest of the batch points (32). Final loss would be loss over all losses from each batch point.
How can I approach designing such a loss function? Any help would be deeply appreciated
P.S.: Let me know if the question is ambiguous
One way to go about this was to use a sigmoid function on the network output, which removes the implicit interdependency between class scores that a softmax function has.
As for the loss function, you can then calculate the loss based on the highest prediction for any of your target classes and ignore all other class predictions. For your example:
# your model output
y_out = torch.tensor([[0.1, 0.2, 0.95, 0.1, 0.01]], requires_grad=True)
# class labels
y = torch.tensor([[0,1,1,0,1]])
since we only care about the highest class probability, we set all other class scores to the maximum value achieved for one of the classes:
class_mask = y == 1
max_class_score = torch.max(y_out[class_mask])
y_hat = torch.where(class_mask, max_class_score, y_out)
From which we can use a regular Cross-Entropy loss function
loss_fn = torch.nn.CrossEntropyLoss()
loss = loss_fn(y_hat, y.float())
loss.backward()
when inspecting the gradients, we see that this only updates the prediction that achieved the highest score as well ass all predictions outside of any of the classes.
>>> y_out.grad
tensor([[ 0.3326, 0.0000, -0.6653, 0.3326, 0.0000]])
Predictions for other target classes do not receive a gradient update. Note that if you have a very high ratio of possible classes, this might slow down your convergence.

GridSearchCv Pipeline MultiOutputClassifier with XGBoostClassifier - how to pass early_stopping_rounds and eval_set?

I want to do multioutput prediction of labels and continuous data. My data consists of time series, one 10 time-points series of 30 observables per sample. I want to predict 10 labels that are binary, and 5 that are continuous, based on this data.
For the sake of simplicity I have flattened the time series data - ending up with one row per sample.
Since there are many labels to predict about the same system, and since there exists relationships between these, I want to use MutliOutputPrediction to do so. My idea is to divide the task into two parts; one for MultiOutputClassification, another for MultiOutputRegression.
I generally like XGBoost and wish to use it for this task, but of course I want to prevent overfitting when doing so. So I have a piece of code as follows, and I wish to pass the early_stopping_rounds to the fit method of the XGBClassifier, but don't know how to.
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.33)
pipeline = Pipeline([
('imputer', SimpleImputer()), # XGBoost can deal with NaNs, but MultiOutputClassifier cannot
('classifier', MultiOutputClassifier(XGBClassifier()))
])
param_grid = dict(
classifier__estimator__n_estimators=[100], # this works
# classifier__estimator__early_stopping_rounds=[30], # needs to be passed to .fit
# classifier__estimator__scale_pos_weight=[scale_pos_weight], # XGBoostError: Invalid Parameter format for scale_pos_weight expect float
)
clf = GridSearchCV(estimator=pipeline, param_grid=param_grid, scoring='roc_auc', refit='roc_auc', cv=5, n_jobs=-1)
clf.fit(X_train, y_train[CLASSIFICATION_LABELS])
y_hat_proba = np.array(clf.predict_proba(X_test))
y_hat = pd.DataFrame(np.array([y_hat_proba[:, i, 0] for i in range(y_hat_proba.shape[1])]), columns=CLASSIFICATION_LABELS)
auc_roc_scores = np.array([roc_auc_score(y_test[label], (y_hat[label] > 0.5).astype(int)) for label in y_hat.columns])
print(f'average ROC AUC score: {np.mean(auc_roc_scores).round(3)}+/-{np.std(auc_roc_scores).round(3)}')
>>> average ROC AUC score: 0.499+/-0.002
I tried passing it to fit as follows:
classifier__estimator__early_stopping_rounds=30
classifier__early_stopping_rounds=30
I get AUC ROC scores of 0.5 on the labels, which means this clearly isn't working and hence why I want to pass the early_stopping_rounds parameter and the eval_set. I suppose that being able to pass scale_pos_weight could also be useful, but probably doesn't work for MultiOutput prediction. At the moment I get the feeling that this is not the way to go to solve this, and in case you agree I would appreciate alternative suggestions.

How to get a RMSE value

I already fit the equation. Now I want the RMSE value
q3_1=data1[['bedrooms', 'bathrooms', 'sqft_living', 'sqft_lot', 'floors', 'zipcode']]
q3_2=data1[['bedrooms', 'bathrooms', 'sqft_living', 'sqft_lot', 'floors','zipcode','condition','grade','waterfront','view','sqft_above','sqft_basement','yr_built','yr_renovated',
'lat', 'long','sqft_living15','sqft_lot15']]
reg = LinearRegression()
reg.fit(q3_1,data1.price)
reg.fit(q3_2,data1.price)
I am not able to proceed from here. I need the RMSE value in both the cases.
As I can understand, you are using TensorFlow on Google Colab.
I don't know exactly what is your LinearRegression object, but IĀ suppose that it is a Keras model with a single node.
Hence, I have a question, how do you train the same model (your reg instance) with datasets with different schema -- one with 6 columns, the other with 16?
By the way, during training/fitting, keras is able to give you the MSE of your epoch, as well as a validation MSE if you provide a validation dataset. Finally, you can use the evaluate method which:
Returns the loss value & metrics values for the model [...]
Just use the "mean_squared_error" metric.
Edit
As you are using scikit-learn you have to take care of the metric yourself.
You can use the predict method to get the predictions from your trained model against a dataset.
Then, there is the mean_squared_error metric which is straighforward to use.
train_x, train_y = data1.features[:-100], data1.price[:-100]
test_x, test_y = data1.features[-100:], data1.price[-100:]
reg = LinearRegression()
reg.fit(train_x, train_y)
predictions = reg.predict(test_x)
mse = sklearn.metrics.mean_squared_error(test_y, predictions)
print("RMSE: %s" % math.sqrt(mse))

Multi-label classification with class weights in Keras

I have a 1000 classes in the network and they have multi-label outputs. For each training example, the number of positive output is same(i.e 10) but they can be assigned to any of the 1000 classes. So 10 classes have output 1 and rest 990 have output 0.
For the multi-label classification, I am using 'binary-cross entropy' as cost function and 'sigmoid' as the activation function. When I tried this rule of 0.5 as the cut-off for 1 or 0. All of them were 0. I understand this is a class imbalance problem. From this link, I understand that, I might have to create extra output labels.Unfortunately, I haven't been able to figure out how to incorporate that into a simple neural network in keras.
nclasses = 1000
# if we wanted to maximize an imbalance problem!
#class_weight = {k: len(Y_train)/(nclasses*(Y_train==k).sum()) for k in range(nclasses)}
inp = Input(shape=[X_train.shape[1]])
x = Dense(5000, activation='relu')(inp)
x = Dense(4000, activation='relu')(x)
x = Dense(3000, activation='relu')(x)
x = Dense(2000, activation='relu')(x)
x = Dense(nclasses, activation='sigmoid')(x)
model = Model(inputs=[inp], outputs=[x])
adam=keras.optimizers.adam(lr=0.00001)
model.compile('adam', 'binary_crossentropy')
history = model.fit(
X_train, Y_train, batch_size=32, epochs=50,verbose=0,shuffle=False)
Could anyone help me with the code here and I would also highly appreciate if you could suggest a good 'accuracy' metric for this problem?
Thanks a lot :) :)
I have a similar problem and unfortunately have no answer for most of the questions. Especially the class imbalance problem.
In terms of metric there are several possibilities: In my case I use the top 1/2/3/4/5 results and check if one of them is right. Because in your case you always have the same amount of labels=1 you could take your top 10 results and see how many percent of them are right and average this result over your batch size. I didn't find a possibility to include this algorithm as a keras metric. Instead, I wrote a callback, which calculates the metric on epoch end on my validation data set.
Also, if you predict the top n results on a test dataset, see how many times each class is predicted. The Counter Class is really convenient for this purpose.
Edit: If found a method to include class weights without splitting the output.
You need a numpy 2d array containing weights with shape [number classes to predict, 2 (background and signal)].
Such an array could be calculated with this function:
def calculating_class_weights(y_true):
from sklearn.utils.class_weight import compute_class_weight
number_dim = np.shape(y_true)[1]
weights = np.empty([number_dim, 2])
for i in range(number_dim):
weights[i] = compute_class_weight('balanced', [0.,1.], y_true[:, i])
return weights
The solution is now to build your own binary crossentropy loss function in which you multiply your weights yourself:
def get_weighted_loss(weights):
def weighted_loss(y_true, y_pred):
return K.mean((weights[:,0]**(1-y_true))*(weights[:,1]**(y_true))*K.binary_crossentropy(y_true, y_pred), axis=-1)
return weighted_loss
weights[:,0] is an array with all the background weights and weights[:,1] contains all the signal weights.
All that is left is to include this loss into the compile function:
model.compile(optimizer=Adam(), loss=get_weighted_loss(class_weights))

Tensorflow- How to display accuracy rate for a linear regression model

I have a linear regression model that seems to work. I first load the data into X and the target column into Y, after that I implement the following...
X_train, X_test, Y_train, Y_test = train_test_split(
X_data,
Y_data,
test_size=0.2
)
rng = np.random
n_rows = X_train.shape[0]
X = tf.placeholder("float")
Y = tf.placeholder("float")
W = tf.Variable(rng.randn(), name="weight")
b = tf.Variable(rng.randn(), name="bias")
pred = tf.add(tf.multiply(X, W), b)
cost = tf.reduce_sum(tf.pow(pred-Y, 2)/(2*n_rows))
optimizer = tf.train.GradientDescentOptimizer(FLAGS.learning_rate).minimize(cost)
init = tf.global_variables_initializer()
init_local = tf.local_variables_initializer()
with tf.Session() as sess:
sess.run([init, init_local])
for epoch in range(FLAGS.training_epochs):
avg_cost = 0
for (x, y) in zip(X_train, Y_train):
sess.run(optimizer, feed_dict={X:x, Y:y})
# display logs per epoch step
if (epoch + 1) % FLAGS.display_step == 0:
c = sess.run(
cost,
feed_dict={X:X_train, Y:Y_train}
)
print("Epoch:", '%04d' % (epoch + 1), "cost=", "{:.9f}".format(c))
print("Optimization Finished!")
accuracy, accuracy_op = tf.metrics.accuracy(labels=tf.argmax(Y_test, 0), predictions=tf.argmax(pred, 0))
print(sess.run(accuracy))
I cannot figure out how to print out the model's accuracy. For example, in sklearn, it is simple, if you have a model you just print model.score(X_test, Y_test). But I do not know how to do this in tensorflow or if it is even possible.
I think I'd be able to calculate the Mean Squared Error. Does this help in any way?
EDIT
I tried implementing tf.metrics.accuracy as suggested in the comments but I'm having an issue implementing it. The documentation says it takes 2 arguments, labels and predictions, so I tried the following...
accuracy, accuracy_op = tf.metrics.accuracy(labels=tf.argmax(Y_test, 0), predictions=tf.argmax(pred, 0))
print(sess.run(accuracy))
But this gives me an error...
FailedPreconditionError (see above for traceback): Attempting to use uninitialized value accuracy/count
[[Node: accuracy/count/read = IdentityT=DT_FLOAT, _class=["loc:#accuracy/count"], _device="/job:localhost/replica:0/task:0/device:CPU:0"]]
How exactly does one implement this?
Turns out, since this is a multi-class Linear Regression problem, and not a classification problem, that tf.metrics.accuracy is not the right approach.
Instead of displaying the accuracy of my model in terms of percentage, I instead focused on reducing the Mean Square Error (MSE) instead.
From looking at other examples, tf.metrics.accuracy is never used for Linear Regression, and only classification. Normally tf.metric.mean_squared_error is the right approach.
I implemented two ways of calculating the total MSE of my predictions to my testing data...
pred = tf.add(tf.matmul(X, W), b)
...
...
Y_pred = sess.run(pred, feed_dict={X:X_test})
mse = tf.reduce_mean(tf.square(Y_pred - Y_test))
OR
mse = tf.metrics.mean_squared_error(labels=Y_test, predictions=Y_pred)
They both do the same but obviously the second approach is more concise.
There's a good explanation of how to measure the accuracy of a Linear Regression model here.
I didn't think this was clear at all from the Tensorflow documentation, but you have to declare the accuracy operation, and then initialize all global and local variables, before you run the accuracy calculation:
accuracy, accuracy_op = tf.metrics.accuracy(labels=tf.argmax(Y_test, 0), predictions=tf.argmax(pred, 0))
# ...
init_global = tf.global_variables_initializer
init_local = tf.local_variables_initializer
sess.run([init_global, init_local])
# ...
# run accuracy calculation
I read something on Stack Overflow about the accuracy calculation using local variables, which is why the local variable initializer is necessary.
After reading the complete code you posted, I noticed a couple other things:
In your calculation of pred, you use
pred = tf.add(tf.multiply(X, W), b). tf.multiply performs element-wise multiplication, and will not give you the fully connected layers you need for a neural network (which I am assuming is what you are ultimately working toward, since you're using TensorFlow). To implement fully connected layers, where each layer i (including input and output layers) has ni nodes, you need separate weight and bias matrices for each pair of successive layers. The dimensions of the i-th weight matrix (the weights between the i-th layer and the i+1-th layer) should be (ni, ni + 1), and the i-th bias matrix should have dimensions (ni + 1, 1). Then, going back to the multiplication operation - replace tf.multiply with tf.matmul, and you're good to go. I assume that what you have is probably fine for a single-class linear regression problem, but this is definitely the way you want to go if you plan to solve a multiclass regression problem or implement a deeper network.
Your weight and bias tensors have a shape of (1, 1). You give the variables the initial value of np.random.randn(), which according to the documentation, generates a single floating point number when no arguments are given. The dimensions of your weight and bias tensors need to be supplied as arguments to np.random.randn(). Better yet, you can actually initialize these to random values in Tensorflow: W = tf.Variable(tf.random_normal([dim0, dim1], seed = seed) (I always initialize random variables with a seed value for reproducibility)
Just a note in case you don't know this already, but non-linear activation functions are required for neural networks to be effective. If all your activations are linear, then no matter how many layers you have, it will reduce to a simple linear regression in the end. Many people use relu activation for hidden layers. For the output layer, use softmax activation for multiclass classification problems where the output classes are exclusive (i.e., where only one class can be correct for any given input), and sigmoid activation for multiclass classification problems where the output classes are not exlclusive.

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