Is there any comfortable way to get value from Vec<Vec<T>>? I can do it for a normal 1D Vec: vec.get(), but if vec is Vec<Vec>, get returns the Some<Vec<T>>, not the value of T. Is there a nice way to 'get' value from 2D matrix (Vec<Vec<T>>)?
Option::and_then lets you chain optional return values (o.and_then(f) is equivalent to o.map(f).flatten()):
vec.get(i).and_then(|v| v.get(j))
It also easily extends to higher dimensions:
vec
.get(i)
.and_then(|v| v.get(j))
.and_then(|v| v.get(k))
.and_then(|v| v.get(l))
// and so on
#Aplet123 is of course right, that's the way to go and his answer should be marked correct.
But in case you wonder how to make this prettier, you could wrap it in a custom trait for Vec<Vec<T>>:
trait Get2D {
type Val;
fn get2d(&self, i: usize, j: usize) -> Option<&Self::Val>;
fn get2d_mut(&mut self, i: usize, j: usize) -> Option<&mut Self::Val>;
}
impl<T> Get2D for Vec<Vec<T>> {
type Val = T;
fn get2d(&self, i: usize, j: usize) -> Option<&T> {
self.get(i).and_then(|e| e.get(j))
}
fn get2d_mut(&mut self, i: usize, j: usize) -> Option<&mut T> {
self.get_mut(i).and_then(|e| e.get_mut(j))
}
}
fn main() {
let mut data: Vec<Vec<i32>> = vec![vec![1, 2, 3], vec![4, 5, 6]];
println!("{}", data.get2d(1, 1).unwrap());
*data.get2d_mut(0, 1).unwrap() = 42;
println!("{:?}", data);
}
5
[[1, 42, 3], [4, 5, 6]]
I would like to do the following and allow my perform function to take an iterator with &usize or with usize items as below.
fn perform<'a, I>(values: I) -> usize
where
I: Iterator<Item = &'a usize>,
{
*values.max().unwrap()
}
fn main() {
let v: Vec<usize> = vec![1, 2, 3, 4];
// Works.
let result = perform(v.iter());
print!("Result: {}", result);
// Does not work: `expected `&usize`, found `usize``.
let result = perform(v.iter().map(|v| v * 2));
print!("Result again: {}", result)
}
Playground example here.
In this case, by making your function more polymorphic, we actually get the behavior for free. Your perform works for any Ord value.
fn perform<'a, I, T>(values: I) -> T
where
I: Iterator<Item = T>,
T: Ord,
{
values.max().unwrap()
}
Now usize is Ord and so is &usize (by a blanket impl that makes references to any orderable type orderable).
Another way may be accepting owned values in perform like this:
fn perform<I>(values: I) -> usize
where
I: Iterator<Item = usize>,
{
values.max().unwrap()
}
fn main() {
let v: Vec<usize> = vec![1, 2, 3, 4];
// Works.
let result = perform(v.iter().map(|x| *x));
print!("Result: {}", result);
// Does not work: `expected `&usize`, found `usize``.
let result = perform(v.iter().map(|v| v * 2));
print!("Result again: {}", result)
}
In python I can write the following to iterate by tuples.
it = iter(range(10))
zip(it, it) # [(0, 1), (2, 3), (4, 5), (6, 7), (8, 9)]
Rust wouldn't let me borrow iterator twice (or use same iterator twice because of the move).
let mut i1 = a.iter();
let i2 = &mut i1;
i1.zip(i2).for_each(|(a, b)| println!("a: {}, b: {}", a, b));
I know about itertools crate, I just wonder if there's some hack that would allow me to get by without it if I only need this functionality.
Obviously you can do something like that.
struct Chunks<I: Iterator<Item = T, T> {
seq: I,
}
impl<I: Iterator<Item = T>, T> Iterator for Chunks<I, T> {
type Item = (T, T);
fn next(&mut self) -> Option<Self::Item> {
self.seq.next().zip(self.seq.next())
}
}
But that works only for tuples and not for triples. Triples would require some kind of macroses.
With std::iter::from_fn you can create one-liner (thanks to #user4815162342).
let mut seq = a.iter();
let chunks = std::iter::from_fn(move || seq.next().zip(seq.next()));
chunks.for_each(|(a, b)| println!("a: {}, b: {}", a, b));
This could be achieved with interior mutability. Note that it is only the next method call that requires a mutable borrow.
use std::cell::RefCell;
struct CellIter<I: Iterator>(RefCell<I>);
impl<I: Iterator> CellIter<I> {
pub fn new(iter: I) -> Self {
Self(RefCell::new(iter))
}
}
impl<I: Iterator> Iterator for &CellIter<I> {
type Item = <I as Iterator>::Item;
fn next(&mut self) -> Option<Self::Item> {
self.0.borrow_mut().next()
}
}
fn main() {
let a = CellIter::new(0..10);
let i1 = &a;
let i2 = &a;
i1.zip(i2).for_each(|(a, b)| println!("a: {}, b: {}", a, b));
}
Output:
a: 0, b: 1
a: 2, b: 3
a: 4, b: 5
a: 6, b: 7
a: 8, b: 9
Here is a solution based on the same idea as Alsein's solution (using a RefCell), but somewhat shorter using std::iter::from_fn as helper:
use std::cell::RefCell;
fn share<T>(iter: impl Iterator<Item = T>) -> impl Fn() -> Option<T> {
let wrapped_iter = RefCell::new(iter);
move || wrapped_iter.borrow_mut().next()
}
fn main() {
let a = share(0..10);
let i1 = std::iter::from_fn(&a);
let i2 = std::iter::from_fn(&a);
i1.zip(i2).for_each(|(a, b)| println!("a: {}, b: {}", a, b));
}
You can use slice windows rather than zipping the iterators: https://doc.rust-lang.org/std/slice/struct.Windows.html
I'm trying to zip two iterators of unequal length, it only returns when when there is value in both and ignores the rest in the longest iterator.
fn main() {
let num1 = vec![1, 2];
let num2 = vec![3];
for i in num1.iter().rev().zip(num2.iter().rev()) {
println!("{:?}", i);
}
}
This returns (2, 3). How do i make it return:
(2, 3)
(1, 0) // default is the 0 here.
Is there any other way to do it?
You could use the zip_longest provided by the itertools crate.
use itertools::{
Itertools,
EitherOrBoth::*,
};
fn main() {
let num1 = vec![1, 2];
let num2 = vec![3];
for pair in num1.iter().rev().zip_longest(num2.iter().rev()) {
match pair {
Both(l, r) => println!("({:?}, {:?})", l, r),
Left(l) => println!("({:?}, 0)", l),
Right(r) => println!("(0, {:?})", r),
}
}
}
Which would produce the following output:
(2, 3)
(1, 0)
Zip will stop as soon as one of iterators stops producing values. If you know which is the longest, you can pad the shorter one with your default value:
use std::iter;
fn main() {
let longer = vec![1, 2];
let shorter = vec![3];
for i in longer
.iter()
.rev()
.zip(shorter.iter().rev().chain(iter::repeat(&0)))
{
println!("{:?}", i);
}
}
If you don't know which is longest, you should use itertools, as Peter Varo suggests.
The key is to detect that one iterator is shorter then the other, you could do it before before in your case vector implement ExactSizeIterator but a general solution would be to have a custom .zip().
itertools already offer a general solution, .zip_longest():
use itertools::EitherOrBoth::{Both, Left, Right};
use itertools::Itertools;
fn main() {
let num1 = vec![1, 2];
let num2 = vec![3];
for i in num1
.iter()
.rev()
.zip_longest(num2.iter().rev())
.map(|x| match x {
Both(a, b) => (a, b),
Left(a) => (a, &0),
Right(b) => (&0, b),
})
{
println!("{:?}", i);
}
}
This require you write the closure everytime, if you need this feature a lot maybe implement a custom trait on iterator with .zip_default() where A and B implement Default:
use std::default::Default;
use std::iter::Fuse;
pub trait MyIterTools: Iterator {
fn zip_default<J>(self, other: J) -> ZipDefault<Self, J::IntoIter>
where
J: IntoIterator,
Self: Sized,
{
ZipDefault::new(self, other.into_iter())
}
}
#[derive(Clone, Debug)]
pub struct ZipDefault<I, J> {
i: Fuse<I>,
j: Fuse<J>,
}
impl<I, J> ZipDefault<I, J>
where
I: Iterator,
J: Iterator,
{
fn new(i: I, j: J) -> Self {
Self {
i: i.fuse(),
j: j.fuse(),
}
}
}
impl<T, U, A, B> Iterator for ZipDefault<T, U>
where
T: Iterator<Item = A>,
U: Iterator<Item = B>,
A: Default,
B: Default,
{
type Item = (A, B);
fn next(&mut self) -> Option<Self::Item> {
match (self.i.next(), self.j.next()) {
(Some(a), Some(b)) => Some((a, b)),
(Some(a), None) => Some((a, B::default())),
(None, Some(b)) => Some((A::default(), b)),
(None, None) => None,
}
}
}
impl<T: ?Sized> MyIterTools for T where T: Iterator {}
fn main() {
let num1 = vec![1, 2];
let num2 = vec![3];
for i in num1
.iter()
.copied()
.rev()
.zip_default(num2.iter().copied().rev())
{
println!("{:?}", i);
}
}
Using itertools we can delegate some logic:
use std::default::Default;
use itertools::Itertools;
use itertools::ZipLongest;
use itertools::EitherOrBoth::{Both, Left, Right};
pub trait MyIterTools: Iterator {
fn zip_default<J>(self, j: J) -> ZipDefault<Self, J::IntoIter>
where
Self: Sized,
J: IntoIterator,
{
ZipDefault::new(self, j.into_iter())
}
}
#[derive(Clone, Debug)]
pub struct ZipDefault<I, J> {
inner: ZipLongest<I, J>,
}
impl<I, J> ZipDefault<I, J>
where
I: Iterator,
J: Iterator,
{
fn new(i: I, j: J) -> Self {
Self {
inner: i.zip_longest(j),
}
}
}
impl<T, U, A, B> Iterator for ZipDefault<T, U>
where
T: Iterator<Item = A>,
U: Iterator<Item = B>,
A: Default,
B: Default,
{
type Item = (A, B);
fn next(&mut self) -> Option<Self::Item> {
match self.inner.next()? {
Both(a, b) => Some((a, b)),
Left(a) => Some((a, B::default())),
Right(b) => Some((A::default(), b)),
}
}
fn size_hint(&self) -> (usize, Option<usize>) {
self.inner.size_hint()
}
}
impl<T: ?Sized> MyIterTools for T where T: Iterator {}
fn main() {
let num1 = vec![1, 2];
let num2 = vec![3];
for i in num1
.iter()
.copied()
.rev()
.zip_default(num2.iter().copied().rev())
{
println!("{:?}", i);
}
}
I saw this neat trick in other guy code in leetcode solution. If you have access to length, you can swap iterators, making iter1 the longest.
fn main() {
let num1 = vec![1, 2];
let num2 = vec![3];
let mut iter1 = num1.iter();
let mut iter2 = num2.iter();
if iter1.len() < iter2.len(){
std::mem::swap(&mut iter1, &mut iter2);
} // now iter1 is the largest
for i in iter1.rev().zip(iter2.rev().chain(std::iter::repeat(&0))) {
println!("{:?}", i);
}
}
If you can get the length of the iterators, as is in this case, a quick and dirty way could be:
use std::iter::repeat;
fn main() {
let a = vec![1, 2, 3];
let b = vec![4, 5, 6, 7];
for i in a
.iter()
.rev()
.chain(repeat(&0).take(b.len().saturating_sub(a.len())))
.zip(
b.iter()
.rev()
.chain(repeat(&0).take(a.len().saturating_sub(b.len()))),
)
{
println!("{:?}", i);
}
}
You can also implement a trait containing a zip_default() using this approach:
pub trait MyIterTools<X: Default + Clone>: ExactSizeIterator<Item = X> {
fn zip_default<J, Y>(self, j: J) -> ZipDefault<Self, J::IntoIter, X, Y>
where
Self: Sized,
J: IntoIterator<Item = Y>,
J::IntoIter: ExactSizeIterator,
Y: Default + Clone,
{
ZipDefault::new(self, j.into_iter())
}
}
#[derive(Clone, Debug)]
pub struct ZipDefault<
I: ExactSizeIterator<Item = X>,
J: ExactSizeIterator<Item = Y>,
X: Default + Clone,
Y: Default + Clone,
> {
inner: Zip<Chain<I, Take<Repeat<X>>>, Chain<J, Take<Repeat<Y>>>>,
}
impl<
I: ExactSizeIterator<Item = X>,
J: ExactSizeIterator<Item = Y>,
X: Default + Clone,
Y: Default + Clone,
> ZipDefault<I, J, X, Y>
{
fn new(a: I, b: J) -> Self {
let a_len = a.len();
let b_len = b.len();
Self {
inner: a
.chain(repeat(X::default()).take(b_len.saturating_sub(a_len)))
.zip(b.chain(repeat(Y::default()).take(a_len.saturating_sub(b_len)))),
}
}
}
impl<
I: ExactSizeIterator<Item = X>,
J: ExactSizeIterator<Item = Y>,
X: Default + Clone,
Y: Default + Clone,
> Iterator for ZipDefault<I, J, X, Y>
{
type Item = (X, Y);
fn next(&mut self) -> Option<Self::Item> {
self.inner.next()
}
fn size_hint(&self) -> (usize, Option<usize>) {
self.inner.size_hint()
}
}
impl<T: ExactSizeIterator<Item = X>, X: Default + Clone> MyIterTools<X> for T {}
fn main() {
let a = vec![1, 2, 3];
let b = vec![4, 5, 6, 7];
a.into_iter()
.zip_default(b.into_iter())
.for_each(|i| println!("{:?}", i));
}
I'd like a method like Iterator::chain() that only computes the argument iterator when it's needed. In the following code, expensive_function should never be called:
use std::{thread, time};
fn expensive_function() -> Vec<u64> {
thread::sleep(time::Duration::from_secs(5));
vec![4, 5, 6]
}
pub fn main() {
let nums = [1, 2, 3];
for &i in nums.iter().chain(expensive_function().iter()) {
if i > 2 {
break;
} else {
println!("{}", i);
}
}
}
One possible approach: delegate the expensive computation to an iterator adaptor.
let nums = [1, 2, 3];
for i in nums.iter()
.cloned()
.chain([()].into_iter().flat_map(|_| expensive_function()))
{
if i > 2 {
break;
} else {
println!("{}", i);
}
}
Playground
The passed iterator is the result of flat-mapping a dummy unit value () to the list of values, which is lazy. Since the iterator needs to own the respective outcome of that computation, I chose to copy the number from the array.
You can create your own custom iterator adapter that only evaluates a closure when the original iterator is exhausted.
trait IteratorExt: Iterator {
fn chain_with<F, I>(self, f: F) -> ChainWith<Self, F, I::IntoIter>
where
Self: Sized,
F: FnOnce() -> I,
I: IntoIterator<Item = Self::Item>,
{
ChainWith {
base: self,
factory: Some(f),
iterator: None,
}
}
}
impl<I: Iterator> IteratorExt for I {}
struct ChainWith<B, F, I> {
base: B,
factory: Option<F>,
iterator: Option<I>,
}
impl<B, F, I> Iterator for ChainWith<B, F, I::IntoIter>
where
B: Iterator,
F: FnOnce() -> I,
I: IntoIterator<Item = B::Item>,
{
type Item = I::Item;
fn next(&mut self) -> Option<Self::Item> {
if let Some(b) = self.base.next() {
return Some(b);
}
// Exhausted the first, generate the second
if let Some(f) = self.factory.take() {
self.iterator = Some(f().into_iter());
}
self.iterator
.as_mut()
.expect("There must be an iterator")
.next()
}
}
use std::{thread, time};
fn expensive_function() -> Vec<u64> {
panic!("You lose, good day sir");
thread::sleep(time::Duration::from_secs(5));
vec![4, 5, 6]
}
pub fn main() {
let nums = [1, 2, 3];
for i in nums.iter().cloned().chain_with(|| expensive_function()) {
if i > 2 {
break;
} else {
println!("{}", i);
}
}
}